MCQ Questions for Class 12 Maths Chapter 2 Inverse Trigonometric Functions with Answers

Students can access the NCERT MCQ Questions for Class 12 Maths Chapter 2 Inverse Trigonometric Functions with Answers Pdf free download aids in your exam preparation and you can get a good hold of the chapter. Use MCQ Questions for Class 12 Maths with Answers during preparation and score maximum marks in the exam. Students can download the Inverse Trigonometric Functions Class 12 MCQs Questions with Answers from here and test their problem-solving skills. Clear all the fundamentals and prepare thoroughly for the exam taking help from Class 12 Maths Chapter 2 Inverse Trigonometric Functions Objective Questions.

Inverse Trigonometric Functions Class 12 MCQs Questions with Answers

Students are advised to solve the Inverse Trigonometric Functions Multiple Choice Questions of Class 12 Maths to know different concepts. Practicing the MCQ Questions on Inverse Trigonometric Functions Class 12 with answers will boost your confidence thereby helping you score well in the exam.

Explore numerous MCQ Questions of Inverse Trigonometric Functions Class 12 with answers provided with detailed solutions by looking below.

Question 1.
If sin-1 x + sin-1 y = \(\frac { 2π }{3}\), then the value of cos-1 x + cos-1 y is
(a) \(\frac { 2π }{3}\)
(b) \(\frac { π }{3}\)
(c) \(\frac { π }{2}\)
(d) π

Answer

Answer: (b) \(\frac { π }{3}\)


Question 2.
tan-1 (√3) – sec-1(-2) is equal to:
(a) π
(b) –\(\frac { π }{3}\)
(c) \(\frac { π }{3}\)
(d) \(\frac { 2π }{3}\)

Answer

Answer: (b) –\(\frac { π }{3}\)


Question 3.
cos-1 (cos \(\frac { 7π }{6}\)) is equal to
(a) \(\frac { 7π }{6}\)
(b) –\(\frac { 5π }{6}\)
(c) \(\frac { π }{3}\)
(d) \(\frac { π }{6}\)

Answer

Answer: (b) –\(\frac { 5π }{6}\)


Question 4.
sin(\(\frac { π }{3}\) – sin-1(-\(\frac { 1 }{2}\))) is equal to
(a) \(\frac { 1 }{2}\)
(b) \(\frac { 1 }{3}\)
(c) \(\frac { 1 }{4}\)
(d) 1

Answer

Answer: (d) 1


Question 5.
tan-1 √3 – cot-1(-√3) is equal to
(a) π
(b) –\(\frac { π }{2}\)
(c) 0
(d) 2√3

Answer

Answer: (b) –\(\frac { π }{2}\)


Question 6.
sin (tan-1 x), |x| < 1, is equal to
(a) \(\frac { x }{\sqrt{1-x^2}}\)
(b) \(\frac { 1 }{\sqrt{1-x^2}}\)
(c) \(\frac { x }{\sqrt{1+x^2}}\)
(d) \(\frac { x }{\sqrt{1+x^2}}\)

Answer

Answer: (d) \(\frac { x }{\sqrt{1+x^2}}\)


Question 7.
sin-1 (1 – x) – 2 sin-1 x = \(\frac { π }{2}\), then x is equal to
(a) 0, \(\frac { 1 }{2}\)
(b) 1, \(\frac { 1 }{2}\)
(c) 0
(d) \(\frac { 1 }{2}\)

Answer

Answer: (c) 0


Question 8.
tan-1 (\(\frac { x }{y}\)) – tan-1 \(\frac { x-y }{x+y}\) is equal to
(a) \(\frac { π }{2}\)
(b) \(\frac { π }{3}\)
(c) \(\frac { π }{4}\)
(d) –\(\frac { 3π }{4}\)

Answer

Answer: (c) \(\frac { π }{4}\)


Question 9.
The value of sin-1(cos(\(\frac { 43π }{5}\))) is
(a) \(\frac { 3π }{5}\)
(b) \(\frac { -7π }{5}\)
(c) \(\frac { π }{10}\)
(d) –\(\frac { -π }{10}\)

Answer

Answer: (d) –\(\frac { -π }{10}\)


Question 10.
The principal value of the expression
cos-1 [cos (-680°)] is
(a) \(\frac { 2π }{9}\)
(b) \(\frac { -2π }{9}\)
(c) \(\frac {34π }{9}\)
(d) –\(\frac { π }{9}\)

Answer

Answer: (a) \(\frac { 2π }{9}\)


Question 11.
The value of cot (sin-1x) is
(a) \(\frac { \sqrt{1+x^2} }{x}\)
(b) \(\frac { x }{\sqrt{1+x^2}}\)
(c) \(\frac {1}{x}\)
(d) \(\frac { \sqrt{1-x^2} }{x}\)

Answer

Answer: (d) \(\frac { \sqrt{1-x^2} }{x}\)


Question 12.
The domain of sin-1 2x is
(a) [0, 1]
(b) [-1, 1]
(c) [\(\frac {-1}{2}\), \(\frac {1}{2}\)]
(d) [-2, 2]

Answer

Answer: (c) [\(\frac {-1}{2}\), \(\frac {1}{2}\)]


Question 13.
The greatest and least values of (sin-1 x)² + (cos-1x)² are respectively
(a) \(\frac { 5π^2 }{4}\) and \(\frac { π^2 }{8}\)
(b) \(\frac { π }{2}\) and \(\frac { -π }{2}\)
(c) \(\frac { π^2 }{4}\) and \(\frac { -π^2 }{4}\)
(d) –\(\frac { π^2 }{4}\) and 0

Answer

Answer: (a) \(\frac { 5π^2 }{4}\) and \(\frac { π^2 }{8}\)


Question 14.
If cos-1 x – cos-1 — = α, then 4x² – 4xy cos α + y² is equal to:
(a) 4
(b) 2 sin² α
(c) -4 sin² α
(d) 4 sin² α.

Answer

Answer: (d) 4 sin² α.
Hint:
MCQ Questions for Class 12 Maths Chapter 2 Inverse Trigonometric Functions with Answers 1
Squaring, 4x² + y² cos² α – 4xy cos α
= 4 sin² α – y² sin² α
⇒ 4x² – 4xy cos α + y² = 4 sin² α.


Question 15.
If sin-1 (\(\frac {5}{4}\)) = \(\frac {π}{2}\), then the value of x is
(a) 3
(b) 4
(c) 5
(d) 1

Answer

Answer: (a) 3
Hint:
MCQ Questions for Class 12 Maths Chapter 2 Inverse Trigonometric Functions with Answers 2


Question 16.
The value of cot (cosec-1\(\frac {5}{3}\) + tan-1\(\frac {2}{3}\)) is
(a) \(\frac { 5 }{17}\)
(b) \(\frac { 6 }{17}\)
(c) \(\frac { 3 }{17}\)
(d) \(\frac { 4 }{17}\)

Answer

Answer: (b) \(\frac { 6 }{17}\)
Hint:
MCQ Questions for Class 12 Maths Chapter 2 Inverse Trigonometric Functions with Answers 3


Question 17.
If tan-1 y = tan-1 x + tan-1(\(\frac { 2x }{1-x^2}\)) when |x| < \(\frac { 1 }{√3}\), then the value of y is:
(a) \(\frac { 3x-x^3 }{1-3x^2}\)
(b) \(\frac { 3x+x^3 }{1-3x^2}\)
(c) \(\frac { 3x-x^3 }{1+3x^2}\)
(d) \(\frac { 3x+x^3 }{1+3x^2}\)

Answer

Answer: (a) \(\frac { 3x-x^3 }{1-3x^2}\)
Hint:
MCQ Questions for Class 12 Maths Chapter 2 Inverse Trigonometric Functions with Answers 4


Fill in the blanks

Question 1.
Principal value of sin-1 (-\(\frac {1}{2}\)) is ………………

Answer

Answer: –\(\frac {π}{6}\)


Question 2.
Principal value of sin-1 (-\(\frac {1}{√2}\)) is ……………….

Answer

Answer: \(\frac {-π}{4}\)


Question 3.
Principal value of cos-1 (\(\frac {-1}{2}\)) is ………………

Answer

Answer: \(\frac {2π}{3}\)


Question 4.
Principal value of tan-1 (-√3) is …………………

Answer

Answer: –\(\frac {π}{3}\)


Question 5.
Principal value of tan-1 (-1) is ……………..

Answer

Answer: –\(\frac {π}{4}\)


Question 6.
Principal value of cot-1 (√3) is ……………….

Answer

Answer: \(\frac {π}{6}\)


Question 7.
Principal value of cosec-1 (-√2) is ……………..

Answer

Answer: –\(\frac {π}{4}\)


Question 8.
sin-1 x + cos-1 x = ………………

Answer

Answer: \(\frac {π}{2}\)


Question 9.
tan-1 x + cot-1 x = ………………..

Answer

Answer: \(\frac {π}{2}\)


Question 10.
sec-1 x + cosec-1 x = ……………….

Answer

Answer: \(\frac {π}{2}\)


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