These NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3 Questions and Answers are prepared by our highly skilled subject experts.
NCERT Solutions for Class 6 Maths Chapter 6 Integers Exercise 6.3
Question 1.
Find:
(a) 35 – (20) = ……………..
(b) 72-(90) = ………………
(c) (-15)-(-18) = ………………..
(d) (-20)-(13) = ………………….
(e) 23-(-12) = ……………………
(f) (-32) – (-40) = ……………………..
Answer:
(a) 35 – (20) = 15
(b) 72-(90) = -18
(c) (-15)-(-18) = -15+ 18 = 3
(d) (-20)-(13) = -20- 13 = -33
(e) 23-(-12) = 23 + 12 = 35
(f) (-32) – (-40) = -32 + 40 = 8
Question 2.
Fill in the blanks with >, < or = sign:
Answer:
(a) (-3) + (-6) ………….. (-3) – (-6)
(b) (-21) – ( – 10) ………….. (-31) + (-11)
(c) 45 – (-11) ………….. 57 +(-4)
(d) (-25) – (-42) ………….. (-42) – (-25)
Answer:
(a) (-3) + (-6) < (-3) – (-6)
(b) (-21) – ( – 10) > (-31) + (-11)
(c) 45 – (-11) > 57 +(-4)
(d) (-25) – (-42)_>_ (-42) – (-25)
Question 3.
Fill in the blanks:
(a) (-8) + ……….. = 0
(b) 13 + ……….. =0
(c) 12 + ……….. = 0
(d) (-4) + ……….. =-12
(e) ……….. – 15 = -10
Answer:
(a) (-8) + 8 = 0
(b) 13+ (-13) =0
(c) 12+ (-12) =0
(d) (-4) + (-8) =-12
(e) 5 – 15 = -10
Question 4.
Find:
(a) (-7)-8-(-25)
(b) (-13)+ 32-8-1
(c) (-7) + (-8) + (-90)
(d) 50 – (-40) – (-2)
Answer:
(a) (-7) – 8 – (-25) = -7 – 8 + 25
= -15 + 25= 10
(b) (-13)+ 32-8-1
= -13 + 32 – 8 – 1 = 32 -22 = 10
(c) (-7) + (-8) + (-90) = -7 – 8 – 90 = -105
(d) 50 – (-40) – (-2) = 50 + 40 + 2 = 92