These NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.6 Questions and Answers are prepared by our highly skilled subject experts.
NCERT Solutions for Class 6 Maths Chapter 7 Fractions Exercise 7.6
Question 1.
Solve
Answer:
In these questions, the denominator is different, so we cannot simply add the numerator. We have to first find the LCM of the denominators and then convert each fraction into that form and then do numerators addition or subtraction.
Question 2.
Sarita bought \(\frac { 2 }{ 5 }\) metre of ribbon and Lalita \(\frac { 3 }{ 4 }\) metre of ribbon. What is the total length of the ribbon they bought?
Answer:
Length of ribbon Saria bought = \(\frac { 2 }{ 5 }\) metre
Length of ribbon Lalita bought = \(\frac { 3 }{ 4 }\) metre
Total length of ribbon = \(\frac{2}{5}+\frac{3}{4}\)
They bought \(\frac{23}{20}\) meters of ribbon together.
Question 3.
Naina was given 1\(\frac { 1 }{ 2 }\) piece of cake and Najma was given 1\(\frac { 1 }{ 3 }\) piece of cake.
Find the total amount of cake was given to both of them.
Answer:
Total amount of cake both have
= \(1 \frac{1}{2}+1 \frac{1}{3}\)
This is mixed fraction, converting into improper traction = \(\frac{3}{2}+\frac{4}{3}=\frac{17}{6}\)
So, they total have \(\frac{17}{6}\) pieces of cake.
Question 4.
Fill in the boxes:
Answer:
Question 5.
Complete the addition-subtraction box.
Answer:
Question 6.
A piece of wire \(\frac { 7 }{ 8 }\) metre long broke into two pieces. One piece was \(\frac { 1 }{ 4 }\) metre long.
How long is the other piece?
Answer:
Length of the piece of wire is = \(\frac { 7 }{ 8 }\) meter
Length of one broken piece is = \(\frac { 1 }{ 4 }\) meter
Length of the other broken piece = total length of the wire – length of one broken piece
= \(\frac{7}{8}-\frac{1}{4}=\frac{5}{8}\) m
Length of the piece of wire is \(\frac{5}{8}\) metre.
Question 7.
Nandini’s house is \(\frac { 9 }{ 10 }\) km from her school. She walked some distance and
then took a bus for \(\frac { 1 }{ 2 }\) km to reach the school. How far did she walk?
Answer:
Distance from Nandini’s house to school = \(\frac { 9 }{ 10 }\) km 10
Distance covered by bus = \(\frac { 1 }{ 2 }\) km
Distance she walked = distance from house to school – distance she covered by bus.
= \(\frac{9}{10}-\frac{1}{2}=\frac{4}{10}=\frac{2}{5}\) km
∴ Distance walked by Nandhini = \(\frac{2}{5}\) km.
Question 8.
Asha and Samuel have bookshelves of the same size partly filled with books.
Asha’s shelf is \(\frac{5}{6}\) th full and Samuel’s shelf is \(\frac{2}{5}\) th full. Whose bookshelf is more full? By what fraction?
Answer:
Fraction of books in Asha’s shelf = \(\frac{5}{6}\)
Fraction of books in Samuel’s shelf = \(\frac{2}{5}\)
We compare the fractions to find whose shelf is more full.
Since these are unlike fraction, we need to first find the LCM of 5 and 6 which is 30
Question 9.
Jaidev takes 2\(\frac{1}{5}\) minutes to walk across the school ground. Rahul takes \(\frac{7}{4}\) minutes to do the same. Who takes less time and by what fraction?
Answer:
Time taken by Jaidev to walk across the ground = \(\frac{1}{5}\) min
Time taken by Rahul to walk across the ground = \(\frac{7}{4}\) min
We compare the fractions to find who takes is less time
Since these are unlike fraction, we need to first find the LCM of 5 and 4 which is 20 11 44
So, Rahul takes lesser time than Jaidev.
Difference = \(\frac{11}{5}-\frac{7}{4}=\frac{9}{20}\)
So, Rahul takes lesser time than Jaidev, by \(\frac{9}{20}\)