NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1

These NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 Questions and Answers are prepared by our highly skilled subject experts.

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Exercise 2.1

Question 1.
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 1
Answer:
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 2
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 3

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1

Question 2.
(i) \(\frac{2}{9}, \frac{2}{3}, \frac{8}{21}\)
(ii) \(\frac{1}{5}, \frac{3}{7}, \frac{7}{10}\)
Answer:
(i) \(\frac{2}{9}, \frac{2}{3}, \frac{8}{21}\)
L.C.M of 9, 3 and 21 = 63
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 4
∴ The descending order is \(\frac{2}{3}, \frac{8}{21}, \frac{2}{9}\)

(ii) \(\frac{1}{5}, \frac{3}{7}, \frac{7}{10}\)
L.C.M of 5, 7 and 10 = 70
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 5
∴ The descending order is \(\frac{7}{10}, \frac{3}{7}, \frac{1}{5}\)

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1

Question 3.
In a ‘magic square the sum of the numbers in each row, in each column
and along the diagonals is the same. Is this a magic square?

\(\frac{4}{11}\) \(\frac{9}{11}\) \(\frac{2}{11}\)
\(\frac{3}{11}\) \(\frac{5}{11}\) \(\frac{7}{11}\)
\(\frac{8}{11}\) \(\frac{1}{11}\) \(\frac{6}{11}\)

(Along the first row \(\frac{4}{11}+\frac{9}{11}+\frac{2}{11}=\frac{15}{11}\))
Answer:
Sum of numbers along the
1strow = \(\frac{4}{11}+\frac{9}{11}+\frac{2}{11}\) = \(\frac{4+9+2}{11}\)
\(\frac{15}{11}\)
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 6
Since, the sum of numbers in each case is the same therefore, it is a magic square.

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1

Question 4.
A rectangular sheet of paper is 12\(\frac{1}{2}\) cm long and 10\(\frac{2}{3}\) cm wide. Find its perimeter.
Answer:
Length of a rectangle = 12\(\frac{1}{2}\) cm = \(\frac{25}{2}\) cm
Width of a rectangle = 10\(\frac{2}{3}\)cm = \(\frac{32}{3}\) cm
Perimeter of a rectangle = 2 (length + breadth)
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 7

Question 5.
Find the perimeters of (i) ΔABE (ii) the rectangle BCDE in this figure. Whose perimeter is greater?
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 8
Answer:
(i) Perimeter of ΔABE = AB + BE + AE
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 9

(ii) Perimeter of rectangle BCDE
= 2 [length + breadth]
= 2 [CD + DE]
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 10
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 11
Thus, the perimeter of ΔABE is greater.

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1

Question 6.
Salil wants to put a picture in a frame. The picture is 7\(\frac { 3 }{ 5 }\) cm wide. To fit in the frame the picture cannot be more than 7\(\frac { 3 }{ 10 }\) cm wide. How much should the picture be trimmed?
Answer:
Width of the picture = 7\(\frac { 3 }{ 5 }\)cm
\(\frac { 38 }{ 5 }\)cm
Required width of the picture
= 7\(\frac { 3 }{ 10 }\) cm = \(\frac { 73 }{ 10 }\) cm
The picture should be trimmed by
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 12
The picture should be trimmed by \(\frac { 3 }{ 10 }\) cm.

Question 7.
Ritu ate \(\frac { 3 }{ 5 }\) part of an apple and the remaining apple was eaten by her brother Somu. How much part of the apple did Somu eat? Who had the larger share? By how much?
Answer:
Ritu ate \(\frac { 3 }{ 5 }\) part of an apple, therefore part of the apple ate by Somu = 1 – \(\frac { 3 }{ 5 }\)
= \(\frac{5-3}{5}=\frac{2}{5}\)
\(\frac{3}{5}>\frac{2}{5}\)
∴ Ritu had the larger share by = \(\frac{3}{5}-\frac{2}{5}\)
= \(\frac{3-2}{5}=\frac{1}{5}\)
Thus, Ritu had the larger share by \(\frac{1}{5}\) part of an apple.

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1

Question 8.
Michael finished colouring a picture in \(\frac{7}{12}\) hour. Vaibhav finished colouring the
same picture in \(\frac{3}{4}\) hour. Who worked longer? By what fraction was it longer?
Answer:
Time taken by Michael = \(\frac{7}{12}\) hour
Time taken by Vaibhav = \(\frac{3}{4}\) hour.
NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.1 13
Thus, Vaibhav worked longer by \(\frac{1}{6}\) hour.

error: Content is protected !!