These NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.7 Questions and Answers are prepared by our highly skilled subject experts.

## NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Exercise 2.7

Question 1.

Find:

(i) 0.4 ÷ 2

(ii) 0.35 ÷ 5

(iii) 2.48 ÷ 4

(iv) 65.4 ÷ 6

(v) 651.2 ÷ 4

(vi) 14.49 ÷ 7

(vii) 3.96 ÷ 4

(viii) 0.80 ÷ 5

Question 2.

Find:

(1) 4.8 ÷ 10

(ii) 52.5 ÷ 10

(iii) 0.7 ÷ 10

(iv) 33.1 ÷ 10

(V) 272.23 ÷ 10

(vi) 0.56 ÷ 10

(vii) 3.97 ÷ 10

Answer:

Question 3.

Find:

(i) 2.7 ÷ 100

(ii) 0.3 ÷ 100

(iii) 0.78 ÷ 100

(iv) 432.6 ÷ 100

(v) 23.6 ÷ 100

(vi) 98.53 ÷ 100

Answer:

(i) 2.7 ÷ 100 \(\frac{2.7}{100}\)

There are two zeros in 100

∴ The decimal point in the quotient is shifted to the left by two places

∴ \(\frac{2.7}{100}\) = 0.027

(ii) 0.3 ÷ 100

There are two zeros in 100

∴ The decimal point in the quotient is shifted to the left by two places

∴ 0.3 ÷ 100 = \(\frac{0.3}{100}\) = 0.003

(iii) 0.78 ÷ 100

There are two zeros in 100

∴ The decimal point in the quotient is shifted to the left by two places

∴ 0.78 ÷ 100 = \(\frac{0.78}{100}\) = 0.0078

(iv) 432.6 ÷ 100

There are two zeros in 100

∴ The decimal point in the quotient is shifted to the left by two places

∴ 432.6 ÷ 100 = \(\frac{432.6}{100}\) = 4.326

(v) 23.6 ÷ 100

There are two zeros in 100

The decimal point in the quotient is shifted to the left by two places

∴ 23.6 ÷ 100 = \(\frac{23.6}{100}\) = 0.236

(vi) 98.53 ÷ 100

There are two zeros in 100

∴ The decimal point in the quotient is shifted to the left by two places

∵ 98.53 ÷ 100 = \(\frac{98.53}{100}\) = 0.9853

Question 4.

(i) 7.9 ÷ 1000

(ii) 26.3 ÷ 1000

(iii) 38.53 ÷ 1000

(iv) 128.9 ÷ 1000

(v) 0.5 ÷ 1000

Answer:

(i) 7.9 ÷ 1000 = \(\frac{7.9}{1000}\) = 0.0079

(ii) 26.3 ÷ 1000 = \(\frac{26.3}{1000}\) = 0.0263

(iii) 38.53 ÷ 1000 = \(\frac{38.53}{1000}\) = 0.03853

(iv) 128.9 ÷ 1000 = \(\frac{128.9}{1000}\) = 0.1289

(v) 0.5 ÷ 1000 = \(\frac{0.5}{1000}\) = 0.0005

Question 5.

(i) 7 ÷ 3.5

(ii) 36 ÷ 0.2

(iii) 3.25 ÷ 0.5

(iv) 30.94 ÷ 0.7

(v) 0.5 ÷ 0.25

(vi) 7.75 ÷ 0.25

(vii) 76.5 ÷ 0.15

(viii) 37.8 ÷ 1.4

(ix) 2.73 ÷ 1.3

Answer:

Question 6.

A vehicle covers a distance of 43.2 km in 2.4 litres of petrol. How much distance

will it cover in one litre of petrol?

Answer:

Total distance covered 43.2 km

Quantity of petrol used = 2.4 litres

∴ Distance covered in one litre petrol

= \(\frac{\text { Total distance covered }}{\text { Total quantity of petrol }}\)

= \(\frac{43.2}{2.4}\) km

= \(\frac{432 \times 10}{24 \times 10}=\frac{432}{24}\) = l8km

Distance covered in one litre of petrol = 18km