{"id":17289,"date":"2022-03-31T14:30:34","date_gmt":"2022-03-31T09:00:34","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=17289"},"modified":"2022-03-31T14:55:42","modified_gmt":"2022-03-31T09:25:42","slug":"ncert-solutions-for-class-12-geography-chapter-2-part-c","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-geography-chapter-2-part-c\/","title":{"rendered":"NCERT Solutions for Class 12 Geography Chapter 2 Data Processing"},"content":{"rendered":"
(iv) Which measure of dispersion is the most unstable statistic and why? \nAnswer: \nIt can be observed that the mean derived from the two data sets given as under is same i.e. 50. The highest and the lowest score shown as above table. A 55 and 45 respectively. The distribution in table B has a high score of 98 and a low score of zero. The range of first distribution is 10 whereas it is 98 in the second distribution. Although the mean for both the groups is same, the first group is obviously stable or homogenous as compared to the distribution of score of the second group which is highly unstable or heterogeneous.<\/p>\n
A. Scores of Individual<\/p>\n
\n\n
\n
Individual<\/strong><\/td>\n
Scores<\/strong><\/td>\n<\/tr>\n
\n
XI<\/td>\n
52<\/td>\n<\/tr>\n
\n
X2<\/td>\n
55<\/td>\n<\/tr>\n
\n
X3<\/td>\n
50<\/td>\n<\/tr>\n
\n
X4<\/td>\n
48<\/td>\n<\/tr>\n
\n
X5<\/td>\n
45<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
B. Scores of Individual<\/p>\n
\n\n
\n
Individual<\/strong><\/td>\n
Scores<\/strong><\/td>\n<\/tr>\n
\n
XI<\/td>\n
28<\/td>\n<\/tr>\n
\n
X2<\/td>\n
00<\/td>\n<\/tr>\n
\n
X3<\/td>\n
98<\/td>\n<\/tr>\n
\n
X4<\/td>\n
55<\/td>\n<\/tr>\n
\n
X5<\/td>\n
69<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
<\/p>\n
(v) Write a detailed note on the degree of correlation. \nAnswer: \nWhen reference has been made about the direction of correlation, negative or positive a natural curiosity arises to know the degree of correspondence or association of the two variables. The maximum degree of correspondence or relationship goes upto 1 (one) in mathematical terms. It can never be more than one.<\/p>\n
Correlation of 1 is known as perfect correlation (whether positive and negative). Between the two points of divergent perfect correlation lies 0 (zero) correlation a point of correlation or absence of any correlation between the variables.<\/p>\n
(vi) What are various steps for the calculation of rank order correlation? \nAnswer: \nThe following steps are as under for the calualtion of rank order correlation:<\/p>\n
\n
Copy the data related to X-Y variable given in the excercise and put them in the first and second column of the table.<\/li>\n
Both the variables are to be ranked separately. The ranks of X-variable are to be recorded in third column headed by XR \n(Rank-x). Similarly the ranks of Y-variables (YR) are to be recorded in the fourth column.<\/li>\n
Now since both XR and YR have been obtained find the difference between two sets of ranks and record it in the fifth column.<\/li>\n
Each of these difference is squared and sum of the column of square is obtained. This value is placed in sixth column.<\/li>\n
Then the computation of the rank correlation is done by the application of the following equation:<\/li>\n<\/ul>\n
\\(\\mathrm{P}=\\frac{6 \\Sigma \\mathrm{D}^{2}}{\\mathrm{~N}\\left(\\mathrm{~N}^{2}-1\\right)}\\) \nWhere P = Rank correlation \n\u03a3D2<\/sub> = Sura of the squares of the difference between two sets of ranks. \nN = The number of Pairs of X-Y<\/p>\n
Detailed, Step-by-Step NCERT Solutions for Class 12 Geography Chapter 2 Data Processing Questions and Answers were solved by Expert Teachers as per NCERT (CBSE) Book guidelines covering each topic in chapter to ensure complete preparation. https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-geography-chapter-2-part-c\/ Data Processing NCERT Solutions for Class 12 Geography Chapter 2 Data Processing Questions and Answers Class 12 Geography Chapter …<\/p>\n