{"id":17652,"date":"2022-05-25T14:11:29","date_gmt":"2022-05-25T08:41:29","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=17652"},"modified":"2022-05-17T11:01:34","modified_gmt":"2022-05-17T05:31:34","slug":"mcq-questions-for-class-11-chemistry-chapter-13","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/mcq-questions-for-class-11-chemistry-chapter-13\/","title":{"rendered":"MCQ Questions for Class 11 Chemistry Chapter 13 Hydrocarbons with Answers"},"content":{"rendered":"

Students are advised to practice the NCERT MCQ Questions for Class 11 Chemistry Chapter 13 Hydrocarbons with Answers Pdf free download is available here. MCQ Questions for Class 11 Chemistry with Answers<\/a> are prepared as per the Latest Exam Pattern. Students can solve these Hydrocarbons Class 11 MCQs Questions with Answers and assess their preparation level.<\/p>\n

Hydrocarbons Class 11 MCQs Questions with Answers<\/h2>\n

Solving the Hydrocarbons Multiple Choice Questions of Class 11 Chemistry Chapter 13 MCQ can be of extreme help as you will be aware of all the concepts. These MCQ Questions on Hydrocarbons Class 11 with answers pave for a quick revision of the Chapter thereby helping you to enhance subject knowledge. Have a glance at the MCQ of Chapter 13 Chemistry Class 11 and cross-check your answers during preparation.<\/p>\n

Question 1.
\nWhich of the following compounds will exhibit geometrical isomerism?
\n(a) 1 – Phenyl – 2 – butene
\n(b) 3 – Phenyl – 1 – butene
\n(c) 2 – Phenyl – 1 butene
\n(d) 1, 1 – Diphenyl – propene.<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) 1 – Phenyl – 2 – butene
\nExplanation:
\nC6<\/sub>H5<\/sub>CH2<\/sub>\u2212CH=CH\u2212CH3<\/sub> (1-phenyl-2-butene) exhibits the phenomenon of geometrical isomerism due to Cab<\/sub> = Cad<\/sub> structure, so its two isomers are possible which are given are follow:
\n\"MCQ<\/p>\n<\/details>\n

\n

Question 2.
\nHydrocarbon containing following bond is most reactive
\n(a) C \u2261 C
\n(b) C = C
\n(c) C – C
\n(d) All of these<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) C\u2261C
\nExplanation:
\n\u2212C\u2261C\u2212is most reactive because sp-hybridization.<\/p>\n<\/details>\n

\n

Question 3.
\nA gas decolourised by KMno4 solution but gives no precipitate with ammoniacal cuprous chloride is
\n(a) Ethene
\n(b) Propane
\n(c) Propene
\n(d) Methane<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) Ethene
\nExplanation:
\nA gas decolourised by KMno4 solution but gives no precipitate with ammoniacal cuprous chloride is Ethene<\/p>\n<\/details>\n

\n

Question 4.
\nA dibromo derivative of an alkane reacts with sodium metal to form an alicyclic hydrocarbon. The derivative is _______
\n(a) 1, 4-dibromobutane
\n(b) 1, 2-dibromoethane
\n(c) carbon
\n(d) none of the above<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) 1, 4-dibromobutane
\nExplanation:
\nA dibromo derivative of an alkane reacts with sodium metal to form an alicyclic hydrocarbon. The derivative is 1, 4-dibromobutane.<\/p>\n<\/details>\n

\n

Question 5.
\nReaction of HBr with propene in the presence of peroxide gives:
\n(a) 3 – Bromo propane
\n(b) Allyl bromide
\n(c) n – Propyl bromide
\n(d) Isoproyl bromide<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (c) n – Propyl bromide<\/p>\n<\/details>\n

\n

Question 6.
\nWhich branched chain isomer of the hydrocarbon with molecular mass 72u gives only one isomer of mono substituted alkyl halide?
\n(a) Neopentane
\n(b) Carbon
\n(c) Isohexane
\n(d) Neohexane<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) Neopentane
\nExplanation:
\nNeopentane chain isomer of the hydrocarbon with molecular mass 72u gives only one isomer of mono substituted alkyl halide.<\/p>\n<\/details>\n

\n

Question 7.
\nAromatic compounds burn with a sooty flame because?
\n(a) They have a ring structure of carbon atoms
\n(b) They have a relatively high percentage of hydrogen
\n(c) They have a relatively high percentage of carbon
\n(d) They resist reaction with oxygen of air<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (c) They have a relatively high percentage of carbon
\nExplanation:
\nDue to the high percentage of carbon, a lot of carbon remains unburnt and escapes as fine particles called soot.<\/p>\n<\/details>\n

\n

Question 8.
\nThe lowest alkene, that is capable of exhibiting geometrical isomerism is
\n(a) Ethene
\n(b) But – 1- ene
\n(c) But – 2 – ene
\n(d) Propene<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (c) But – 2 – ene
\nExplanation:
\nThe lowest alkene which is capable of exhibiting geometrical isomerism is 2-Butene<\/p>\n<\/details>\n

\n

Question 9.
\nWhich one of these is NOT TRUE for benzene?
\n(a) Heat of hydrogenation of benzene is less than the theoretical value
\n(b) There are three carbon-carbon single bonds and three carbon-carbon double bonds
\n(c) It forms only one type of monosubstituted product
\n(d) The bond angle between carbon-carbon bonds is 120o<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (b) There are three carbon-carbon single bonds and three carbon-carbon double bonds
\nExplanation:
\nThe structure of benzene is
\n\"MCQ
\nBond order = (number of bonds) \/(number of resonating structures) = (4\/3) = 1.33
\nSince, the bond order is in between single and double bond, thus it contains delocalised n bonds. Hence, it is not possible to obtain number of single and double bonds in benzene.
\n\"MCQ<\/p>\n<\/details>\n

\n

Question 10.
\nEthyl benzene cannot be prepared by _____.
\n(a) Wurtz Reaction
\n(b) Wurtz Fittig reaction
\n(c) Clemmensen Reduction
\n(d) Carbon<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) Wurtz Reaction
\nExplanation:
\nEthyl benzene cannot be prepared by Wurtz Reaction.<\/p>\n<\/details>\n

\n

Question 11.
\nPropyne on polymerization yields
\n(a) Mesitylene
\n(b) Benzene
\n(c) Ethyl benzene
\n(d) Propyl benzene.<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) Mesitylene
\nExplanation:
\nThis process is similar to the process of obtaining benzene by trimerisation of ethyne.If ethyne is substituted by propyne leading to the formation of mesitylene.
\n\"MCQ<\/p>\n<\/details>\n

\n

Question 12.
\nA gas decolourised by KMno4 solution but gives no precipitate with ammoniacal cuprous chloride is
\n(a) Ethene
\n(b) Propane
\n(c) Propene
\n(d) Methane<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) Ethene
\nExplanation:
\nA gas decolourised by KMno4 solution but gives no precipitate with ammoniacal cuprous chloride is Ethene<\/p>\n<\/details>\n

\n

Question 13.
\nAmong the following compounds the one that is most reactive towards electrophilic nitration is
\n(a) Toluene
\n(b) Benzene
\n(c) Benzoic Acid
\n(d) Nitrobenzene<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) Toluene
\nExplanation:
\nToluene contains electron donating methyl group which shows +I effect and increases the electron density on benzene ring thus making it suitable for electrophilic substitution reaction.<\/p>\n<\/details>\n

\n

Question 14.
\nHBr reacts with CH2<\/sub> = CH – OCH3<\/sub> under anhydrous conditions at room temperature to give
\n(a) CH3<\/sub>CHO and CH3<\/sub>Br
\n(b) BrCH2<\/sub>CHO and CH3<\/sub>OH
\n(c) BrCH2<\/sub> – CH2<\/sub> – OCH3<\/sub>
\n(d) H3<\/sub>C – CHBr – OCH3<\/sub><\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (d) H3<\/sub>C – CHBr – OCH3<\/sub>
\nExplanation:
\nMethyl vinyl ether is a very reactive gas. It is hydrolysed rapidly by dilute acids at room temperature to give methanol and aldehyde. However, under anhydrous conditions at room temperature, it undergoes many addition reactions at the double bond.
\n\"MCQ<\/p>\n<\/details>\n

\n

Question 15.
\nThe angle strain in cyclobutane is
\n(a) 24\u00b044
\n(b) 29\u00b016
\n(c) 19\u00b022
\n(d) 9\u00b044<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (d) 9\u00b044
\nExplanation:
\nAccording to Baeyers strain theory, the amount of the strain is directly proportional to the angle through which a valency bond has deviated from its normal position. i.e., Amount of deviation) in cyclobutane (d) = (109\u00b028 \u2212 90\u00b0)\/(2) = 9\u00b044<\/p>\n<\/details>\n

\n

Question 16.
\nThe lowest alkene, that is capable of exhibiting geometrical isomerism is
\n(a) Ethene
\n(b) But – 1- ene
\n(c) But – 2 – ene
\n(d) Propene.<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (c) But – 2 – ene
\nExplanation:
\nThe lowest alkene which is capable of exhibiting geometrical isomerism is 2-Butene<\/p>\n<\/details>\n

\n

Question 17.
\nA dibromo derivative of an alkane reacts with sodium metal to form an alicyclic hydrocarbon. The derivative is ______.
\n(a) 2, 2-dibromobutane
\n(b) 1, 1-dibromopropane
\n(c) 1, 4-dibromobutane
\n(d) 1, 2-dibromoethane<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (c) 1, 4-dibromobutane
\nExplanation:
\nThe derivative is 1,4 dibromobutane. This on reaction with sodium metal gives cyclobutane.
\n\"MCQ
\nThis reaction is an example of internal Wurtz reaction.<\/p>\n<\/details>\n

\n

Question 18.
\nPhenyl magnesium bromide reacts with methanol to give
\n(a) A mixture of Benzene and Mg(OME) Br
\n(b) A mixture of Propane and Mg(OME) Br
\n(c) A mixture of Methane and Mg(OME) Br
\n(d) All of the above<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) A mixture of Benzene and Mg(OME) Br
\nExplanation:
\nPhenyl magnesium bromide reacts with methanol to give a mixture of benzene and Mg(OME)Br.<\/p>\n<\/details>\n

\n

Question 19.
\nA gas decolourised by KMnO4<\/sub> solution but gives no precipitate with ammoniacal cuprous chloride is
\n(a) Ethane
\n(b) Methane
\n(c) Ethene
\n(d) Acetylene<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (c) Ethene
\nExplanation:
\nA gas decolourised by KMnO4<\/sub> solution but gives no precipitate with ammonical cuprous chloride is ethene CH2<\/sub> = CH2<\/sub>. Since it contains carbon-carbon double bond, it reacts with KMnO4<\/sub>. to form vicinal diol. Hence, KMnO4<\/sub> is decolourised.
\nCH2<\/sub> = CH2<\/sub> + H2<\/sub>O +(O) \u00e0 HO-CH2<\/sub>-CH2<\/sub>-OH
\nAcetylene gives a precipitate with ammonical cuprous chloride.<\/p>\n<\/details>\n

\n

Question 20.
\nWhen cyclohexane is poured on water, it floats because
\n(a) Cyclohexane is in boat form
\n(b) Cyclohexane is in chair form
\n(c) Cyclohexane is in crown fromorm
\n(d) Cyclohexane is less dense than water.<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (d) Cyclohexane is less dense than water.
\nExplanation:
\nAs alkanes and cycloalkanes are non-polar molecules and are insoluble in H2<\/sub>O they are also denser than H2<\/sub>O and that is why can float on water.<\/p>\n<\/details>\n

\n

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Students are advised to practice the NCERT MCQ Questions for Class 11 Chemistry Chapter 13 Hydrocarbons with Answers Pdf free download is available here. MCQ Questions for Class 11 Chemistry with Answers are prepared as per the Latest Exam Pattern. Students can solve these Hydrocarbons Class 11 MCQs Questions with Answers and assess their preparation …<\/p>\n

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