{"id":19215,"date":"2022-05-03T14:30:29","date_gmt":"2022-05-03T09:00:29","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=19215"},"modified":"2022-05-21T12:27:42","modified_gmt":"2022-05-21T06:57:42","slug":"mcq-questions-for-class-12-maths-chapter-2","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/mcq-questions-for-class-12-maths-chapter-2\/","title":{"rendered":"MCQ Questions for Class 12 Maths Chapter 2 Inverse Trigonometric Functions with Answers"},"content":{"rendered":"

Students can access the NCERT MCQ Questions for Class 12 Maths Chapter 2 Inverse Trigonometric Functions with Answers Pdf free download aids in your exam preparation and you can get a good hold of the chapter. Use MCQ Questions for Class 12 Maths with Answers<\/a> during preparation and score maximum marks in the exam. Students can download the Inverse Trigonometric Functions Class 12 MCQs Questions with Answers from here and test their problem-solving skills. Clear all the fundamentals and prepare thoroughly for the exam taking help from Class 12 Maths Chapter 2 Inverse Trigonometric Functions Objective Questions.<\/p>\n

Inverse Trigonometric Functions Class 12 MCQs Questions with Answers<\/h2>\n

Students are advised to solve the Inverse Trigonometric Functions Multiple Choice Questions of Class 12 Maths to know different concepts. Practicing the MCQ Questions on Inverse Trigonometric Functions Class 12 with answers will boost your confidence thereby helping you score well in the exam.<\/p>\n

Explore numerous MCQ Questions of Inverse Trigonometric Functions Class 12 with answers provided with detailed solutions by looking below.<\/p>\n

Question 1.
\nIf sin-1<\/sup> x + sin-1<\/sup> y = \\(\\frac { 2\u03c0 }{3}\\), then the value of cos-1<\/sup> x + cos-1<\/sup> y is
\n(a) \\(\\frac { 2\u03c0 }{3}\\)
\n(b) \\(\\frac { \u03c0 }{3}\\)
\n(c) \\(\\frac { \u03c0 }{2}\\)
\n(d) \u03c0<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (b) \\(\\frac { \u03c0 }{3}\\)<\/p>\n<\/details>\n

\n

Question 2.
\ntan-1<\/sup> (\u221a3) – sec-1<\/sup>(-2) is equal to:
\n(a) \u03c0
\n(b) –\\(\\frac { \u03c0 }{3}\\)
\n(c) \\(\\frac { \u03c0 }{3}\\)
\n(d) \\(\\frac { 2\u03c0 }{3}\\)<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (b) –\\(\\frac { \u03c0 }{3}\\)<\/p>\n<\/details>\n

\n

Question 3.
\ncos-1<\/sup> (cos \\(\\frac { 7\u03c0 }{6}\\)) is equal to
\n(a) \\(\\frac { 7\u03c0 }{6}\\)
\n(b) –\\(\\frac { 5\u03c0 }{6}\\)
\n(c) \\(\\frac { \u03c0 }{3}\\)
\n(d) \\(\\frac { \u03c0 }{6}\\)<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (b) –\\(\\frac { 5\u03c0 }{6}\\)<\/p>\n<\/details>\n

\n

Question 4.
\nsin(\\(\\frac { \u03c0 }{3}\\) – sin-1<\/sup>(-\\(\\frac { 1 }{2}\\))) is equal to
\n(a) \\(\\frac { 1 }{2}\\)
\n(b) \\(\\frac { 1 }{3}\\)
\n(c) \\(\\frac { 1 }{4}\\)
\n(d) 1<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (d) 1<\/p>\n<\/details>\n

\n

Question 5.
\ntan-1<\/sup> \u221a3 – cot-1<\/sup>(-\u221a3) is equal to
\n(a) \u03c0
\n(b) –\\(\\frac { \u03c0 }{2}\\)
\n(c) 0
\n(d) 2\u221a3<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (b) –\\(\\frac { \u03c0 }{2}\\)<\/p>\n<\/details>\n

\n

Question 6.
\nsin (tan-1<\/sup> x), |x| < 1, is equal to
\n(a) \\(\\frac { x }{\\sqrt{1-x^2}}\\)
\n(b) \\(\\frac { 1 }{\\sqrt{1-x^2}}\\)
\n(c) \\(\\frac { x }{\\sqrt{1+x^2}}\\)
\n(d) \\(\\frac { x }{\\sqrt{1+x^2}}\\)<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (d) \\(\\frac { x }{\\sqrt{1+x^2}}\\)<\/p>\n<\/details>\n

\n

Question 7.
\nsin-1<\/sup> (1 – x) – 2 sin-1<\/sup> x = \\(\\frac { \u03c0 }{2}\\), then x is equal to
\n(a) 0, \\(\\frac { 1 }{2}\\)
\n(b) 1, \\(\\frac { 1 }{2}\\)
\n(c) 0
\n(d) \\(\\frac { 1 }{2}\\)<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (c) 0<\/p>\n<\/details>\n

\n

Question 8.
\ntan-1<\/sup> (\\(\\frac { x }{y}\\)) – tan-1<\/sup> \\(\\frac { x-y }{x+y}\\) is equal to
\n(a) \\(\\frac { \u03c0 }{2}\\)
\n(b) \\(\\frac { \u03c0 }{3}\\)
\n(c) \\(\\frac { \u03c0 }{4}\\)
\n(d) –\\(\\frac { 3\u03c0 }{4}\\)<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (c) \\(\\frac { \u03c0 }{4}\\)<\/p>\n<\/details>\n

\n

Question 9.
\nThe value of sin-1<\/sup>(cos(\\(\\frac { 43\u03c0 }{5}\\))) is
\n(a) \\(\\frac { 3\u03c0 }{5}\\)
\n(b) \\(\\frac { -7\u03c0 }{5}\\)
\n(c) \\(\\frac { \u03c0 }{10}\\)
\n(d) –\\(\\frac { -\u03c0 }{10}\\)<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (d) –\\(\\frac { -\u03c0 }{10}\\)<\/p>\n<\/details>\n

\n

Question 10.
\nThe principal value of the expression
\ncos-1<\/sup> [cos (-680\u00b0)] is
\n(a) \\(\\frac { 2\u03c0 }{9}\\)
\n(b) \\(\\frac { -2\u03c0 }{9}\\)
\n(c) \\(\\frac {34\u03c0 }{9}\\)
\n(d) –\\(\\frac { \u03c0 }{9}\\)<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) \\(\\frac { 2\u03c0 }{9}\\)<\/p>\n<\/details>\n

\n

Question 11.
\nThe value of cot (sin-1<\/sup>x) is
\n(a) \\(\\frac { \\sqrt{1+x^2} }{x}\\)
\n(b) \\(\\frac { x }{\\sqrt{1+x^2}}\\)
\n(c) \\(\\frac {1}{x}\\)
\n(d) \\(\\frac { \\sqrt{1-x^2} }{x}\\)<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (d) \\(\\frac { \\sqrt{1-x^2} }{x}\\)<\/p>\n<\/details>\n

\n

Question 12.
\nThe domain of sin-1<\/sup> 2x is
\n(a) [0, 1]
\n(b) [-1, 1]
\n(c) [\\(\\frac {-1}{2}\\), \\(\\frac {1}{2}\\)]
\n(d) [-2, 2]<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (c) [\\(\\frac {-1}{2}\\), \\(\\frac {1}{2}\\)]<\/p>\n<\/details>\n

\n

Question 13.
\nThe greatest and least values of (sin-1<\/sup> x)\u00b2 + (cos-1<\/sup>x)\u00b2 are respectively
\n(a) \\(\\frac { 5\u03c0^2 }{4}\\) and \\(\\frac { \u03c0^2 }{8}\\)
\n(b) \\(\\frac { \u03c0 }{2}\\) and \\(\\frac { -\u03c0 }{2}\\)
\n(c) \\(\\frac { \u03c0^2 }{4}\\) and \\(\\frac { -\u03c0^2 }{4}\\)
\n(d) –\\(\\frac { \u03c0^2 }{4}\\) and 0<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) \\(\\frac { 5\u03c0^2 }{4}\\) and \\(\\frac { \u03c0^2 }{8}\\)<\/p>\n<\/details>\n

\n

Question 14.
\nIf cos-1<\/sup> x – cos-1<\/sup> \u2014 = \u03b1, then 4x\u00b2 – 4xy cos \u03b1 + y\u00b2 is equal to:
\n(a) 4
\n(b) 2 sin\u00b2 \u03b1
\n(c) -4 sin\u00b2 \u03b1
\n(d) 4 sin\u00b2 \u03b1.<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (d) 4 sin\u00b2 \u03b1.
\nHint:
\n\"MCQ
\nSquaring, 4x\u00b2 + y\u00b2 cos\u00b2 \u03b1 – 4xy cos \u03b1
\n= 4 sin\u00b2 \u03b1 – y\u00b2 sin\u00b2 \u03b1
\n\u21d2 4x\u00b2 – 4xy cos \u03b1 + y\u00b2 = 4 sin\u00b2 \u03b1.<\/p>\n<\/details>\n

\n

Question 15.
\nIf sin-1<\/sup> (\\(\\frac {5}{4}\\)) = \\(\\frac {\u03c0}{2}\\), then the value of x is
\n(a) 3
\n(b) 4
\n(c) 5
\n(d) 1<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) 3
\nHint:
\n\"MCQ<\/p>\n<\/details>\n

\n

Question 16.
\nThe value of cot (cosec-1<\/sup>\\(\\frac {5}{3}\\) + tan-1<\/sup>\\(\\frac {2}{3}\\)) is
\n(a) \\(\\frac { 5 }{17}\\)
\n(b) \\(\\frac { 6 }{17}\\)
\n(c) \\(\\frac { 3 }{17}\\)
\n(d) \\(\\frac { 4 }{17}\\)<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (b) \\(\\frac { 6 }{17}\\)
\nHint:
\n\"MCQ<\/p>\n<\/details>\n

\n

Question 17.
\nIf tan-1<\/sup> y = tan-1<\/sup> x + tan-1<\/sup>(\\(\\frac { 2x }{1-x^2}\\)) when |x| < \\(\\frac { 1 }{\u221a3}\\), then the value of y is:
\n(a) \\(\\frac { 3x-x^3 }{1-3x^2}\\)
\n(b) \\(\\frac { 3x+x^3 }{1-3x^2}\\)
\n(c) \\(\\frac { 3x-x^3 }{1+3x^2}\\)
\n(d) \\(\\frac { 3x+x^3 }{1+3x^2}\\)<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: (a) \\(\\frac { 3x-x^3 }{1-3x^2}\\)
\nHint:
\n\"MCQ<\/p>\n<\/details>\n

\n

Fill in the blanks<\/span><\/p>\n

Question 1.
\nPrincipal value of sin-1<\/sup> (-\\(\\frac {1}{2}\\)) is ………………<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: –\\(\\frac {\u03c0}{6}\\)<\/p>\n<\/details>\n

\n

Question 2.
\nPrincipal value of sin-1<\/sup> (-\\(\\frac {1}{\u221a2}\\)) is ……………….<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: \\(\\frac {-\u03c0}{4}\\)<\/p>\n<\/details>\n

\n

Question 3.
\nPrincipal value of cos-1<\/sup> (\\(\\frac {-1}{2}\\)) is ………………<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: \\(\\frac {2\u03c0}{3}\\)<\/p>\n<\/details>\n

\n

Question 4.
\nPrincipal value of tan-1<\/sup> (-\u221a3) is …………………<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: –\\(\\frac {\u03c0}{3}\\)<\/p>\n<\/details>\n

\n

Question 5.
\nPrincipal value of tan-1<\/sup> (-1) is ……………..<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: –\\(\\frac {\u03c0}{4}\\)<\/p>\n<\/details>\n

\n

Question 6.
\nPrincipal value of cot-1<\/sup> (\u221a3) is ……………….<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: \\(\\frac {\u03c0}{6}\\)<\/p>\n<\/details>\n

\n

Question 7.
\nPrincipal value of cosec-1<\/sup> (-\u221a2) is ……………..<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: –\\(\\frac {\u03c0}{4}\\)<\/p>\n<\/details>\n

\n

Question 8.
\nsin-1<\/sup> x + cos-1<\/sup> x = ………………<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: \\(\\frac {\u03c0}{2}\\)<\/p>\n<\/details>\n

\n

Question 9.
\ntan-1<\/sup> x + cot-1<\/sup> x = ………………..<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: \\(\\frac {\u03c0}{2}\\)<\/p>\n<\/details>\n

\n

Question 10.
\nsec-1<\/sup> x + cosec-1<\/sup> x = ……………….<\/p>\n

\nAnswer<\/span><\/summary>\n

Answer: \\(\\frac {\u03c0}{2}\\)<\/p>\n<\/details>\n

\n

We believe the knowledge shared regarding NCERT MCQ Questions for Class 12 Maths Chapter 2 Inverse Trigonometric Functions with Answers Pdf free download has been useful to the possible extent. If you have any other queries regarding CBSE Class 12 Maths Inverse Trigonometric Functions MCQs Multiple Choice Questions with Answers, feel free to reach us via the comment section and we will guide you with the possible solution.<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can access the NCERT MCQ Questions for Class 12 Maths Chapter 2 Inverse Trigonometric Functions with Answers Pdf free download aids in your exam preparation and you can get a good hold of the chapter. Use MCQ Questions for Class 12 Maths with Answers during preparation and score maximum marks in the exam. Students …<\/p>\n

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