{"id":23728,"date":"2021-08-24T19:22:26","date_gmt":"2021-08-24T13:52:26","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=23728"},"modified":"2022-03-02T10:21:15","modified_gmt":"2022-03-02T04:51:15","slug":"ncert-solutions-for-class-9-science-chapter-4","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-9-science-chapter-4\/","title":{"rendered":"NCERT Solutions for Class 9 Science Chapter 4 Structure of the Atom"},"content":{"rendered":"
These NCERT Solutions for Class 9 Science<\/a> Chapter 4 Structure of the Atom Questions and Answers are prepared by our highly skilled subject experts to help students while preparing for their exams.<\/p>\n Question 1. Question 2. Question 3. Question 4. Question 5. Question 6. Question 7. The total number of electrons in a sodium atom is 11. The distribution of electrons in sodium atom is given by: Question 8. Question 9. Question 10. Question 11. Question 12. Question 1. Question 2. Question 3. Question 4. These discrete orbits or shells are shown in the following diagram. Question 5. The maximum number of electrons present in an orbit of n = 1 is given by 2n2<\/sup> = 2 \u00d7 12 = 2 Question 6. If the number of valence electrons of the atom of an element is less than or equal to four, then the valency of that element is equal to the number of valence electrons. For example, the atom of silicon has four valence electrons. Thus, the valency of silicon is four.<\/p>\n On the other hand, if the number of valence electrons of the atom of an element is greater than four, then the valency of that element is obtained by subtracting the number of valence electrons from eight. For example, the atom of oxygen has six valence electrons. Thus, tire valency of oxygen is(8 – 6) i.e., two.<\/p>\n Question 7. (ii) Mass number: (iii) Isotopes: (iv) Isobars: Two uses of isotopes are:<\/p>\n Question 8. Question 9. Question 10. Therefore, Question 11. Therefore, the element with Z = 3 is lithium.<\/p>\n Question 12. Question 13. Question 14. Question 15. Question 16. Question 17. Very Short Answer Questions<\/span><\/p>\n Question 1. Question 2. Question 3. Question 4. Question 5. Question 6. Question 7. Question 8. Question 9. Question 10. Question 11. Question 12. Question 13. Question 14. Short Answer Questions<\/span><\/p>\n Question 1. Question 2. Question 3. Question 4. Question 5. Question 6. Question 7. Question 8. Question 9. Question 10. Question 11. Question 12. Question 13. Question 14. Question 15. Question 16. Long Answer Questions<\/span><\/p>\n Question 1. Question 2. The charge on a proton is equal to the charge on an electron, 1.6 \u00d7 10-19<\/sup>C but is resite in sign being positively charged.<\/p>\n Question 3. <\/p>\n Question 4. Conclusion from observation:<\/p>\n These NCERT Solutions for Class 9 Science Chapter 4 Structure of the Atom Questions and Answers are prepared by our highly skilled subject experts to help students while preparing for their exams. Structure of the Atom NCERT Solutions for Class 9 Science Chapter 4 Class 9 Science Chapter 4 Structure of the Atom InText Questions …<\/p>\nStructure of the Atom NCERT Solutions for Class 9 Science Chapter 4<\/h2>\n
Class 9 Science Chapter 4 Structure of the Atom InText Questions and Answers<\/span><\/h3>\n
\nWhat are canal rays?
\nAnswer:
\nCanal rays are positively charged radiations. These rays consist of positively charged particles known as protons. They were discovered by Goldstein in 1886.<\/p>\n
\nIf an atom contains one electron and one proton, will it cany any charge or not?
\nAnswer:
\nAn electron is a negatively charged; particle, whereas a proton is a positively charged; particle. The magnitude of their charges is equal. Therefore, an atom containing one electron and one proton will not carry any charge. Thus, it will be a neutral atom.<\/p>\n
\nName the three sub-atomic particles of an atom.
\nAnswer:
\nThe three sub-atomic particles of an atom are:<\/p>\n\n
\nHelium atom has an atomic mass of 4 u and two protons in its nucleus. How many neutrons does it have?
\nAnswer:
\nA helium atom has two neutrons. The mass of an atom is the sum of the masses of protons and neutrons present in its nucleus. Since helium atom has two protons, mass contributed by the two protons is (2 \u00d7 1) u = 2 u. Then, the remaining mass (4 – 2) u = 2 u is contributed \\(\\frac{2 \\mathrm{u}}{1 \\mathrm{u}}\\) = 2 by neutrons.<\/p>\n
\nDraw a sketch of Bohr’s model of an atom with three shells.
\nAnswer:
\nBohr’s model of an atom with three shells
\n<\/p>\n
\nWhat do you think would be the observation if the a-particle scattering experiment is carried out using a foil of a metal other than gold?
\nAnswer:
\nIf the a-scattering experiment is carried out using a foil of a metal rather than gold, there would be no change in the observation. In the a- scattering experiment, a gold foil was taken because gold is malleable and a thin foil of gold can be easily made. It is difficult to make such foils from other metals.<\/p>\n
\nWrite the distribution of electrons in carbon and sodium atoms?
\nAnswer:
\nThe total number of electrons in a carbon atom is 6. The distribution of electrons in carbon atom is given by:
\nFirst orbit or K-shell = 2 electrons
\nSecond orbit or L-shell = 4 electrons
\nOr, we can write the distribution of electrons in a carbon atom as 2, 4.<\/p>\n
\nFirst orbit or K-shell = 2 electrons
\nSecond orbit or L-shell = 8 electrons
\nThird orbit or M-shell = 1 electron
\nOr, we can write the distribution of electrons in a sodium atom as 2, 8, 1.<\/p>\n
\nIf K and L shells of an atom are full, then what would be the total number of electrons in the atom?
\nAnswer:
\nThe maximum number of electrons that can occupy K and L-shells of an atom are 2 and 8 respectively. Therefore, if K and L-shells of an atom are full, then the total number of electrons in the atom would be (2 + 8) = 10 electrons.<\/p>\n
\nIf number of electrons in an atom is 8 and number of protons is also 8, then (i) what is the atomic number of the atom and (ii) what is the charge on the atom?
\nAnswer:
\n(i) The atomic number is equal to the number of protons. Therefore, the atomic number of the atom is 8.
\n(ii) Since the number of both electrons and protons is equal, therefore, the charge on the atom is 0.<\/p>\n
\nWith the help of Table 4.1, find out the mass number of oxygen and sulphur atom.
\nAnswer:
\nMass number of oxygen = Number of protons + Number of neutrons<\/a>
\n= 8 + 8
\n= 16
\nMass number of sulphur=Number of protons + Number of neutrons
\n= 16 + 16
\n= 32<\/p>\n
\nFor the symbol H, D and T tabulate three sub-atomic particles found in each of them.
\nAnswer:<\/p>\n\n\n
\n Symbol<\/td>\n Proton<\/td>\n Neutron<\/td>\n Electron<\/td>\n<\/tr>\n \n H<\/td>\n 1<\/td>\n 0<\/td>\n 1<\/td>\n<\/tr>\n \n D<\/td>\n 1<\/td>\n 1<\/td>\n 1<\/td>\n<\/tr>\n \n T<\/td>\n 1<\/td>\n 2<\/td>\n 1<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
\nWrite the electronic configuration of any one pair of isotopes and isobars.
\nAnswer:
\nTwo isoto of carbon are \\(\\frac {12}{6}\\)C and \\(\\frac {14}{6}\\)C.
\nThe electronic configuration of \\(\\frac {12}{6}\\)C is 2, 4.
\nThe electronic configuration of \\(\\frac {14}{6}\\)C is 2, 4.
\n[Isotopes have the same electronic configuration]
\n\\(\\frac {40}{20}\\)Ca and \\(\\frac {40}{18}\\)Ar are a pair of isobars
\nThe electronic configuration of \\(\\frac {40}{20}\\)Ca is 2, 8, 8, 2.
\nThe electronic configuration of \\(\\frac {40}{18}\\)Ar is 2, 8, 8.<\/p>\nClass 9 Science Chapter 4 Structure of the Atom Textbook Questions and Answers<\/span><\/h3>\n
\nCompare properties of electrons, protons and neutrons.
\nAnswer:<\/p>\n\n\n
\n Electron<\/td>\n Proton<\/td>\n Neutron<\/td>\n<\/tr>\n \n (i) Electrons are present outside the nucleus of an atom<\/td>\n (i) Protons are present in the nucleus of an atom.<\/td>\n (i) Neutrons are present in the of an atom<\/td>\n<\/tr>\n \n (ii) Electrons are negatively charged<\/td>\n (ii) Protons are positively charged<\/td>\n (ii) Neutrons are neutral<\/td>\n<\/tr>\n \n (iii) The mass of an electron is considered to negligible<\/td>\n (iii) The mass of a proton is approximately 2000 times as times as the mass of an of an electron<\/td>\n (iii) The mass of neutron is nearly equal to the mass of a proton<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
\nWhat are the limitations of J.J. Thomson’s model of the atom?
\nAnswer:
\nAccording to J.J. Thomson’s model of an atom, an atom consists of a positively charged sphere with electrons embedded in it. However, it was later found that the positively charged particles reside at the centre of the atom called the nucleus, and the electrons revolve around the nucleus.<\/p>\n
\nWhat are the limitations of Rutherford’s model of the atom?
\nAnswer:
\nAccording to Rutherford’s model of an atom, electrons revolve around the nucleus in fixed orbits. But, an electron revolving in circular orbits will not be stable because during revolution, it will experience acceleration. Due to acceleration, the electrons will lose energy in the form of radiation and fall into the nucleus. In such a case, the atom would be highly unstable and collapse.<\/p>\n
\nDescribe Bohr’s model of the atom.
\nAnswer:
\nBohr’s model of the atom:
\nNiels Bohr proposed the following postulates regarding the model of the atom.<\/p>\n\n
\n
\nThe first orbit (i.e., for n = 1) is represented by letter K. Similarly, for n = 2, it is L – shell, for n = 3, it is M – shell and for n = 4, it is N – shell. These orbits or shells are also called energy levels.<\/p>\n
\nSummarize the rules for writing of distribution of electrons in various shells for the first eighteen elements.
\nAnswer:
\nThe rules for writing of the distribution of electrons in various shells for the first eighteen elements are given below.
\n(i) The maximum number of electrons that a shell can accommodate is given by the formula ‘2n2<\/sup>‘, where ‘n’ is the orbit number or energy level index (n = 1, 2,3..).<\/p>\n
\nSimilarly, for second orbit, it is 2n2<\/sup> = 2 \u00d7 22<\/sup> = 8
\nFor third orbit, it is 2n2<\/sup> = 2 \u00d7 32<\/sup> = 18
\nAnd so on ……
\n(ii) The outermost orbit can be accommodated by a maximum number of 8 electrons.
\n(iii) Shells are filled with electrons in a stepwise manner i.e., the outer shell is not occupied with electrons unless the inner shells are completely filled with electrons.<\/p>\n
\nDefine valency by taking examples of silicon and oxygen.
\nAnswer:
\nThe valency of an element is the combining capacity of that element. The valency of an element is determined by the number of valence electrons present in the atom of that element.<\/p>\n
\nExplain with examples (i) Atomic number (ii) Mass number (iii) Isotopes and (iv) Isobars. Give any two uses of isotopes.
\nAnswer:
\n(i) Atomic number:
\nThe atomic number of an element is the total number of protons present in the atom of that element. For example, nitrogen has 7 protons in its atom. Thus, the atomic number of nitrogen is 7.<\/p>\n
\nThe mass number of an element is the sum of the number of protons and neutrons present in the atom of that element. For example, tire atom of boron has 5 protons and 6 neutrons. So, the mass number of boron is 5 + 6 = 11.<\/p>\n
\nIsotopes are atoms of the same element having the same atomic number, but different mass numbers. For example, hydrogen has three isotopes. They are protium \\(\\left({ }_{1}^{1} \\mathrm{H}\\right)\\), deuterium \\(\\left({ }_{1}^{2} \\mathrm{H}\\right)\\), and tritium \\(\\left({ }_{1}^{3} \\mathrm{H}\\right)\\).<\/p>\n
\nIsobars are atoms having the same mass number, but different atomic numbers i.e., isobars are atoms of different elements having the same mass number. For example, \\({ }_{20}^{40} \\mathrm{Ca}\\) and \\({ }_{18}^{40} \\mathrm{Ar}\\) andare isobars.<\/p>\n\n
\nNa+<\/sup> has completely filled K and L shells. Explain.
\nAnswer:
\nAn atom of Na has a total of 11 electrons. Its electronic configuration is 2,8,1. But, Na+<\/sup> ion has one electron less than Na atom i.e., it has 10 electrons. Therefore, 2 electrons go to K-shell and 8 electrons go to L-shell, thereby completely filling K and L shells.<\/p>\n
\nIf bromine atom is available in tile form of, say, two isotopes \\({ }_{35}^{79} \\mathrm{Br}\\) (49.7%) and \\({ }_{35}^{81} \\mathrm{Br}\\) (50.3%), calculate the average atomic mass of bromine atom.
\nAnswer:
\nIt is given that two isotopes of bromine are \\({ }_{35}^{79} \\mathrm{Br}\\)(49.7%) and \\({ }_{35}^{81} \\mathrm{Br}\\) (50.3%). Then, the average atomic mass of bromine atom is given by:
\n
\n= 80.006 u
\n= 80 u (approx)<\/p>\n
\nThe average atomic mass of a sample of an clement X is 16.2 u. What are the
\npercentages of isotopes \\({ }_{8}^{16} \\mathrm{X}\\) and \\({ }_{8}^{18} \\mathrm{X}\\) in the sample?
\nAnswer:
\nIt is given that the average atomic mass of the sample of element X is 16.2 u.
\nLet the percentage of isotope \\({ }_{8}^{18} \\mathrm{X}\\) be y%. Thus,
\nthe percentage of isotope \\({ }_{8}^{16} \\mathrm{X}\\) will be (100 – y) %.<\/p>\n
\n
\n\u21d2 18y + 1600 = 1620
\n\u21d2 2y + 1600 = 1620
\n\u21d2 2y +1620 – 1600
\n\u21d2 2y = 20
\n\u21d2 y = 10
\nTherefore, the percentage of isotope \\({ }_{8}^{18} \\mathrm{X}\\) is 10%.
\nAnd, the percentage of isotope \\({ }_{8}^{16} \\mathrm{X}\\) is (100 – 10) % = 90%.<\/p>\n
\nIf Z = 3, what would be the valency of the element? Also, name the element
\nAnswer:
\nBy Z = 3, we mean that the atomic number of the element is 3. Its electronic configuration is 2, 1. Hence, the valency of the element is 1 (since the outermost shell has only one electron).<\/p>\n
\nComposition of the nuclei of two atomic species X and Y are given as under
\n
\nGive the mass numbers of X and Y. What is the relation between the two species?
\nAnswer:
\nMass number of X = Number of protons + Number of neutrons
\n= 6 + 6
\n= 12
\nMass number of Y = Number of protons + Number of neutrons
\n= 6 + 8
\n= 14
\nThese two atomic species X and Y have the same atomic number, but different mass numbers. Hence, they are isotopes.<\/p>\n
\nFor the following statements, write T for ‘True’ and F for ‘False’.
\n(a) J.J. Thomson proposed that the nucleus of an atom contains only nucleons.
\n(b) A neutron is formed by an electron and a proton combining together. Therefore, it is neutral.
\n(c) The mass of an electron is about \\(\\frac{1}{2000}\\) times that of proton.
\n(d) An isotope of iodine is used for making tincture iodine, which is used as a medicine.
\nAnswer:
\n(a) J.J. Thomson proposed that the nucleus of an atom contains only nucleons: (F)
\n(b) A neutron is formed by an electron and a proton combining together. Therefore, it is neutral (F).
\n(c) The mass of an electron is about \\(\\frac{1}{2000}\\) times that of proton. (T)
\n(d) An isotope of iodine is used for making tincture iodine, which is used as a medicine. (F)<\/p>\n
\nPut tick (\u221a) against correct choice and cross (\u00d7) against wrong choice in the following question:
\nRutherford’s alpha-particle scattering experiment was responsible for the discovery of
\n(a) Atomic nucleus
\n(b) Electron
\n(c) Proton
\n(d) Neutron
\nAnswer:
\nRutherford’s alpha-particle scattering experiment was responsible for the discovery of
\n(a) Atomic nucleus (\u221a)
\n(b) Electron
\n(c) Proton
\n(d) Neutron<\/p>\n
\nPut tick (\u221a) against correct choice and cross (\u00d7) against wrong choice in the following question:
\nIsotopes of an element have
\n(a) the same physical properties
\n(b) different chemical properties
\n(c) different number of neutrons
\n(d) different atomic numbers
\nAnswer:
\nIsotopes of an element have
\n(a) the same physical properties
\n(b) different chemical properties
\n(c) different number of neutrons (\u221a)
\n(d) different atomic numbers<\/p>\n
\nPut tick (\u221a) against correct choice and cross (\u00d7) against wrong choice in the following question:
\nNumber of valence electrons in Cl- ion are:
\n(a) 16
\n(b) 8
\n(c) 17
\n(d) 18
\nAnswer:
\nNumber of valence electrons in Cl- ion are:
\n(a) 16
\n(b) 8(\u221a)
\n(c) 17
\n(d) 18<\/p>\n
\nWhich one of the following is a correct electronic configuration of sodium?
\n(a) 2, 8
\n(b) 8, 2, 1
\n(c) 2, 1, 8
\n(d) 2, 8, 1
\nAnswer:
\n(d) The correct electronic configuration of sodium is 2, 8, 1.<\/p>\nClass 9 Science Chapter 4 Structure of the Atom Additional Important Questions and Answers<\/span><\/h3>\n
\nWhat are nucleons?
\nAnswer:
\nThe subatomic particles present in the nucleus of an atom are called nucleons. These include protons and neutrons.<\/p>\n
\nWhich element does not contain any neutron?
\nAnswer:
\nHydrogen<\/p>\n
\nWho discovered the presence of the protons in an atom?
\nAnswer:
\nGoldstein after his discovery of anode rays.<\/p>\n
\nWhat did Rutherford discover from his alpha particle scattering experiment?
\nAnswer:
\nRutherford from alpha particle scattering experiment had discovered the nucleus of an atom.<\/p>\n
\nWhich subatomic particles were not known when Rutherford performed his experiment?
\nAnswer:
\nNeutrons<\/p>\n
\nWhat is the number of protons and neutrons present in a helium atom?
\nAnswer:
\nIn a helium atom the number of both protons and neutrons is two.<\/p>\n
\nWhat is common in isotopes of an element?
\nAnswer:
\nAtomic number<\/p>\n
\nWhat was the major drawback of Rutherford\u2019s model of atom?
\nAnswer:
\nRutherford had failed to describe the stability of an atom.<\/p>\n
\nWhat are the fundamental building blocks of matter?
\nAnswer:
\nAtoms and molecules<\/p>\n
\nWhat is the mass and charge of a proton?
\nAnswer:
\nThe mass of a .proton is taken as one unit and so also its charge is taken as one positive unit.<\/p>\n
\nWhat is the charge on the nucleus of an atom?
\nAnswer:
\nThe nucleus of an atom is positively charged.<\/p>\n
\nWhat are valence electrons?
\nAnswer:
\nThe electrons present in the outermost shell of an atom are called valence electrons.<\/p>\n
\nIf an atom has atomic number-16, what are the number of valence electrons and what is its valency?
\nAnswer:
\nElectronic configuration: 2, 8, 6.
\nValence electrons = 6
\nValency = 2<\/p>\n
\nWhich isotope of uranium is used as nuclear fuel in nuclear reactor?
\nAnswer:
\nU-235.<\/p>\n
\nHow will you prove that matter is electrical in nature but neutral?
\nAnswer:
\nWhen a glass rod rubbed with silk cloth is brought near an inflated balloon, the balloon gets attracted to the rod but when a glass rod without being rubbed to silk cloth is brought close to an inflated balloon nothing happens shows that matter is electrical in nature but neutral.<\/p>\n
\nWhat made the scientists to realize that atom is divisible after Dalton proposed his theory of atom in which he described atom as indivisible?
\nAnswer:
\nThe attraction of bits of paper by a comb after combing dry hair or gluing of a balloon to a wall after rubbing made the scientists think that atom is divisble.<\/p>\n
\nWhat is the charge and mass of an electron and a proton?
\nAnswer:
\nCharge on an electron = -1.6 x 10-19<\/sup>C
\nMass of an electron = 1\/1840 times of a proton
\nCharge on a proton = + 1.6 x 10-19<\/sup>C
\nMass of an electron = mass of a hydrogen atom<\/p>\n
\n(i) What are the mass number (A) and atomic number (Z) of an element?
\n(ii) How are they indicated in a symbol of an atom?
\nAnswer:
\n(i) Mass number refers to the sum of the numbers of protons and neutrons present in atom while the atomic number refers to the number of protons present in the nucleus of an atom.
\n(ii) Mass number is always written in superscript and atomic number in the subscript as shown below.
\n<\/p>\n
\n(i) What is the nucleus of atom?
\n(ii) What charge does the nucleus of an atom carry?
\nAnswer:
\n(i) Nucleus is a small dense region present in the centre of an atom. It is 10s times smaller than an atom. It is like a football placed in the centre of football field, (ii) It contains positively charged protons and neutral neutrons, therefore it is positively charged.<\/p>\n
\nWhat did Thomson propose about the model of an atom?
\nAnswer:
\nThomson proposed that:
\n<\/p>\n\n
\nIf in an element K shell is completely filled then what will be the
\n(a) number of valence electrons
\n(b) valence and
\n(c) name of element.
\nAnswer:
\n(a) Number of valence electrons = 2
\n(b) Valence = Zero
\n(c) Name of element = Helium<\/p>\n
\nIf chlorine atom is available in the form of say two isotopes 35<\/sup>C17<\/sub>(75%). 37<\/sup>Cl17<\/sub>(25%). Calculate the average atomic mass of bromine.
\nAnswer:
\nThe average atomic mass of bromine would be
\n<\/p>\n
\nThe average atomic mass of a sample of an element X is 12.2 u. What is the percentage of isotopes 12<\/sup>X6<\/sub> and 14<\/sup>X6 <\/sub>in the sample?
\nAnswer:
\nAtomic mass of X =12 unit
\nLet the percentage of 12<\/sup>X6<\/sub> = X %
\nPercentage of 14<\/sup>X6<\/sub> = Y% = (100 – x)%
\n<\/p>\n
\nWhat are isotopes? State their uses.
\nAnswer:
\nIsotopes of an element are the atoms which have the same atomic number: different atomic mass number because of the presence of the different number neutrons. These isotopes are used in<\/p>\n\n
\nHow is an isotope different from an isobar?
\nAnswer:
\nIsotopes are the atoms of an element which have same atomic number – differ in the atomic mass number because they carry different number of neutrons but Isobars are the atoms of different elements which have same atomic mass number but they differ in their atomic number.<\/p>\n
\nWhich of the following are the isotopes and isobars? Why?
\n18<\/sup>X8<\/sub>, 18<\/sup>Y6<\/sub>, 16<\/sup>X8<\/sub>
\nAnswer:
\n18<\/sup>X8<\/sub>, and 18<\/sup>Y6<\/sub> are isobars because they have different atomic number but same atomic mass number.
\n18<\/sup>X8<\/sub>, and 16<\/sup>X8<\/sub> are isotopes because they have same atomic number but different atomic masses.<\/p>\n
\nHow is an alpha particle different from an atom of helium?
\nAnswer:
\nAlpha particle is the nucleus of helium represented by the formula without any electron but an atom of helium consists of 2 electrons along nucleus having two protons and neutrons.<\/p>\n
\nCalculate the number of electrons, protons and neutrons in the following
\n40<\/sup>X20<\/sub>, 14<\/sup>Y6<\/sub>, 238<\/sup>Z92<\/sub>
\nAnswer:
\n40<\/sup>X20<\/sub> – Number of protons = 20, Number of electrons = 20 Number of neutrons = 20
\n14<\/sup>Y6<\/sub> – Number of protons = 6, Number of electrons = 6 Number of neutrons = 8
\n238<\/sup>Z92<\/sub> – Number of protons = 92, Number of electrons = 92 Number of neutrons = 146<\/p>\n
\nWhy the valence electrons are considered responsible for the chemical activity of an element?
\nAnswer:
\nValence electrons are the electrons present in the outermost shell of an atom. The number of these electrons determines that how many electrons an atom need to gain or lose, to gain stability. The lesser is the number of electrons required to be lost or gained, the reactive is the element.<\/p>\n
\nHow is a discharge tube different from an ordinary tube?
\nAnswer:
\nA discharge is a tube with the gas under very low pressure i.e. 1 atmospheric pressure where it is possible to generate the electric discharge but in an ordinary tube has average atmospheric pressure in which an electrical discharge cannot be produced in any condition.<\/p>\n
\nWhat are cathode rays? How are they produced?
\nAnswer:
\nWhen an electric discharge is produced in a discharge tube at low pressure 10-2<\/sup> atmospheric pressure and the voltage of 10,000 V, the rays emitted from the cathode are called cathode rays. These rays consist of negatively charge particles called electrons because they get deflected towards the positively charged electrode when passing through an electric field.
\n
\nIn discharge tube, the low pressure is maintained to have less number of molecules hence, minimum interference in the path of the cathode rays emitted from cathode. The emission of these rays proved that the atoms are not indivisible as stated by Dalton in his atomic theory but contain negatively charge electrons.<\/p>\n
\nWhat are anode rays? Describe their nature.
\nAnswer:
\nAnode rays are the positively charged rays produced in a discharge tube having a perforated cathode. These rays consist of positively charge particles called protons. These rays get deflected towards the negatively charged electrode when passing through an electric field.<\/p>\n
\nWhat observations did Rutherford made in his alpha particles scattering experiment? What did he conclude from his observations?
\nAnswer:
\nRutherford in his alpha particle experiment when he made the alpha particles incident on the surface of a very thin and fine gold foil observed that<\/p>\n\n
\n
\nFrom his observations Rutherford concluded and proposed that<\/li>\n
\nExplain Rutherford’s \u03b1-particle scattering experiment and give its observation and conclusion drawn.
\nAnswer:
\nRutherford’s \u03b1-particle scattering experiment:
\nFast moving \u03b1-particles were made to fall on a thin gold foil. Particles have + 2 charge and 4u mass, and considerable amount of energy.
\n
\nObservations:<\/p>\n\n
\n