{"id":24686,"date":"2021-06-19T18:04:00","date_gmt":"2021-06-19T12:34:00","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=24686"},"modified":"2022-03-02T10:38:13","modified_gmt":"2022-03-02T05:08:13","slug":"ncert-solutions-for-class-6-maths-chapter-14-ex-14-1","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-6-maths-chapter-14-ex-14-1\/","title":{"rendered":"NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.1"},"content":{"rendered":"

These NCERT Solutions for Class 6 Maths<\/a> Chapter 14 Practical Geometry Ex 14.1 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Exercise 14.1<\/h2>\n

Question 1.
\nDraw a circle of radius 3.2 cm.
\nAnswer:
\n\"NCERT
\nSteps of construction:
\n(a) Open the compass for the required radius of 3.2 cm.
\n(b) Make a point with a sharp pencil where we want the centre of circle to be.
\n(c) Name it O.
\n(d) Place the pointer of compasses on O.
\n(e) Turn the compasses slowly to draw the circle.
\nHence, it is the required circle.<\/p>\n

Question 2.
\nWith the same centre O, draw two circles of radii 4 cm and 2.5 cm.
\nAnswer:
\n\"NCERT
\nSteps of construction:
\n(a) Marks a point \u2018O\u2019 with a sharp pencil where we want the centre of the circle.
\n(b) Open the compasses 4 cm.
\n(c) Place the pointer of the compasses on O.
\n(d) Turn the compasses slowly to draw the circle.
\n(e) Again open the compasses 2.5 cm and place the pointer of the compasses on O.
\n(f) Turn the compasses slowly to draw the second circle.
\nHence, it is the required figure.<\/p>\n

\"NCERT<\/p>\n

Question 3.
\nDraw a circle and any two of its diameters. If you join the ends of these diameters, what is the figure obtained? What figure is obtained if the diameters are perpendicular to each other? How do you check your answer?
\n\"NCERT
\nAnswer:
\n(i) By joining the ends of two diameters, we get a rectangle. By measuring, we find AB = CD = 3 cm, BC = AD = 2 cm, i.e., pairs of opposite sides are equal and also \u2220A = \u2220B = \u2220C = \u2220D = 90\u00b0,
\ni.e. each angle is of 90\u00b0.
\nHence, it is a rectangle.
\n\"NCERT<\/p>\n

(ii) If the diameters are perpendicular to each other, then by joining the ends of two diameters, we get a square. By measuring, we find that AB = BC = CD = DA = 2.5 cm, i.e., all four sides are equal. Also \u2220A = \u2220B = \u2220C = \u2220D = 90\u00b0, i.e. each angle is of 90\u00b0.
\nHence, it is a square.<\/p>\n

Question 4.
\nDraw any circle and mark points A, B and C such that:
\n(a) A is on the circle.
\n(b) B is in the interior of the circle.
\n(c) C is in the exterior of the circle.
\n\"NCERT
\nAnswer:
\n(i) Mark a point \u2018O\u2019 with sharp pencil where we want centre of the circle,
\n(ii) Place the pointer of the compasses at \u2018O\u2019. Then move the compasses slowly to draw a circle.
\n(a) Point A is on the circle.
\n(b) Point B is in interior of the circle.
\n(c) Point C is in the exterior of the circle.<\/p>\n

\"NCERT<\/p>\n

Question 5.
\nLet A, B be the centres of two circles of equal radii; draw them so that each one of them passes through the centre of the other. Let them intersect at C and D. Examine whether \\(\\overline{\\mathrm{AB}}\\) and \\(\\overline{\\mathrm{CD}}\\) are at right angles.
\nAnswer:
\nDraw two circles of equal radii taking A and B as their centre such that one of them passes through the centre of the other. They intersect at C and D. Join AB and CD.
\nYes, AB and CD intersect at right angle as \u2220COB is 90\u00b0.
\n\"NCERT<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.1 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Exercise 14.1 Question 1. Draw a circle of radius 3.2 cm. Answer: Steps of construction: (a) Open the compass for the …<\/p>\n

NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.1<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[10],"tags":[],"yoast_head":"\nNCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.1 - MCQ Questions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-6-maths-chapter-14-ex-14-1\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.1 - MCQ Questions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.1 Questions and Answers are prepared by our highly skilled subject experts. 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