NCERT Solutions for Class 9 Maths<\/a> Chapter 4 Linear Equations in Two Variables Ex 4.1 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\nNCERT Solutions for Class 9 Maths Chapter 4 Linear Equations in Two Variables Exercise 4.1<\/h2>\n Question 1. \nThe cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement. \nSolution: \nLet the cost of a notebook is Rs. x and the cost of a pen is Rs. y \nAccording to question \nx = 2y or, x – 2y = 0 \nTherefore the linear equation in two variables to represent this statement is x – 2y = 0<\/p>\n
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Question 2. \nExpress the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case: \n(i) 2x + 3y = 9.\\(\\bar{35}\\) \n(ii) x – \\(\\frac {y}{5}\\) – 10 = 0 \n(iii) -2x + 3y = 6 \n(iv) x = 3y \n(v) -2x = -5y \n(vi) 3x + 2 = 0 \n(vii) y – 2 = 0 \n(viii) 5 = 2x \nSolution: \n(i) We have given that \n2x + 3y = 9.\\(\\bar{35}\\) \n2x + 3y – 9.\\(\\bar{35}\\) = 0 \nNow, it is the form of ax + by + c = 0 \nTherefore the values of a, b and c are 2, 3 and -9.\\(\\bar{35}\\) respectively.<\/p>\n
(ii) We have given that \nx – \\(\\frac {y}{5}\\) – 10 = 0 \nWe can also write \n1x + (\\(\\frac {-y}{5}\\)) y + (-10) = 0 \nNow, it is in the form of ax + by + c = 0 \nTherefore values of a, b and c are 1, \\(\\frac {-y}{5}\\), and -10 respectively.<\/p>\n
(iii) We have given that \n-2x + 3y = 6 \nor, -2x + 3y – 6 = 0 \nWe can also write \n(-2)x + 3y + (-6) = 0 \nNow, it is in the form of ax + by + c = 0 \nTherefore, the values of a, b and c are -2, 3 and -6 respectively.<\/p>\n
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(iv) We have given that, \nx = 3y \nor, x – 3y = 0 \nWe can also write \n1x + (-3)y + 0 = 0 \nNow, it is in the form of ax + by + c = 0 and the values of a, b and c are 1, -3 and 0 respectively.<\/p>\n
(v) We have given that \n2x = -5y \nor, 2x + 5y = 0 \nWe can also write 2x + 5y + 0 = 0 \nNow, it is in the form of ax + by + c = 0. \nTherefore, the values of a, b and c are 2, 5 and 0 respectively.<\/p>\n
(vi) We have given that \n3x + 2 = 0 \nWe can also write 3x + 0y + 2 = 0 \nNow, it is in the form of ax + by + c = 0 \nTherefore, the values of a, b and c are 3, 0 and 2 respectively.<\/p>\n
(vii) y – 2 = 0 \nWe can also write, \n0x + 1y + (-2) = 0 \nNow, it is in the form of ax + by + c = 0. \nTherefore, the values of a, b and c are 0, 1 and -2 respectively.<\/p>\n
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(viii) we have given that \n5 = 2x \nor, 2x – 5 = 0 \nWe can also write \n2x + 0y + (-5) = 0 \nNow it is in the form of ax + by + c = 0. \nTherefore, the values of a, b and c are 2, 0 and (-5) respectively.<\/p>\n","protected":false},"excerpt":{"rendered":"
These NCERT Solutions for Class 9 Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 9 Maths Chapter 4 Linear Equations in Two Variables Exercise 4.1 Question 1. The cost of a notebook is twice the cost of a …<\/p>\n
NCERT Solutions for Class 9 Maths Chapter 4 Linear Equations in Two Variables Ex 4.1<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[6],"tags":[],"yoast_head":"\nNCERT Solutions for Class 9 Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 - MCQ Questions<\/title>\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n\t \n\t \n\t \n