{"id":24993,"date":"2021-06-21T18:10:37","date_gmt":"2021-06-21T12:40:37","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=24993"},"modified":"2022-03-02T10:38:04","modified_gmt":"2022-03-02T05:08:04","slug":"ncert-solutions-for-class-6-maths-chapter-3-ex-3-3","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-6-maths-chapter-3-ex-3-3\/","title":{"rendered":"NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.3"},"content":{"rendered":"

These\u00a0NCERT Solutions for Class 6 Maths<\/a> Chapter 3 Playing With Numbers Ex 3.3 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Exercise 3.3<\/h2>\n

Question 1.
\nUsing divisibility tests, determine which of the following numbers are divisible by 2; by 3; by 4; by 5; by 6; by 8; by 9; by 10; by 11 (say, yes or no):
\nAnswer:
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 2.
\nUsing divisibility tests, determine which of the following numbers are divisible by 4; by 8:
\n(a) 572
\n(b) 726352
\n(c) 5500
\n(d) 6000
\n(e) 12159
\n(f) 14560
\n(g) 21084
\n(h) 31795072
\n(i) 1700
\n(j) 2150
\nAnswer:
\n(a) 572
\n\u2192 Divisible by 4 as its last two digits are divisible by 4.
\n\u2192 Not divisible by 8 as its last three digits are not divisible by 8.<\/p>\n

(b) 726352
\n\u2192 Divisible by 4 as its last two digits are divisible by 4.
\n\u2192 Divisible by 8 as its last three digits are divisible by 8.<\/p>\n

(c) 5500
\n\u2192 Divisible by 4 as its last two digits are divisible by 4.
\n\u2192 Not divisible by 8 as its last three digits are not divisible by 8.<\/p>\n

(d) 6000
\n\u2192 Divisible by 4 as its last two digits are 0.
\n\u2192 Divisible by 8 as its last three digits are 0.<\/p>\n

(e) 12159
\n\u2192 Not divisible by 4 and 8 as it is an odd number.<\/p>\n

(f) 14560
\n\u2192 Divisible by 4 as its last two digits are divisible by 4.
\n\u2192 Divisible by 8 as its last three digits are divisible by 8.<\/p>\n

(g) 21084
\n\u2192 Divisible by 4 as its last two digits are divisible by 4.
\n\u2192 Not divisible by 8 as its last three digits are not divisible by 8.<\/p>\n

(h) 31795072
\n\u2192 Divisible by 4 as its last two digits are divisible by 4.
\n\u2192 Divisible by 8 as its last three digits are divisible by 8.<\/p>\n

\"NCERT<\/p>\n

(i) 1700
\n\u2192 Divisible by 4 as its last two digits are 0.
\n\u2192 Not divisible by 8 as its last three digits are not divisible by 8.<\/p>\n

(j) 2150
\n\u2192 Not divisible by 4 as its last two digits are not divisible by 4.
\n\u2192 Not divisible by 8 as its last three digits are not divisible by 8.<\/p>\n

Question 3.
\nUsing divisibility tests, determine which of following numbers are divisible by 6:
\n(a) 297144
\n(b) 1258
\n(c) 4335
\n(d) 61233
\n(e) 901352
\n(f) 438750
\n(g) 1790184
\n(h) 12583
\n(i) 639210
\n(j) 17852
\nAnswer:
\n(a) 297144
\n\u2192 Divisible by 2 as its unit\u2019s place is an even number.
\n\u2192 Divisible by 3 as sum of its digits (= 27) is divisible by 3.
\nSince the number is divisible by both 2 and 3, therefore, it is also divisible<\/p>\n

(b) 1258
\n\u2192 Divisible by 2 as its units place is an even number.
\n\u2192 Not divisible by 3 as sum of its digits (= 16) is not divisible by 3.
\nSince the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.<\/p>\n

(c) 4335
\n\u2192 Not divisible by 2 as its unit\u2019s place is not an even number.
\n\u2192 Divisible by 3 as sum of its digits (= 15) is divisible by 3.
\nSince the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.<\/p>\n

(d) 61233
\n\u2192 Not divisible by 2 as its unit\u2019s place is not an even number.
\n\u2192 Divisible by 3 as sum of its digits (= 15) is divisible by 3.
\nSince the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.<\/p>\n

(e) 901352
\n\u2192 Divisible by 2 as its unit\u2019s place is an even number.
\n\u2192 Not divisible by 3 as sum of its digits (= 20) is not divisible by 3.
\nSince the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.<\/p>\n

\"NCERT<\/p>\n

(f) 438750
\n\u2192 Divisible by 2 as its unit\u2019s place is an even number.
\n\u2192 Divisible by 3 as sum of its digits (= 27) is divisible by 3.
\nSince the number is divisible by both 2 and 3, therefore, it is divisible by 6.<\/p>\n

(g) 1790184
\n\u2192 Divisible by 2 as its unit\u2019s place is an even number.
\n\u2192 Divisible by 3 as sum of its digits (= 30) is divisible by 3.
\nSince the number is divisible by both 2 and 3, therefore, it is divisible by 6.<\/p>\n

(h) 12583
\n\u2192 Not divisible by 2 as its unit\u2019s place is not an even number.
\n\u2192 Not divisible by 3 as sum of its digits (= 19) is not divisible by 3.
\nSince the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.<\/p>\n

(i) 639210
\n\u2192 Divisible by 2 as its unit\u2019s place is an even number.
\n\u2192 Divisible by 3 as sum of its digits (= 21) is divisible by 3.
\nSince the number is divisible by both 2 and 3, therefore, it is divisible by 6.<\/p>\n

(j) 17852
\n\u2192 Divisible by 2 as its units place is an even number.
\n\u2192 Not divisible by 3 as sum of its digits (= 23) is not divisible by 3.
\nSince the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.<\/p>\n

Question 4.
\nUsing divisibility tests, determine which of the following numbers are divisible by 11:
\n(a) 5445
\n(b) 10824
\n(c) 7138965
\n(d) 70169308
\n(e) 10000001
\n(f) 901153
\nAnswer:
\n(a) 5445
\nSum of the digits at odd places =4+5=9
\n\u2192 Sum of the digits at even places =4+5=9
\n\u2192 Difference of both sums = 9-9 = 0 Since the difference is 0, therefore, the number is divisible by 11.<\/p>\n

(b) 10824
\n\u2192 Sum of the digits at odd places = 4 + 8 +1 = 13
\n\u2192 Sum of the digits at even places =2+0=2
\n\u2192 Difference of both sums = 13 – 2 = 11 Since the difference is 11, therefore, the number is divisible by 11.<\/p>\n

(c) 7138965
\n\u2192 Sum of the digits at odd places = 5 + 9 + 3 + 7 = 24
\n\u2192 Sum of the digits at even places = 6 + 8 + 1 = 15
\n\u2192 Difference of both sums = 24 – 15 = 9
\nSince the difference is neither 0 nor 11, therefore, the number is not divisible by 11.<\/p>\n

\"NCERT<\/p>\n

(d) 70169308
\n\u2192 Sum of the digits at odd places = 8 + 3 + 6 + 0 = 17
\n\u2192 Sum of the digits at even places = 0 + 9 + 1 + 7 = 17
\n\u2192 Difference of both sums = 17 – 17 = 0
\nSince the difference is 0, therefore, the number is divisible by 11.<\/p>\n

(e) 10000001
\n\u2192 Sum of the digits at odd places
\n= 1 + 0 + 0 + 0 = 1
\n\u2192 Sum of the digits at even places
\n= 0 + 0 + 0 + 1 = 1
\n\u2192 Difference of both sums =1-1=0 Since the difference is 0, therefore, the number is divisible by 11.<\/p>\n

(f) 901153
\nSum of the digits at odd places = 3 + 1 +0 = 4
\n\u2192 Sum of the digits at even places = 5 + 1 + 9 = 15
\n\u2192 Difference of both sums =15 – 4 = 11
\nSince the difference is 11, therefore, the number is divisible by 11.<\/p>\n

Question 5.
\nWrite the smallest digit and the greatest digit in the blanks space of each of the following numbers so that the number formed is divisibly by 3:
\n(a) ………………. 6724
\n(b) 4765 ………………. 2
\nAnswer:
\n(a) We know that a number is divisible by 3 if the sum of all digits is divisible by 3.
\nTherefore, Smallest digit: 2 \u2192 26724 = 2 + 6 + 7 + 2 + 4 = 21
\nLargest digit: 8 \u2192 86724 = 8 + 6 + 7 + 2 + 4 = 27<\/p>\n

(b) We know that a number is divisible by 3 if the sum of all digits is divisible by 3.
\nTherefore, Smallest digit: 0 \u2192 476502 =4+7+6+5+0+2=24
\nLargest digit: 9 \u2192 476592 = 9 + 4 + 7 + 6 + 5 + 0 + 2 = 33<\/p>\n

Question 6.
\nWrite a digit in the blank space of each of the following numbers so that the number formed is divisibly by 11:
\n(a) 92 …………… 389
\n(b) 8 ……………….. 9484
\nAnswer:
\n(a) We know that a number is divisible by 11 if the difference of the sum of the digits at odd places and that of even places should be either 0 or 11.
\nTherefore, 928389 \u2192
\nOdd places = 9 + 8 + 8 = 25
\nEven places = 2 + 3 + 9 = 14
\nDifference = 25 – 14 = 11<\/p>\n

\"NCERT<\/p>\n

(b) We know that a number is divisible by 11 if the difference of the sum of the digits at odd places and that of even places should be either 0 or 11.
\nTherefore, 869484 \u2192
\nOdd places = 8 + 9 + 8 = 25
\nEven places = 6 + 4 + 4 = 14
\nDifference = 25 – 14 = 11<\/p>\n","protected":false},"excerpt":{"rendered":"

These\u00a0NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.3 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Exercise 3.3 Question 1. Using divisibility tests, determine which of the following numbers are divisible by 2; by 3; by …<\/p>\n

NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.3<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[10],"tags":[],"yoast_head":"\nNCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.3 - MCQ Questions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-6-maths-chapter-3-ex-3-3\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.3 - MCQ Questions\" \/>\n<meta property=\"og:description\" content=\"These\u00a0NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Ex 3.3 Questions and Answers are prepared by our highly skilled subject experts. 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