NCERT Solutions for Class 6 Maths<\/a> Chapter 5 Understanding Elementary Shapes Ex 5.5 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\nNCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Exercise 5.5<\/h2>\n Question 1. \nWhich of the following are models for perpendicular lines: \n(a) The adjacent edges of a table top. \n(b) The lines of a railway track. \n(c) The line segments forming the letter \u2018L’. \n(d) The letter V. \nAnswer: \n(a) The adjacent edges of a table top. \n \n.’. They form perpendicular lines,<\/p>\n
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(b) The lines of a railway track \n \nHere, the two adjacent sides don\u2019t meet. \n\u03c7 They do not form perpendicular lines<\/p>\n
(c) The line segments forming the letter \u2018L\u2019. \n \nHere, the line segments form a right angle \n\u2234 They form perpendicular lines.<\/p>\n
(d) Here, the angle between the lines is not a right angle. \n \n\u2234 They do not form perpendicular lines.<\/p>\n
Question 2. \nLet \\(\\overline{\\mathrm{PQ}}\\) be the perpendicular to the line segment \\(\\overline{\\mathrm{XY}}\\). Let \\(\\overline{\\mathrm{PQ}}\\) and \\(\\overline{\\mathrm{XY}}\\) intersect in the point A. What is the measure of \u2220PAY? \nAnswer: \n \nSince, \\(\\overline{\\mathrm{XY}}\\) \u22a5 PQ \nAngle between them is a right angle. \n.’. \u2220PAY = 90\u00b0<\/p>\n
Question 3. \nThere are two set-squares in your box. What are the measures of the angles that are formed at their corners? Do they have any angle measure that is common? \nAnswer: \n \nThe angle are 90\u00b0, 45\u00b0, 45\u00b0 \nThe angles are 90\u00b0, 60\u00b0, 30\u00b0 \nSo, Angle 90\u00b0 is common between them<\/p>\n
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Question 4. \nStudy the diagram. The line l is perpendicular to line m. \n \n(a) Is CE = EG? \n(b) Does PE bisect CG? \n(c) Identify any two line segments for which PE is the perpendicular bisector. \n(d) Are these true? \n(i) AC > FG (ii) CD = GH (iii) BC < EH \nAnswer: \n(a) CE = CD + DE = 1 + 1=2 EG = EF + FG = 1 + 1 = 2<\/p>\n
(b) PE & CG Intersect at point E & CE = EG \n.’. PE is the bisector of CG<\/p>\n
(c) PE is perpendicular bisector for \n\\(\\overline{\\mathrm{CG}}\\) \nAs CE = EG = 2 \n& \\(\\overline{\\mathrm{CE}}\\) = EG = 2 \n\\(\\overline{\\mathrm{XY}}\\) \u22a5 \\(\\overline{\\mathrm{CG}}\\) \n\\(\\overline{\\mathrm{BH}}\\) \nAs \\(\\overline{\\mathrm{BE}}=\\overlline{\\mathrm{BE}}\\) = 3 \n\\(\\overline{\\mathrm{PE}}=\\overlline{\\mathrm{BH}}\\)<\/p>\n
(d) (i) True \nAC = AB + BC = 1 + 1 = 2 \nFG = 1 \n\u2234 AC > FG<\/p>\n
(ii) True \nCD = 1 \nGH = 1 \nCD > GH<\/p>\n
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(iii) True \nBC = 1 \nEH = EF + FG + GH = 1 + 1 + 1 = 3 \n\u2234 CD > GH<\/p>\n","protected":false},"excerpt":{"rendered":"
These\u00a0NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.5 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Exercise 5.5 Question 1. Which of the following are models for perpendicular lines: (a) The adjacent edges of a table …<\/p>\n
NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.5<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[10],"tags":[],"yoast_head":"\nNCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.5 - MCQ Questions<\/title>\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n\t \n\t \n\t \n