NCERT Solutions for Class 6 Maths<\/a> Chapter 11 Algebra Ex 11.4 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\nNCERT Solutions for Class 6 Maths Chapter 11 Algebra Exercise 11.4<\/h2>\n Question 1. \nAnswer the following: \n(a) Take Sarita\u2019s present age to be y years \n(i) What will be her age 5 years from now? \n(ii) What was her age 3 years back? \n(iii) Sarita\u2019s grandfather is 6 times her age. What is the age of her grandfather? \n(iv) Grandmother is 2 years younger than grandfather. What is grandmother\u2019s age? \n(v) Sarita\u2019s father\u2019s age is 5 years more than 3 times Sarita\u2019s age. What is her father\u2019s age?<\/p>\n
(b) The length of a rectangular hall is 4 meters less than 3 times the breadth of the hall. What is the length, if the breadth is b meters?<\/p>\n
(c) A rectangular box has height h cm. Its length is S times the height and breadth is 10 cm less than the \nlength. Express the length and the breadth of the box in terms of the height.<\/p>\n
(d) Meena, Beena and Leena are climbing the steps to the hill top. Meena is at step s, Beena is 8 steps ahead and Leena 7 steps behind. Where are Beena and Meena? The total number of steps to the hill top is 10 less than 4 times what Meena has reached. Express the total number of steps using s.<\/p>\n
(e) A bus travels at v km per hour. It is going from Daspur to Beespur. After the bus has travelled 5 hours, Beespur is still 20 km away. What is the distance from Daspur to Beespur? Express it using v. \nAnswer: \n(a) \n(i) y + 5 \n(ii) y – 3 \n(iii) 6 y \n(iv) 6y – 2 \n(v) 3y + 5<\/p>\n
(b) Length = 3b and Breadth \n= (3b – 4) meters<\/p>\n
(c) Height of the box = h cm \nLength of the box \n= 5 times the height = 5h cm \nBreadth of the box \n= 10 cm less than length \n= (5h – 10) cm<\/p>\n
(d) Meena\u2019s position = s \nBeena\u2019s position \n= 8 steps ahead = s + 8 \nLeenas position \n= 7 steps behind = s – 7 \nTotal number of steps = 4s – 10<\/p>\n
(e) Speed of the bus = v km\/h \nDistance travelled in 5 hours = 5v km \nRemaining distance = 20 km \nTherefore, total distance = (5v + 20) km<\/p>\n
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Question 2. \nChange the following statements using expressions into statements in ordinary language. \n(For example, Given Salim scores r runs in a cricket match, Nalin scores \n(r + 15) runs. In ordinary language- Nalin scores 15 runs more than Salim.)<\/p>\n
(a) A note book costs \u20b9 p. A book costs \u20b9 3 p. \n(b) Tony puts q marbles on the table. He has 8 q marbles in his box. \n(c) Our class has n students. The school has 20 n students. \n(d) Jaggu is z years old. His uncle is 4 z years old and his aunt is (4z – 3) years old. \n(e) In an arrangement of dots there are r rows. Each row contains 5 dots. \nAnswer: \n(a) A book cost 3 times the cost of a notebook. \n(b) The number of marbles in box is 8 times the marble on the table. \n(c) Total number of students in the school is 20 times that in our class. \n(d) Jaggu\u2019s uncle’s age is 4 times the age of Jaggu. Jaggu\u2019s aunt is 3 years younger than his uncle. \n(e) The total number of dots is 5 times the number of rows.<\/p>\n
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Question 3. \n(a) Given Munnu\u2019s age to hex years, can you guess what (x – 2) may show? (Hint: Think of Mannu\u2019s younger brother.) \nCan you guess what (x + 4) may show? What (3x + 7) may show?<\/p>\n
(b) Given Sara\u2019s age today to be y years. \nThink of her age in the future or in the past. \nWhat will the following expression indicate? \ny + 7, y – 3, y + 4\\(\\frac { 1 }{ 2 }\\), y – 2 \\(\\frac { 1 }{ 2 }\\)<\/p>\n
(c) Given n students in the class like football, what may 2n show? What may \\(\\frac { n }{ 2 }\\) show? (Hint: Think of games other than football).<\/p>\n
Answer: \n(a) Munnu\u2019s age = \u00d7 years \nHis younger brother is 2 years younger than him = (x – 2) years \nHis elder brother\u2019s age is 4 years more than his age = (x + 4) years \nHis father is 7 year\u2019s more than thrice of his age = (3x + 7) years<\/p>\n
(b) Her age in past = (y = 3),\\(\\left(y=2 \\frac{1}{2}\\right)\\) \nHer age in future = (y + 7),\\(\\left(y=4 \\frac{1}{2}\\right)\\)<\/p>\n
(c) Number of students like hockey is twice the students liking football, i.e., 2n \nNumber of students like tennis is half the students like football, i.e.,\\(\\frac{n}{2}\\)<\/p>\n","protected":false},"excerpt":{"rendered":"
These NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.4 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 6 Maths Chapter 11 Algebra Exercise 11.4 Question 1. Answer the following: (a) Take Sarita\u2019s present age to be y years (i) What will be her age 5 …<\/p>\n
NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.4<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[10],"tags":[],"yoast_head":"\nNCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.4 - MCQ Questions<\/title>\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n\t \n\t \n\t \n