{"id":25573,"date":"2021-06-23T13:52:16","date_gmt":"2021-06-23T08:22:16","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=25573"},"modified":"2022-03-02T10:36:18","modified_gmt":"2022-03-02T05:06:18","slug":"ncert-solutions-for-class-6-maths-chapter-11-ex-11-5","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-6-maths-chapter-11-ex-11-5\/","title":{"rendered":"NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.5"},"content":{"rendered":"
Question 3. \nPick out the solution from the values given in the bracket next to each equation. Show that the other values do not satisfy the equation. \n(a) 5m = 60 (10,5,12,15) \n(b) n + 12= 20(12,8,20,0) \n(c) p – 5 = 5 (0, 10, 5,-5) \n(d) \\(\\frac{\\mathrm{q}}{2}\\) = 7 (7, 2, 10, 14) \n(e) r – 4 = 0 (4,-4, 8,0) \n(f) x + 4 = 2 (-2, 0, 2, 4) \nAnswer: \n(a) 5m = 60 \nPutting the given values in L.H.S., \n5 \u00d7 10 = 50 \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 m = 10 is not the solution \n5 \u00d7 5 = 25 \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 m = 5 is not the solution \n5 \u00d7 12 = 60 \n\u2235 L.H.S. = R.H.S \n\u2234 m = 12 is a solution \n5 \u00d7 15 = 75 \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 m = 15 is not the solution<\/p>\n
(b) n + 12 = 20 \nPutting the given values in L.H.S., \n12 + 12 = 24 \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 n = 12 is not the solution \n8 + 12 = 20 \n\u2235 L.H.S. = R.H.S \n\u2234 n = 8 is a solution \n20 + 12 = 32 \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 n = 20 is not the solution \n0 + 12 = 12 \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 n = 0 is not the solution<\/p>\n
(c) p – 5 = 5 \nPutting the given values in L.H.S., \n0 – 5 = -5 \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 p = 0 is not the solution \n10 – 5 = 5 \n\u2235 L.H.S. = R.H.S \n\u2234 p = 10 is a solution \n5 – 5 = 0 \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 p = 5 is not the solution \n-5 -5 = -10 \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 p = -5 is not the solution<\/p>\n
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(d) \\(\\frac{\\mathrm{q}}{2}\\) = 7 \nPutting the given values in L.H.S., \n\\(\\frac{\\mathrm{7}}{2}\\) \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 q = 7 is not the solution \n\\(\\frac{\\mathrm{2}}{2}\\) = 1 \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 q = 2 is not the solution \n\\(\\frac{\\mathrm{10}}{2}\\) = 5 \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 q = 10 is not the solution \n\\(\\frac{\\mathrm{14}}{2}\\) = 7 \n\u2235 L.H.S. = R.H.S \n\u2234 q = 14 is a solution<\/p>\n
(e) r – 4 = 0 \nPutting the given values in L.H.S., \n4 – 4 = 0 \n\u2235 L.H.S. = R.H.S \n\u2234 r = 4 is a solution \n– 4 -4 = -8 \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 r = – 4 is not the solution \n8 – 4 = 4 \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 r = 8 is not the solution \n0 – 4 = – 4 \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 r = 0 is not the solution<\/p>\n
(f) x + 4 = 2 \nPutting the given values in L.H.S., \n-2 + 4 = 2 \n\u2235 L.H.S. = R.H.S \n\u2234 x = -2 is a solution \n0 + 4 = 4 \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 x = 0 is not the solution \n2 + 4 = 6 \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 x = 0 is not the solution \n4 + 4 = 8 \n\u2235 L.H.S. \u2260 R.H.S \n\u2234 x = 4 is not the solution<\/p>\n
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Question 4. \n(a) Complete the table and by inspection of the table, find the solution to the equation m + 10 = 16. \n<\/p>\n
(b) Complete the table and by inspection of the table, find the solution to the equation 5t = 35. \n<\/p>\n
(c) Complete the table and find the solution of the equation z\/3 = 4 using the table. \n<\/p>\n
(d) Complete the table and find the solution to the equation m – 7 = 3 \n \nAnswer: \n(a) \n \n\u2235 At m = 6, m + 10 = 16 \u2234 m = 6 is the solution.<\/p>\n
(b) \n \n\u2235 At t = 7, 5t = 35 \u2234 t = 7 is the solution.<\/p>\n
(c) \n \n\u2235 At z = 12, z\/3 = 4 \u2234 z = 12 is the solution.<\/p>\n
(d) \n \n\u2235 At m = 10, m- 7= 3 \u2234 m = 10 is the solution.<\/p>\n
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Question 5. \nSolve the following riddles, you may yourself construct such riddles. \nWho am I? \n(i) Go round a square \nCounting every corner \nThrice and no more! \nAdd the count to me \nTo get exactly thirty four!<\/p>\n
(ii) For each day of the week \nMake an upcount from me \nIf you make no mistake \nYou will get twenty three!<\/p>\n
(iii) I am a special number \nTake away from me a six! \nA whole cricket team \nYou will still be able to fix!<\/p>\n
(iv) Tell me who I am \nI shall give a pretty clue! \nYou will get me back \nIf you take me out of twenty two! \nAnswer: \n(i) According to the condition, \n1 + 12 = 34 or \u00d7 + 12 = 34 \n\u2234 By inspection, we have \n22 + 12 = 34 \nSo, I am 22.<\/p>\n
(ii) Let I am \u2018\u00d7\u2019. \nWe know that there are 7 days in a week. \n\u2234 up-counting from \u00d7 for 7, the sum = 23 \nBy inspections, we have \n16 + 7 = 23 \n\u2234 \u00d7 = 16 \nThus I am 16.<\/p>\n
(iii) Let the special number be x and there are 11 players in cricket team. \n\u2234 Special Number -6 = 11 \n\u00d7 – 6 = 11 \nBy inspection, we get \n17 – 6 = 11 \n\u2234 \u00d7 = 17 \nThus I am 17.<\/p>\n
(iv) Suppose I am \u2018\u00d7\u2019 \n\u2234 22 – 1 = 1 \nor 22 – \u00d7 = \u00d7 \nBy inspection, we have \n22 -11 = 11 \n\u2234 \u00d7 = 11 \nThus I am 11.<\/p>\n","protected":false},"excerpt":{"rendered":"
These NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.5 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 6 Maths Chapter 11 Algebra Exercise 11.5 Question 1. State which of the following are equations (with a variable). Give reason for your answer. Identify the variable from …<\/p>\n