2<\/sup><\/p>\n(d) Area of rectangle \n= lenght \u00d7 breadth \n= 2m ( lm = 100cm) \n= 200 cm \u00d7 70 cm = 14000sq.cm<\/p>\n
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Question 2. \nFind the areas of the squares whose sides are: \n(a) 10 cm \n(b) 14 cm \n(c) 5 m \nAnswer: \n(a) Area of square = side \u00d7 side \n= 10 cm \u00d7 10 cm = 100 cm2<\/sup><\/p>\n(b) Area of square = side \u00d7 side \n= 14 cm \u00d7 14 cm = 196 cm2<\/sup><\/p>\n(c) Area of square = side \u00d7 side \n= 5 m \u00d7 5 m = 25 m2<\/sup><\/p>\nQuestion 3. \nThe length and breadth of three rectangles are as given below: \n(a) 9 m and 6 m \n(b) 17 m and 3 m \n(c) 4 m and 14 m \nWhich one has the largest area and which one has the smallest? \nAnswer: \n(a) Area of rectangle \n= length \u00d7 breadth \n= 9 m \u00d7 6 m = 54 m2<\/sup><\/p>\n(b) Area of rectangle \n= length \u00d7 breadth \n= 3 m \u00d7 17 m = 51 m2<\/sup><\/p>\n(c) Area of rectangle \n= length \u00d7 breadth \n= 4 m \u00d7 14 m = 56 m2<\/sup> \nThus, the rectangle (c) has largest area, and rectangle (b) has smallest area.<\/p>\n <\/p>\n
Question 4. \nThe area of a rectangular garden 50 m long is 300 sq m. Find the width of the garden. \nAnswer: \nLength of rectangle \n= 50 m and Area of rectangle = 300 m2 <\/sup>Since, Area of rectangle \n= length \u00d7 breadth \nTherefore, breadth \n\\(\\frac{\\text { Area of rectangle }}{\\text { Length }}\\) = \\(\\frac{300}{50}\\) = 6m \nThus, the breadth of the garden is 6 m.<\/p>\nQuestion 5. \nWhat is the cost of tiling a rectangular plot of land 500 m long and 200 m wide at the rate of \u20b9 8 per hundred sq m? \nAnswer: \nLength of land \n= 500 m and Breadth of land = 200 m \nArea of land = length \u00d7 breadth \n= 500 m \u00d7 200 m = 1,00,000 m2<\/sup> \nCost of tilling 100 sq. m of land = 8 \n\u2234 Cost of tilling 1,00,000 sq. m of land \n\\(\\frac{8 \\times 100000}{100}\\) = 8000<\/p>\nQuestion 6. \nA table-top measures 2 m by 1 m 50 cm. What is its area in square metres? \nAnswer: \nLength of table = 2 m \nBreadth of table = 1 m 50 cm = 1.50 m \nArea of table = length \u00d7 breadth \n= 2 m \u00d7 1.50 m = 3 m2<\/sup><\/p>\n <\/p>\n
Question 7. \nA room is 4 m long and 3 m 50 cm wide. How many square metres of carpet is needed to cover the floor of the room? \nAnswer: \nLength of room = 4 m \nBreadth of room = 3 m 50 cm = 3.50 m \nArea of carpet = length \u00d7 breadth \n= 4 \u00d7 3.50= 14 m2<\/sup><\/p>\nQuestion 8. \nA floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the floor. Find the area of the floor that is not carpeted. \nAnswer: \nLength of floor \n= 5 m and breadth of floor = 4 m \nArea of floor = length \u00d7 breadth \n= 5m \u00d7 4m = 20m2<\/sup> \nNow, Side of square carpet = 3 m \nArea of square carpet = side \u00d7 side \n= 3 \u00d7 3 = 9 m2<\/sup> \nArea of floor that is not carpeted = 20m2<\/sup> – 9m2<\/sup> = 11m2<\/sup><\/p>\nQuestion 9. \nFive square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land? \nAnswer: \nSide of square bed = 1 m \nArea of square bed = side \u00d7 side \n= 1m \u00d7 1m = 1m2<\/sup> \n\u2234 Area of 5 square beds = 1 \u00d7 5 = 5 m2<\/sup> \nNow, Length of land = 5 m \nBreadth of land = 4 m \n\u2234 Area of land = length \u00d7 breadth \n= 5 m \u00d7 4 m = 20 m2<\/sup> \nArea of remaining part \n= Area of land – Area of 5 flower beds = 20 m2<\/sup> – 5 m2<\/sup> = 15 m2<\/sup><\/p>\n <\/p>\n
Question 10. \nBy splitting the following figures into rectangles, find their areas (The measures are given in centimetres). \n \nAnswer: \n \nArea of HKLM = 3 \u00d7 3 = 9 cm2<\/sup> \nArea of IJGH = 1 \u00d7 2 = 2 cm2<\/sup> \nArea of FEDG = 3 \u00d7 3 = 9 cm2<\/sup> \nArea of ABCD = 2 \u00d7 4 = 8 cm2<\/sup> \nTotal area of the figure \n= 9 + 2 +9 + 8 \n= 28 cm2<\/sup><\/p>\n \nArea of ABCD = 3 \u00d7 1 = 3 cm2<\/sup> \nArea of BDEF = 3 \u00d7 1 = 3 cm2<\/sup> \nArea of FGHI = 3 \u00d7 1 = 3 cm2<\/sup> \nTotal area of the figure = 3 + 3 + 3 = 9 cm2<\/sup><\/p>\n <\/p>\n
Question 11. \nSplit the following shapes into rectangles and find their areas. (The measures are given in centimetres) \n \nAnswer: \n(a) Area of rectangle ABCD \n= 2 \u00d7 10 = 20 cm2<\/sup> \nArea of rectangle DEFG \n= 10 \u00d7 2 = 20 cm2<\/sup> \nTotal area of the figure \n= 20 + 20 = 40 cm2<\/sup> \n <\/p>\n(b) There are 5 squares each of side 7 cm. \nArea of one square \n= 7 \u00d7 7 = 49 cm2<\/sup> \nArea of 5 square \n= 49 \u00d7 5 = 245 cm2 \n <\/p>\n(c) Area of rectangle ABCD \n= 5 \u00d7 1 = 5 cm2<\/sup> \nArea of rectangle EFGH \n= 4 \u00d7 1 = 4 cm2<\/sup> \nTotal area of the figure \n= 5 + 4 cm2<\/sup> \n <\/p>\n <\/p>\n
Question 12. \nHow many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively: \n(a) 100 cm and 144 cm \n(b) 70 cm and 36 cm \nAnswer: \n(a) Area of region \n= 100 cm \u00d7 144 cm = 14400 cm2<\/sup> \nArea of one tile \n= 5 cm \u00d7 12 cm = 60 cm2<\/sup> \nNumber of tiles = \\(\\frac{\\text { Area of region }}{\\text { Area of one tile }}\\) = \\(\\frac{14400}{60}\\) = 240 \nThus, 240 tiles are required.<\/p>\n(b) Area of region \n= 70 cm \u00d7 36 cm = 2520 cm2<\/sup> \nArea of one tile \n= 5 cm \u00d7 12 cm = 60 cm2<\/sup> \nNumber of tiles \n= \\(\\frac{\\text { Area of region }}{\\text { Area of one tile }}\\) = \\(\\frac{2520}{60}\\) = 42 \nThus, 42 tiles are required.<\/p>\n","protected":false},"excerpt":{"rendered":"These NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.3 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Exercise 10.3 Question 1. Find the areas of the rectangles whose sides are: (a) 3 cm and 4 cm (b) 12 m and …<\/p>\n
NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.3<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[10],"tags":[],"yoast_head":"\nNCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.3 - MCQ Questions<\/title>\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n\t \n\t \n\t \n