{"id":25737,"date":"2021-06-23T19:26:41","date_gmt":"2021-06-23T13:56:41","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=25737"},"modified":"2022-03-02T10:36:10","modified_gmt":"2022-03-02T05:06:10","slug":"ncert-solutions-for-class-6-maths-chapter-7-ex-7-3","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-6-maths-chapter-7-ex-7-3\/","title":{"rendered":"NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.3"},"content":{"rendered":"

These\u00a0NCERT Solutions for Class 6 Maths<\/a> Chapter 7 Fractions Ex 7.3 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Exercise 7.3<\/h2>\n

Question 1.
\nWrite the fractions. Are all these fractions equivalent?
\n\"NCERT
\nAnswer:
\n(a) We can find fraction in each figure by the formula
\n\\(\\frac{\\text { Dark part }}{\\text { Total part }}\\)
\n\\(=\\frac{1}{2}, \\frac{2}{4}=\\frac{1}{2}, \\frac{3}{6}=\\frac{1}{2}, \\frac{4}{8}=\\frac{1}{2}\\)
\nThese all fractions are equivalent.<\/p>\n

(b) We can find fraction in each figure by the formula Dark part Total part
\n\\(\\frac{\\text { Dark part }}{\\text { Total part }}\\)
\n\\(=\\frac{4}{12}=\\frac{1}{3}, \\frac{3}{9}=\\frac{1}{3}, \\frac{2}{6}=\\frac{1}{3}, \\frac{6}{15}=\\frac{2}{5}\\)
\nThese all are not equivalent fractions.<\/p>\n

\"NCERT<\/p>\n

Question 2.
\nWrite the fractions and pair up the equivalent fractions from each row.
\n\"NCERT
\nAnswer:
\nEquivalent fraction would be then
\n\"NCERT
\n(a) and (ii) = \\(\\frac { 1 }{ 2 }\\)
\n(b) and (iv) = \\(\\frac { 2 }{ 3 }\\)
\n(c) and (i) = \\(\\frac { 1 }{ 3 }\\)
\n(d) and(v)= \\(\\frac { 1 }{ 4 }\\)
\n(e) and (iii) = \\(\\frac { 3 }{ 4 }\\)<\/p>\n

Question 3.
\nReplace \u25a1 in each of the following by the correct number:
\n\"NCERT
\nAnswer:
\n\"NCERT
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 4.
\nFind the equivalent fraction of \\(\\frac { 3 }{ 5 }\\) having
\n(a) denominator 20 1
\n(b) numerator 9
\n(c) denominator 30
\n(d) numerator 27
\nAnswer:
\nTo find an equivalent fraction, we may multiply\/divide both the numerator and the denominator by the same number.<\/p>\n\n\n\n\n\n\n
(a)<\/td>\nTo make denominator 20, we need to multiple both by 4<\/td>\n\\(\\frac { 12 }{ 20 }\\)<\/td>\n<\/tr>\n
(b)<\/td>\nTo make numerator 9, we need to multiple both by 3<\/td>\n\\(\\frac { 9 }{ 15 }\\)<\/td>\n<\/tr>\n
(c)<\/td>\nTo make denominator 30, we need to multiple both by 6<\/td>\n\\(\\frac { 18 }{ 30 }\\)<\/td>\n<\/tr>\n
(d)<\/td>\nTo make numerator 27, we need to multiple both by 9<\/td>\n\\(\\frac { 27 }{ 45 }\\)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Question 5.
\nFind the equivalent fraction of \\(\\frac { 36 }{ 48 }\\) with
\n(a) numerator 9
\n(b) denominator 4
\nAnswer:<\/p>\n\n\n\n\n
(a)<\/td>\nTo make numerator 9, we need to divide both by 4<\/td>\n\\(\\frac { 9 }{ 12 }\\)<\/td>\n<\/tr>\n
(b)<\/td>\nTo make denominator 4, we need to divide both by 12<\/td>\n\\(\\frac { 3 }{ 4 }\\)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

(a) Hence, the equivalent fraction is \\(\\frac { 9 }{ 12 }\\)
\n(b) Hence, the equivalent fraction is \\(\\frac { 3 }{ 4 }\\)<\/p>\n

Question 6.
\nCheck whether the given fractions are equivalent:
\n(a) \\(\\frac{5}{9}, \\frac{30}{54}\\)
\n(b) \\(\\frac{3}{10}, \\frac{12}{50}\\)
\n(c) \\(\\frac{7}{13}, \\frac{5}{11}\\)
\nAnswer:
\n(a) \\(\\frac{5}{9}, \\frac{30}{54}\\)
\nWe have 5 x 54 = 270
\nand 9 x 30 = 270
\nHere 5 x 54 = 9 x 30
\n\\(\\frac{5}{9}\\) and \\(\\frac{30}{54}\\) are equivalent fractions.<\/p>\n

(b) \\(\\frac{3}{10}, \\frac{12}{50}\\)
\nWe have 3 x 50 = 150
\nand 10 x 12 = 120
\nHere 3 x 50 \u2260 10 x 12
\n\\(\\frac{3}{10}\\) and \\(\\frac{12}{50}\\) are not equivalent fractions.<\/p>\n

(c) \\(\\frac{7}{13}, \\frac{5}{11}\\)
\nWe have 7 x 11 = 77 and 5 x 13 = 65
\nHere 7 x 11 \u2260 5 x 13
\n\\(\\frac{7}{13}\\) anCl \\(\\frac{5}{11}\\) ecluivalent fractions.<\/p>\n

\"NCERT<\/p>\n

Question 7.
\nReduce the following fractions to simplest form:
\n(a) \\(\\frac { 48 }{ 60 }\\)
\n(b) \\(\\frac { 150 }{ 60 }\\)
\n(c) \\(\\frac { 84 }{ 98 }\\)
\n(d) \\(\\frac { 12 }{ 52 }\\)
\n(e) \\(\\frac { 7 }{ 28 }\\)
\nAnswer:
\nTo reduce the fraction to simplest form, we need to find the HCF of numerator and denominator<\/p>\n\n\n\n\n\n\n\n
(a)<\/td>\nHCF of 48 and 60 is 12, So dividing by 12 on both numerator and denominator<\/td>\n\\(\\frac { 4 }{ 5 }\\)<\/td>\n<\/tr>\n
(b)<\/td>\nHCF of 150 and 60 is 12, So dividing by 30 on both numerator and denominator<\/td>\n\\(\\frac { 5 }{ 2 }\\)<\/td>\n<\/tr>\n
(c)<\/td>\nHCF of 84 and 98 is 14, So dividing by 14 on both numerator and denominator<\/td>\n\\(\\frac { 6 }{ 7 }\\)<\/td>\n<\/tr>\n
(d)<\/td>\nHCF of 12 and 52 is 4, So dividing by 4 on both numerator and denominator<\/td>\n\\(\\frac { 3 }{ 13 }\\)<\/td>\n<\/tr>\n
(e)<\/td>\nHCF of 7 and 28 is 7, So dividing by 7 on both numerator and denominator<\/td>\n\\(\\frac { 1 }{ 4 }\\)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Question 8.
\nRamesh had 20 pencils, Sheelu had 50 pencils and Jamaal had 80 pencils. After 4 months, Ramesh used up 10 pencils, Sheelu used up 25 pencils and Jamaal used up 40 pencils. What fraction did each use up? Check if each has used up an equal fraction of her\/his pencils?
\nAnswer:
\nFraction of pencils used by Ramesh
\n\\(=\\frac{\\text { Used pencil }}{\\text { Total pencil }}=\\frac{10}{20}=\\frac{1}{2}\\)
\nFraction of pencils used by Sheelu
\n\\(=\\frac{\\text { Used pencil }}{\\text { Total pencil }}=\\frac{25}{50}=\\frac{1}{2}\\)
\nFractions of pencils used by Jamaal
\n\\(=\\frac{\\text { Used pencil }}{\\text { Total pencil }}=\\frac{40}{80}=\\frac{1}{2}\\)
\nYes, they have all used up an equal fraction of his\/her pencils i.e. \\(\\frac{1}{2}\\)<\/p>\n

\"NCERT<\/p>\n

Question 9.
\nMatch the equivalent fractions and write two more for each.<\/p>\n\n\n\n\n
(i)<\/td>\n\u00a0\\(\\frac { 250 }{ 440 }\\)<\/span><\/td>\n(a) \\(\\frac { 2 }{ 3 }\\)<\/td>\n<\/tr>\n
(ii)<\/td>\n\u00a0\\(\\frac { 180 }{ 200 }\\)<\/td>\n(b) \\(\\frac { 2 }{ 5 }\\)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n\n\n
(iii)<\/td>\n\\(\\frac { 660 }{ 990 }\\)<\/td>\n(c) \\(\\frac { 1 }{ 2 }\\)<\/td>\n<\/tr>\n
(iv)<\/td>\n\\(\\frac { 180 }{ 360 }\\)<\/td>\n(d) \\(\\frac { 5 }{ 8 }\\)<\/td>\n<\/tr>\n
(v)<\/td>\n\\(\\frac { 220 }{ 550 }\\)<\/td>\n(e) \\(\\frac { 9 }{ 10 }\\)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Answer:<\/p>\n\n\n\n\n
(i)<\/td>\n\u00a0\\(\\frac { 250 }{ 440 }\\)(Dividing both nu<\/span>merator and denominator by 50)<\/td>\n(d) \\(\\frac { 5 }{ 8 }\\)<\/td>\n<\/tr>\n
(ii)<\/td>\n\u00a0\\(\\frac { 180 }{ 200 }\\) (Dividing both numerator and denominator by 20)<\/td>\n(e) \\(\\frac { 9 }{ 10 }\\)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n\n\n\n\n\n
(iii)<\/td>\n\\(\\frac { 660 }{ 990 }\\) (Dividing both numerator and denominator by 330)<\/td>\n(a) \\(\\frac { 2 }{ 3 }\\)<\/td>\n<\/tr>\n
(iv)<\/td>\n\\(\\frac { 180 }{ 360 }\\) (Dividing both numerator and denominator by 180)<\/td>\n(c) \\(\\frac { 1 }{ 2 }\\)<\/td>\n<\/tr>\n
(v)<\/td>\n\\(\\frac { 220 }{ 550 }\\) (Dividing both numerator and denominator by 110)<\/td>\n(b) \\(\\frac { 2 }{ 5 }\\)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

These\u00a0NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.3 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 6 Maths Chapter 7 Fractions Exercise 7.3 Question 1. Write the fractions. Are all these fractions equivalent? Answer: (a) We can find fraction in each figure by the formula …<\/p>\n

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.3<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[1],"tags":[],"yoast_head":"\nNCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.3 - MCQ Questions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-6-maths-chapter-7-ex-7-3\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.3 - MCQ Questions\" \/>\n<meta property=\"og:description\" content=\"These\u00a0NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.3 Questions and Answers are prepared by our highly skilled subject experts. 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