{"id":25748,"date":"2021-06-24T10:50:58","date_gmt":"2021-06-24T05:20:58","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=25748"},"modified":"2022-03-02T10:36:08","modified_gmt":"2022-03-02T05:06:08","slug":"ncert-solutions-for-class-6-maths-chapter-7-ex-7-4","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-6-maths-chapter-7-ex-7-4\/","title":{"rendered":"NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.4"},"content":{"rendered":"
If the numerator is same, then the smaller of the denominator fraction is bigger<\/td>\n
><\/td>\n<\/tr>\n
\n
(b)<\/td>\n
\\(\\frac{2}{4}=\\frac{1}{2}\\) and \\(\\frac{3}{6}=\\frac{1}{2}\\)<\/span><\/td>\n
=<\/td>\n<\/tr>\n
\n
(c)<\/td>\n
These are unlike fractions, So, \\(\\frac{3}{5}=\\frac{9}{15}\\) and \\(\\frac{2}{3}=\\frac{10}{15}\\)<\/span><\/td>\n
<<\/td>\n<\/tr>\n
\n
(d)<\/td>\n
\\(\\frac{3}{4}=\\frac{3}{4}\\) and \\(\\frac{2}{8}=\\frac{1}{4}\\)<\/span><\/td>\n
><\/td>\n<\/tr>\n
\n
(e)<\/td>\n
Like fraction<\/td>\n
<<\/td>\n<\/tr>\n
\n
(f)<\/td>\n
Like fraction<\/td>\n
><\/td>\n<\/tr>\n
\n
(g)<\/td>\n
\\(\\frac{1}{4}=\\frac{1}{4}\\) and \\(\\frac{2}{8}=\\frac{1}{4}\\)<\/td>\n
=<\/sup><\/td>\n<\/tr>\n
\n
(h)<\/td>\n
\\(\\frac{6}{10}=\\frac{3}{5}\\) and \\(\\frac{4}{5}=\\frac{4}{5}\\)<\/span><\/td>\n
<<\/td>\n<\/tr>\n
\n
(i)<\/td>\n
Unlike fraction<\/td>\n
<<\/td>\n<\/tr>\n
\n
(j)<\/td>\n
\\(\\frac{6}{10}=\\frac{3}{5}\\)<\/td>\n
=<\/td>\n<\/tr>\n
\n
(k)<\/td>\n
\\(\\frac{5}{7}=\\frac{15}{21}\\)<\/td>\n
=<\/sup><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
<\/p>\n
Question 6. \nThe following fractions represent just three different numbers. Separate them into three groups of equivalent fractions, by changing each one to its simplest form. \nAnswer: \nSimplifying the fractions into simplest form. \n \nTotally these are three graps of equivalent fractions 1 \n\\(\\frac { 1 }{ 6 }\\) = (i) (v) (viii) (x) (xi) \n\\(\\frac { 1 }{ 5 }\\) = (ii) (vi) (vii) \n\\(\\frac { 4 }{ 25 }\\) = (iii) (iv) (ix) (xii)<\/p>\n
Question 7. \nFind answers to the following. Write and indicate how you solved them. \n(a) Is \\(\\frac { 5 }{ 9 }\\) equal to \\(\\frac { 4 }{ 5 }\\) ? \n(b) Is \\(\\frac { 9 }{ 16 }\\) equal to \\(\\frac { 5 }{ 9 }\\) ? \n(c) Is \\(\\frac { 4 }{ 5 }\\) equal to \\(\\frac { 16 }{ 20 }\\) ? \n(d) Is \\(\\frac { 1 }{ 15 }\\) equal to \\(\\frac { 4 }{ 30 }\\) ? \nAnswer: \nWe need to first simplify each fraction. After simplification if they are equal, else it is not equal \n(a) Not equal \n(b) Not equal \n(c) Equal \n(d) Not equal<\/p>\n
<\/p>\n
Question 8. \nIla read 25 pages of a book containing 100 pages. Lalita read \\(\\frac { 2 }{ 5 }\\) of the same book. who read less? \nAnswer: \nTotal number of pages in the book = 100 pages \nNumber of pages read by Ila = 25 pages \nFraction of pages read by Ila = \\(\\frac { 25 }{ 100 }\\) \n= \\(\\frac { 1 }{ 4 }\\) \nLauta read \\(\\frac { 2 }{ 5 }\\) of the same book \nSo, basically we need to compare the fraction \\(\\frac { 1 }{ 4 }\\) and \\(\\frac { 2 }{ 5 }\\) \nSince, they are unlike fractions, we need to find LCM of 4 and 5 which is 20. \nSo \\(\\frac{1}{4}=\\frac{5}{20}\\) \n\\(\\frac{2}{5}=\\frac{8}{20}\\) \nNow, 8 > 5 \nSo Ila read lesser than Lauta.<\/p>\n
Question 9. \nRafiq exercised for \\(\\frac { 3 }{ 6 }\\) of an hour, while Rohit exercised for \\(\\frac { 3 }{ 4 }\\) of an hour. Who exercised for a longer time? \nAnswer: \nRafiq = \\(\\frac { 3 }{ 6 }\\) \nRohit = \\(\\frac { 3 }{ 4 }\\) \nWe need to compare the fractions. Since these are unlike fraction, we need to calculate the LCM and 4 and 6. LCM of 4 and 6 is 12. \nRafiq = \\(\\frac{3}{6}=\\frac{6}{12}\\) \nRahit = \\(\\frac{3}{4}=\\frac{9}{12}\\) \n\\(\\frac{9}{12}>\\frac{6}{12}\\) \n\u2234 Rohit exercised for a longer time than Rafiq.<\/p>\n
Question 10. \nIn a class A of 25 students, 20 passed with 60% or more marks; in another class B of 30 students, 24 passed with 60% or more marks. In which class was a greater fraction of students getting with 60% or more marks? \nAnswer: \nTotal number of students in class A = 25 Number of students passed in first class in class A = 20. \nFraction of students of class A who passed in first class = \\(\\frac{20}{25}=\\frac{4}{5}\\) \nTotal number of students in class B = 30 Number of students passed in first class = 24. \nFraction of students of class B who passed in first class = \\(\\frac{24}{30}=\\frac{4}{5}\\) \nBoth class A and B have the same fraction of students who passed in first class.<\/p>\n","protected":false},"excerpt":{"rendered":"
These\u00a0NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.4 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 6 Maths Chapter 7 Fractions Exercise 7.4 Question 1. Write shaded portion as fraction. Arrange them in ascending and descending order using correct sign \u2018<‘, \u2018>’ between the fractions: …<\/p>\n