{"id":26510,"date":"2021-06-26T12:41:06","date_gmt":"2021-06-26T07:11:06","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=26510"},"modified":"2022-03-02T10:47:31","modified_gmt":"2022-03-02T05:17:31","slug":"ncert-solutions-for-class-6-maths-chapter-7-intext-questions","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-6-maths-chapter-7-intext-questions\/","title":{"rendered":"NCERT Solutions for Class 6 Maths Chapter 7 Fractions InText Questions"},"content":{"rendered":"

These NCERT Solutions for Class 7 Maths<\/a> Chapter 7 Fractions InText Questions Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 7 Fractions InText Questions<\/h2>\n

NCERT In-text Question Page No. 137<\/span><\/p>\n

Question 1.
\nShow \\(\\frac { 3 }{ 5 }\\) on a number line.
\nAnswer:
\nFirst we write 1 as \\(\\frac { 3 }{ 5 }\\) and divide the number line into 5 equal parts.
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 2.
\nShow \\(\\frac{1}{10}, \\frac{0}{10}, \\frac{5}{10}\\) and \\(\\frac{10}{10}\\) on a number line.
\nAnswer:
\nWe draw a number line. Divide the length between 0 and 1 into 10 equal parts.
\n\"NCERT
\nThe point B represents \\(\\frac{1}{10}\\)
\nThe point A represents \\(\\frac{0}{10}\\)
\nThe point C represents \\(\\frac{5}{10}\\)
\nThe point D represents \\(\\frac{10}{10}\\)<\/p>\n

Question 3.
\nCan you show any other fraction between 0 and 1? Write five more fractions that you can show and depict them on the number line.
\nAnswer:
\nStep-by-step explanation:
\nTo find the fraction between 0 and 1.
\nWe should always remember one thing that \u201cDenominator should be large than the numerator always\u201d.
\nThus, the fraction between 0 and 1 is:
\n\\(\\frac { 2 }{ 5 }\\) = 0.4 5
\n\\(\\frac { 34 }{ 35 }\\) = 0.97
\n\\(\\frac { 1 }{ 10 }\\) = 0.4
\n\\(\\frac { 51 }{ 65 }\\) = 0.78
\n\\(\\frac { 24 }{ 28 }\\) = 0.85<\/p>\n

Question 4.
\nHow many fractions lie between 0 and 1?
\nThink, discuss and write your answer?
\nAnswer:
\nAn infinite number of fractions lie between 0 and 1.<\/p>\n

\"NCERT<\/p>\n

NCERT In-text Question Page No. 138<\/span><\/p>\n

Question 1.
\nGive a proper fraction :
\n(a) whose numerator is 5 and denominator is 7.
\n(b) whose denominator is 9 and numerator is 5.
\n(c) whose numerator and denominator add up to 10. How many fractions of this kind can you make?
\n(d) whose denominator is 4 more than the numerator.
\nAnswer:
\nA proper fraction whose:
\n(a) numerator is 5 and denominator is 7 = \\(\\frac { 5 }{ 7 }\\)
\n(b) denominator is 9 and numerator is 5 = \\(\\frac { 5 }{ 9 }\\)
\n(c) numerator and denominator add up to 10.
\nPairs of numbers having sum 10 ‘ =(1,9), (2, 8), (3, 7), (4, 6) (5, 5)
\nTherefore, the proper fractions are \\(\\frac{1}{9}, \\frac{2}{8}, \\frac{3}{7}, \\frac{4}{6}\\)
\n(d) denominator is 4 more than the numerator.
\n\\(=\\frac{1}{5}, \\frac{2}{6}, \\frac{15}{19}, \\frac{105}{109}, \\frac{199}{203}\\)<\/p>\n

Question 2.
\nA fraction is given. How will you decide, by just looking at it, whether, the fraction is
\n(a) less than 1? (b) equal to 1?
\nAnswer:
\n(a) If the numerator is smaller than the denominator, then the fraction will be less than 1.
\n(b) If the numerator is equal to the denominator, then the fraction will be equal to 1<\/p>\n

\"NCERT<\/p>\n

Question 3.
\nFill up using one of these : \u201c>\u2019, \u2018<\u2019 or ‘=\u2019
\n\"NCERT
\n\"NCERT
\nAnswer:
\n\"NCERT<\/p>\n

NCERT In-text Question Page No. 142<\/span><\/p>\n

Question 1.
\nAre \\(\\frac { 1 }{ 3 }\\) and \\(\\frac{2}{7} ; \\frac{2}{5}\\) and \\(\\frac{2}{7} ; \\frac{2}{9}\\) and \\(\\frac{6}{27}\\) equivalent ? Give reason.
\nAnswer:
\n(i) \\(\\frac { 1 }{ 3 }\\) and\\(\\frac { 2 }{ 7 }\\) \u2235 1 x 7 = 7, 3 x 2 = 6 and 7 \u2260 6 , i.e. 1 x 7 \u2260 3 x 2
\n\u2234 \\(\\frac { 1 }{ 3 }\\) and\\(\\frac { 2 }{ 7 }\\) are not equivalent and are not equivalent fractions.<\/p>\n

(ii) \\(\\frac { 2 }{ 5 }\\) and\\(\\frac { 2 }{ 7 }\\) \u2234 2 x 7 = 14, 5 x 2 = 10 and 14 \u2260 10, i.e. 2 x 7 \u2260 5 x 2<\/p>\n

(iii) \\(\\frac { 2 }{ 9 }\\) and\\(\\frac { 6 }{ 27 }\\) \u2235 2 x 27 = 54, 9 x 6 = 54
\nand 54 = 54, i.e. 2 x 27 = 9 x 6
\n\\(\\frac { 2 }{ 9 }\\) and\\(\\frac { 6 }{ 27 }\\)<\/p>\n

Question 2.
\nGive example of four equivalent fractions.
\nAnswer:
\nFollowing pairs of fractions are equivalent.
\n(a) \\(\\frac { 2 }{ 8 }\\) and \\(\\frac { 1 }{ 4 }\\)
\n(b) \\(\\frac { 5 }{ 12 }\\) and \\(\\frac { 15 }{ 36 }\\)
\n(c) \\(\\frac { 8 }{ 11 }\\) and \\(\\frac { 16 }{ 22 }\\)
\n(d) \\(\\frac { 4 }{ 26 }\\) and \\(\\frac { 2 }{ 13 }\\)<\/p>\n

\"NCERT<\/p>\n

Question 3.
\nIdentify the fractions in each. Are there fractions equivalent?
\n\"NCERT
\nAnswer:
\n(i) The given figure represents the fraction \\(\\frac { 6 }{ 8 }\\)
\nWe have: \\(\\frac{6}{8}=\\frac{6 \\div 2}{8 \\div 2}=\\frac{3}{4}\\)<\/p>\n

(ii) The given figure represents the fraction \\(\\frac { 9 }{ 12 }\\)
\nWe have \\(\\frac{9}{12}=\\frac{9 \\div 3}{12 \\div 3}=\\frac{3}{4}\\)<\/p>\n

(iii) The given figure represents the
\nfraction \\(\\frac { 12 }{ 16 }\\)
\nWe have: \\(\\frac{12}{16}=\\frac{12 \\div 4}{16 \\div 4}=\\frac{3}{4}\\)<\/p>\n

(iv) The given figure represents the fraction \\(\\frac { 4 }{ 26 }\\)
\nWe have: \\(\\frac{12}{16}=\\frac{12 \\div 4}{16 \\div 4}=\\frac{3}{4}\\)
\nSince, all the fractions represent \\(\\frac { 3 }{ 4 }\\),
\ni.e. \\(\\frac{6}{8}=\\frac{9}{12}=\\frac{13}{16}=\\frac{15}{20}\\) = (each \\(\\frac { 3 }{ 4 }\\))
\nThus, the given figures represent equivalent fractions.<\/p>\n

\"NCERT<\/p>\n

NCERT In-text Question Page No. 143<\/span><\/p>\n

Question 1.
\nFind five equivalent fractions of each of the following:
\n(i) \\(\\frac { 2 }{ 3 }\\)
\n(ii) \\(\\frac { 1 }{ 5 }\\)
\n(iii) \\(\\frac { 3 }{ 5 }\\)
\n(iv) \\(\\frac { 5 }{ 9 }\\)
\nAnswer:
\n\"NCERT
\n\"NCERT
\n\"NCERT<\/p>\n

NCERT In-text Question Page No. 146<\/span><\/p>\n

Question 1.
\nWrite the simplest form of:
\n(i) \\(\\frac{15}{75}\\)
\n(ii) \\(\\frac{16}{72}\\)
\n(iii) \\(\\frac{17}{51}\\)
\n(iv) \\(\\frac{48}{28}\\)
\n(v) \\(\\frac{80}{24}\\)
\nAnswer:
\n(i) Factors of 15 are: 1, 3, 5 and 15
\nFactors of 75 are: 1, 3, 5, 15 25 and 75
\nCommon factors are: 1, 3, 5 and 15
\n\u2234 HCF of 15 and 75 = 15
\nNow, \\(\\frac{15}{75}=\\frac{15 \\div 15}{75 \\div 15}=\\frac{1}{5}\\)
\nThus, simplest form of \\(\\frac{15}{75} \\text { is } \\frac{1}{5}\\)<\/p>\n

(ii) Factors of 16 are: 1, 2, 4, 6, 8 and 16 Factors of 72 are: 1, 2, 3, 4, 6, 8, 9, 12, 18 24, 36 and 72
\n\u2234 Common factors are: 1, 2, 4, 6 and 8
\nNow, \\(\\frac{16}{72}=\\frac{16 \\div 8}{72 \\div 8}=\\frac{2}{9}\\)
\nThus, the simplest form of \\(\\frac{16}{72}\\) is \\(\\frac{2}{9}\\)<\/p>\n

\"NCERT<\/p>\n

(iii) Factors of 17 are: 1 and 17
\nFactors of 151 are: 1, 3 and 17
\nCommon factors is 17
\n\u2234 HCF of 17 and 51 – 17
\nNow \\(\\frac{17}{51}=\\frac{17 \\div 17}{51 \\div 17}=\\frac{1}{3}\\)
\nThus, the simplest form ot \\(\\frac { 17 }{ 51 }\\) is \\(\\frac { 1 }{ 3 }\\).<\/p>\n

(iv) Factors of 42 are: 1, 2, 3, 6, 7, 14, 21 and 42
\nFactors of 28 are: 1, 2, 4, 7, 14 and 28 Common factors are: 1, 2, 7 and 14
\n\u2234 HCF of 42 and 28 = 14
\nNow \\(\\frac{42}{28}=\\frac{42 \\div 14}{28 \\div 14}=\\frac{3}{2}\\)
\nThus, the simplest form of \\(\\frac{42}{28} \\text { is } \\frac{3}{2}\\)<\/p>\n

(v) Factors of 80 are: 1, 2, 4, 5, 8, 10, 16, 20, 40 and 80
\nFactors of 24 are: 1, 2, 3, 4, 6, 8, 12 and 24
\nCommon factors are: 1, 2, 4 and 8
\n\u2234 HCF of 80 and 24 = 8
\nNow, \\(\\frac{80}{24}=\\frac{80 \\div 8}{24 \\div 8}=\\frac{10}{3}\\)
\nThus, the simplest torm \\(\\frac{80}{24} \\text { is } \\frac{10}{3}\\)<\/p>\n

Question 2.
\nIs \\(\\frac{49}{64}\\) in its simplest form?
\nAnswer:
\nSteps to simplifying fractions. Find the HCF of numerator and denominator GCD of 42 and 64 is 2. Divide both the numerator and denominator by the GCD 21
\nReduced fraction: \\(\\frac { 21 }{ 32 }\\) .Therefore, 42\/64
\n21 32 simplified is \\(\\frac { 21 }{ 32 }\\).<\/p>\n

\"NCERT<\/p>\n

NCERT In-text Question Page No. 148<\/span><\/p>\n

Question 1.
\nYou get one-fifth of a bottle of juice and your sister gets one third of the same size of a bottle of juice. Who gets more?
\nAnswer:
\nMy sister gets more because \\(\\frac{1}{3}>\\frac{1}{5}\\)<\/p>\n

NCERT In-text Question Page No. 149<\/span><\/p>\n

Question 2.
\nWhich is the larger fraction?
\n(i) \\(\\frac{7}{10} \\text { or } \\frac{8}{10}\\)
\n(ii) \\(\\frac{11}{24} \\text { or } \\frac{13}{24}\\)
\n(iii) \\(\\frac{17}{102} \\text { or } \\frac{12}{102}\\)
\nWhy are these comparisons easy to make?
\nAnswer:
\n(i) \\(\\frac{7}{10}<\\frac{8}{10}\\)
\nDenominators are same and 7 < 8
\n\u2234 \\(\\frac{7}{10}<\\frac{8}{10}\\)<\/p>\n

(ii) \\(\\frac{11}{24}<\\frac{13}{24}\\)
\nDenominators are same and 11 < 13
\n\u2234 \\(\\frac{11}{24}<\\frac{13}{24}\\)<\/p>\n

(iii) \\(\\frac{17}{102} \\text { and } \\frac{12}{102}\\)
\nDenominators are same and 17< 12
\n\u2234 \\(\\frac{17}{102}>\\frac{12}{102}\\)
\n(b) These comparisons are easy because these are like fractions.<\/p>\n

\"NCERT<\/p>\n

Question 3.
\nWrite these in ascending and also in descending order:
\n(a) \\(\\frac{1}{8}, \\frac{5}{8}, \\frac{3}{8}\\)
\n(a) \\(\\frac{1}{5}, \\frac{11}{5}, \\frac{4}{5}, \\frac{3}{5}, \\frac{7}{5}\\)
\n(a) \\(\\frac{1}{7}, \\frac{3}{7}, \\frac{13}{7}, \\frac{11}{7}, \\frac{7}{7}\\)
\nAnswer: We can write the like fractions in ascending or in descending order according to the order of their numerators.
\n(a) \\(\\frac{1}{8}, \\frac{5}{8}, \\frac{3}{8}\\)
\n\u2235 1,3 and 5 are in ascending order.
\n\u2234 \\(\\frac{1}{8}, \\frac{3}{8}\\) and \\(\\frac{5}{8}\\) are in ascending order
\nand \\(\\frac{5}{3}, \\frac{3}{8}\\) and \\(\\frac{1}{8}\\) are in descending order.<\/p>\n

(b) \\(\\frac{1}{5}, \\frac{11}{5}, \\frac{4}{5}, \\frac{3}{5}, \\frac{7}{5}\\)
\n\u2235 1, 3, 4, 7 11 are in ascending order and 11, 7, 4, 3 and 1 are in descending order.
\n\u2234 Fractions in ascending order:
\n\\(\u2234\\)
\n\u2234 Fractions in descending order:
\n\\(\\frac{11}{5}, \\frac{7}{5}, \\frac{4}{5}, \\frac{3}{5}, \\frac{1}{5}\\)<\/p>\n

(c) \\(\\frac{1}{7}, \\frac{3}{77}, \\frac{13}{7}, \\frac{11}{7}, \\frac{7}{7}\\)
\n\u2235 1, 3, 7, 11 and 13 are in ascending order and 13, 11, 7, 3 and 1 are in descending order.
\n\\(\\frac{1}{7}, \\frac{3}{7}, \\frac{7}{7}, \\frac{11}{7}, \\frac{13}{7}\\)
\n\u2234 Fractions in descending order:
\n\\(\\frac{13}{7}, \\frac{11}{7}, \\frac{7}{7}, \\frac{3}{7}, \\frac{1}{7}\\)<\/p>\n

\"NCERT<\/p>\n

NCERT In-text Question Page No. 151<\/span><\/p>\n

Question 1.
\nArrange the following in ascending and descending order:
\n(a) \\(\\frac{1}{12}, \\frac{1}{23}, \\frac{1}{5}, \\frac{1}{7}, \\frac{1}{50}, \\frac{1}{9}, \\frac{1}{17}\\)
\n(b) \\(\\frac{3}{7}, \\frac{3}{11}, \\frac{3}{5}, \\frac{3}{2}, \\frac{3}{13}, \\frac{3}{4}, \\frac{3}{17}\\)
\n(c) Write 3 more similar examples and arrange them in ascending and descending order.
\nAnswer:
\nWe know that in ‘unlike’ fractions having same numerator, the greater the value of the denominator, the smaller the value of the fractional number.
\n(a) \u2235 50, 23, 17, 12, 9, 7 and 5 are in descending order.
\n\u2234 Fractions in ascending order are:
\n\\(\\frac{1}{50}, \\frac{1}{23}, \\frac{1}{17}, \\frac{1}{12}, \\frac{1}{9}, \\frac{1}{7}, \\frac{1}{5}\\) and fractions in descending order are:
\n\\(\\frac{1}{50}, \\frac{1}{23}, \\frac{1}{17}, \\frac{1}{12}, \\frac{1}{9}, \\frac{1}{7}, \\frac{1}{5}\\)<\/p>\n

(b) \u2235 17, 13, 11, 7, 5, 4 and 2 are in descending order
\n\u2234 Ascending order of the given fractions is \\(\\frac{3}{17}, \\frac{3}{13}, \\frac{3}{11}, \\frac{3}{7}, \\frac{3}{5}, \\frac{3}{4}, \\frac{3}{2}\\) and descending order of the given fraction is
\n\\(\\frac{3}{2}, \\frac{3}{4}, \\frac{3}{5}, \\frac{3}{7}, \\frac{3}{11}, \\frac{3}{13}, \\frac{3}{17}\\)<\/p>\n

(c) Three more examples of unlike fractions with same numerator are:
\n\"NCERT
\nArrange the above in ascending and descending order by yourself
\nAnswer:
\n\"NCERT
\n\"NCERT<\/p>\n

NCERT In-text Question Page No. 155<\/span><\/p>\n

Question 1.
\nMy mother divided an apple into 4 equal parts. She gave me two parts and my brother one part. How much apple did she give to both of us together?
\nAnswer:
\nmother gave to me \\(\\frac { 1 }{ 2 }\\) part
\nmother gave to my brother \\(\\frac { 1 }{ 4 }\\) part
\nShe gave both off us
\n\\(\\frac{1}{2}+\\frac{1}{4}=\\frac{3}{4}\\) part<\/p>\n

\"NCERT<\/p>\n

Question 2.
\nMother asked Neelu and her brother to pick stones from the wheat. Neelu picked one fourth of the total stones in it and her brother also picked up one fourth of the stones. What fraction of the stones did both pick up together?
\nAnswer:
\nneelu picked stones = \\(\\frac { 1 }{ 4 }\\)
\nbrother picked up the stones = \\(\\frac { 1 }{ 4 }\\)
\nThe total fraction of the stones they both 1 1 1
\npick up together = \\(\\frac{1}{4}+\\frac{1}{4}=\\frac{1}{2}\\) of total stones.<\/p>\n

Question 3.
\nSohan was putting covers on his note books. He put one fourth of the covers on Monday. He put another one fourth on Tuesday and the remaining on Wednesday. What fraction of the covers did he put on Wednesday?
\nAnswer:
\nSohan put one-fourth of the covers on Monday, i.e., 1\/4 covers.
\nHe put one-fourth on Tuesday, i.e., 1\/4 covers and the remaining on Wednesday.
\nNow, covers put on Monday and Tuesday
\n= \\(\\frac{1}{4}+\\frac{1}{4}=\\frac{1+1}{4}=\\frac{2}{4}\\)
\nSo, covers put on Wednesday
\n\"NCERT<\/p>\n

NCERT In-text Question Page No. 156<\/span><\/p>\n

Question 4.
\nAdd with the help of a diagram.
\n(i) \\(\\frac{1}{8}+\\frac{1}{8}\\)
\n(ii) \\(\\frac{2}{5}+\\frac{3}{5}\\)
\n(iii) \\(\\frac{1}{6}+\\frac{1}{6}+\\frac{1}{6}\\)
\nAnswer:
\nMethod I: Look at the figure. It is divided into 8 equal parts.
\n\"NCERT
\nIts shaded part = \\(\\frac { 2 }{ 8 }\\)
\ni.e. = \\(\\frac{1}{8}+\\frac{1}{8}=\\frac{1+1}{8}=\\frac{2}{8} \\text { or } \\frac{1}{4}\\)
\nMethod II: We can also represent the above sum in the following manner:
\n\"NCERT
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 5.
\nAdd \\(\\frac{1}{12}+\\frac{1}{12}\\) How will we show this pictorially and by using paper folding?
\nAnswer:
\nWe have \\(\\frac{1}{12}+\\frac{1}{12}=\\frac{1+1}{12}=\\frac{2}{12}=\\frac{1}{6}\\)
\nTo show \\(\\frac{1}{12}+\\frac{1}{12}\\) pictorially, we have:
\n\"NCERT
\nUsing paper folding (the activity): Do it yourself.<\/p>\n

Question 6.
\nMake 5 more examples of problems given in 1 and 2 above. Solve them with your friends.
\nAnswer:
\nDo it yourself.<\/p>\n

NCERT In-text Question Page No. 157<\/span><\/p>\n

Question 1.
\nFind the difference between \\(\\frac { 7 }{ 8 }\\) and \\(\\frac { 3 }{ 8 }\\) .
\nAnswer:
\n\\(\\frac{7}{8}-\\frac{3}{8}=\\frac{7-3}{8}=\\frac{4}{8}=\\frac{1}{2}\\)
\nThe difference between \\(\\frac { 7 }{ 8 }\\) and \\(\\frac { 3 }{ 8 }\\) is \\(\\frac { 1 }{ 2 }\\).<\/p>\n

Question 2.
\nMother made a gud patti in a round shape. She divided it into 5 parts. Seema ate one piece from it. If I eat another piece then how much would be left?
\nAnswer:
\nSeema ate = \\(\\frac { 1 }{ 5 }\\)
\n1 eat = \\(\\frac { 1 }{ 5 }\\)
\nTotal part eaten is
\n\\(\\frac{1}{5}+\\frac{1}{5}=\\frac{2}{5}\\)
\nThe left part would be
\n= \\(1-\\frac{2}{5}=\\frac{5-2}{5}=\\frac{3}{5}\\)<\/p>\n

\"NCERT<\/p>\n

Question 3.
\nMy elder sister divided the watermelon into 16 parts. I ate 7 out them. My friend ate 4. How much did we eat between us? How much more of the watermelon did I eat than my friend? What portion of the watermelon remained?
\nAnswer:
\n1 ate = \\(\\frac { 7 }{ 16 }\\)
\nMy friend ate = \\(\\frac { 4 }{ 16 }\\)
\nWe both eat \\(\\frac{7}{16}+\\frac{4}{16}=\\frac{7+4}{16}=\\frac{11}{16}\\)
\nthe watermelon more I eat than my friend is \\(\\frac{7}{16}+\\frac{4}{16}=\\frac{7-4}{16}=\\frac{3}{16}\\)
\nThe portion of the watermelon remained \\(1-\\frac{11}{16}=\\frac{16-11}{16}=\\frac{5}{16}\\)<\/p>\n

Question 4.
\nMake five problems of this type and solve them with your friends.
\nAnswer:
\nDo it yourself.<\/p>\n

NCERT In-text Question Page No. 159<\/span><\/p>\n

Question 1.
\nSubtract \\(\\frac { 2 }{ 5 }\\) from \\(\\frac { 5 }{ 7 }\\) .
\nAnswer:
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 2.
\nSubtract \\(\\frac { 2 }{ 5 }\\) from \\(\\frac { 5 }{ 7 }\\) .
\nAnswer:
\n\\(\\frac{5}{7}-\\frac{2}{5}\\)
\n\u2235 LCM of 7 and 5 is 35.
\n\u2234 \\(\\frac{2}{5}=\\frac{2 \\times 7}{5 \\times 7}=\\frac{14}{35}\\)
\nNow, we have:
\n\\(\\frac{5}{7}-\\frac{2}{5}=\\frac{25}{35}-\\frac{14}{35}=\\frac{35-14}{35}=\\frac{11}{35}\\)<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 7 Maths Chapter 7 Fractions InText Questions Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 7 Maths Chapter 7 Fractions InText Questions NCERT In-text Question Page No. 137 Question 1. Show on a number line. Answer: First we write 1 as and divide …<\/p>\n

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