{"id":26647,"date":"2021-06-26T14:53:16","date_gmt":"2021-06-26T09:23:16","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=26647"},"modified":"2022-03-02T10:47:30","modified_gmt":"2022-03-02T05:17:30","slug":"ncert-solutions-for-class-9-maths-chapter-15-ex-15-1","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-9-maths-chapter-15-ex-15-1\/","title":{"rendered":"NCERT Solutions for Class 9 Maths Chapter 15 Probability Ex 15.1"},"content":{"rendered":"

These NCERT Solutions for Class 9 Maths<\/a> Chapter 15 Probability Ex 15.1 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 9 Maths Chapter 15 Probability Exercise 15.1<\/h2>\n

Question 1.
\nIn a cricket match, a batswoman hits a boundary 6 times out of 30 balls she plays. Find the probability that she did not hit a boundary.
\nSolution:
\nTotal number of balls she plays = 30
\nTotal number of balls that she hits a boundary = 6
\nThe total number of balls that she does not hit a boundary = 30 – 6 = 24 balls.
\nLet us denote the event that she does not hit a ball is E: So,
\nP(E) = \\(\\frac{24}{30}=\\frac{4}{5}\\)<\/p>\n

\"NCERT<\/p>\n

Question 2.
\n1500 families with two children were selected randomly, and the following data were recorded.
\n\"NCERT
\nCompute the probability of a family, chosen at random having.
\n(i) 2 girls
\n(ii) 1 girl
\n(iii) No girls
\nAlso, check whether the sum of these probabilities is 1.
\nSolution:
\nTotal number of families = 1500
\n(i) Total number of families which have 2 girls are 475.
\n\u2234 P(2 girls in a family) = \\(\\frac{475}{1500}=\\frac{19}{60}\\)<\/p>\n

(ii) Total number of families which have 1 girl is 814.
\n\u2234 P(1 girl in a family) = \\(\\frac{814}{1500}=\\frac{407}{750}\\)<\/p>\n

(iii) Total number of families which ahve no girl is 211.
\n\u2234 P(no girl in a family) = \\(\\frac{211}{1500}\\)<\/p>\n

Check:
\nSum of probabilities = \\(\\frac{9}{60}+\\frac{407}{750}+\\frac{211}{1500}\\)
\n= \\(\\frac{475+814+211}{1500}\\)
\n= \\(\\frac{1500}{1500}\\)
\n= 1<\/p>\n

Question 3.
\nRefer to example 5, section 14.4, chapter 14 final the probability that a student of the class was born in August.
\nSolution:
\nTotal number of students who were born in August = 6
\nTotal number of students = 40
\nTherefore,
\nP(Number of students bom in August) = \\(\\frac{6}{40}\\) = \\(\\frac{3}{20}\\)<\/p>\n

\"NCERT<\/p>\n

Question 4.
\nThree coins are tossed simultaneously 200 times with the following frequencies of different outcomes:
\n\"NCERT
\nIf the three coins are simultaneously tossed again, compute the probability of 2 heads coming up.
\nSolution:
\nSince the coin is tossed 200 times, so the total number of trials is 200.
\nLet us call the events of getting 2 heads is E.
\nThen the number of times E happens, i.e. two heads coming up is 72.
\nSo, P(E) = \\(\\frac{72}{200}=\\frac{9}{25}\\)<\/p>\n

Question 5.
\nAn organization selected 2400 families at random and surveyed them to determine a relationship between income level and the number of vehicles in a home. The information gathered is listed in the table below:
\n\"NCERT
\nSuppose a family is chosen. Find the probability that the family chosen is:
\n(i) earning Rs. 10,000 – 13,000 per month and owning exactly 2 vehicles.
\n(ii) earning Rs. 16000 or more per month and owning exactly 1 vehicle.
\n(iii) earning less than Rs. 7000 per month and does not own any vehicle.
\n(iv) earning Rs. 13,000 – 16,000 per month and owning more than 2 vehicles.
\n(v) owning not more than 1 vehicle.
\nSolution:
\nThe total number of families = 2400.
\n(i) The number of families earning Rs. 10,000 – 13,000 per month and owning exactly two vehicles is 29.
\nSo, P(family earning Rs. 10,000 – 13,000 per month and owning exactly two vehicles) = \\(\\frac{29}{2400}\\)<\/p>\n

(ii) The number of families earning Rs. 16,000 or more per month and owning exactly one vehicle is 579.
\nSo, P(earning Rs. 16,000 or more per month and owning exactly one vehicle) = \\(\\frac{579}{2400}\\)<\/p>\n

(iii) The number of families earning less than Rs. 7000 per month and does not own any vehicle is 10.
\nSo, P(earning less than Rs. 7000 per month and does not own any vehicle) = \\(\\frac{10}{2400}=\\frac{1}{240}\\)<\/p>\n

(iv) The number of families earning Rs. 13,000 – 16,000 per month and owning more than two vehicles is 25.
\nSo, P(earning Rs. 13,000 – 16,000 per month and owning more than two vehicles) = \\(\\frac{25}{2400}=\\frac{1}{96}\\)<\/p>\n

(v) The number of families owning not more than 1 vehicle is 2062 (family owning exactly one vehicle + family owning no vehicle)
\nSo, P(owning not more than one vehicle) = \\(\\frac{2062}{2400}=\\frac{1031}{1200}\\)<\/p>\n

\"NCERT<\/p>\n

Question 6.
\nRefer to table 14.7, chapter 14
\n(i) Find the probability that a student obtained less than 20% in the mathematics test.
\n(ii) Find the probability that a student obtained marks 60 or above.
\nSolution:
\n(i) Total number of students = 90
\nNumber of students who gets less than 20% marks in mathematics test = 7.
\n\u2234 P(student obtained less than 20% marks) = \\(\\frac{7}{90}\\)<\/p>\n

(ii) Number of student getting 60 or above marks is 23.
\n\u2234 P(student obtained 60 or above marks) = \\(\\frac{23}{90}\\)<\/p>\n

Question 7.
\nTo know the opinion of the students about the subject statistics, a survey of 200 students was conducted. The data is recorded in the following table.
\n\"NCERT
\nFind the probability that a student is chosen at random
\n(i) like statistics
\n(ii) does not like it.
\nSolution:
\nThe total number of students = 200.
\n(i) Total number of students like statistics = 135
\nSo, P(like statistics) = \\(\\frac{135}{200}=\\frac{27}{40}\\)<\/p>\n

(ii) Total number of students does not like statistics = 65.
\nSo, P(does not like statistics) = \\(\\frac{65}{200}=\\frac{13}{40}\\)<\/p>\n

\"NCERT<\/p>\n

Question 8.
\nRefer to Q.2, Exercise-14.2. What is the empirical probability that an engineer lives:
\n(i) less than 7 km from her place of work?
\n(ii) more than or equal to 7 km from her place of work?
\n(iii) within \\(\\frac {1}{2}\\) km. from her place of work?
\nSolution:
\n(i) Total number of female engineers whose residence to their place of work given is 40.
\nThe number of engineers whose residence is less than 7 km from their place of work = 9.
\n\u2234 P(less than 7 km from her place of work) = \\(\\frac{9}{40}\\)<\/p>\n

(ii) Number of engineer who’s residence is more than or equal to 7 km from her place of work = 31.
\n\u2234 P(more than or equal to 7 km from place of work) = \\(\\frac{31}{40}\\)<\/p>\n

(iii) Number of engineer who’s residence is within \\(\\frac {1}{2}\\) km. from her place of work = 0.
\n\u2234 P(within \\(\\frac {1}{2}\\) km. from place of work) = \\(\\frac {0}{40}\\) = 0<\/p>\n

Question 9.
\nActivity: Note the frequency of two-wheelers, three-wheelers, and four-wheelers going past during the time interval, in front of your school gate. Find the probability that any one vehicle out of the total vehicles you have observed is a two-wheeler.
\nAnswer:
\nLet the person saw the vehicles for half an hour.
\nThe number of vehicles seen by the person.
\nTwo wheelers = 5
\nThree wheelers = 10
\nFour wheelers = 15
\nSo,total number of space = 5 + 10 + 15 = 30
\nNumber of events when two wheeler is seen = 5
\nProbability = \\(\\frac{\\text { no. of event }}{\\text { no. of space }}\\)
\n= \\(\\frac{5}{30}\\)
\n= \\(\\frac{1}{5}\\)<\/p>\n

\"NCERT<\/p>\n

Question 10.
\nActivity: Ask all the students in your class to write a three-digit number. Choose any student from the room at random, what is the probability that the number written by her\/him is divisible by 3? Remember that a number is divisible by 3 if the sum of its digits is divisible by 3.
\nSolution:
\nThe total number of students in my class = 40.
\nOut of 40 students, 10 students write a three-digit number which is divisible by 3.
\n\u2234 P(student write a number which is divisible by 3) = \\(\\frac{10}{40}=\\frac{1}{4}\\)<\/p>\n

Question 11.
\nEleven bags of wheat flour, each marked 5 kg. actually contained the following weights of flour (in kg): 4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 4.98, 5.04, 5.07, 5.00
\nFind the probability that any of these bags chosen at random contains more than 5 kg. of flour.
\nSolution:
\nThe total number of wheat flour bags is 11.
\nThe total number of wheat flour bags which contain more than 5 kg. of flour is 7.
\n\u2234 P(bags contain more than 5 kg of flour) = \\(\\frac{7}{11}\\)<\/p>\n

Question 12.
\nIn Q.5 Exercise 14.2, you were asked to prepare a frequency distribution table, regarding the concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days. Using this table, find the probability of the concentration of sulphur dioxide in the interval 0.12 – 0.16 on any of these days.
\nSolution:
\nThe total number of observations = 30.
\nNumber of observation lie in the interval 0.11 – 0.16 is 2.
\n\u2234 P(The concentration of sulphur dioxide in the interval 0.12 – 0.16 = \\(\\frac{2}{30}=\\frac{1}{15}\\)<\/p>\n

\"NCERT<\/p>\n

Question 13.
\nIn Q. 1, Exercise 14.2, you were asked to prepare a frequency distribution table regarding the blood groups of 30 students of a class. Use this table to determine the probability that a student of this class, selected at random, has blood group AB.
\nSolution:
\nTotal number of students whose blood group are recorded = 30.
\nNumber of students which have blood group AB is 3
\n\u2234 P(student has blood group AB) = \\(\\frac{3}{30}=\\frac{1}{10}\\)<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 9 Maths Chapter 15 Probability Ex 15.1 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 9 Maths Chapter 15 Probability Exercise 15.1 Question 1. In a cricket match, a batswoman hits a boundary 6 times out of 30 balls she plays. Find the …<\/p>\n

NCERT Solutions for Class 9 Maths Chapter 15 Probability Ex 15.1<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[6],"tags":[],"yoast_head":"\nNCERT Solutions for Class 9 Maths Chapter 15 Probability Ex 15.1 - MCQ Questions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-9-maths-chapter-15-ex-15-1\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 9 Maths Chapter 15 Probability Ex 15.1 - MCQ Questions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 9 Maths Chapter 15 Probability Ex 15.1 Questions and Answers are prepared by our highly skilled subject experts. 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