NCERT Solutions for Class 8 Maths<\/a> Chapter 1 Rational Numbers Ex 1.1 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\nNCERT Solutions for Class 8 Maths Chapter 1 Rational Numbers Exercise 1.1<\/h2>\n Question 1. \nUsing appropriate properties, find: \n(i) \\(\\frac{-2}{3} \\times \\frac{3}{5}+\\frac{5}{2}-\\frac{3}{5} \\times \\frac{1}{6}\\) \n(ii) \\(\\frac{2}{5} \\times\\left(\\frac{-3}{7}\\right)-\\frac{1}{6} \\times \\frac{3}{2}+\\frac{1}{14} \\times \\frac{2}{5}\\) \nSolution: \n <\/p>\n
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Question 2. \nWrite the additive inverse of each of the following: \n(i) \\(\\frac{2}{8}\\) \n(ii) \\(\\frac{-5}{9}\\) \n(iii) \\(\\frac{-6}{-5}\\) \n(iv) \\(\\frac{2}{-9}\\) \n(v) \\(\\frac{19}{-6}\\) \nSolution: \n(i) Additive inverse of \\(\\frac{2}{8}\\) is \\(\\frac{-2}{8}\\) \n(ii) Additive inverse of \\(\\frac{-5}{9}\\) is \\(\\frac{5}{9}\\) \n(iii) Additive inverse of \\(\\frac{-6}{-5}\\) is \\(\\frac{-6}{5}\\) \n(iv) Additive inverse of \\(\\frac{2}{-9}=\\left(\\frac{-2}{9}\\right)\\) is \\(\\frac{2}{9}\\) \n(v) Additive inverse of \\(\\frac{19}{-6}=\\left(\\frac{-19}{6}\\right)\\) is \\(\\frac{19}{6}\\)<\/p>\n
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Question 3. \nVerify that -(-x) = x for: \n(i) x = \\(\\frac{11}{15}\\) \n(ii) x = \\(\\frac{-13}{17}\\) \nSolution: \n <\/p>\n
Question 4. \nFind the multiplicative inverse of the following: \n(i) -13 \n(ii) \\(\\frac{-13}{19}\\) \n(iii) \\(\\frac{1}{5}\\) \n(iv) \\(\\frac{-5}{8} \\times \\frac{-3}{7}\\) \n(v) \\(-1 \\times \\frac{-2}{5}\\) \n(vi) -1 \nSolution: \n(i) Multiplicative inverse of -13 is \\(\\frac{-1}{13}\\) \n(ii) Multiplicative inverse of \\(\\frac{-13}{19}\\) is \\(\\frac{-19}{13}\\) \n(iii) Multiplicative inverse of \\(\\frac{1}{5}\\) is 5. \n(iv) \\(\\left(\\frac{-5}{8} \\times \\frac{-3}{7}\\right)=\\frac{(-5) \\times(-3)}{8 \\times 7}=\\frac{56}{15}\\) \nMultiplicative inverse of \\(\\frac{-5}{8} \\times \\frac{-3}{7}\\) is \\(\\frac{15}{56}\\) \n(v) \\(-1 \\times \\frac{-2}{5}=\\frac{(-1) \\times(-2)}{5}=\\frac{2}{5}\\) \nMultiplicative inverse of \\(-1 \\times \\frac{-2}{5}\\) is \\(\\frac{5}{2}\\) \n(vi) Multiplicative inverse of -1 is -1.<\/p>\n
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Question 5. \nName the property under multiplication used in each of the following: \n(i) \\(\\frac{-4}{5} \\times 1=1 \\times \\frac{-4}{5}=\\frac{-4}{5}\\) \n(ii) \\(\\frac{-13}{17} \\times \\frac{-2}{7}=\\frac{-2}{7} \\times \\frac{-13}{17}\\) \n(iii) \\(\\frac{-19}{29} \\times \\frac{29}{-19}=1\\) \nSolution: \n(i) \\(\\frac{-4}{5} \\times 1=1 \\times \\frac{-4}{5}=\\frac{-4}{5}\\) \n1 is the multiplicative identity.<\/p>\n
(ii) \\(\\frac{-13}{17} \\times \\frac{-2}{7}=\\frac{-2}{7} \\times \\frac{-13}{17}\\) \nMultiplication is commutative.<\/p>\n
(iii) \\(\\frac{-19}{29} \\times \\frac{29}{-19}=1\\) \nMultiplicative inverse.<\/p>\n
Question 6. \nMultiply \\(\\frac{6}{13}\\) by the reciprocal of \\(\\frac{-7}{16}\\). \nSolution: \n <\/p>\n
Question 7. \nTell what property allows you to compute \\(\\frac{1}{3} \\times\\left(6 \\times \\frac{4}{3}\\right) \\text { as }\\left(\\frac{1}{3} \\times 6\\right) \\times \\frac{4}{3}\\) \nSolution: \n\\(\\frac{1}{3} \\times\\left(6 \\times \\frac{4}{3}\\right) \\text { as }\\left(\\frac{1}{3} \\times 6\\right) \\times \\frac{4}{3}\\) \nIn the given question, we use the associative property.<\/p>\n
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Question 8. \nIs \\(\\frac{8}{9}\\) the multiplicative inverse of -1\\(\\frac{1}{8}\\)? Why or why not? \nSolution: \n\\(\\frac{8}{9} \\times-\\frac{9}{8}=-1\\) but is not equal to 1. \nSo, \\(\\frac{8}{9}\\) is not the multiplicative inverse of -1\\(\\frac{1}{8}\\)<\/p>\n
Question 9. \nIs 0.3 the multiplicative inverse of 3\\(\\frac{1}{3}\\)? Why or why not? \nSolution: \n0.3 = \\(\\frac{3}{10}\\) \n3\\(\\frac{1}{3}\\) = \\(\\frac{10}{3}\\) \n\\(\\frac{3}{10} \\times \\frac{10}{3}=1\\) \n\u2234 Multiplicative inverse of 3\\(\\frac{1}{3}\\) is 0.3.<\/p>\n
Question 10. \nWrite: \n(i) The rational number that does not have a reciprocal. \n(ii) The rational numbers that are equal to their reciprocals. \n(iii) The rational number that is equal to its negative. \nSolution: \n(i) The rational number \u20180\u2019 does not have a reciprocal. \n(ii) The rational numbers 1 and (-1) are equal to their reciprocal. \n(iii) The rational number \u20180\u2019 is equal to its negative [(0) + (0) = 0] \n\u2234 The negative of 0 is 0.<\/p>\n
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Question 11. \nFill in the blanks: \n(i) Zero has ________ reciprocal. \n(ii) The numbers ________ and ________ are their own reciprocals. \n(iii) The reciprocal of -5 is ________ \n(iv) Reciprocal of \\(\\frac{1}{\\mathrm{x}}\\) when x \u2260 0 is ________ \n(v) The product of two rational numbers is always a ________ \n(vi) The reciprocal of a positive rational number is ________ \nSolution: \n(i) no \n(ii) 1 and -1 \n(iii) \\(\\frac{-1}{5}\\) \n(iv) x \n(v) rational number \n(vi) positive<\/p>\n","protected":false},"excerpt":{"rendered":"
These NCERT Solutions for Class 8 Maths Chapter 1 Rational Numbers Ex 1.1 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 8 Maths Chapter 1 Rational Numbers Exercise 1.1 Question 1. Using appropriate properties, find: (i) (ii) Solution: Question 2. Write the additive inverse of each of the …<\/p>\n
NCERT Solutions for Class 8 Maths Chapter 1 Rational Numbers Ex 1.1<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[7],"tags":[],"yoast_head":"\nNCERT Solutions for Class 8 Maths Chapter 1 Rational Numbers Ex 1.1 - MCQ Questions<\/title>\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n\t \n\t \n\t \n