{"id":26794,"date":"2021-06-28T10:29:49","date_gmt":"2021-06-28T04:59:49","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=26794"},"modified":"2022-03-02T10:47:29","modified_gmt":"2022-03-02T05:17:29","slug":"ncert-solutions-for-class-8-maths-chapter-2-ex-2-1","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-8-maths-chapter-2-ex-2-1\/","title":{"rendered":"NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1"},"content":{"rendered":"

These NCERT Solutions for Class 8 Maths<\/a> Chapter 2 Linear Equations in One Variable Ex 2.1 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Exercise 2.1<\/h2>\n

Solve the following equations.<\/span><\/p>\n

Question 1.
\nx – 2 = 7
\nSolution:
\nx – 2 = 7
\nTransposing (-2) to R.H.S., we get
\nx = 7 + 2
\n\u2234 x = 9<\/p>\n

\"NCERT<\/p>\n

Question 2.
\ny + 3 = 10
\nSolution:
\ny + 3 = 10
\nTransposing 3 to R.H.S., we get
\ny = 10 – 3
\n\u2234 y = 7<\/p>\n

Question 3.
\n6 = z + 2
\nSolution:
\n6 = z + 2
\nTransposing 2 to L.H.S., we get
\n6 – 2 = z
\n4 = z
\n\u2234 z = 4<\/p>\n

\"NCERT<\/p>\n

Question 4.
\n\\(\\frac{3}{7}+x=\\frac{17}{7}\\)
\nSolution:
\n\\(\\frac{3}{7}+x=\\frac{17}{7}\\)
\nTransposing \\(\\frac{3}{7}\\) to R.H.S., we get
\nx = \\(\\frac{17}{7}-\\frac{3}{7}=\\frac{17-3}{7}=\\frac{14}{7}=2\\)
\n\u2234 x = 2<\/p>\n

Question 5.
\n6x = 12
\nSolution:
\n6x = 12
\nDivided by 6 on both sides, we get
\n\\(\\frac{6 x}{6}=\\frac{12}{6}\\)
\n\u2234 x = 2<\/p>\n

\"NCERT<\/p>\n

Question 6.
\n\\(\\frac{t}{5}=10\\)
\nSolution:
\n\\(\\frac{\\mathrm{t}}{5}\\) = 10
\nMultiplying both sides by 5, we get
\n\\(\\frac{\\mathrm{t}}{5}\\) \u00d7 5 = 10 \u00d7 5
\n\u2234 t = 50<\/p>\n

Question 7.
\n\\(\\frac{2 x}{3}=18\\)
\nSolution:
\n\\(\\frac{2 x}{3}=18\\)
\nMultiplying both sides, by 3, we get
\n\\(\\frac{2 x}{3}\\) \u00d7 3 = 18 \u00d7 3
\n2x = 18 \u00d7 3
\nx = \\(\\frac{18 \\times 3}{2}\\) = 9 \u00d7 3 = 27
\n\u2234 x = 27<\/p>\n

\"NCERT<\/p>\n

Question 8.
\n1.6 = \\(\\frac{\\mathrm{y}}{1.5}\\)
\nSolution:
\n1.6 = \\(\\frac{\\mathrm{y}}{1.5}\\)
\nMultiplying both sides by 1.5, we get
\n1.6 \u00d7 1.5 = \\(\\frac{\\mathrm{y}}{1.5}\\) \u00d7 1.5
\n2.4 = y
\n\u2234 y = 2.4<\/p>\n

Question 9.
\n7x – 9 = 16
\nSolution:
\n7x – 9 = 16
\nTransposing (-9) to R.H.S., we get
\n7x = 16 + 9
\nDividing both sides by 7, we get
\n\u2234 x = \\(\\frac{25}{7}\\)<\/p>\n

\"NCERT<\/p>\n

Question 10.
\n14y – 8 = 13
\nSolution:
\n14y – 8 = 13
\nTransposing (-8) to R.H.S., we get
\n14y = 13 + 8
\n14y = 21
\nDividing both sides by 14 we get,
\n\\(\\frac{14 y}{14}\\) = \\(\\frac{21}{14}\\)
\n\u2234 y = \\(\\frac{3}{2}\\)<\/p>\n

Question 11.
\n17 + 6p = 9
\nSolution:
\n17 + 6P = 9
\nTransposing 17 to RHS, we get
\n6P = 9 – 17
\n6P = -8
\nDividing both sides by 6, we have
\n\\(\\frac{6 P}{6}=\\frac{-8}{6}\\)
\n\u2234 P = \\(\\frac{-4}{3}\\)<\/p>\n

\"NCERT<\/p>\n

Question 12.
\n\\(\\frac{x}{3}+1=\\frac{7}{15}\\)
\nSolution:
\n\\(\\frac{x}{3}+1=\\frac{7}{15}\\)
\nTransposing 1 to R.H.S, we get
\n\\(\\frac{x}{3}=\\frac{7}{15}-1\\)
\n\\(\\frac{x}{3}=\\frac{7-15}{15}\\)
\n\\(\\frac{x}{3}=\\frac{-8}{15}\\)
\nMultiplying both sides by 3, we have
\n\\(\\frac{x}{3} \\times 3=\\frac{-8}{15} \\times 3\\)
\n\u2234 x = \\(\\frac{-8}{5}\\)<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Exercise 2.1 Solve the following equations. Question 1. x – 2 = 7 Solution: x …<\/p>\n

NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[7],"tags":[],"yoast_head":"\nNCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1 - MCQ Questions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-8-maths-chapter-2-ex-2-1\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1 - MCQ Questions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1 Questions and Answers are prepared by our highly skilled subject experts. 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