{"id":26801,"date":"2021-06-28T11:23:48","date_gmt":"2021-06-28T05:53:48","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=26801"},"modified":"2022-03-02T10:47:29","modified_gmt":"2022-03-02T05:17:29","slug":"ncert-solutions-for-class-7-maths-chapter-13-intext-questions","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-13-intext-questions\/","title":{"rendered":"NCERT Solutions for Class 7 Maths Chapter 13 Exponents and Powers InText Questions"},"content":{"rendered":"

These NCERT Solutions for Class 7 Maths<\/a> Chapter 13 Exponents and Powers InText Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 13 Exponents and Powers InText Questions<\/h2>\n

NCERT In-text Question Page No. 250<\/span><\/p>\n

Question 1.
\nFind five more such examples, where a number is expressed in exponential form. Also identify the base and the exponent in each case.
\nAnswer:<\/p>\n\n\n\n\n\n\n\n\n
Number<\/td>\nExponential form<\/td>\nBase<\/td>\nExponent<\/td>\n<\/tr>\n
(i) 243 = 3 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 3<\/td>\n35<\/sup><\/td>\n3<\/td>\n5<\/td>\n<\/tr>\n
(ii) 625 = 5 \u00d7 5 \u00d7 5 \u00d7 5<\/td>\n54<\/sup><\/td>\n5<\/td>\n4<\/td>\n<\/tr>\n
(iii) 343 = 7 \u00d7 7 \u00d7 7 .<\/td>\n73<\/sup><\/td>\n7<\/td>\n3<\/td>\n<\/tr>\n
(iv) 1331 = 11 \u00d7 11 \u00d7 11<\/td>\n113<\/sup><\/td>\n11<\/td>\n3<\/td>\n<\/tr>\n
(v) 64 = 8 \u00d7 8<\/td>\n82<\/sup><\/td>\n8<\/td>\n2<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Note: 1. xxxxxxx = x4is read as \u2018x raised to the power 4\u2019 or \u20184th<\/sup> power of x\u2019.
\n2. x2<\/sup>y5<\/sup> is read as \u2018x squared into y raised to power 5\u2019.
\n3. p6<\/sup>q3<\/sup> is reas as \u2018p raised to the power 6 into q cubed\u2019.<\/p>\n

\"NCERT<\/p>\n

NCERT In-text Question Page No. 251<\/span><\/p>\n

Question 1.
\nExpress:
\n(i) 729 as a power of 3
\n(ii) 128 as a power of 2
\n(iii) 343 as a power of 7
\nAnswer:
\n(i) 729
\nWe have: 729 = 3 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 3 = 36<\/sup>
\nThus, 729 = 36<\/sup>
\n\"NCERT<\/p>\n

(ii) 128
\nWe have: 128 = 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 = 27<\/sup>
\nThus, 128 = 27<\/sup>
\n\"NCERT<\/p>\n

(iii) 343
\nWe have: 343 = 7 \u00d7 7 \u00d7 7 \u00d7 7= 73<\/sup>
\nThus, 343 = 73<\/sup>
\n\"NCERT<\/p>\n

NCERT In-text Question Page No. 254<\/span><\/p>\n

Question 1.
\nSimplify and write in exponential form:
\n(i) 25<\/sup> \u00d7 23<\/sup>
\n(ii) p3<\/sup> \u00d7 p2<\/sup>
\n(iii) 43<\/sup> \u00d7 42<\/sup>
\n(iv) a3<\/sup> \u00d7 a2<\/sup> \u00d7 a7<\/sup>
\n(v) 53<\/sup> \u00d7 57<\/sup> \u00d7 512<\/sup>
\n(vi) (-4)100<\/sup> \u00d7 (-4)20<\/sup>
\nAnswer:
\n(i) 25<\/sup> \u00d7 23<\/sup>
\nWe have: 25<\/sup> \u00d7 23<\/sup> = 25 + 3<\/sup> = 28<\/p>\n

\"NCERT<\/p>\n

(ii) p3<\/sup> \u00d7 p2<\/sup>
\nWe have: p3<\/sup> \u00d7 p2<\/sup> = p3 + 2<\/sup> = p5<\/sup><\/p>\n

(iii) 43<\/sup> \u00d7 42<\/sup>
\nWe have: 43<\/sup> \u00d7 42<.sup> = 43+2<\/sup> = p5<\/sup><\/sup><\/p>\n

(iv) a3<\/sup> \u00d7 a2<\/sup> \u00d7 a7<\/sup>
\nWe have: a3<\/sup> \u00d7 a2<\/sup> \u00d7 a7<\/sup> = a3 + 2 + 7<\/sup> = a12<\/sup><\/p>\n

(v) 53<\/sup> \u00d7 57<\/sup> \u00d7 512<\/sup>
\nWe have: 53<\/sup> \u00d7 57<\/sup> \u00d7 512<\/sup> = 53 + 7 + 12<\/sup> = 522<\/sup><\/p>\n

(vi) (-4)100<\/sup> \u00d7 (-4)20<\/sup>
\nWe have: (-4)100<\/sup> \u00d7 (-4)20<\/sup> = (-4)100+2<\/sup> = (4)120<\/sup><\/p>\n

Note: The above rule is possible only for same bases. It is not true for different bases. Thus, 23<\/sup> x 32<\/sup> will no obev this rule.<\/p>\n

NCERT In-text Question Page No. 255<\/span><\/p>\n

Question 1.
\nSimplify and write in exponential form: (eg., 116<\/sup> \u00f7 112<\/sup> = 114<\/sup>)
\n(i) 29<\/sup> \u00f7 23<\/sup>
\n(ii) 108<\/sup> \u00f7 104<\/sup>
\n(iii) 911<\/sup> \u00f7 97<\/sup>
\n(iv) 2015<\/sup> \u00f7 2013<\/sup>
\n(v) 713<\/sup> \u00f7 710<\/sup>
\nAnswer:
\nSince am<\/sup> an<\/sup> = am-n<\/sup>, therefore;
\n(i) 29<\/sup> \u00f7 23<\/sup>
\nWe have: 29<\/sup> \u00f7 23<\/sup> = 29-3<\/sup> = 26<\/sup><\/p>\n

\"NCERT<\/p>\n

(ii) 108<\/sup> \u00f7 104<\/sup>
\nWe have: 108<\/sup> \u00f7 104<\/sup> = 108-4<\/sup> = 104<\/sup><\/p>\n

(iii) 911<\/sup> \u00f7 97<\/sup>
\nWe have: 911<\/sup> \u00f7 97<\/sup> = 911-7<\/sup>= 94<\/sup><\/p>\n

(iv) 2015<\/sup> \u00f7 2013<\/sup>
\nWe have: 2015<\/sup> \u00f7 2013<\/sup> = 2015 -13<\/sup> = 202<\/sup><\/p>\n

(v) 713<\/sup> \u00f7 710<\/sup>
\nWe have: 713<\/sup> \u00f7 710<\/sup> = 713-10<\/sup> = 73<\/sup><\/p>\n

Question 15.
\nSimplify and write the answer in exponential form:
\n(i) (62<\/sup>)4<\/sup>
\n(ii) (22<\/sup>)100<\/sup>
\n(iii) (750<\/sup>)2<\/sup>
\n(iv) ( 53<\/sup>)7<\/sup>
\nAnswer:
\nSince (am<\/sup>)n<\/sup> = amxn<\/sup> = amn<\/sup>, therefore;
\n(i) (62<\/sup>)4<\/sup>
\nWe have: (62<\/sup>)4<\/sup> = 62 \u00d7 4<\/sup> = 68<\/sup><\/p>\n

(ii) (22<\/sup>)100<\/sup>
\nWe have: ( 22<\/sup>)100<\/sup> = 22 \u00d7 100<\/sup> = 2200<\/sup><\/p>\n

(iii) (750<\/sup>)2<\/sup>
\nWe have: (750<\/sup> )2<\/sup> = 750 \u00d7 2<\/sup> = 7100<\/sup><\/p>\n

(iv) ( 53<\/sup>)7<\/sup>
\nWe have: (53<\/sup>)7<\/sup> = 53 \u00d7 7<\/sup> = 521<\/sup><\/p>\n

\"NCERT<\/p>\n

NCERT In-text Question Page No. 256<\/span><\/p>\n

Question 1.
\nPut into another form using am<\/sup> \u00d7 bm<\/sup>= (ab)m<\/sup>
\n(i) 43<\/sup> \u00d7 23<\/sup>
\n(ii) 25<\/sup> \u00d7 b5<\/sup>
\n(iii) a2<\/sup> \u00d7 t2<\/sup>
\n(iv) 56<\/sup> \u00d7 (-2)6<\/sup>
\n(v) (-2)4<\/sup> \u00d7 (-3)4<\/sup>
\nAnswer:
\nSince am<\/sup> \u00f7 an<\/sup> = am-n<\/sup>, therefore;
\n(i) 43<\/sup> \u00d7 23<\/sup>
\nWe have: 43<\/sup> \u00d7 23<\/sup> = (4 \u00d7 2)3<\/sup> = 83<\/sup><\/p>\n

(ii) 25<\/sup> x b5<\/sup>
\nWe have: 25<\/sup> \u00d7 b5<\/sup> = (2 \u00d7 b)5<\/sup>= (2b)5<\/sup><\/p>\n

(iii) a2<\/sup> \u00d7 t2<\/sup>
\nWe have: a2<\/sup> x t2<\/sup> = (a \u00d7 t)2<\/sup> = (at)2<\/sup><\/p>\n

(iv) 56<\/sup> x (-2)6<\/sup>
\nWe have: 56<\/sup> \u00d7 (-2)6<\/sup> = [5 \u00d7 (-2)]6<\/sup> = (-10)6<\/sup><\/p>\n

(v) (-2)4<\/sup> x (-3)4<\/sup>
\nWe have: (-2)4<\/sup> \u00d7 (-3)4<\/sup> = [(-2) \u00d7 (-3)]4<\/sup> = (6)4<\/sup><\/p>\n

NCERT In-text Question Page No. 257<\/span><\/p>\n

Question 2.
\nPut into another form using am<\/sup> \u00f7 bm<\/sup>
\n(i) 45<\/sup> \u00f7 35<\/sup>
\n(ii) (-2)5<\/sup> \u00f7 b5<\/sup>
\n(iii) (-2)3<\/sup> \u00f7 b3<\/sup>
\n(iv) p4<\/sup> \u00f7 q4<\/sup>
\n(v) 56<\/sup> \u00f7 (-2)6<\/sup>
\nAnswer:
\n(i) 45<\/sup> \u00f7 35<\/sup>
\nWe have: 45<\/sup> \u00f7 35<\/sup> = \\(\\left(\\frac{4}{3}\\right)^{5}\\)<\/p>\n

(ii) (-2)5<\/sup> \u00f7 b5<\/sup>
\nWe have: (-2)5<\/sup> \u00f7 b5<\/sup> = \\(\\left(\\frac{2}{b}\\right)^{5}\\)<\/p>\n

\"NCERT<\/p>\n

(iii) (-2)3<\/sup> \u00f7 b3<\/sup>
\nWe have: (-2)3<\/sup> \u00f7 b3<\/sup> = \\(\\left(\\frac{-2}{b}\\right)^{3}\\)<\/p>\n

(iv) p4<\/sup> \u00f7 q4<\/sup>
\nWe have: p4<\/sup> \u00f7 q4<\/sup> = \\(\\left(\\frac{p}{q}\\right)^{4}\\)<\/p>\n

(v) 56<\/sup> \u00f7 (-2)6<\/sup>
\nWe have: 56<\/sup> \u00f7 (-2)6<\/sup> = \\(\\left(\\frac{5}{-2}\\right)^{6}\\) = \\(\\left(-\\frac{5}{2}\\right)^{6}\\)<\/p>\n

NCERT In-text Question Page No. 261<\/span><\/p>\n

Question 1.
\nExpand by expressing powers of 10 in the exponential form:
\n(i) 172
\n(ii) 5,643
\n(iii) 56,439
\n(iv) 1,76,428
\nAnswer:
\n(i) 172:
\nWe have:
\n172 =(1 \u00d7 100) + ( 7 \u00d7 10) + (2 \u00d7 1)
\n= 1 \u00d7 102<\/sup> + 7 \u00d7 101<\/sup> + 2 \u00d7 1)
\n(\u2235100<\/sup> = 1)<\/p>\n

(ii) 5,643:
\nWe have:
\n5,643 = 5 \u00d7 1000 + 6 \u00d7 100 + 4 \u00d7 10 + 3 \u00d7 1
\n= 5 \u00d7 103<\/sup> + 6 \u00d7 102<\/sup> + 4 \u00d7 101<\/sup> + 3 \u00d7 100<\/sup><\/p>\n

(iii) 56,439:
\nWe have:
\n56,439 = 5 \u00d7 10000 + 6 \u00d7 1000 + 4 \u00d7 100 + 3 \u00d7 10 + 9 \u00d7 1
\n= 5 \u00d7 104<\/sup> + 6 \u00d7 103<\/sup> + 4 \u00d7 102<\/sup> + 3 \u00d7 101<\/sup> + 9 \u00d7 100<\/sup><\/p>\n

\"NCERT<\/p>\n

(iv) 1,76,428:
\nWe have:
\n1,76,428 = 1,00,000 + 7 \u00d7 10,000 + 6 \u00d7 1000 + 4 \u00d7 100 + 2 \u00d7 10 + 8 \u00d7 1
\n= 1 \u00d7 105<\/sup> + 7 \u00d7 104<\/sup> + 6 \u00d7 103<\/sup> + 4 \u00d7 102<\/sup> + 2 \u00d7 101<\/sup> + 8 \u00d7 100<\/sup><\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 7 Maths Chapter 13 Exponents and Powers InText Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 7 Maths Chapter 13 Exponents and Powers InText Questions NCERT In-text Question Page No. 250 Question 1. Find five more such examples, where a number is expressed …<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 13 Exponents and Powers InText Questions<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[1],"tags":[],"yoast_head":"\nNCERT Solutions for Class 7 Maths Chapter 13 Exponents and Powers InText Questions - MCQ Questions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-13-intext-questions\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 7 Maths Chapter 13 Exponents and Powers InText Questions - MCQ Questions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 7 Maths Chapter 13 Exponents and Powers InText Questions and Answers are prepared by our highly skilled subject experts. 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NCERT Solutions for Class 7 Maths Chapter 13 Exponents and Powers InText Questions NCERT In-text Question Page No. 250 Question 1. 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