Try These (Page No. 43)<\/span><\/p>\nTake a regular hexagon Fig 3.10.
\n<\/p>\n
Question 1.
\nWhat is the sum of the measures of its exterior angles x, y, z, p, q, r?
\nSolution:
\n\u2220x + \u2220y + \u2220x + \u2220z + \u2220p + \u2220q + \u2220r = 360\u00b0
\n[\u2235 Sum of exterior angles of a polygon = 360\u00b0]<\/p>\n
<\/p>\n
Question 2.
\nIs x = y = z = p = q = r? Why?
\nSolution:
\nSince, all the sides of the polygon are equal.
\n\u2234 It is a regular hexagon.
\nSo, its interior angles are equal.
\n\u2234 x = (180\u00b0 – a)
\ny = (180\u00b0 – a)
\nz = (180\u00b0 – a)
\np = (180\u00b0 – a)
\nq = (180\u00b0 – a)
\nr = (180\u00b0 – a)
\n\u2234 x = y = z = p = q = r<\/p>\n
Question 3.
\nWhat is the measure of each?
\n(i) exterior angle
\n(ii) interior angle
\nSolution:
\n(i) x + y + z = p + q = r = 360\u00b0 [sum of exterior angles = 360\u00b0]
\nand all these angles are equal
\n\u2234 Measure of each exterior angles = \\(\\frac{360^{\\circ}}{6}\\) = 60\u00b0<\/p>\n
(ii) \u2235 Exterior angle = 60\u00b0
\n\u2234 180\u00b0 – 60\u00b0 = Interior angle
\nor 120\u00b0 = Interior angle
\nor Measure of interior angle = 120\u00b0<\/p>\n
<\/p>\n
Question 4.
\nRepeat this activity for the cases of
\n(i) a regular octagon
\n(ii) a regular 20-gon
\nSolution:
\n(i) In a regular octagon, number of sides (n) = 8
\n\u2234 Each exterior angle = \\(\\frac{360^{\\circ}}{8}\\) = 45\u00b0
\n\u2234 Each interior angle = 180\u00b0 – 45\u00b0 = 135\u00b0<\/p>\n
(ii) For a regular 20-gon, the number of sides (n) = 20
\n\u2234 Each exterior angle = \\(\\frac{360^{\\circ}}{20}\\) = 18\u00b0
\nThus, each interior angle = 180\u00b0 – 18\u00b0 = 162\u00b0<\/p>\n
Try These (Page No. 47)<\/span><\/p>\nQuestion 5.
\nTake two identical set squares with angles 30\u00b0 – 60\u00b0 – 90\u00b0 and place them adjacently to form a parallelogram as shown in Fig 3.20. Does this help you to verify the above property?
\n
\nSolution:
\nThe given figure helps us to verify that opposite sides of a parallelogram are of equal length.<\/p>\n
<\/p>\n
Try These (Page No. 48)<\/span><\/p>\nQuestion 6.
\nTake two identical 30\u00b0 – 60\u00b0 – 90\u00b0 set-squares and form a parallelogram as before. Does the figure obtain the help you to confirm the above property?
\nSolution:
\nThe above figure also helps us to confirm that: opposite angles of a parallelogram are equal.<\/p>\n","protected":false},"excerpt":{"rendered":"
These NCERT Solutions for Class 8 Maths Chapter 3 Understanding Quadrilaterals InText Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 8 Maths Chapter 3 Understanding Quadrilaterals InText Questions Try These (Page No. 43) Take a regular hexagon Fig 3.10. Question 1. What is the sum of the measures …<\/p>\n
NCERT Solutions for Class 8 Maths Chapter 3 Understanding Quadrilaterals InText Questions<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[7],"tags":[],"yoast_head":"\nNCERT Solutions for Class 8 Maths Chapter 3 Understanding Quadrilaterals InText Questions - MCQ Questions<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n