NCERT Solutions for Class 8 Maths<\/a> Chapter 4 Practical Geometry Ex 4.3 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\nNCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Exercise 4.3<\/h2>\n Question 1. \nConstruct the following quadrilaterals: \n(i) Quadrilateral MORE \nMO = 6 cm \nOR = 4.5 cm \n\u2220M = 60\u00b0 \n\u2220O = 105\u00b0 \n\u2220R = 105\u00b0<\/p>\n
(ii) Quadrilateral PLAN \nPL = 4 cm \n\u2220A = 6.5 cm \n\u2220P = 90\u00b0 \n\u2220A = 110\u00b0 \n\u2220N = 85\u00b0<\/p>\n
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(iii) Parallelogram HEAR \nHE = 5 cm \nEA = 6 cm \n\u2220R = 85\u00b0<\/p>\n
(iv) Rectangle OKAY \nOK = 7 cm \nKA = 5 cm \nSolution: \n(i) \n \nSteps of construction: \nI. Draw a line segment MO = 6 cm. \nII. At M, draw \\(\\overrightarrow{\\mathrm{MX}}\\), such that \u2220OMX = 60\u00b0 \nIII. At O, draw \\(\\overrightarrow{\\mathrm{OY}}\\), such that \u2220MOY = 105\u00b0 \nIV. From \\(\\overrightarrow{\\mathrm{OY}}\\), cut off OR = 4.5 cm. \nV. At R, draw RZ, such that \u2220ORZ = 105\u00b0. Let \\(\\overrightarrow{\\mathrm{RZ}}\\) intersects \\(\\overrightarrow{\\mathrm{MX}}\\) at E. Thus, MORE is the required quadrilateral.<\/p>\n
(ii) \n \nSteps of construction: \nI. Draw a line segment PL = 4 cm \nII. At L, draw \\(\\overrightarrow{\\mathrm{LX}}\\) such that \u2220PLX = 75\u00b0 \nIII. From \\(\\overrightarrow{\\mathrm{LX}}\\), cut off LA = 6.5 cm \nIV. At A, draw \\(\\overrightarrow{\\mathrm{AY}}\\) such that \u2220LAY = 110\u00b0 \nV. At P, draw \\(\\overrightarrow{\\mathrm{PZ}}\\) such that \u2220LPZ = 90\u00b0. Let \\(\\overrightarrow{\\mathrm{PZ}}\\) and \\(\\overrightarrow{\\mathrm{AY}}\\) intersect at N. Thus, PLAN is required quadrilateral.<\/p>\n
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(iii) \n \nSteps of Construction: \nI. Draw a line segment \\(\\overrightarrow{\\mathrm{HE}}\\) = 5 cm \nII. At E, draw \\(\\overrightarrow{\\mathrm{EX}}\\) such that \u2220HEA = 85\u00b0 \nIII. From \\(\\overrightarrow{\\mathrm{EX}}\\), cut-off EA = 6 cm. \nIV. With centre at A and radius = 5 cm, draw an arc. \nV. With centre at H and radius = 6 cm, draw an arc such that it intersects the previous arc at R. \nVI. Join RA and RH. Thus, HEAR is the required parallelogram.<\/p>\n
(iv) \n \nSteps of Construction: \nI. Draw a line segment OK = 7 cm. \nII. At O, draw \\(\\overrightarrow{\\mathrm{OP}}\\) such that \u2220KOP = 90\u00b0. \nIII. From \\(\\overrightarrow{\\mathrm{OP}}\\), cut-off \\(\\overrightarrow{\\mathrm{OY}}\\) = 5 cm. \nIV. At K, draw \\(\\overrightarrow{\\mathrm{KQ}}\\) such that \u2220OKQ = 90\u00b0 \nV. From \\(\\overrightarrow{\\mathrm{KQ}}\\), cut-off \\(\\overrightarrow{\\mathrm{KA}}\\) = 5 cm. \nVI. Join AY. Thus, OKAY is the required rectangle.<\/p>\n","protected":false},"excerpt":{"rendered":"
These NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.3 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Exercise 4.3 Question 1. Construct the following quadrilaterals: (i) Quadrilateral MORE MO = 6 cm OR = 4.5 cm \u2220M = …<\/p>\n
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.3<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[7],"tags":[],"yoast_head":"\nNCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.3 - MCQ Questions<\/title>\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n\t \n\t \n\t \n