{"id":27049,"date":"2021-06-29T12:04:29","date_gmt":"2021-06-29T06:34:29","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=27049"},"modified":"2022-03-02T10:47:25","modified_gmt":"2022-03-02T05:17:25","slug":"ncert-solutions-for-class-8-maths-chapter-4-ex-4-4","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-8-maths-chapter-4-ex-4-4\/","title":{"rendered":"NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.4"},"content":{"rendered":"

These NCERT Solutions for Class 8 Maths<\/a> Chapter 4 Practical Geometry Ex 4.4 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Exercise 4.4<\/h2>\n

Question 1.
\nConstruct the following quadrilaterals.
\n(i) Quadrilateral DEAR
\nDE = 4 cm
\nEA = 5 cm
\nAR = 4.5 cm
\n\u2220E = 60\u00b0
\n\u2220A = 90\u00b0<\/p>\n

\"NCERT<\/p>\n

(ii) Quadrilateral TRUE
\nTR = 3.5 cm
\nRU = 3 cm
\nUE = 4 cm
\n\u2220R = 75\u00b0
\n\u2220U = 120\u00b0
\nSolution:
\n(i)
\n\"NCERT
\nSteps of construction:
\nI. Draw a line segment DE = 4 cm.
\nII. At E, draw \\(\\overrightarrow{\\mathrm{EX}}\\) such that \u2220DEX = 60\u00b0.
\nIII. From \\(\\overrightarrow{\\mathrm{EX}}\\), cut-off EA = 5 cm.
\nIV. At A, draw ray \\(\\overrightarrow{\\mathrm{AY}}\\) such that \u2220EAY = 90\u00b0.
\nV. From \\(\\overrightarrow{\\mathrm{AY}}\\), cut-off AR = 4.5 cm.
\nVI. Join R and D. Thus, DEAR is the required quadrilateral.<\/p>\n

\"NCERT<\/p>\n

(ii)
\n\"NCERT
\nSteps of construction:
\nI. Draw a line segment \\(\\overrightarrow{\\mathrm{TR}}\\) = 3.5 cm.
\nII. At R, draw a ray \\(\\overrightarrow{\\mathrm{RX}}\\), such that \u2220TRX = 75\u00b0
\nIII. From \\(\\overrightarrow{\\mathrm{RX}}\\), cut-off RU = 3 cm.
\nIV. At U, draw \\(\\overrightarrow{\\mathrm{UY}}\\) such that \u2220RUY = 120\u00b0.
\nV. From UY, cut-off \\(\\overrightarrow{\\mathrm{UE}}\\) = 4 cm.
\nVI. Join E and T. Thus, TRUE is the required quadrilateral.<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.4 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Exercise 4.4 Question 1. Construct the following quadrilaterals. (i) Quadrilateral DEAR DE = 4 cm EA = 5 cm AR = …<\/p>\n

NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.4<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[7],"tags":[],"yoast_head":"\nNCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.4 - MCQ Questions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-8-maths-chapter-4-ex-4-4\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.4 - MCQ Questions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.4 Questions and Answers are prepared by our highly skilled subject experts. 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