{"id":27073,"date":"2021-06-29T12:50:45","date_gmt":"2021-06-29T07:20:45","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=27073"},"modified":"2022-03-02T10:47:24","modified_gmt":"2022-03-02T05:17:24","slug":"ncert-solutions-for-class-7-maths-chapter-12-intext-questions","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-12-intext-questions\/","title":{"rendered":"NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions InText Questions"},"content":{"rendered":"

These NCERT Solutions for Class 7 Maths<\/a> Chapter 12 Algebraic Expressions InText Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions InText Questions<\/h2>\n

NCERT In-text Question Page No. 230<\/span><\/p>\n

Question 1.
\nDescribe how the following expressions are obtained:
\n(i) 7xy + 5
\n(ii) x2<\/sup>
\n(ii) 4x2<\/sup> – 5x
\nAnswer:
\n(i) 7xy + 5
\nTo obtain this expression, we first multiply two variables x and y, i.e. x \u00d7 y = xy. Then we multiply their product by 7 to get 7xy. Next, we add 5 to 7xy to obtain 7xy + 5.<\/p>\n

\"NCERT<\/p>\n

(ii) x:y
\nFirst, x is multiplied by itself i.e., x \u00d7 x = x2<\/sup> Then multiply x2<\/sup> by y to get the required expression, i.e. x2<\/sup> \u00d7 y = x2<\/sup>y<\/p>\n

(iii) 4x2<\/sup> – 5x
\nHere, the variable x is multiplied by itself,
\ni. e. x \u00d7 x = x2<\/sup>
\nThen x2<\/sup> is multiplied by, i.e. x2<\/sup> \u00d7 4 = 4x2<\/sup>
\nNext, we multiply the variable x by 5, i.e. x \u00d7 5 = 5x
\nNow, we subtract 5x from 4x2<\/sup> to get 4x2<\/sup> – 5x<\/p>\n

\"NCERT<\/p>\n

NCERT In-text Question Page No. 231<\/span><\/p>\n

Question 1.
\nWhat are the terms in the followig expressions? Show how the terms are formed. Draw a tree diagram for each expression:
\n(i) 8y + 3x2<\/sup>
\n(ii) 7mn – 4
\n(iii) 2x2<\/sup>y
\nAnswer:
\n(i) 8y + 3x2<\/sup>
\nTerms of 8y + 3x2<\/sup> are: 8y and 3x2<\/sup> the term 8y is formed by multiplying the variable y by 8.
\nThe term 3x2<\/sup> is formed by first multiplying the variable x with itself to get x \u00d7 x = x2<\/sup> and then multiplying x2<\/sup> by 3.
\nTree diagram:
\n\"NCERT
\nTerms of 7mn – 4 are 7 mn and -4. The term 7 mn formed by first multiplying variables m and n to get m \u00d7 n = mn
\nThen multiplying mn by constant 7 to get 7 \u00d7 mn = 7 mn. The term -4 is a constant.
\nTree diagram:
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

(iii) 2x2<\/sup>y
\nThis expression has only one term, i.e. 2x2<\/sup>y. To form this term first we multiply the variable x by itself to get x \u00d7 x = x2<\/sup>. Then the variable y is multiplied by x2 <\/sup>to get
\ny \u00d7 x2<\/sup> = x2<\/sup>y
\nNext, the product x2<\/sup>y is multiplied by 2 to ‘ get
\n2 \u00d7 x2<\/sup>y = 2x2<\/sup>y
\nTree diagram:
\n\"NCERT<\/p>\n

Question 11.
\nWrite three expressions each having 4
\nterms.
\nAnswer:
\n(i) 2x3<\/sup> – 4x2<\/sup> + 9xy + 8
\n(ii) 6x3<\/sup> + 9y2<\/sup> – 3xy2<\/sup> – 12
\n(iii) 9x2<\/sup> – 3x + 12xy – 1<\/p>\n

NCERT In-text Question Page No. 231<\/span><\/p>\n

Question 1.
\nIdentify the coefficients of the terms of following expressions:
\nAnswer:
\n(i) 4x – 3y
\n(ii) a + b + 5
\n(iii) 2y + 5
\n(iv) 2xy
\nAnswer:
\n(i) 4x – 3y
\nThe coefficient of x in 4x is 4.
\nThe coefficient of y in -3y is (-3)<\/p>\n

(ii) a + b + 5
\nThe coefficient of a is 1.
\nThe coefficient of b is 1.
\nThe coefficient of 5 is 1.<\/p>\n

\"NCERT<\/p>\n

(iii) 2y + 5
\nThe coefficient of y in 2y is 2.
\nThe coefficient of 5 is 1.<\/p>\n

(iii) 2xy
\nThe coefficient of xy in 2xy is 2.
\nThe coefficient of y in 2xy is 2x.
\nThe coefficient of x in 2xy is 2y.<\/p>\n

NCERT In-text Question Page No. 233<\/span><\/p>\n

Question 1.
\nGroup the like terms together from the following:
\n12x, 12, -25x, -25, -25y, 1, x, 12y, y
\nAnswer:
\nWe have:
\n(i) 12x, -25x and x are like terms.
\n(ii) -25y, 12y and y are like terms.
\n(iii) 12, -25 and 1 are like terms.<\/p>\n

\"NCERT<\/p>\n

NCERT In-text Question Page No. 233<\/span><\/p>\n

Question 1.
\nClassify the following expressions as a monomial, a binomial or a trianomial: a, a + b, ab + a + b, ab + a + b -5, xy, xy + 5, 5x2<\/sup>– x + 2,4pq – 3q + 5p, 7,4m – 7n + 10, 4mn + 7.
\nAnswer:
\n(i) a is containing 1 term. It is a monomial.
\n(ii) a + b is containing 2 terms. It is a binomial.
\n(iii) ab + a + b is containing 3 terms, it is a trinomial.
\n(iv) ab + a + b – 5 is containing 4 terms. It is a polynomial.
\n(v) xy is containing only 1 term. It is a monomial.
\n(vi) xy + 5 is containing 2 terms. It is a binomial.
\n(vii) 5x2<\/sup> – x + 2 is containing 3 terms. It is a trinomial.
\n(viii) 4pq – 3q + 5p is containing 3 terms. It is a trinomial.
\n(ix) 7 is containing only 1 term. It is a monomial.
\n(x) 4 m – 7n + 10 is containing 3 terms. It is a trinomial.
\n(xi) 4mn + 7 is containing 2 terms. It is a binomial.<\/p>\n

NCERT In-text Question Page No. 236<\/span><\/p>\n

Question 1.
\nThink of at least two situations in which you need to form two algebraic expressions and add or subtract them.
\nAnswer:
\nSituation-I
\nRohan\u2019s per month earning is twice the per month earning of Bibha. Kavita\u2019s per month earnings is RS. 400 more than the sum of Rohan\u2019s and Vibha\u2019s per month earnings. What is the montly earning of Kavita?
\nSituation-II
\nMahesh has twice the number of toys Kanta has: Lata has 5 toys more than twice the number of toys Mahesh and Kanta together have. What is the number of toys that Kanta has?<\/p>\n

\"NCERT<\/p>\n

NCERT In-text Question Page No. 238<\/span><\/p>\n

Question 1.
\nAdd and subtract:
\n(i) m – n, m + n
\n(ii) mn + 5-2, mn + 3
\nAnswer:
\n(i) Adding (m – n) and (m + n), we have:
\n(m-n) + (m + n) = m- n + m + n
\nCollecting like terms, we have:
\n(m + m) + (-n + n)
\n= (1 + 1)m + (-1 + 1)n
\n= 2m + (0)n
\n= 2m
\nNow subtracting (m – n) from (m + n), we have:
\n(m + n)-(m-n) = m + n- m + n
\n= (m – m) + (n + n)
\n= (1 – 1)m + (1 + 1)n
\n= 0m + 2n
\n= 2n<\/p>\n

(ii) Adding mn + 5-2 and mn + 3, we have:
\n(mn + 5 – 2) + (mn + 3)
\n= mn + 5 – 2 + mn + 3
\n= (mn + mn) + (5 – 2 + 3)
\n= (1 + 1)mn + (6)
\n= 2 mn + 6
\nNow, subtracting (mn + 3) from (mn + 5 – 2), we have:
\n(mn + 5 – 2) – (mn + 3)
\n= mn + 5 – 2 – mn – 3
\n= (mn – mn) + (5 – 2 – 3)
\n= (0)mn + 0 = 0 + 0 = 0<\/p>\n

\"NCERT<\/p>\n

NCERT In-text Question Page No. 245<\/span><\/p>\n

Question 1.
\nMake similar pattern with basic figure as shown
\n\"NCERT<\/p>\n

\"NCERT
\n(The number of segments required to make the figure is given to the right. Also, the expression for the number of segments required to make n shapes is also given.)
\nAnswer:
\nDiscover more such patterns as follow.
\n\"NCERT<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions InText Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions InText Questions NCERT In-text Question Page No. 230 Question 1. Describe how the following expressions are obtained: (i) 7xy + 5 (ii) …<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions InText Questions<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[9],"tags":[],"yoast_head":"\nNCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions InText Questions - MCQ Questions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-12-intext-questions\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions InText Questions - MCQ Questions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions InText Questions and Answers are prepared by our highly skilled subject experts. 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