NCERT Solutions for Class 7 Maths<\/a> Chapter 4 Simple Equations Ex 4.4 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\nNCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Exercise 4.4<\/h2>\n Question 1. \nSet up equations and solve them to find the unknown numbers in the following cases: \n(a) Add 4 to eight times a number; you get 60. \n(b) One-fifth of a number minus 4 gives 3. \n(c) If I take three-fourths of a number and add 3 to it, I get 21. \n(d) When I subtracted 11 from twice a number, the result was 15. \n(e) Munna subtracts thrice the number of notebooks he has from 50, he finds the result to be 8. \n(f) Ibenhal thinks of a number. If she adds 19 to it and divides the sum by 5, she will get 8. \n(g) Anwar thinks of a number. If he takes away 7 from \\(\\frac{5}{2}\\) of the number, the result is 23. \nAnswer: \n(a) Let the required number be x \n\u2234 Eight times of the number = 8x \nAccording to the given question, we get \n8x + 4 =60 \nTransposing 4 to R.H.S \n8x = 60 – 4 \n8x = 56 \nDividing both sides by 8, we get \n\\(\\frac{8 x}{8}=\\frac{56}{8}\\) \nx = 7 \n\u2234 The required number = 7<\/p>\n
(b) Let the number be x \none-fifth of the number = \\(\\frac{1}{5}\\) x \nAccording to the given question, we get \n\\(\\frac{1}{5}\\) x – 4 = 3 \nTransposing -4 to R.H.S \n\\(\\frac{1}{5}\\)x = 3 + 4 \n\\(\\frac{1}{5}\\)x = 7 \nMultiplying both sides by 5, we get 1 \n\\(\\frac{1}{5}\\)x \u00d7 5 = 7 \u00d7 5 \nx = 35 \n\u2234 The required number = 35<\/p>\n
(c) Let the number be x \nThree-fourths of the number = \\(\\frac{3}{4}\\) x \nAccording to the given question, we get \n\\(\\frac{3}{4}\\) x + 3 = 21 \nTransposing 3 to R.H.S \n\\(\\frac{3}{4}\\) x = 21 – 3 \n\\(\\frac{3}{4}\\) x = 18 \nMultiplying both sides by 4, we get \n\\(\\frac{3}{4}\\) x \u00d7 4 = 18 \u00d7 4 \n3x = 72 \nDividing both sides by 3, we get \n\\(\\frac{3 x}{3}=\\frac{72}{3}\\) \nx = 24 \n\u2234 Thus, the required number = 24<\/p>\n
(d) Let the number be x \nTwice a number = 2x \nAccording to the given question \n2x – 11 = 15 \nTransposing -11 to R.H.S \n2x = 15 + 11 \n2x = 26 \nDividing both sides by 2, we get \n\\(\\frac{2 \\mathrm{x}}{2}=\\frac{26}{2}\\) \nx = 13 \n\u2234 The required number 13.<\/p>\n
(e) Let the number of notebooks with Munna be \u2018x\u2019 \nThrice the number of notebooks = 3x \nAccording to the given question, we get \n50 – 3x = 8 \nTransposing 50 to R.H.S \n-3x = 8 – 50 \n-3x = -42 \nDividing both sides by (-3), we get \n\\(\\frac{-3 x}{-3}=\\frac{-42}{-3}\\) \nx = 14 \n\u2234 The required number of notebooks is 14.<\/p>\n
(f) Let the number be x \nAccording to the given question, we get \n\\(\\frac{x+19}{5}\\) = 8 \nMultiplying both sides by 5, we get \n\\(\\frac{x+19}{5}\\) \u00d7 5 = 8 \u00d7 5 \nx + 19 = 40 \nTransposing 19 to R.H.S \nx = 40 – 19 \nx = 21 \n\u2234 The required number = 21<\/p>\n
(g) Let the number be x \n\\(\\frac{5}{2}\\) of the number = \\(\\frac{5}{2}\\) x \nAccording to the given question, we get \n\\(\\frac{5}{2}\\) x – 7 = 23 \nTransposing -7 to R.H.S \n\\(\\frac{5}{2}\\)x = 23 + 7 \n\\(\\frac{5}{2}\\)x = 30 \nMultiplying both sides by 2, we get \n\\(\\frac{5}{2}\\) x \u00d7 2 = 30 \u00d7 2 \n5x = 60 \nDividing both sides by 5, we get \n\\(\\frac{5 x}{5}=\\frac{60}{5}\\) \nx = 12 \nThe required number = 12.<\/p>\n
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Question 2. \nSolve the following: \n(a) The teacher tells the class that the highest marks obtained by a student in her class is twice the lowest marks plus 7. The highest score is 87. What is the lowest score?<\/p>\n
(b) In an isosceles triangle, the base angles are equal. The vertex angle is 40\u00b0. What are the base angles of the triangle? (Remember, the sum of three angles of a triangle is 180\u00b0).<\/p>\n
(c) Sachin scored twice as many runs as Rahul. Together, their runs fell two short of a double century. How many runs did each one score? \nAnswer: \n(a) Let the lowest marks scored be x \nTwice the lowest marks = 2x \nAccording to the given question, we get \n2x + 7 = 87 \nTransposing 7 to R.H.S \n2x = 87 – 7 \n2x = 80 \nDividing both sides by 2, we get \n\\(\\frac{2 x}{2}=\\frac{80}{2}\\) \nx = 40 \n\u2234 The lowest marks = 40<\/p>\n
(b) Let the base angle be x\u00b0 \n\u2234 The other base angle = x\u00b0 \nThe vertex angle = 40\u00b0 \n\u2234 Sum of the angles = x + x + 40 \n= 2x + 40 \nAccording to the given question, we get \n2x + 40 = 180\u00b0 \n(Sum of the three angles of a triangle) \n2x = 180\u00b0 – 40\u00b0 \n2x = 140\u00b0 \nDividing both sides by 2, we get \n\\(\\frac{2 x}{2}=\\frac{140}{2}\\) \nx = 70\u00b0 \n\u2234 The base angle of the triangle \n= 70\u00b0<\/p>\n
(c) Let the runs scored by Rahul be x \n\u2234 Sachins runs = 2x \nAccording to the given question, we get \nx + 2x =2(100) -2 \n3x = 200 – 2 \n3x = 198 \nDividing both sides by 3, we get \n\\(\\frac{3 x}{x}=\\frac{198}{3}\\) \nx = 66 \n\u2234 Rahul score = 66 runs and Sachins score = 2 \u00d7 66 = 132 runs<\/p>\n
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Question 3. \nSolve the following: \n(i) Ifran says that he has 7 marbles more than five times the marbles Parmit has. Irfan has 37 marbles. How many marbles does Parmit have?<\/p>\n
(ii) Laxmi\u2019s father is 49 years old. He is 4 years older than three times Laxmi\u2019s age. What is Laxmi\u2019s age?<\/p>\n
(iii) People of Sundargram planted trees in the village garden. Some of the trees were fruit trees. The number of non-fruit trees were two more than three times the number of fruit trees. What was the number of fruit trees planted if the number of non-fruit trees planted was 77? \nAnswer: \n(i) Let the number of marbles with Parmit be x \nNumber of marbles with Irfan = 37 \nAccording to the given question, we get \n5x + 7 = 37 \nTransposing 7 to R.H.S \n5x = 37 – 7 \n5x = 30 \nDividing both sides by 5, we get \n\\(\\frac{5 x}{5}=\\frac{30}{5}\\) \n\\(\\frac{5 x}{5}=\\frac{30}{5}\\) \u21d2 x = 6 \n\u2234 Parmit has 6 marbles.<\/p>\n
(ii) Let Laxmi\u2019s age be x years \nThree times Laxmi s age = 3x \nAccording to the given question, we get \n3x + 4 = 49 \nTransposing 4 to R.H.S \n3x = 49 – 4 \n3x = 45 \nDividing both sides by 3, we get \n\\(\\frac{3 x}{3}=\\frac{45}{3}\\) \nx = 15 \n\u2234 Laxmi\u2019s age= 15 years<\/p>\n
(iii) Let the number of fruit trees be x \nThree times fruit trees = 3x \nNumber of non-fruit trees = 2 + 3x \nAccording to the given question, we get \n2 + 3 x = 77 \nTransposing 2 to R.H.S \n3x = 77 – 2 \n3x = 75 \nDividing both sides by 3, we get \n\\(\\frac{3 x}{3}=\\frac{75}{3}\\) \n\u21d2 x = 25 \n\u2234 The number of fruit trees = 25<\/p>\n
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Question 4. \nSolve the following riddle : \nI am a number, \nTell my identity! \nTake me seven times over \nAnd add a fifty! \nTo reach a triple century \nYou still need forty! \nAnswer: \nLet the required number be x \n7 times the number = 7x \neach triple century = 3 \u00d7 100 = 300 \nAccording to the given riddle, we get \n7x + 50 = 300 – 40 \n7x + 50 = 260 \nTransposing 50 to R.H.S \n7x = 260 – 50 \n7x = 210 \nDividing both sides by 7, we get \n\\(\\frac{7 \\mathrm{x}}{7}=\\frac{210}{7}\\) \nx = 30 \n\u2234 The required number is 30.<\/p>\n","protected":false},"excerpt":{"rendered":"
These NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.4 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Exercise 4.4 Question 1. Set up equations and solve them to find the unknown numbers in the following cases: (a) Add …<\/p>\n
NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.4<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[9],"tags":[],"yoast_head":"\nNCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.4 - MCQ Questions<\/title>\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n\t \n\t \n\t \n