{"id":27246,"date":"2021-06-30T10:13:26","date_gmt":"2021-06-30T04:43:26","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=27246"},"modified":"2022-03-02T10:31:32","modified_gmt":"2022-03-02T05:01:32","slug":"ncert-solutions-for-class-7-maths-chapter-11-ex-11-4","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/","title":{"rendered":"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4"},"content":{"rendered":"

These NCERT Solutions for Class 7 Maths<\/a> Chapter 11 Perimeter and Area Ex 11.4 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Exercise 11.4<\/h2>\n

Question 1.
\nA garden is 90 m long and 75 m broad. A path 5 m wide is to be built outside and around it. Find the area of the path. Also, find the area of the garden in hectare.
\nAnswer:
\nLength of the garden (1) = 90 m
\nBreadth of the garden (b) = 75 m
\nArea of the garden = 1 x b sq units = 90 m x 75 m = 6750 m2<\/sup>
\n\"NCERT
\nLength of the outer rectangle (L)
\n= 90 + 5 + 5 m
\n= 100 m
\nBreadth of the outer rectangle (B)
\n= 75 + 5 + 5 m
\n= 85 m
\nArea of the outer rectangle
\n= L x B = 100 x 85 m2<\/sup>
\n= 8500 m2<\/sup>
\nArea of the pathway = Area of the outer rectangle- Area of the inner rectangle
\n= (8500 – 6750)m2<\/sup>
\n= 1750m2<\/sup>
\n(i) Area of the garden = 6750 m2<\/sup>
\n= \\(\\frac{6750}{10000}\\) ha
\n= 0.675 ha (1 m2<\/sup> = \\(\\frac{1}{10000}\\) ha)
\n(ii) Area of the path = 1750 m2<\/sup><\/p>\n

\"NCERT<\/p>\n

Question 2.
\nA 3 m wide path runs outside and around a rectangular park of length 125 m and breadth 65 m. Find the area of the path.
\nAnswer:
\nLength of the park (1) = 125 m
\nbreadth of the park (b) = 65 m
\nArea of the park = l x b
\n= 125 x 65 m2<\/sup>
\n= 8125m2<\/sup>
\n\"NCERT
\nLength of the outer region (L)
\n= (125 + 3 + 3) m
\n= 131 m
\nBreadth of the outer region (B)
\n= (65 + 3+ 3) = 71 m
\nArea of the outer region
\n= L x B m2<\/sup>
\n= (131 x 71) m2<\/sup>
\n= 9301 m2<\/sup>
\nArea of the path = Area of the outer region – Area of the park
\n= 9301 m2<\/sup> – 8125 m2<\/sup>
\n= 1176 m2<\/sup><\/p>\n

Question 3.
\nA picture is painted on a cardboard 8 cm long and 5 cm wide such that there is a margin of 1.5 cm along each of its sides. Find the total area of the margin.
\nAnswer:
\nLength of the cardboard (l) = 8 cm
\nWidth of the cardboard (b) = 5 cm
\nArea of the card board = 1 x b sq.
\n= 8 x 5 = 40 cm2<\/sup>
\n\"NCERT
\nWidth of the margin = 1.5 cm
\nLength of the inner rectangle
\n= 8 – (1.5 + 1.5) cm
\n= 5 cm
\nBreadth of the inner rectangle
\n= 5 – (1.5 + 1.5)cm
\n= 2 cm
\nArea of the inner rectangle
\n= 5 x 2 = 10 cm2<\/sup>
\nArea of the margin = Area of the cardboard – Area of the inner rectangle
\n= 40 cm2<\/sup> – 10 cm2<\/sup>
\n= 30 cm2<\/sup><\/p>\n

\"NCERT<\/p>\n

Question 4.
\nA verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find:
\n(i) the area of the verandah.
\n(ii) the cost of cementing the floor of the verandah at the rate of \u20b9 200 per m2<\/sup> .
\nAnswer:
\nLength of the room= 5.5 m
\nBreadth of the room = 4 m
\nArea of the room = 5.5 m x 4 m = 22 m2<\/sup>
\nWidth of the verandah = 2.25 m
\nLength of the verandah
\n= 5.5 + (2.25 +2.25) m
\n= 10 m
\n\"NCERT
\nBreadth of the Verandah
\n= 4 + (2.25 + 2.25) m
\n= 8.5 m
\nArea of the outer rectangle
\n= 10 m x 8.5 m ‘
\n= 85 m2<\/sup>
\nArea of the verandah = Area of the outer rectangle – Area of the inner rectangle
\n= 85 m2<\/sup> – 22 m2<\/sup>
\n= 63 m2<\/sup>
\nCost of cementing the verandah
\n= \u20b9 200 x 63
\n= \u20b9 12600<\/p>\n

Question 5.
\nA path 1 m wide is built along the border and inside a square garden of side 30 m. Find:
\n(i) the area of the path
\n(ii) the cost of planting grass in the remaining portion of the garden at the rate of? 40 per m2<\/sup>.
\nAnswer:
\n(i) Length of the outer square = 30 m
\nArea of the outer square = side x side
\n= 30 x 30 = 900 m2<\/sup>
\n\"NCERT
\nLet width of the path = 1 m
\nSide of the inner square
\n= [30 – (1 + 1)3 m
\n= 30m-2m = 28m
\nArea of the inner square
\n= (28 x 28) m2<\/sup>
\n= 784 m2<\/sup>
\nArea of the path = Area of the outer square – Area of the inner square
\n= (900 – 784) m2<\/sup>
\nArea of the path = 116 m2<\/sup><\/p>\n

(ii) Rate of planting grass
\n= \u20b9 40 per m2<\/sup>
\nCost of planting grass = \u20b9 40 x 784
\n= \u20b9 31,360<\/p>\n

\"NCERT<\/p>\n

Question 6.
\nTwo cross roads, each of width 10 m, cut at right angles through the centre of a rectangular park of length 700 m and breadth 300 m and parallel to its sides. Find the area of the roads. Also find the area of the park excluding cross roads. Give the answer in hectares.
\nAnswer:
\nLength of the rectangular park (l) = 700 m
\nBreadth of the rectangular Park (b) = 300 m
\n\"NCERT
\nArea of the park = l x b sqm
\n= 700 x 300 m2<\/sup>
\n= 210000 m2<\/sup>
\nArea of the road HEFG (length wise)
\n= 700 m x 10 m
\n= 7000 m2<\/sup>
\nArea of the road PQRS (breadth wise)
\n= 300 x 10 = 3000 m2<\/sup>
\nArea of KLMN = 10 x 10 = 100 m2<\/sup>
\nArea of the roads = Area of the road HEFG + Area of the Road PQRS – Area of KLMN (which is repeated two times.)
\n= (7000 +3000-100) m2<\/sup>
\n= 9900 m2<\/sup>
\nArea of the park excluding cross roads = Area of the park – Area of the cross roads
\n= 21,0000 m2<\/sup> – 9900 m2<\/sup> = 200100 m2<\/sup>
\n= \\(\\frac{200100}{10000}\\) ha
\n\u2234 Area of the park = 20.01ha<\/p>\n

Question 7.
\nThrough a rectangular field of length 90 m and breadth 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the fields. If the width of each road is 3 m, find
\n(i) the area covered by the roads.
\n(ii) the cost of constructing the roads at the rate of? 110 per m2.
\nAnswer:
\nLength of the rectangular field = 90 m
\nBreadth of the rectangular field = 60 m
\nWidth of each road = 3m.
\n\"NCERT
\nArea of the road ABCD = 90 x 3 m2<\/sup>
\n= 270 m2<\/sup>
\nArea of the road EFGH = 60 x 3
\n= 180 m2<\/sup>
\nArea of PQRS = 3 x 3 = 9 m2<\/sup>
\n(i) Area covered by the roads = Area of the road ABCD + Area of the road EFGH – Area of PQRS (which is repeated two times)
\n= (270 + 180 – 9) m2<\/sup>
\n= 450 m2<\/sup> – 9 m2<\/sup>
\n= 441 m2<\/sup>
\n(ii) Rate of construction of roads = \u20b9 110\/m2<\/sup>
\nCost of construction of roads
\n= \u20b9 110 x 441
\n= \u20b9 48510<\/p>\n

\"NCERT<\/p>\n

Question 8.
\nPragya wrapped a cord around a circular pipe of radius 4 cm (figure given below) and cut off the length required of the cord. Then she wrapped it around a square box of side 4 cm (also shown). Did she have any cord left? (\u03c0 = 3.14)
\nAnswer:
\nRadius of the circular pipe (r) = 4 cm
\nCircumference of the pipe = 2\u03c0r.
\n= 2 x 3.14 x 4 cm = 25.12 cm
\n\"NCERT
\nSide of the square box = 4 cm
\nPerimeter of the square box
\n= 4 x 4 cm
\n= 16 cm
\nSince, 25.12 cm > 16 cm
\nDifference in length
\n= 25.12 cm – 16 cm
\n= 9.12 cm.
\nYes, she has 9.12 cm of length cord left.<\/p>\n

Question 9.
\nThe adjoining figure represents a rectangular lawn with a circular flower bed in the middle. Find: (Take \u03c0 = 3.14)
\n(i) the area of the whole land
\n(ii) the area of the flower bed
\n(iii) the area of the lawn excluding the area of the flower bed
\n(iv) the circumference of the flower bed.
\nIn the following figure, find the area of the shaded portions:
\n\"NCERT
\nAnswer:
\nLength of the land = 10 m
\nBreadth of the land = 5 m
\n(i) Area of the whole land
\n= (10 x 5) m2<\/sup>
\n= 50 m2<\/sup>
\n(ii) Radius of the flower bed (r)
\n= 2 m.
\nArea of the flower bed = \u03c0r2<\/sup> sq.m
\n= 3.14 x 2 x 2 m2<\/sup> = 12.56 m2<\/sup><\/p>\n

(iii) Area of the lawn excluding the area of the flower bed = 50 m2<\/sup> – 12.56 m2<\/sup>
\n= 37.44 m2<\/sup><\/p>\n

(iv) Circumference of the flower bed
\n= 2\u03c0r.
\n= 2 x 3.14 x 2 m
\n= 12.56 m<\/p>\n

Question 10.
\nIn the following figures, find the area of the shaded portions.
\n\"NCERT
\nAnswer:
\n(i) Area of the whole rectangle ABCD
\n= 18 x 10 cm2<\/sup> = 180 cm2<\/sup>
\nArea of the right \u0394AEF
\n= \\(\\frac { 1 }{ 2 }\\) x base x height
\n= \\(\\frac { 1 }{ 2 }\\) x 6 x 10 cm2<\/sup>
\n= 30 cm2<\/sup>
\nArea of the right \u0394CBE
\n= \\(\\frac { 1 }{ 2 }\\) x base x height
\n= \\(\\frac { 1 }{ 2 }\\) x 8 x 10 cm2<\/sup>
\n= 40 cm2<\/sup>
\nArea of the shaded portion = Area of ABCD – (Area of \u0394AEF + Area of \u0394CBE)
\n= 180 – (30 + 40)cm2<\/sup> = 180 cm2<\/sup> – 70 cm2<\/sup> = 110 cm2<\/sup>
\n(ii) Side of the square PQRS = 20 cm
\nArea of the square PQRS
\n= Side x Side
\n= 20 x 20 cm2<\/sup>
\n= 400 cm2<\/sup>
\nArea of the right \u0394QPT
\n= \\(\\frac { 1 }{ 2 }\\) x base x height
\n= \\(\\frac { 1 }{ 2 }\\) x 20 x 10 cm2<\/sup>
\n= 100 cm2<\/sup>
\nArea of the right\u0394TSU
\n= \\(\\frac { 1 }{ 2 }\\) x 10 x 10 cm2<\/sup>
\n= 50 cm2<\/sup>
\nArea of the right AQRU
\n= \\(\\frac { 1 }{ 2 }\\) x 10 x 20 cm2<\/sup>
\n= 100 cm2<\/sup>
\nArea of the shaded portion = Area of the square PQRS – (Area of \u0394QPT + Area of \u0394TSU + Area of \u0394QRU)
\n= 400 cm2<\/sup> – (100 + 50 + 100) cm2<\/sup>
\n= (400 – 250) cm2<\/sup>
\n= 150 cm2<\/sup><\/p>\n

\"NCERT<\/p>\n

Question 11.
\nFind the area of the quadrilateral ABCD. Here, AC = 22 cm, BM = 3 cm, DN = 3 cm, and BM \u22a5 AC, DN \u22a5 AC
\nAnswer:
\nArea of \u0394ABC
\n\"NCERT
\n= \\(\\frac { 1 }{ 2 }\\) x AC x BM
\n= \\(\\frac { 1 }{ 2 }\\) x 22 x 3 cm2<\/sup>
\n= 33 cm2<\/sup>
\nArea of AACD = \\(\\frac { 1 }{ 2 }\\) x AC x ND
\n= \\(\\frac { 1 }{ 2 }\\) x 22 x 3 cm2<\/sup>
\n= 33 cm2<\/sup>
\n\u2234 Area of the quadrilateral ABCD = Area of \u0394ABC + Area of \u0394ACD
\n= 33 cm2<\/sup> + 33 cm2<\/sup>
\n= 66 cm2<\/sup><\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Exercise 11.4 Question 1. A garden is 90 m long and 75 m broad. A path 5 m wide …<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[9],"tags":[],"yoast_head":"\nNCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4 - MCQ Questions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4 - MCQ Questions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Exercise 11.4 Question 1. A garden is 90 m long and 75 m broad. A path 5 m wide … NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4 Read More »\" \/>\n<meta property=\"og:url\" content=\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ Questions\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/NCERTSolutionsGuru\/\" \/>\n<meta property=\"article:published_time\" content=\"2021-06-30T04:43:26+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2022-03-02T05:01:32+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/mcq-questions.com\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-7-Maths-Chapter-11-Perimeter-and-Area-Ex-11.4-1.png\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@ncertsolguru\" \/>\n<meta name=\"twitter:site\" content=\"@ncertsolguru\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Prasanna\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"12 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebSite\",\"@id\":\"https:\/\/mcq-questions.com\/#website\",\"url\":\"https:\/\/mcq-questions.com\/\",\"name\":\"MCQ Questions\",\"description\":\"MCQ Questions for Class 1 to 12\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/mcq-questions.com\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"en-US\"},{\"@type\":\"ImageObject\",\"@id\":\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/#primaryimage\",\"inLanguage\":\"en-US\",\"url\":\"https:\/\/i2.wp.com\/mcq-questions.com\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-7-Maths-Chapter-11-Perimeter-and-Area-Ex-11.4-1.png?fit=278%2C192&ssl=1\",\"contentUrl\":\"https:\/\/i2.wp.com\/mcq-questions.com\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-7-Maths-Chapter-11-Perimeter-and-Area-Ex-11.4-1.png?fit=278%2C192&ssl=1\",\"width\":278,\"height\":192,\"caption\":\"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4 1\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/#webpage\",\"url\":\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/\",\"name\":\"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4 - MCQ Questions\",\"isPartOf\":{\"@id\":\"https:\/\/mcq-questions.com\/#website\"},\"primaryImageOfPage\":{\"@id\":\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/#primaryimage\"},\"datePublished\":\"2021-06-30T04:43:26+00:00\",\"dateModified\":\"2022-03-02T05:01:32+00:00\",\"author\":{\"@id\":\"https:\/\/mcq-questions.com\/#\/schema\/person\/4ba9570f32f2057e70e670c7885e47f3\"},\"breadcrumb\":{\"@id\":\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/#breadcrumb\"},\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/mcq-questions.com\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4\"}]},{\"@type\":\"Person\",\"@id\":\"https:\/\/mcq-questions.com\/#\/schema\/person\/4ba9570f32f2057e70e670c7885e47f3\",\"name\":\"Prasanna\",\"image\":{\"@type\":\"ImageObject\",\"@id\":\"https:\/\/mcq-questions.com\/#personlogo\",\"inLanguage\":\"en-US\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/174540ad43736c7d1a4c4f83c775e74d?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/174540ad43736c7d1a4c4f83c775e74d?s=96&d=mm&r=g\",\"caption\":\"Prasanna\"},\"url\":\"https:\/\/mcq-questions.com\/author\/prasanna\/\"}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4 - MCQ Questions","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/","og_locale":"en_US","og_type":"article","og_title":"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4 - MCQ Questions","og_description":"These NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Exercise 11.4 Question 1. A garden is 90 m long and 75 m broad. A path 5 m wide … NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4 Read More »","og_url":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/","og_site_name":"MCQ Questions","article_publisher":"https:\/\/www.facebook.com\/NCERTSolutionsGuru\/","article_published_time":"2021-06-30T04:43:26+00:00","article_modified_time":"2022-03-02T05:01:32+00:00","og_image":[{"url":"https:\/\/mcq-questions.com\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-7-Maths-Chapter-11-Perimeter-and-Area-Ex-11.4-1.png"}],"twitter_card":"summary_large_image","twitter_creator":"@ncertsolguru","twitter_site":"@ncertsolguru","twitter_misc":{"Written by":"Prasanna","Est. reading time":"12 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebSite","@id":"https:\/\/mcq-questions.com\/#website","url":"https:\/\/mcq-questions.com\/","name":"MCQ Questions","description":"MCQ Questions for Class 1 to 12","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/mcq-questions.com\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"ImageObject","@id":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/#primaryimage","inLanguage":"en-US","url":"https:\/\/i2.wp.com\/mcq-questions.com\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-7-Maths-Chapter-11-Perimeter-and-Area-Ex-11.4-1.png?fit=278%2C192&ssl=1","contentUrl":"https:\/\/i2.wp.com\/mcq-questions.com\/wp-content\/uploads\/2021\/06\/NCERT-Solutions-for-Class-7-Maths-Chapter-11-Perimeter-and-Area-Ex-11.4-1.png?fit=278%2C192&ssl=1","width":278,"height":192,"caption":"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4 1"},{"@type":"WebPage","@id":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/#webpage","url":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/","name":"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4 - MCQ Questions","isPartOf":{"@id":"https:\/\/mcq-questions.com\/#website"},"primaryImageOfPage":{"@id":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/#primaryimage"},"datePublished":"2021-06-30T04:43:26+00:00","dateModified":"2022-03-02T05:01:32+00:00","author":{"@id":"https:\/\/mcq-questions.com\/#\/schema\/person\/4ba9570f32f2057e70e670c7885e47f3"},"breadcrumb":{"@id":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-11-ex-11-4\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/mcq-questions.com\/"},{"@type":"ListItem","position":2,"name":"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4"}]},{"@type":"Person","@id":"https:\/\/mcq-questions.com\/#\/schema\/person\/4ba9570f32f2057e70e670c7885e47f3","name":"Prasanna","image":{"@type":"ImageObject","@id":"https:\/\/mcq-questions.com\/#personlogo","inLanguage":"en-US","url":"https:\/\/secure.gravatar.com\/avatar\/174540ad43736c7d1a4c4f83c775e74d?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/174540ad43736c7d1a4c4f83c775e74d?s=96&d=mm&r=g","caption":"Prasanna"},"url":"https:\/\/mcq-questions.com\/author\/prasanna\/"}]}},"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/posts\/27246"}],"collection":[{"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/users\/9"}],"replies":[{"embeddable":true,"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/comments?post=27246"}],"version-history":[{"count":1,"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/posts\/27246\/revisions"}],"predecessor-version":[{"id":33927,"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/posts\/27246\/revisions\/33927"}],"wp:attachment":[{"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/media?parent=27246"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/categories?post=27246"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/tags?post=27246"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}