NCERT In-text Question Page No. 206<\/span><\/p>\nQuestion 1. \nExperiment with several such shapes and cutouts. You might find it useful to draw these shapes on squared sheets and compute their areas and perimeters. You have seen that increase in perimeter does not mean that area will also increase. \nAnswer: \nPlease do this question yourself with the help of your subject teacher.<\/p>\n
Question 2. \nGive two examples where the area increases as the perimeter increases. \nAnswer: \nPlease do this question yourself with the help of your subject teacher.<\/p>\n
Question 3. \nGive two examples where the area does not increase when perimeter increases. \nAns: Please do this question yourself with the help of your subject teacher.<\/p>\n
<\/p>\n
NCERT In-text Question Page No. 210<\/span><\/p>\nQuestion 1. \nEach of the following rectangles of length 6 cm and breadth 4 cm is composed of congruent polygons. Find the area of each polygon. \n \nAnswer: \n\u2234 Length of the rectangle (l) = 6 cm \nBreadth of the rectangle (b) = 4 cm \n\u2234 Area of the rectangle = (l x b) \n= 6 x 4 cm2<\/sup> = 24 cm2<\/sup> \n(i) Here, number of congruent polygons = 6 \n\u2234 Area of each polygon = \\(\\frac{24}{6}\\) cm2<\/sup> = 4 cm2<\/sup><\/p>\n(ii) Here, number of congruent polygons = 4 \nArea of each polygon = \\(\\frac{24}{4}\\)cm2<\/sup> = 6 cm2<\/sup><\/p>\n(iii) Here, number of congruent polygons = 2 \n\u2234 Area of each polygon = \\(\\frac{24}{2}\\)cm2<\/sup> = 12 cm2<\/sup><\/p>\n(iv) Number of congruent polygons = 2 \n\u2234 Area of each polygon = \\(\\frac{24}{2}\\)cm2<\/sup> = 12 cm2<\/sup><\/p>\n(v) Number of congruent polygons = 8 \n\u2234 Area of each polygon = \\(\\frac{24}{8}\\)cm2<\/sup> = 3 cm2<\/sup><\/p>\nNCERT In-text Question Page No. 212<\/span><\/p>\nQuestion 1. \nFind the area of the following parallelograms: \n \n(iii) In a parallelogram ABCD, AB = 7.2 cm and the perpendicular from C on AB is 4.5 cm. \nAnswer: \n(i) Base = 8 cm, Height = 3.5 cm \n\u2234 Area of the parallelogram = Base x \nHeight = 8 cm x 3.5 cm = 28 cm2<\/sup><\/p>\n(ii) Base = 8 cm, Height = 2.5 cm \nArea of the parallelogram = Base x Height = 8 cm x 2.5 cm = 20 cm2<\/sup><\/p>\n <\/p>\n
(iii) Base of parallelogram ABCD = (AB) = 7.2 cm \nHeight of parallelogram ABCD = 4.5 cm \nArea of parallelogram ABCD \n= Base x Height \n= 7.2 cm x 4.5 cm = \\(\\frac { 72 }{ 10 }\\)cm x \\(\\frac { 45 }{ 10 }\\)cm \n= \\(\\frac{3240}{100}\\) cm2<\/sup> = 32.40 cm2<\/sup><\/p>\nNCERT In-text Question Page No. 213<\/span><\/p>\nQuestion 1. \nTry the activity given on page 213, NCERT Textbook with different types of triangles. \nAnswer: \nDo it yourself.<\/p>\n
Question 2. \nTake different parallelograms. Divide each of the parallelograms into two triangles by cutting any of its diagonals. Are the triangles congruents. \nAnswer: \nDo it yourself.<\/p>\n
NCERT In-text Question Page No. 219<\/span><\/p>\nQuestion 1. \nIn the adjoining figure, \n(a) Which square has the larger perimeter? \n(b) Which is larger, perimeter of smaller square or the circumference of the circle? \nAnswer: \n(a) The outer square has the larger perimeter. \n(b) The circumference of the circle is larger than the perimeter of the smaller square. \n <\/p>\n
<\/p>\n
NCERT In-text Question Page No. 222<\/span><\/p>\nQuestion 1. \nDraw circles of different radii on a graph paper. Find the drea by counting the number of squares. Also find the area by using the formula. Compare the two answers. \nAnswer: \nDo it yourself.<\/p>\n
NCERT In-text Question Page No. 225<\/span><\/p>\nQuestion 1. \nConvert the following: \n(i) 50 cm2<\/sup> in mm2<\/sup> \n(ii) 2 ha in m2<\/sup> \n(iii) 10 m2 in cm2<\/sup> \n(iv) 1000 cm2<\/sup> in m2<\/sup> \nAnswer: \n(i) 50 cm2<\/sup> in mm2<\/sup> \n\u2235 1 cm2<\/sup> = 100 mm2<\/sup> \n\u2234 50 cm2<\/sup> = 50 x 100 mm2<\/sup> = 5000 mm2<\/sup><\/p>\n(ii) 2 ha in m2<\/sup> \n1 ha = 1000 m2<\/sup> \n\u2234 2 ha = 2 x 1000 m2 = 20000 m2<\/sup><\/p>\n(iii) 10 m2<\/sup> in cm2<\/sup> \n\u2235 1 cm2<\/sup> = 10000 cm2<\/sup> \n\u2234 10 m2<\/sup>= 10 x 10000 cm2<\/sup> = 100000 cm2<\/sup><\/p>\n <\/p>\n
(iv) 1000 cm2<\/sup> in m2<\/sup> \n\u2235 10000 cm2<\/sup> = 1 m2<\/sup> \n\u2234 1 cm2<\/sup> = \\(\\frac{1}{10000}\\) m2<\/sup> \nSo, 1000 cm2<\/sup> = \\(\\frac{1}{10000}\\) x 1000 m2<\/sup> \n= \\(\\frac{1}{10}\\) m2<\/sup> = 0.1m2<\/sup><\/p>\n","protected":false},"excerpt":{"rendered":"These NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area InText Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area InText Questions NCERT In-text Question Page No. 205 Question 1. What would you need to find, area or perimeter, to …<\/p>\n
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area InText Questions<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[9],"tags":[],"yoast_head":"\nNCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area InText Questions - MCQ Questions<\/title>\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n\t \n\t \n\t \n