{"id":27330,"date":"2021-06-30T14:36:00","date_gmt":"2021-06-30T09:06:00","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=27330"},"modified":"2022-03-02T10:31:28","modified_gmt":"2022-03-02T05:01:28","slug":"ncert-solutions-for-class-7-maths-chapter-10-ex-10-3","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-10-ex-10-3\/","title":{"rendered":"NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3"},"content":{"rendered":"

These NCERT Solutions for Class 7 Maths<\/a> Chapter 10 Practical Geometry Ex 10.3 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Exercise 10.3<\/h2>\n

Question 1.
\nConstruct a ADEF such that DE = 5 cm, DF = 3 cm and m\u2220EDF = 90 .
\nAnswer:
\nSteps of Construction
\n\"NCERT
\n(i) First we draw a rough sketch with measures marked on it.
\n(ii) Draw a line segment DE = 5 cm.
\n(iii) At D, construct \u2220EDX = 90
\n(iv) From the ray DX, cut off DF = 3 cm.
\n(v) Join EF.
\nThen, \u2206DEF is the required triangle.<\/p>\n

\"NCERT<\/p>\n

Question 2.
\nConstruct an isosceles triangle in which the lengths of each of its equal sides is 6.5 cm and the angle between them is 110.
\nAnswer:
\nSteps of Construction
\n\"NCERT
\n(i) First we draw a rough sketch with measures marked on it.
\n(ii) Draw a line segment AB = 6.5 cm.
\n(iii) At B, using protractor construct \u2220ABX = 110\u00b0.
\n(iv) From BX, cut off BC = 6.5 cm.
\n(v) Join AC.
\nThus, \u2206ABC is the required isosceles triangle.<\/p>\n

\"NCERT<\/p>\n

Question 3.
\nConstruct \u2206ABC with BC = 7.5 cm AC = 5 cm and m\u2220C – 60
\nAnswer:
\nSteps of Construction
\n(i) First we draw a rough sketch with measures marked on it.
\n(ii) Draw a line segment BC = 7.5 cm.
\n(iii) At \u2018C\u2019 using protractor construct \u2220BCX = 60\u00b0.
\n\"NCERT
\n(iv) From the ray CX, cut off CA = 5 cm.
\n(v) Join AB.
\nThus, \u2206ABC is the required triangle.<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Exercise 10.3 Question 1. Construct a ADEF such that DE = 5 cm, DF = 3 cm and m\u2220EDF = 90 …<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[9],"tags":[],"yoast_head":"\nNCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 - MCQ Questions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-10-ex-10-3\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 - MCQ Questions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 Questions and Answers are prepared by our highly skilled subject experts. 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