NCERT Solutions for Class 7 Maths<\/a> Chapter 10 Practical Geometry Ex 10.4 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\nNCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Exercise 10.4<\/h2>\n Question 1. \nConstruct \u2206ABC given m\u2220A = 60\u00b0 , m \u2220B = 30 and AB = 5.8 cm. \nAnswer: \nSteps of Construction \n(i) Draw a rough diagram with measures marked on it. \n(ii) Draw a line segment AB = 5.8 cm. \n(iii) Construct \u2220BAX = 60\u00b0 at A. \n(iv) At B, construct \u2220ABY = 30\u00b0 . \n \n(v) Let the rays AX and BY intersect at C. Thus, \u2206ABC is the required triangle.<\/p>\n
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Question 2. \nConstruct \u2206PQR if PQ = 5 cm, m\u2220PQR = 105\u00b0 and m \u2220QRP = 40\u00b0. \n(Hint : Recall angle-sum property of a triangle) \nAnswer: \nHere the line segment PQ is given. We can construct the triangle, if the measure of \u2220QPR is known. \n\u2220QPR = 180\u00b0 – [\u2220PQR + \u2220QRP] \n= 180\u00b0-(105\u00b0+ 40\u00b0) \n= 180\u00b0 – 145\u00b0 \n\u2220QPR = 35\u00b0 \nSteps of Construction \n \n \n(i) Draw a rough diagram with measures marked on it. \n(ii) Draw a line, segment PQ = 5 cm. \n(iii) At P, construct \u2220QPX = 35 . \n(iv) At Q, construct \u2220PQY = 105 . \n(v) Let the rays \\(\\overline{\\mathrm{PX}}\\) and \\(\\overline{\\mathrm{QY}}\\) intersect at R. \nThus, \u2206PQR is the required triangle.<\/p>\n
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Question 3. \nExamine whether you can construct \u2206DEF such that EF = 7.2 cm, m\u2220E = 110 and m\u2220F = 80\u00b0. Justify your answer. \nAnswer: \nHere m\u2220E =110 and m\u2220F = 80\u00b0 \ni. e. m\u2220E + m\u2220F= 110\u00b0+ 80\u00b0= 190\u00b0>180\u00b0 \nSince, sum of the three angles of a triangle is 180\u00b0. \n\u2206DEF is not possible, having sum of two angles > 180\u00b0 \nThus, \u2206DEF cannot be constructed.<\/p>\n","protected":false},"excerpt":{"rendered":"
These NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.4 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Exercise 10.4 Question 1. Construct \u2206ABC given m\u2220A = 60\u00b0 , m \u2220B = 30 and AB = 5.8 cm. Answer: …<\/p>\n
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.4<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[9],"tags":[],"yoast_head":"\nNCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.4 - MCQ Questions<\/title>\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n\t \n\t \n\t \n