NCERT Solutions for Class 7 Maths<\/a> Chapter 8 Comparing Quantities Ex 8.2 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\nNCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Exercise 8.2<\/h2>\n Question 1. \nConvert the given fractional numbers to per cents \n(i) \\(\\frac{1}{9}\\) \n(b) \\(\\frac{5}{4}\\) \n(c) \\(\\frac{3}{40}\\) \n(d) \\(\\frac{2}{7}\\) \nAnswer: \n <\/p>\n
Question 2. \nConvert the given decimal fractions to per cents. \n(a) 0.65 \n(b) 2.1 \n(c) 0.02 \n(d) 12.35 \nAnswer: \n(a) 0.65 : \\(\\frac{64}{100}=\\frac{65}{100}\\) \u00d7 100% = 65% \n(b) 2.1 = \\(\\frac{21}{10}=\\frac{21}{10}\\) \u00d7 100% = 210% \n(c) 0.02 = \\(\\frac{2}{100}=\\frac{2}{100}\\) \u00d7 100% =2 % \n(d) 12.35 = \\(\\frac{1235}{100}=\\frac{1235}{100}\\) \u00d7 100% = 1235<\/p>\n
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Question 3. \nEstimate what part of the figures is shaded and hence find the per cent which is shaded. \n \nAnswer: \n(i) \\(\\frac{1}{4}\\) part is shaded. \n\\(\\frac{1}{4}=\\frac{1}{4}\\) \u00d7 100% = % = 25 % \nThis coloured part is 25%.<\/p>\n
(ii) 3 parts out of 5 parts are shaded so, \n\\(\\frac{3}{5}\\) part is shaded \n\\(\\frac{3}{5}=\\frac{3}{5}\\) \u00d7 100% = 3 \u00d7 20% = 60% \nThis coloured part is 60%.<\/p>\n
(iii) Here 3 parts out of 8 parts are shaded 3 \nso, \\(\\frac{3}{8}\\) part is shaded. \n\\(\\frac{3}{8}=\\frac{3}{8}\\) \u00d7 100% = \\(\\frac{3}{2}\\) x 25% \n= 37\\(\\frac { 1 }{ 2 }\\)% or 37.5% \nThis 37\\(\\frac { 1 }{ 2 }\\) part is shaded.<\/p>\n
Question 4. \nFind: \n(a) 15% of 250 \n(b) 1% of 1 hour \n(c) 20% of \u20b9 2500 \n(d) 75% of 1 kg \nAnswer: \n(a) 15% of 250 = \\(\\frac{15}{100}\\) of 250 \n= \\(\\frac{15}{100} \\times 250=\\frac{15 \\times 250}{100}=\\frac{75}{2}\\) \n= 37\\(\\frac{1}{2}\\) or 37.5 \n\u2234 15% of 250 = 37 \\(\\frac{1}{2}\\) or 37.5 2<\/p>\n
(b) 1% of 1 hour = \\(\\frac{1}{100}\\) \u00d7 60 minutes \n= \\(\\frac{1 \\times 60}{100}=\\frac{3}{5}\\) minutes \n= \\(\\frac { 3 }{ 5 }\\) \u00d7 60 seconds = 36 seconds \n\u2234 1% of 1 hour = 36 seconds<\/p>\n
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(c) 20% of \u20b9 2500 = \\(\\frac { 20 }{ 100 }\\) of \n2500 = \\(\\frac { 20 }{ 100 }\\) x 2500 \n= \u20b9 \\(\\frac{20 \\times 2500}{100}\\) = \u20b9 500 \n\u2234 20% of \u20b9 2500 = \u20b9 500<\/p>\n
(d) 75% of 1 kg = 75% of 1000 g \n= \\(\\frac{75}{100} \\times 100 \\mathrm{~g}=\\frac{75 \\times 1000}{100}\\) = 750 g \n\u2234 75% of 1 kg = 750g<\/p>\n
Question 5. \nFind the whole quantity if \n(a) 5% of it is 600. \n(b) 12% of it is \u20b9 1080. \n(c) 40% of it is 500 km. \n(d) 70% of it is 14 minutes. \n(e) 8% of it is 40 litres. \nAnswer: \n(a) 5% of a quantity is 600. \nLet the quantity be x \n5% of x = 600 \n\\(\\frac { 5 }{ 100 }\\) \u00d7 x = 600 \nx = \\(\\frac{600 \\times 100}{5}\\) \n= 120 \u00d7 100 \n= 12000 \nThus the required quantity is 12000.<\/p>\n
(b) 12% of it is \u20b9 1080 \nLet the required amount be x \n12% of x = 1080 \n\\(\\frac { 12 }{ 100 }\\) \u00d7 x = 1080 \nx = \\(\\frac{1080 \\times 100}{12}\\) \n= \\(\\frac{1080 \\times 25}{3}\\) \nThe required amount = \u20b9 9000 \n= 360 \u00d7 25 = \u20b9 9000<\/p>\n
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(c) 40% of it is 500 km \nLet the total quantity be x \n40% of x = 500 \n\\(\\frac { 4 }{ 100 }\\) \u00d7 x = 500 \nx = \\(\\frac{500 \\times 100}{40}\\) km \n= 50 \u00d7 25 km \n= 1250 km \nThe required quantity is 1250 km.<\/p>\n
(d) 70% of it is 14 minutes \nLet the required time be x \n70% of x = 14 minutes \n\\(\\frac{70}{100}\\) \u00d7 x = 14 \nx = \\(\\frac{14 \\times 100}{70}\\) \n= 20 minutes \nThus, the required quantity is 20 minutes.<\/p>\n
(e) 8% of a quantity is 40 litres \nLet the quantity be x \n8% of x =40 litres \n\\(\\frac { 8 }{ 100 }\\) \u00d7 x = 40 \nx = \\(\\frac{40 \\times 100}{8}\\) = 500litres \nThe required quantity is 500 litres.<\/p>\n
Question 6. \nConvert given per cents to decimal fractions and also to fractions in simplest forms: \n(a) 25% \n(b) 150% \n(c) 20% \n(d) 5% \nAnswer: \n(a) 25% = \\(\\frac{25}{100}=\\frac{1}{4}\\) \nThus, 20% = \\(\\frac{1}{4}\\) = 0.25<\/p>\n
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(b) 150% = \\(\\frac{150}{100}=\\frac{3}{2}\\) \nThus 150% = \\(\\frac{3}{2}\\) (or) 1\\(\\frac{1}{2}\\) = 1.5<\/p>\n
(c) 20% = \\(\\frac{20}{100}=\\frac{1}{5}\\) = 0.2 \nThus 20% = \\(\\frac{1}{5}\\) = 0.2<\/p>\n
(d) 5% = \\(\\frac{5}{100}=\\frac{1}{20}\\) \nThus 5% = \\(\\frac{1}{20}\\) = 0.05<\/p>\n
Question 7. \nIn a city, 30% are females, 40% are males and remaining are children. What per cent are children? \nAnswer: \nFemales are 30% and males are 40% \nNumber of children = 100% – (30% + 40%) \n= 100% – 70% = 30% \nThus, children are 30% of the population.<\/p>\n
Question 8. \nOut of 15,000 voters in a constituency, 60% voted. Find the percentage of voters who did not vote. Can you now find how many actually did not vote? \nAnswer: \nTotal number of voters = 15,000 \nPart of voters who voted = 60% \nPart of voters who did not vote = 100% – 60% = 40% \n40% of 15000 = \\(\\frac{40}{100}\\) \u00d7 15000 \n= 40 \u00d7 150 = 6000 \nThus, 6000 voters did not vote.<\/p>\n
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Question 9. \nMeeta saves \u20b9 4000 from her salary. If this is 10% of her salary. What is her salary? \nAnswer: \nMeeta saving = \u20b9 4000 \nLet the salary be \u20b9 x \nSaving = 10% of x \n10% of x =4000 \n\\(\\frac{10}{100}\\) \u00d7 x = 4000 \nx = \\(\\frac{4000 \\times 100}{10}\\) \n= \u20b9 40,000 \nMeeta salary = \u20b9 40,000\/-<\/p>\n
Question 10. \nA local cricket team played 20 matches in one season. It won 25% of them. How many matches did they win? \nAnswer: \nTotal number of matches played = 20 \nPart of matches won = 25% \n25% of 20 = \\(\\frac{25}{100}\\) \u00d7 20 = \\(\\frac{25 \\times 20}{100}\\) = 5 \nThe team won 5 matches.<\/p>\n","protected":false},"excerpt":{"rendered":"
These NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Exercise 8.2 Question 1. Convert the given fractional numbers to per cents (i) (b) (c) (d) Answer: Question 2. Convert the …<\/p>\n
NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[9],"tags":[],"yoast_head":"\nNCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.2 - MCQ Questions<\/title>\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n\t \n\t \n\t \n