NCERT Solutions for Class 8 Maths<\/a> Chapter 9 Algebraic Expressions and Identities Ex 9.2 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\nNCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Exercise 9.2<\/h2>\n Question 1. \nFind the product of the following pairs of monomials \n(i) 4, 7p \n(ii) -4p, 7p \n(iii) -4p, 7pq \n(iv) 4p3<\/sup>, – 3p \n(v) 4p, 0 \nSolution: \n(i) 4 \u00d7 7p \n= (4 \u00d7 7)p \n= 28p<\/p>\n(ii) -4p \u00d7 7p \n= {(-4) \u00d7 7} \u00d7 (p \u00d7 p) \n= (-28) \u00d7 p2<\/sup> \n= -28p2<\/sup><\/p>\n(iii) -4p \u00d7 7pq \n= {(-4) \u00d7 7} \u00d7 {p \u00d7 (pq)} \n= -28 \u00d7 (p \u00d7 p \u00d7 q) \n= -28p2<\/sup>q<\/p>\n <\/p>\n
(iv) 4p3<\/sup> \u00d7 -3p \n= {4 \u00d7 (-3)} \u00d7 (p3<\/sup> \u00d7 p) \n= -12 \u00d7 (p4<\/sup>) \n= -12p4<\/sup><\/p>\n(v) 4p \u00d7 0 \n= (4 \u00d7 0) \u00d7 p \n= 0 \u00d7 p \n= 0<\/p>\n
Question 2. \nFind the areas of rectangles, with the following pairs of monomials as their lengths and breadths respectively. \n(p, q); (10m, 5n); (20x2<\/sup>, 5y2<\/sup>); (4x, 3x2<\/sup>); (3mn, 4np) \nSolution: \n(i) (p, q) \nArea of the rectangle = length \u00d7 breadth \n= p x q \n= pq<\/p>\n(ii) (10m, 5n) \nArea of the rectangle = length \u00d7 breadth \n= 10m \u00d7 5n \n= (10 \u00d7 5) \u00d7 (m \u00d7 n) \n= 50 \u00d7 mn \n= 50mn<\/p>\n
(iii) 20x2<\/sup>, 5y2<\/sup> \nArea of the rectangle = length \u00d7 breadth \n= 20x2<\/sup> \u00d7 5y2<\/sup> \n= (20 \u00d7 5) \u00d7 (x2<\/sup> \u00d7 y2<\/sup>) \n= 100 \u00d7 x2<\/sup>y2<\/sup> \n= 100x2<\/sup>y2<\/sup><\/p>\n <\/p>\n
(iv) (4x, 3x2<\/sup>) \nArea of the rectangle = length \u00d7 breadth \n= 4x \u00d7 3x2<\/sup> \n= (4 \u00d7 3) \u00d7 (x \u00d7 x2<\/sup>) \n= 12 \u00d7 x3<\/sup> \n= 12x3<\/sup><\/p>\n(v) (3mn, 4np) \nArea of the rectangle = length \u00d7 breadth \n= 3mn \u00d7 4np \n= (3 \u00d7 4) \u00d7 (mn \u00d7 np) \n= 12 \u00d7 m \u00d7 (n \u00d7 n) \u00d7 p \n= 12 \u00d7 m \u00d7 n2<\/sup> \u00d7 p \n= 12mn2<\/sup>p<\/p>\nQuestion 3. \nComplete the table products. \n \nSolution: \n <\/p>\n
Question 4. \nObtain the volume of rectangular boxes with the following length, breadth and height respectively. \n(i) 5a, 3a2<\/sup>, 7a4 \n(ii) 2p, 4q, 8r \n(iii) xy, 2x2<\/sup>y, 2xy2<\/sup> \n(iv) a, 2b, 3c \nSolution: \n(i) 5a, 3a2<\/sup>, 7a4<\/sup> \nVolume of the rectangular box = length \u00d7 breadth \u00d7 height \n= (5a) \u00d7 (3a2<\/sup>) \u00d7 (7a4<\/sup>) \n= (5 \u00d7 3 \u00d7 7) \u00d7 (a \u00d7 a2<\/sup> \u00d7 a4<\/sup>) \n= 105a7<\/sup><\/p>\n <\/p>\n
(ii) 2p, 4q, 8r \nVolume of the rectangular box = Length \u00d7 Breadth \u00d7 Height \n= 2p \u00d7 4q \u00d7 8r \n= (2 \u00d7 4 \u00d7 8) \u00d7 (p \u00d7 q \u00d7 r) \n= 64pqr<\/p>\n
(iii) xy; 2x2<\/sup>y; 2xy2<\/sup> \nVolume of the rectangular box = length \u00d7 breadth \u00d7 height \n= xy \u00d7 2x2<\/sup>y \u00d7 2xy2<\/sup> \n= (1 \u00d7 2 \u00d7 2) \u00d7 (x \u00d7 x2<\/sup> \u00d7 x) \u00d7 (y \u00d7 y \u00d7 y2<\/sup>) \n= 4 \u00d7 x4<\/sup> \u00d7 y4<\/sup> \n= 4x4<\/sup>y4<\/sup><\/p>\n(iv) a, 2b, 3c \nVolume of the rectangular box = length \u00d7 breadth \u00d7 height \n= a \u00d7 2b \u00d7 3c \n= (1 \u00d7 2 \u00d7 3) \u00d7 (a \u00d7 b \u00d7 c) \n= 6abc<\/p>\n
Question 5. \nObtain the product of \n(i) xy, yz, zx \n(ii) a, -a2<\/sup>, a3<\/sup> \n(iii) 2, 4y, 8y2<\/sup>, 16y3<\/sup> \n(iv) a, 2b, 3c, 6abc \n(v) m, -mn, mnp \nSolution: \n(i) xy, yz, zx \n(xy) \u00d7 (yz) \u00d7 (zx) \n= (x \u00d7 x) \u00d7 (y \u00d7 y) \u00d7 (z \u00d7 z) \n= x2<\/sup> \u00d7 y2<\/sup> \u00d7 z2<\/sup> \n= x2<\/sup>y2<\/sup>z2<\/sup><\/p>\n(ii) a; -a2<\/sup>; a3<\/sup> \n(a) \u00d7 (-a2<\/sup>) \u00d7 (a3<\/sup>) \n= -(a \u00d7 a2<\/sup> \u00d7 a3<\/sup>) \n= -a6<\/sup><\/p>\n(iii) 2, 4y, 8y2<\/sup>, 16y3<\/sup> \n(2) \u00d7 (4y) \u00d7 (8y2<\/sup>) \u00d7 (16y3<\/sup>) \n= (2 \u00d7 4 \u00d7 8 \u00d7 16) \u00d7 (y \u00d7 y2<\/sup> \u00d7 y3<\/sup>) \n= 1024y6<\/sup><\/p>\n <\/p>\n
(iv) a, 2b, 3c, 6abc \n(a) \u00d7 (2b) \u00d7 (3c) \u00d7 (6abc) \n= (2 \u00d7 3 \u00d7 6) \u00d7 (a \u00d7 a) \u00d7 (b \u00d7 b) \u00d7 (c \u00d7 c) \n= 36 \u00d7 a2<\/sup> \u00d7 b2<\/sup> \u00d7 c2<\/sup> \n= 36a2<\/sup>b2<\/sup>c2<\/sup><\/p>\n(v) m, -mn, mnp \n(m) \u00d7 (-mn) \u00d7 (mnp) \n= -1 \u00d7 (m \u00d7 m \u00d7 m) \u00d7 (n \u00d7 n) \u00d7 p \n= -1 \u00d7 m3<\/sup> \u00d7 n2<\/sup> \u00d7 p \n= -m3<\/sup>n2<\/sup>p<\/p>\n","protected":false},"excerpt":{"rendered":"These NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.2 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Exercise 9.2 Question 1. Find the product of the following pairs of monomials (i) 4, 7p (ii) …<\/p>\n
NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.2<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[7],"tags":[],"yoast_head":"\nNCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.2 - MCQ Questions<\/title>\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n\t \n\t \n\t \n