{"id":27871,"date":"2021-07-02T12:24:15","date_gmt":"2021-07-02T06:54:15","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=27871"},"modified":"2022-03-02T10:30:58","modified_gmt":"2022-03-02T05:00:58","slug":"ncert-solutions-for-class-7-maths-chapter-8-intext-questions","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-8-intext-questions\/","title":{"rendered":"NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities InText Questions"},"content":{"rendered":"

These NCERT Solutions for Class 7 Maths<\/a> Chapter 8 Comparing Quantities InText Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities InText Questions<\/h2>\n

NCERT In-text Question Page No. 158<\/span><\/p>\n

Question 1.
\nFind the percentage of children of different heights for the following data.
\nAnswer:
\n\"NCERT<\/p>\n

Question 2.
\nA shop has the following number of shoe pairs of different sizes.
\nSize 2 : 20
\nSize 3 : 30
\nSize 4 : 28
\nSize 5 : 14
\nSize 6 : 8
\nWrite this information in tabular form as done earlier and find the percentage of each shoe size available in the shop.
\nAnswer:
\n\"NCERT<\/p>\n

NCERT In-text Question Page No. 159 & 160<\/span><\/p>\n

Question 1.
\nA collection of 10 chips with different colours is given.
\nAnswer:
\n\"NCERT<\/p>\n

Question 2.
\nMala has a collection of bangles. She has 20 gold bangles and 10 silver bangles. What is the percentage of bangles of each type? Can you put it in the tabular form as done in the above example?
\nAnswer:
\nWe have
\n\"NCERT
\nNote: We can use percentages for comparing various quantities.<\/p>\n

NCERT In-text Question Page No. 160<\/span><\/p>\n

Question 1.
\nLook at the examples below and in each of them, discuss which is better for comparison.
\nIn the atmosphere, 1 g of air contains:
\n(i) .78g Nitrogen – 78 % Nitrogen
\n.21 g Oxygen or 21 % Oxygen
\n.01g Nitrogen – 1 % Other Gas
\n(ii) A shirt has:
\n\\(\\frac{2}{5}\\) Cotton 60% Cotton
\nor
\n\\(\\frac{2}{5}\\) Polyester 40% Polyester
\nAnswer:
\nThe second one (i.e. percentage) is better for comparison in both the cases.<\/p>\n

NCERT In-text Question Page No. 161<\/span><\/p>\n

Question 1.
\nConvert the following to per cents:
\n(a) \\(\\frac{12}{16}\\)
\n(b) 3.5
\n(c) \\(\\frac{49}{50}\\)
\n(d) \\(\\frac{2}{2}\\)
\n(e) 0.05
\nAnswer:
\n(a) \\(\\frac{12}{16}\\) = (\\(\\frac{12}{16}\\) x 100) % = ( \\(\\frac{3}{4}\\) x 100) %
\n= (3 x 25)% = 75%<\/p>\n

(b) 3.5 = (3.5 x 100)% = 350%<\/p>\n

(c) \\(\\frac{49}{50}\\) ( \\(\\frac{49}{50}\\) x 100)%
\n= (\\(\\frac{49}{50}\\) x 100)%
\n= (49 x 2)% = 98%<\/p>\n

(d) \\(\\frac{2}{2}\\) = ( \\(\\frac{2}{2}\\) x 100)%
\n= (1 x 100)%
\n= 100%
\n(e) 0.05 = (0.05 x 100) % = 5 %<\/p>\n

Question 2.
\n(i) Out of 32 students, 8 are absent.
\nWhat per cent of the students are absent?
\n(ii) There are 25 radios, 16 of them are out of order. What per cent of radios are out of order?
\n(iii) A shop has 500 parts, out of which 5 are defective. What per cent are defective?
\n(iv) There are 120 voters, 90 of them voted yes. What per cent voted yes?
\nAnswer:
\n\"NCERT
\n= (3 x 25)% = 75%
\n75% voters voted ‘yes’<\/p>\n

NCERT In-text Question Page No. 162<\/span><\/p>\n

Question 1.
\nFill in the blanks
\n(i) 35% + ……………. % = 100%.
\n(ii) 64% + 20% + ……………. % = 100%
\n(iii) 45% = 100% – ……………. %.
\n(iv) 70% = ……………. % – 30%
\nAnswer:
\n(i) 100% – 35% = 65%
\n35% + 65% = 100%
\n(ii) 64%+ 20% =84%
\n100% – 84% = 16%
\n64% + 20% + 16% = 100%
\n(iii) 100%-45% =55%
\n45% = 100% – 55%
\n(iv) 70% + 30% = 100%
\n70% = 100% – 30%<\/p>\n

Question 16.
\nIf 65% of students in a class have a bicycle, what per cent of the student do not have bicycles?
\n\"NCERT
\nAnswer:
\nPart of students having bicycles = 65%
\nRemaining part of students
\n= 100% – 65% = 35%
\nThus, 35% of students do not have bicycles.<\/p>\n

Question 17.
\nWe have a basket full of apples, oranges and mangoes. If 50% are apples, 30% are oranges, then what per cent are mangoes?
\nAnswer:
\nQuantity of apples = 50%
\nQuantity of oranges = 30%
\nQuantity of mangoes in the basket
\n= 100% – (50% + 30%)
\n= 100% -80% = 20%
\nThus, the percent of mangoes in the basket = 20%<\/p>\n

NCERT In-text Question Page No. 163<\/span><\/p>\n

Question 1.
\nWhat per cent of these figures are shaded?
\n\"NCERT
\nAnswer:
\n(i) Fraction which is shaded
\n\\(=\\left(\\frac{1}{4}+\\frac{1}{4}+\\frac{1}{4}\\right)=\\left(\\frac{1+1+1}{4}\\right)=\\frac{3}{4}\\)
\nPercentage of shaded part
\n= \\(\\frac { 3 }{ 4 }\\) x 100% = 75%
\n(ii) Fraction of diagram which is shaded
\n\\(=\\frac{1}{4}+\\frac{1}{8}+\\frac{1}{8}=\\frac{2+1+1}{8}=\\frac{4}{8}=\\frac{1}{2}\\)
\nPercentage of diagram which is shaded = \\(\\frac { 1 }{ 2 }\\) x 100% = 50%<\/p>\n

NCERT In-text Question Page No. 164<\/span><\/p>\n

Question 1.
\nFind
\n(a) 50% of 164
\n(b) 75% of 12]
\n(c) 12 \\(\\frac { 1 }{ 2 }\\) % of 64
\nAnswer:
\n(a) 50% of 164 = \\(\\frac { 50 }{ 100 }\\) x 164
\n= \\(\\frac { 1 }{ 2 }\\) x 164 = 82<\/p>\n

(b) 75% of 12 = \\(\\frac { 75 }{ 100 }\\) x 12 = \\(\\frac { 3 }{ 4 }\\) x 12
\n= 3 x 3 = 9<\/p>\n

(c) 12\\(\\frac { 1 }{ 2 }\\) % of 64 = \\(\\frac { 25 }{ 2 }\\)% or 64
\n= \\(\\frac{2}{100} \\times 64=\\frac{25}{100} \\times \\frac{64}{2}\\)
\n= \\(\\frac { 1 }{ 8 }\\) x 64 = 8<\/p>\n

Question 2.
\n8% children of a class of 25 like getting wet in the rain. How many children like getting wet in the rain?
\nAnswer:
\nNumber of children who like getting wet in rain
\n= 8% of 25 = \\(\\frac { 8 }{ 100 }\\) x 25 = 2<\/p>\n

Question 3.
\n9 is 25% of what number?
\nAnswer:
\nLet the required be P
\n25% of P = 9
\n\\(\\frac { 25 }{ 100 }\\) x P = 9
\n25 P = 9 x 100
\nP = \\(\\frac { 9 x 100 }{ 25 }\\) = 9 x 4 = 36
\nThe required number is 36.<\/p>\n

Question 4.
\n75% of what number is 15?
\nAnswer:
\nLet the required number be p
\n75% of P = 15
\n= \\(\\frac { 75 }{ 100 }\\) x P = 15
\n\\(\\frac { 3 }{ 4 }\\) x P = 15
\n\\(\\frac { 3P }{ 4 }\\) = 15
\n3P = 15 x 4
\nP = \\(\\frac{15 \\times 4}{3}\\) = 5 x 4 = 20
\nThe required number is 20<\/p>\n

NCERT In-text Question Page No. 166<\/span><\/p>\n

Question 1.
\nDivide 15 sweets between Manu and Sonu so that they get 20% and 80% of them respectively.
\nAnswer:
\nShare of Manu = 20% of 15 sweets
\n= \\(\\frac { 20 }{ 100 }\\) x 15 sweets
\n= 3 sweets
\nShare of Sonu = 80% of 15 sweets
\n= \\(\\frac { 80 }{ 100 }\\) x 15
\n= \\(\\frac { 4 }{ 5 }\\) x 15
\n= 4 x 3 = 12 sweets
\nManu share = 3 sweets and Sonu share =12 sweets.<\/p>\n

Question 1.
\nIf the angles of a triangle are in the ratio 2:3:4, find the value of each angle.
\nAnswer:
\nWe know that sum of three angles of a triangle =180\u00b0
\nLet the three angles be 2x, 3x, and 4x
\n2x +3x + 4x = 180\u00b0
\n9x = 180\u00b0
\nx = \\(\\frac { 180\u00b0 }{ 9 }\\) = 20\u00b0
\nThe three angles are 2(20\u00b0 ); 3(20\u00b0 ) and 4(20\u00b0)
\ni.e. 40\u00b0, 60\u00b0 and 80\u00b0<\/p>\n

NCERT In-text Question Page No. 167<\/span><\/p>\n

Question 1.
\nFind percentage of increase or decrease
\n(a) Price of shirt decreased from \u20b9 80 to \u20b9 60
\n(b) Marks in a test increased from 20 to 30
\nAnswer:
\n(a) Initial price of the shirt = \u20b9 80
\nDecrease price of the shirt = \u20b9 60
\nDecrease in the price
\n= \u20b980 – \u20b960 = \u20b920
\nPer cent of decrease in price 20
\n= \\(\\frac { 20 }{ 80 }\\) x 100%
\n= \u20b9 25%<\/p>\n

(b) Initial marks = 20
\nIncreased marks = 30
\nIncrease in marks = 30 – 20 = 10
\nPercent of increase in marks
\n= \\(\\frac { 10 }{ 20 }\\) x 100% = 50%<\/p>\n

Question 2.
\nMy mother says in her childhood petrol was \u20b9 1 a litre. It is \u20b9 52 per litre today. By what per centage has the price gone up?
\nAnswer:
\nInitial Price = \u20b9 1
\nIncrease price = \u20b9 52
\nIncrease in price = \u20b952 – \u20b91 = \u20b951
\nPercentage of increase in petrol
\n= \\(\\frac { 51 }{ 1 }\\) x 100%
\n= 5100%<\/p>\n

NCERT In-text Question Page No. 169<\/span><\/p>\n

Question 1.
\nA shopkeeper bought a chair for \u20b9 375 and sold it for \u20b9 400. Find the gain percentage.
\nAnswer:
\nC.P of a chair = \u20b9 375
\nS.P of a chair = \u20b9 400
\nProfit = S.P – C.P
\n= \u20b9 400 – \u20b9 375 = \u20b9 25
\nProfit percentage = \\(\\frac { Profit }{ C.P }\\) x 100%
\n= \\(\\frac { 25 }{ 375 }\\) x 100%
\n= \\(\\frac { 1 }{ 15 }\\) x 100% = \\(\\frac { 20 }{ 3 }\\)%
\n= 6\\(\\frac { 2 }{ 3 }\\)%<\/p>\n

Question 2.
\nCost of an item is\u20b950 It was sold with a profit of 12%. Find the selling price.
\nAnswer:
\nWe have
\nCP of the item = \u20b950
\nProfit % = 12%
\nProfit = 12% of \u20b950
\n= \u20b9\\(\\frac { 12 }{ 100 }\\) x 50 = \u20b96
\nSP = CP + Profit
\n= \u20b950 + \u20b96 = \u20b956<\/p>\n

Question 3.
\nAn article was sold for \u20b9250 with a profit of 5%. What was its cost price?
\nAnswer:
\nLet the cost price be \u20b9 x.
\nProfit % = 5%
\n\u2234 Profit = 5% of x = \u20b9 \\(\\frac { 5 }{ 100 }\\) x x =\u20b9 \\(\\frac { x }{ 20 }\\)
\n\u2234 SP = CP + Profit
\n\u2234 \u20b9 250 = \u20b9 x + \\(\\frac { x }{ 20 }\\) [\u2235 \u20b9 = \u20b9 250]
\nor \u20b9 250 = \u20b9 \\(\\frac { 21 }{ 20 }\\)x
\nor x = \\(\\frac{250 \\times 20}{21}=\\frac{5000}{21}=238 \\frac{2}{21}\\)
\nThus cost price of the article = \u20b9 238 \\(\\frac { 2 }{ 21 }\\)<\/p>\n

Question 4.
\nAn item was sold for \u20b9 540 at a loss of 5% what was its cost price?
\nAnswer:
\nLet the cost rice be \u20b9 x
\nLoss% = 5%
\nLoss = 5% of \u20b9 x
\n= \\(\\frac { 5 }{ 100 }\\) x x = \\(\\frac { x }{ 20 }\\)
\nSelling price = Cost price – Loss
\n540 = x – \\(\\frac { x }{ 20 }\\)
\n540 = \\(\\frac{20 x-x}{20}=\\frac{19 x}{20}\\)
\n19x = 540 x 20
\nx = \\(\\frac{540 \\times 20}{19}\\)
\n= \\(\\frac{10800}{19}=568 \\frac{8}{19}\\)
\nor \u20b9 568.40 (approx.)
\nCost price of the article
\n= \u20b9 568\\(\\frac{8}{19}\\) or \u20b9 568.42<\/p>\n

NCERT In-text Question Page No. 170<\/span><\/p>\n

Question 1.
\n\u20b9 10,000 is invested at 5% interest rate p.a. Find the interest at the end of one year.
\nAnswer:
\nPrincipal (P) = \u20b9 10,000
\nRate (R) = 5% p.a.
\nTime (T) = 1 year
\n\"NCERT<\/p>\n

Question 2.
\n\u20b9 3,500 is given at 7% p.a. rate of interest. Find the interest which will be received at the end of two years.
\nAnswer:
\nPrincipal (P) = \u20b9 3,500; Rate (R) = 7% p.a. Time (T) = 2 years
\n\u2234 Simple interest = \\(\\frac{\\mathrm{P} \\times \\mathrm{R} \\times \\mathrm{T}}{100}\\)
\n= \u20b9 \\(\\frac{3,500 \\times 7 \\times 2}{100}\\)
\n= \u20b9 35 x 7 x 2 = \u20b9 490.<\/p>\n

Question 3.
\n\u20b9 6,050 is borrowed at 6.5% rate of interest p.a. Find the interest and the amount to be paid at the end of 3 years.
\nAnswer:
\nPrincipal (P) = \u20b9 60,50
\nRate (R) = 6.5% p.a.
\nTime (T) = 3% years
\n\u2234 Simple interest
\n\"NCERT
\nSince, Amount = Principal + Interest
\n= \u20b9 6,050 + \u20b9 1,17.75 = \u20b9 7,229.75
\nThus, the amount to be paid at the end of 3 years = 7,229.75.<\/p>\n

Question 4.
\n\u20b9 7000 is borrowed at 3.5% rate of interest p.a. borrowed for 2 years. Find the amount to be paid at the end of the second year.
\nAnswer:
\nPrincipal (P) = \u20b9 7,000
\nRate = 3.5% p.a.
\nTime (T) = 2 years
\n\u2234 Simple interest = \\(\\frac{\\mathrm{P} \\times \\mathrm{R} \\times \\mathrm{T}}{100}\\)
\n= \u20b9 \\(\\begin{aligned}
\n&7,000 \\times 3.5 \\times 2\\\\
\n&0
\n\\end{aligned}\\) = \u20b9 70 x \\(\\frac{35}{10}\\) x 2
\n= \u20b9 7 x 35 x 2 = \u20b9 490
\nSince, Amount = Principal + Interest
\nAmount to be paid at th end of 2nd year = \u20b9 7,000 + \u20b9 490 = \u20b9 7,490.<\/p>\n

NCERT In-text Question Page No. 171<\/span><\/p>\n

Question 1.
\nYou have \u20b9 2,400 in you account and the interest rate is 5%. After how many years would you earn \u20b9 240 as interest.
\nAnswer:
\nHere, principal (P) = 2,400
\nRate (R) = 5% p.a.
\nTime (T) = ?
\nSimple interest = \u20b9 2,40
\n\u2235 Simple interest = \\(\\frac{\\mathrm{P} \\times \\mathrm{R} \\times \\mathrm{T}}{100}\\)
\n\u2234 240 = \\(\\frac{2400 \\times 5 \\times \\mathrm{T}}{100}\\)
\n\u2234 T = \\(\\frac{240 \\times 100}{2400 \\times 5}\\) = 2 years
\nThus, an interest of ? 240 will be obtained after 2 years.<\/p>\n

Question 2.
\nOn a certain sum, the interest paid after 3 years is \u20b9 450 at 5% rate of interest per annum. Find the sum.
\nAnswer:
\nLet the sum be \u2018P\u2019
\n450 = \\(\\frac{3 \\mathrm{P}}{20}\\)
\nInterest (I) = \u20b9 450
\n3P = 450 x 20
\nRate (R) = 5% p.a
\nP = \\(\\)
\nTime (T) = 3 years = 150 x 20
\nI = \\(\\frac{\\mathrm{P} \\times \\mathrm{R} \\times \\mathrm{T}}{100}\\)
\n= \u20b9 3000
\n450 = \\(\\frac{\\mathrm{P} \\times 5 \\times 3}{100}\\)
\nThe required sum is \u20b9 3000.<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities InText Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities InText Questions NCERT In-text Question Page No. 158 Question 1. Find the percentage of children of different heights for the following data. …<\/p>\n

NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities InText Questions<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[9],"tags":[],"yoast_head":"\nNCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities InText Questions - MCQ Questions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-7-maths-chapter-8-intext-questions\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities InText Questions - MCQ Questions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities InText Questions and Answers are prepared by our highly skilled subject experts. 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NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities InText Questions NCERT In-text Question Page No. 158 Question 1. 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