{"id":27965,"date":"2021-07-02T14:53:02","date_gmt":"2021-07-02T09:23:02","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=27965"},"modified":"2022-03-02T10:30:57","modified_gmt":"2022-03-02T05:00:57","slug":"ncert-solutions-for-class-8-maths-chapter-16-ex-16-1","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-8-maths-chapter-16-ex-16-1\/","title":{"rendered":"NCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers Ex 16.1"},"content":{"rendered":"

These NCERT Solutions for Class 8 Maths<\/a> Chapter 16 Playing with Numbers Ex 16.1 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n

NCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers Exercise 16.1<\/h2>\n

Question 1.
\nFind the values of the letters in each of the following and give reasons for the steps involved.
\n\"NCERT
\n\"NCERT
\nAnswer:
\n1. Let us see the sum in units column. It is A + 5 and we get 2 from this
\n(A+ 5 = 7 + 5= 12). So, A has to be 7
\nFor sum in ten\u2019s column, we have
\n1 + 3 + 2 = B
\n\u2234 B = 6
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 2.
\nHere, there are three letters A, B and C whose values are to be found out.
\nAnswer:
\nLet us see the sums in units column.
\nIt is A + 8 and we get 3 from that so A has to be 5 (A + 8 = 5 + 8 = 13)
\nNow, for the sum in tens column, we have
\nI + 4 + 9= 14
\n\u2234 B = 4, C = 1
\n\u2234 The given puzzle is solved,
\ni. e. A = 5, B = 4 and C = 1
\n\"NCERT<\/p>\n

Question 3.
\nUnits digit of A x A is A
\nAnswer:
\n\u2234 A = 1 or 5 or 6
\nWhen, A = 1
\nII \u2260 9A
\n\u2234 A \u2260 1
\nWhen, A = 5
\n15 x 5 \u2260 9A;
\n\u2234 A \u2260 5
\nWhen, A = 6
\n16 x 6 = 96
\n\u2234 A = 6
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 4.
\nHere, there are two letters A and B whose values are to be found out.
\nAnswer:
\nB + 7 gives A
\nand A + 3 gives 6
\nThe possible values are 0 + 7 = 7
\nA = 7 but 7 + 3 \u2260 6 so it is not acceptable.
\n1 + 7 = 8
\nA = 8 but 8 + 3 \u2260 6 so not acceptable
\n2 + 7 = 9
\nA = 9 but 9 + 3 \u2260 6 so not acceptable
\n3 + 7= 10
\nA = 0 but 1+0 + 3 \u2260 6 so, not acceptable.
\n4 + 7= 11
\nA = 1 but 1 + 1 + 3 \u2260 6 so not acceptable.
\n5 + 7= 12
\nA = 2 Also 1 + 2 + 3 = 6
\nSo B = 5 works and then we get A as 2
\n\u2234 the puzzle is solved as shown below
\n\"NCERT
\ni. e. A = 2 and B = 5.<\/p>\n

5. We need B x 3 = \u25a1 B
\nSince 5 x 3 = 15
\n\u2234 Possible value of B can be 5.
\nAlso 0 x 3 = 0, i.e., B = 0 can be another possible value
\n\u2235 A x 3 = A + 0 = A
\n\u2234 Possible value of A = 5 or A = 0
\n\u2234 Since C \u2260 0
\n\u2234 Possible value of A = 5
\n30, B must be
\nThus, B = 0.
\n\"NCERT<\/p>\n

6. B can be either 5 or 0.
\n\u2235 A x 5 = A
\n\u2234 B must be 0
\nAgain A can either 5 or 0
\n\u2234 C \u2260 0
\n\u2234 A \u2260 0
\n\u2234 A must be equal to 5
\nThus, we have
\nTherefore, A = 5, B = 0, C = 2
\n\"NCERT<\/p>\n

7. B can be 2, 4, 6 or 8
\nWe need product 111 or 222, or 333 or 444 or 888 out of them 111 and 333 are rejected Possible products are 222, 444 or 888 To obtain
\nThe possible value is B = 4
\n\"NCERT
\n\u2234 A can be either 2 or 7
\n\"NCERT
\n\u2234 A x 6 = 7 x 6 is the accepted value
\n\"NCERT
\nThus, A = 7 and B = 4<\/p>\n

\"NCERT<\/p>\n

\"NCERT
\nThus, A = 7 and B = 9<\/p>\n

9. \u2235\u00a0 8 – 1 = 7
\n\u2234 B = 7
\n7 + 4= 11 \u2234 A = 4
\n\"NCERT
\nNow, we have
\nThus A = 4 and B = 7<\/p>\n

10. 10 – 2 = 8
\n\u2234 A = 8
\nAlso 9 – 8 = 1
\n\"NCERT
\n\u2234 B = 1
\nNow, we have
\nThus, A = 8 and B = 1<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers Ex 16.1 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers Exercise 16.1 Question 1. Find the values of the letters in each of the following and give reasons for …<\/p>\n

NCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers Ex 16.1<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[7],"tags":[],"yoast_head":"\nNCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers Ex 16.1 - MCQ Questions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-8-maths-chapter-16-ex-16-1\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers Ex 16.1 - MCQ Questions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers Ex 16.1 Questions and Answers are prepared by our highly skilled subject experts. 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