NCERT Solutions for Class 8 Maths<\/a> Chapter 10 Visualizing Solid Shapes Ex 10.3 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\nNCERT Solutions for Class 8 Maths Chapter 10 Visualizing Solid Shapes Exercise 10.3<\/h2>\n Question 1. \nCan a polyhedron have for its faces. \n(i) 3 triangles \n(ii) 4 triangles \n(iii) a square and four triangles? \nAnswer: \n(i) No, it is not possible \n(ii) Yes, four triangles can be the faces of a polyhedron. \n(iii) Yes, a square and four triangles can be the faces.<\/p>\n
Question 2. \nIs it possible to have a polyhedron with any given number of faces? \n(Hint: Think of a pyramid) \nAnswer: \nPossible only if the number of faces is greater than or equal to 4.<\/p>\n
<\/p>\n
Question 3. \nWhich are prisms among the following? \n \n \n(i) A nail \n(ii) Unsharpened pencil \nAnswer: \n(i) No, a nail is not a prism. \n(ii) Yes, unsharpened pencil is a prism. \n(iii) No, table weight is not a prism. \n(iv) Yes, box is a prism.<\/p>\n
Question 4. \n(i) How are prisms and cylinders alike? \n(ii) How are pyramids and cones alike? \nAnswer: \n(i) A prism becomes a cylinder as the number of sides of its base becomes larger and larger. \n(ii) A pyramid becomes a cone as the number of sides of its base becomes larger and larger.<\/p>\n
Question 5. \nIs a square prism same as a cube? \nExplain: \nAnswer: \nNo, it can be a cuboid also.<\/p>\n
<\/p>\n
Question 6. \nVerify Euler\u2019s formula for these solids. \n \nAnswer: \nIn the given figure, \nF = 7, V = 10 and E = 15 \nF + V – E = 7 + 10 – 15 = 17 – 15 \nF + V – E = 2 \nThus, Euler\u2019s formula is verified.<\/p>\n
(ii) In the given figure, \nF = 9, V = 9 and E = 16 \nF + V- E = 9 + 9 – 16 = 18 – 16 \nThus, Euler\u2019s formula is verified.<\/p>\n
Question 7. \nUsing Euler\u2019s formula find the unknown. \n \nAnswer: \n(i) Here V = 6 and E = 12 \nF + V – E = 2 \nF + 6 – 12 = 2 \nF – 6 = 2 \nF = 6 + 2 = 8<\/p>\n
(ii) F = 5, E = 9 \nF + V – E = 2 \n5 + V – 9 = 2 \nV – 4 = 2 \nV = 2 + 4 = 6<\/p>\n
(iii) Here F = 20 V = 12 \nF + V – E = 2 \n20 + 12 – E = 2 \n32 – E = 2 \n32 – 2 = E \n30 = E<\/p>\n
<\/p>\n
Question 8. \nCan a polyhedron have 10 faces, 20 edges and 15 vertices? \nAnswer: \nHere, F = 10, E = 20, V = 15 \nWe know that F + V – E = 2 \nHere, F + V – E =10 + 15 – 20 \n= 25 – 20 \n= 15 \u2260 2 \n\u2234 Such a polyhedron is not possible.<\/p>\n","protected":false},"excerpt":{"rendered":"
These NCERT Solutions for Class 8 Maths Chapter 10 Visualizing Solid Shapes Ex 10.3 Questions and Answers are prepared by our highly skilled subject experts. NCERT Solutions for Class 8 Maths Chapter 10 Visualizing Solid Shapes Exercise 10.3 Question 1. Can a polyhedron have for its faces. (i) 3 triangles (ii) 4 triangles (iii) a …<\/p>\n
NCERT Solutions for Class 8 Maths Chapter 10 Visualizing Solid Shapes Ex 10.3<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[7],"tags":[],"yoast_head":"\nNCERT Solutions for Class 8 Maths Chapter 10 Visualizing Solid Shapes Ex 10.3 - MCQ Questions<\/title>\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n\t \n\t \n\t \n