Page no. 240<\/span><\/p>\nQuestion 1.
\nWhich of the following correctly describes the magnetic Field near a long straight wire?
\n(a) The field consists of straight lines perpendicular to the wire.
\n(b) The field consists of straight lines parallel to the Wire.
\n(c) The field consists of radial lines originating from the wire.
\n(d) The field consists of concentric circles centered on the wire.
\nAnswer:
\n(d) The field consists of concentric circles centered on the wire.<\/p>\n
Question 2.
\nThe phenomenon of electromagnetic induction is wire.
\n(a) the process of charging a body.
\n(b) the process of generating magnetic field due to a current passing through a coil.
\n(c) producing induced current in a coil due to a relative motion between a magnet and the coil.
\n(d) the process of rotating a coil of an electric motor.
\nAnswer:
\n(c) Producing induced current in a coil due to relative motion between 1 magnet and the coil.<\/p>\n
Question 3.
\nThe device used for producing electric current is called a
\n(a) galvanometer
\n(b) generator
\n(c) motor
\n(d) ammeter
\nAnswer:
\n(a) Generator.<\/p>\n
<\/p>\n
Question 4.
\nThe essential difference between AC generator and a DC generator is that
\n(a) AC generator has an electromagnet while a DC generator has permanent magnet.
\n(b) DC generator will generate a higher voltage.
\n(c) AC generator will generate a higher voltage.
\n(d) AC generator has slip rings while the DC generator has a commutator.
\nAnswer:
\n(d) AC generator has slip rings while the DC generator has a commutator.<\/p>\n
Question 5.
\nAt the time of short circuit, the current in the circuit.
\n(a) reduces substantially
\n(b) does not change
\n(c) increases heavily
\n(d) vary continuously
\nAnswer:
\n(c) Increase heavily<\/p>\n
Question 6.
\nState whether the following statements are true or false:
\n(a) An electric motor converts mechanical energy into electric energy
\n(b) An electric generator works on the principle of electromagnetic induction.
\n(c) The field at the Centre of a long circular coil carrying current will be parallel straight lines.
\n(d) A wire with a green insulation is usually the live wire.
\nAnswer:
\n(a) False,
\n(b) True,
\n(c) True,
\n(d) False.<\/p>\n
Question 7.
\nList three sources of magnetic fields.
\nAnswer:
\nSolenoid, Bar magnet, Magnetite.<\/p>\n
Question 8.
\nHow does a solenoid behave like a magnet ? Can you determine the north and south poles of a current carrying solenoid with a help of bar magnet ? Explain.
\nAnswer:
\nA solenoid is a long, helically round coil of insulated Wire.<\/p>\n
When an electric current flows through a solenoid a magnetic field is set up which is similar to the magnetic field of a bar magnet. One end of the solenoid acts as south pole and the other end acts as north pole. If the current flows in a clockwise direction when the coil is seen end-on, then that end of the solenoid acts as a South pole. On the other hand if the current flows in anticlockwise direction when the coil is seen-end- on, then that end of the solenoid acts as a North pole.<\/p>\n
When the North pole of a bar magnet is placed near the one end of the solenoid and if it is repelled, then end of the solenoid will be North pole and if it is attracted than end of the solenoid will be South pole.<\/p>\n
Question 9.
\nWhen is the force experienced by a current-carrying conductor placed in a magnetic field is largest ?
\nAnswer:
\nThe force will be largest when the direction of current is at right angles to the direction of the magnetic field.<\/p>\n
<\/p>\n
Question 10.
\nImagine you are sitting in a chamber with your back to one wall. An electron beam, moving horizontally from back wall towards the front wall, is deflected by a strong magnetic field to your right side. Hat is the direction of magnetic field?
\nAnswer:
\nMagnetic field is horizontally towards front wall.<\/p>\n
Question 11.
\nDraw a labelled diagram of an electric motor. Explain its principle and working. What is the function of a split ring in An electric motor ?
\nAnswer:
\nPrinciple: Electric motor is based on the principle that “when a current carrying conductor is placed in a magnetic field Then it experiences a mechanical force tending to rotate the Conductor” and the direction of the force experienced is given by Fleming’s Left Hand Rule.<\/p>\n
Working : Suppose D.C. current (from a battery) is passed via Brushes, and commutator through armature, when the plane of The coil ABCD is parallel to the magnetic field as shown in Fig. (a) According to Fleming’s left hand rule, the limb AB of the coil Experiences an upward force. While the limb CD experiences a Downward force: Now these two equal, but opposite forces acting At AB and CD constitutes a couple, which rotates the coil in Clockwise direction. It may be noted that the moment of the couple
\n
\n
\nis maximum to start with, but it goes on decreasing and becomes Zero, when the coil becomes perpendicular to magnetic lines of Force. Consequently, the coil should stop at this position. However Due to inertia of the moving coil, it crosses this position and the Coil again becomes parallel to the magnetic lines of force Contact of the brushes (B1<\/sub> and B2<\/sub>) with the segments (S1<\/sub> and S2<\/sub>) Gets reversed and the direction of current through the coil also gets Reversed, thereby the current starts flowing along DCBA as shown In Fig. (b): Consequently, the limb DC of the coil starts moving Upwards; while the limb AB os the coil starts moving downwards In accordance with Fleming’s left hand rule. In this way, the Motion of the armature is always same (clockwise, in this case) And becomes continuous.<\/p>\nQuestion 12.
\nName some devices in which electric motors are used.
\nAnswer:
\nFans, Cooler, Air conditioner, CD Player etc.<\/p>\n
Question 13.
\nA coil of insulated copper wire is connected to a Galvanometer. What will happen if a bar magnet is (i) pushed into the coil (ii) with drawn from inside the coil (iii) held stationary Inside the coil ?
\nAnswer:
\n(i) We will see a deflection in the galvanometer.
\n(ii) The needle of galvanometer again shows deflection, but in The opposite direction.
\n(iii) No deflection in the galvanometer.<\/p>\n
Question 14.
\nTwo circular coils A and B are placed closed to each Other. If the current in the coil “A” is changed, will some current Be induced in the coil ‘B’ ? Give reason.
\nAnswer:
\nYes, some current will be induced in the coil B as Current is changed in coil A due to electromagnetic induction. In electromagnetic induction by changing magnetic field in a conductor induces a current in another conductor because as the Current changes in coil ‘A the magnetic field associated with it. Also changes. Thus the magnetic field lines around the coil B Also change. Hence the chance magnetic field lines associated With the coil ‘B’ is the cause of the induced current in it.<\/p>\n
Question 15.
\nState the rule to determine the direction of a (i) Magnetic field produced around a straight conductor Current (ii) force experienced by a Current-carrying straight Conductor placed in a magnetic field which is perpendicular it and (iii) current induced in a coil due to its rotation Magnetic field.
\nAnswer:
\n(i) Right hand thumb rule
\n(ii) Flemings left hand rule
\n(iii) Fleming’s right hand rule.<\/p>\n
<\/p>\n
Question 16.
\nExplain the underlying principle and working of an Electric generator by drawing a labelled diagram. What is The Function of brushes?
\nAnswer:
\nPrinciple : It is based on the principle Electromagnetic induction, Which states in simple form As “whenever a conductor is Rotated mechanically in a Magnetic field, there is a Brushes Change in the magnetic lines of force within it and an Induced current is generated In the conductor”. The Direction of induced current is given by Fleming’s right hand rule.<\/p>\n
Construction : It consists of a rotating armature ABCD containing coils of wire, pole pieces, brushes and a commutator. The two ends of the armature ABCD are connected to two metallic Rings S1<\/sub> and S2<\/sub> the two brushes B1<\/sub> and B2<\/sub> which are connected To a galvanometer G are in contact with the rings S1<\/sub> and S2<\/sub> Respectively.<\/p>\nWorking : When the armature coil ABCD rotates in the magnetic field provided by the strong field magnet, it cuts the magnetic lines of force. Thus the changing magnetic field produces induced current in the coil. The current flows out through the brush B, in one direction in the first half of the revolution and through the Brush B, in the next half revolution in the reverse direction. This Process is repeated. Therefore, induced current produced is of alternating nature. Such a current is called alternating current.
\n<\/p>\n
Question 17.
\nWhen does an electric short circuit occur?
\nAnswer:
\nIf the plastic insulation of the live wire and neutral wire gets torn, than the two wires touch each other. The touching of the live wire and neutral wire directly is known as short circuiting. It occurs by the direct touching of live and neutral wires.<\/p>\n
Question 18.
\nWhat is the function of an earth wire ? Why is it necessary to earth metallic appliances?
\nAnswer:
\nFunction : A very high current flows through the earth Wire and the fuse of household wiring blows out or melts and it cuts of the power supply. We earth the metallic appliances to save ourselves from electric shocks. If by chance, the live wire touches. The metal part of the electric appliance, which has been earthed, then the current passes directly to the earth through the earth wire. It does not need our body to pass the current and thus we do not get an electric shock.<\/p>\n
Class 10 Science Chapter 13 Magnetic Effects of Electric Current Textbook Activities<\/h3>\n
Activity 13.1 (Page 223)<\/span><\/p>\n