{"id":29051,"date":"2021-09-29T11:16:53","date_gmt":"2021-09-29T05:46:53","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=29051"},"modified":"2022-03-02T10:21:07","modified_gmt":"2022-03-02T04:51:07","slug":"ncert-solutions-for-class-10-maths-chapter-14-ex-14-3","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-10-maths-chapter-14-ex-14-3\/","title":{"rendered":"NCERT Solutions for Class 10 Maths Chapter 14 Statistics Ex 14.3"},"content":{"rendered":"
These NCERT Solutions for Class 10 Maths<\/a> Chapter 14 Statistics Ex 14.3 Questions and Answers are prepared by our highly skilled subject experts.<\/p>\n <\/p>\n Question 1. (ii) Mode Here f1<\/sub> = 20, f2<\/sub> = 14, f0<\/sub> = 13, l = 125, h = 0 (iii) Mean online median calculator<\/a> tool makes the calculation faster, and it displays the measures of central tendencies in a fraction of seconds.<\/p>\n <\/p>\n Question 2. Question 3.NCERT Solutions for Class 10 Maths Chapter 14 Statistics Exercise 14.3<\/h2>\n
\nThe following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them.
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\nSolution:
\nThe cumulative frequency distribution of given frequency distribution given below.
\n
\n(i) Median
\n\\(\\frac { n }{ 2 }\\) = \\(\\frac { 68 }{ 2 }\\) = 34
\nTherefore, median class is (125 -145)
\n
\n\u2234 Median of the given frequency distribution is 137 units.<\/p>\n
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\n\u2234 Mode of the given data is 135.76<\/p>\n
\nWe know that relation between mean, mode and median is
\n3 Median = Mode + 2 Mean
\n2 Mean = 3 Median – Mode
\n2 Mean = 3 (137) – (135.76)
\n= 411 – 135.76
\n= 275.24
\nHence Mean = 137.62
\n\u2234 Mean of the given data is 137.62.<\/p>\n
\nIf the median of the distribution given below is 28.5, find the values of x and y.
\n
\nSolution:
\n<\/p>\n
\nA life insurance agent found the following data for distribution of ages of 100 policy holders. Calculate the median age, if policies are given only to persons having age 18 years onwards but less than 60 years.
\n
\nSolution:
\n
\n
\nHence, median age is 35.76 years.<\/p>\n