NCERT Solutions for Class 12 Maths<\/a> Chapter 2 Inverse Trigonometric Functions Miscellaneous Exercise Questions and Answers are prepared by our highly skilled subject experts. https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-2-miscellaneous-exercise\/<\/p>\nNCERT Solutions for Class 12 Maths Chapter 2 Inverse Trigonometric Functions Miscellaneous Exercise<\/h2>\n
<\/p>\n
Question 1.
\ncos-1<\/sup>(cos\\(\\frac { 13\u03c0 }{ 6 }\\))
\nSolution:
\nThe principal value brach of cos-1<\/sup> is [0, p]
\n<\/p>\nQuestion 2.
\ntan-1<\/sup>(tan\\(\\frac { 7\u03c0 }{ 6 }\\))
\nSolution:
\nThe principal value brach of tan-1<\/sup> is (- \\(\\frac { \u03c0 }{ 2 }\\), \\(\\frac { \u03c0 }{ 2 }\\))
\n<\/p>\n<\/p>\n
Question 3.
\n2sin-1<\/sup>\\(\\frac { 3 }{ 5 }\\) = tan-1<\/sup>\\(\\frac { 24 }{ 7 }\\)
\nSolution:
\n<\/p>\nQuestion 4.
\nsin-1<\/sup>\\(\\frac { 8 }{ 17 }\\) + sin-1<\/sup>\\(\\frac { 3 }{ 5 }\\) = tan-1<\/sup>\\(\\frac { 77 }{ 36 }\\)
\nSolution:
\n<\/p>\n<\/p>\n
Question 5.
\ncos-1<\/sup>\\(\\frac { 4 }{ 5 }\\) + cos-1<\/sup>\\(\\frac { 12 }{ 13 }\\) = cos-1<\/sup>\\(\\frac { 33 }{ 65 }\\)
\nSolution:
\n<\/p>\nQuestion 6.
\ncos-1<\/sup>\\(\\frac { 12 }{ 13 }\\) + sin-1<\/sup>\\(\\frac { 3 }{ 5 }\\) = sin-1<\/sup>\\(\\frac { 56 }{ 65 }\\)
\nSolution:
\n<\/p>\nQuestion 7.
\ntan-1<\/sup>\\(\\frac { 63 }{ 16 }\\) = sin-1<\/sup>\\(\\frac { 5 }{ 13 }\\) + cos-1<\/sup>\\(\\frac { 3 }{ 5 }\\)
\nSolution:
\n<\/p>\n<\/p>\n
Question 8.
\ntan-1<\/sup>\\(\\frac { 1 }{ 5 }\\) + tan-1<\/sup>\\(\\frac { 1 }{ 7 }\\) + tan-1<\/sup>\\(\\frac { 1 }{ 3 }\\) + tan-1<\/sup>\\(\\frac { 1 }{ 8 }\\) = \\(\\frac { \u03c0 }{ 4 }\\)
\nSolution:
\n<\/p>\nQuestion 9.
\ntan-1<\/sup>\\(\\sqrt{x}\\) = \\(\\frac { 1 }{ 2 }\\)cos-1<\/sup>\\(\\left(\\frac{1-x}{1+x}\\right), x \\in[0,1]\\)
\nSolution:
\n<\/p>\nQuestion 10.
\ncot-1<\/sup>\\(\\left(\\frac{\\sqrt{1+\\sin x}+\\sqrt{1-\\sin x}}{\\sqrt{1+\\sin x}-\\sqrt{1-\\sin x}}\\right)\\) = \\(\\frac { x }{ 2 }\\) x \u2208 (0, \\(\\frac { \u03c0 }{ 4 }\\))
\nSolution:
\n<\/p>\n<\/p>\n
Question 11.
\ntan-1<\/sup>\\(\\left(\\frac{\\sqrt{1+x}-\\sqrt{1-x}}{\\sqrt{1+x}+\\sqrt{1-x}}\\right)\\) = \\(\\frac { \u03c0 }{ 4 }\\) – \\(\\frac { 1 }{ 2 }\\) cos-1<\/sup> x, – \\(\\frac{1}{\\sqrt{2}} \\leq x \\leq 1\\)
\nSolution:
\n<\/p>\nQuestion 12.
\n\\(\\frac { 9p }{ 8 }\\) – \\(\\frac { 9 }{ 4 }\\)sin-1<\/sup>\\(\\frac { 1 }{ 3 }\\) = \\(\\frac { 9 }{ 4 }\\)sin-1<\/sup>\\(\\frac{2 \\sqrt{2}}{3}\\)
\nSolution:
\n<\/p>\nQuestion 13.
\n2tan-1<\/sup>(cosx) = tan-1<\/sup>(2cosecx)
\nSolution:
\n<\/p>\nQuestion 14.
\ntan-1<\/sup>\\(\\frac{1-x}{1+x}\\) = \\(\\frac { 1 }{ 2 }\\) tan-1<\/sup>x, (x > 0)
\nSolution:
\n<\/p>\n<\/p>\n
Question 15.
\nsin(tan-1<\/sup>x), |x| < 1 is equal to
\na. \\(\\frac{x}{\\sqrt{1-x^{2}}}\\)
\nb. \\(\\frac{1}{\\sqrt{1-x^{2}}}\\)
\nc. \\(\\frac{1}{\\sqrt{1+x^{2}}}\\)
\nd. \\(\\frac{x}{\\sqrt{1+x^{2}}}\\)
\nSolution:
\nd. \\(\\frac{x}{\\sqrt{1+x^{2}}}\\)
\n<\/p>\nQuestion 16.
\nsin-1<\/sup>(1 – x) – 2sin-1<\/sup>x = \\(\\frac { \u03c0 }{ 2 }\\), then x is equal to
\na. 0, \\(\\frac { 1 }{ 2 }\\)
\nb. 1, \\(\\frac { 1 }{ 2 }\\)
\nc. 0
\nd. \\(\\frac { 1 }{ 2 }\\)
\nSolution:
\nc. 0
\n
\nBut x \u2260 \\(\\frac { 1 }{ 2 }\\), since sin-1<\/sup>(1 – \\(\\frac { 1 }{ 2 }\\)) \u2260 \\(\\frac { \u03c0 }{ 2 }\\) + 2 sin-1<\/sup>\\(\\frac { 1 }{ 2 }\\)
\n\u2234 x = 0.<\/p>\nQuestion 17.
\ntan-1<\/sup> \\(\\frac { x }{ y }\\) – tan-1<\/sup> \\(\\frac{x-y}{x+y}\\)
\nSolution:
\na. \\(\\frac { \u03c0 }{ 2 }\\)
\nb. \\(\\frac { \u03c0 }{ 3 }\\)
\nc. \\(\\frac { \u03c0 }{ 4 }\\)
\nd. \\(\\frac { -3\u03c0 }{ 4 }\\)
\nSolution:
\nc. \\(\\frac { \u03c0 }{ 4 }\\)
\n<\/p>\n<\/p>\n","protected":false},"excerpt":{"rendered":"
These NCERT Solutions for Class 12 Maths Chapter 2 Inverse Trigonometric Functions Miscellaneous Exercise Questions and Answers are prepared by our highly skilled subject experts. https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-2-miscellaneous-exercise\/ NCERT Solutions for Class 12 Maths Chapter 2 Inverse Trigonometric Functions Miscellaneous Exercise Question 1. cos-1(cos) Solution: The principal value brach of cos-1 is [0, p] Question 2. tan-1(tan) …<\/p>\n
NCERT Solutions for Class 12 Maths Chapter 2 Inverse Trigonometric Functions Miscellaneous Exercise<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[3],"tags":[],"yoast_head":"\nNCERT Solutions for Class 12 Maths Chapter 2 Inverse Trigonometric Functions Miscellaneous Exercise - MCQ Questions<\/title>\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\t\n