NCERT Solutions for Class 12 Maths<\/a> Chapter 5 Continuity and Differentiability Ex 5.2 Questions and Answers are prepared by our highly skilled subject experts. https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-2\/<\/p>\nNCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Exercise 5.2<\/h2>\n <\/p>\n
Class 12 Maths Chapter 5 Exercise 5.2 Question 1.<\/strong> \nsin(x\u00b2 + 5) \nSolution: \nLet y = sin(x\u00b2 + 5), \nput x\u00b2 + 5 = t \ny = sint \nt = x\u00b2+5 \n\\(\\frac { dy }{ dx } =\\frac { dy }{ dt } .\\frac { dt }{ dx } \\) \n\\(\\frac { dy }{ dx } =cost.\\frac { dt }{ dx } =cos({ x }^{ 2 }+5)\\frac { d }{ dx } ({ x }^{ 2 }+5)\\) \n= cos (x\u00b2 + 5) \u00d7 2x \n= 2x cos (x\u00b2 + 5)<\/p>\nEx 5.2 Class 12 NCERT Solutions Question 2.<\/strong> \ncos (sin x) \nSolution: \nlet y = cos (sin x) \nput sinx = t \n\u2234 y = cost, \nt = sinx \n\u2234\\(\\frac { dy }{ dx } =-sin\\quad t,\\frac { dt }{ dx } =cos\\quad x \\) \n\\(\\frac { dy }{ dx } =\\frac { dy }{ dt } .\\frac { dt }{ dx } =(-sint)\\times cosx\\) \nPutting the value of t, \\(\\frac { dy }{ dx } =-sin(sinx)\\times cosx\\) \n\\(\\frac { dy }{ dx } =-[sin(sinx)]cosx\\)<\/p>\n <\/p>\n
Ncert Solutions For Class 12 Maths Chapter 5 Exercise 5.2 Question 3.<\/strong> \nsin(ax+b) \nSolution: \nlet = sin(ax+b) \nput ax+bx = t \n\u2234 y = sint \nt = ax+b \n\\(\\frac { dy }{ dt } =cost,\\frac { dt }{ dx } =\\frac { d }{ dx } (ax+b)=a\\) \n\\(Now\\frac { dy }{ dx } =\\frac { dy }{ dt } .\\frac { dt }{ dx } =cost\\times a=acos\\quad t\\) \n\\(\\frac { dy }{ dx } =acos(ax+b)\\)<\/p>\nExercise 5.2 Class 12 NCERT Solutions Question 4.<\/strong> \nsec(tan(\\(\\sqrt{x}\\))) \nSolution: \nlet y = sec(tan(\\(\\sqrt{x}\\))) \nby chain rule \n\\(\\frac { dy }{ dx } =sec(tan\\sqrt { x } )tan(tan\\sqrt { x } )\\frac { d }{ dx } (tan\\sqrt { x } )\\) \n\\(\\frac { dy }{ dx } =sec(tan\\sqrt { x } ).tan(tan\\sqrt { x } ){ sec }^{ 2 }\\sqrt { x } .\\frac { 1 }{ 2\\sqrt { x } } \\)<\/p>\nQuestion 5. \n\\(\\\\ \\frac { sin(ax+b) }{ cos(cx+d) } \\) \nSolution: \n <\/p>\n
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Question 6. \ncos x\u00b3 . sin\u00b2(x5<\/sup>) = y(say) \nSolution: \nLet y = cos x\u00b3 . sin\u00b2(x5<\/sup>) \n <\/p>\nQuestion 7. \n\\(2\\sqrt { cot({ x }^{ 2 }) }\\) \nSolution: \n <\/p>\n
Question 8. \ncos(\\(\\sqrt{x}\\)) \nSolution: \n <\/p>\n
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Question 9. \nProve that the function f given by f (x) = |x – 1|, x \u2208 R is not differential at x = 1. \nSolution: \n \n\u2234 f is not differentiable at x = 1<\/p>\n
Question 10. \nProve that the greatest integer function defined by f (x) = [x], 0 < x < 3 is not differential at x = 1 and x = 2. \nSolution: \n \nHence f is not differentiable at x = 2<\/p>\n","protected":false},"excerpt":{"rendered":"
These NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.2 Questions and Answers are prepared by our highly skilled subject experts. https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-2\/ NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Exercise 5.2 Class 12 Maths Chapter 5 Exercise 5.2 Question 1. sin(x\u00b2 + 5) Solution: Let y = …<\/p>\n
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.2<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[3],"tags":[],"yoast_head":"\nNCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.2 - MCQ Questions<\/title>\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n\t \n\t \n\t \n