{"id":30043,"date":"2022-03-29T12:00:24","date_gmt":"2022-03-29T06:30:24","guid":{"rendered":"https:\/\/mcq-questions.com\/?p=30043"},"modified":"2022-03-29T12:28:05","modified_gmt":"2022-03-29T06:58:05","slug":"ncert-solutions-for-class-12-maths-chapter-5-ex-5-5","status":"publish","type":"post","link":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/","title":{"rendered":"NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5"},"content":{"rendered":"

These NCERT Solutions for Class 12 Maths<\/a> Chapter 5 Continuity and Differentiability Ex 5.5 Questions and Answers are prepared by our highly skilled subject experts. https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/<\/p>\n

NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Exercise 5.5<\/h2>\n

\"NCERT<\/p>\n

Ex 5.5 Class 12 NCERT Solutions Question 1.<\/strong>
\ncos x. cos 2x. cos 3x
\nSolution:
\nLet y = cos x. cos 2x . cos 3x,
\nTaking log on both sides,
\nlog y = log (cos x. cos 2x. cos 3x)
\nlog y = log cos x + log cos 2x + log cos 3x,
\nDifferentiating w.r.t. x, we get
\n\"Ex<\/p>\n

Exercise 5.5 Class 12 Maths Solutions Question 2.<\/strong>
\n\\(\\sqrt{\\frac{(x-1)(x-2)}{(x-3)(x-4)(x-5)}}\\)
\nSolution:
\n\"Exercise<\/p>\n

\"NCERT<\/p>\n

Ex 5.5 Class 12 Maths Ncert Question 3.<\/strong>
\n(log x)cosx<\/sup>
\nSolution:
\nlet y = (log x)cosx<\/sup>
\nTaking log on both sides,
\nlog y = log (log x)cosx<\/sup>
\nlog y = cos x log (log x),
\nDifferentiating w.r.t. x,
\n\"Ex<\/p>\n

Exercise 5.5 Class 12 NCERT Solutions\u00a0 Question 4.<\/strong>
\nx – 2sinx<\/sup>
\nSolution:
\nlet y = x – 2sinx<\/sup>,
\n\u2234 y = u – v
\nDifferentiating w.r.t. x,
\n\"Exercise<\/p>\n

\"NCERT<\/p>\n

Ch 5 Maths Class 12 Ex 5.5 NCERT Solutions Question 5.<\/strong>
\n(x+3)2<\/sup>.(x + 4)3<\/sup>.(x + 5)4<\/sup>
\nSolution:
\nlet y = (x + 3)2<\/sup>.(x + 4)3<\/sup>.(x + 5)4<\/sup>
\nTaking log on both side,
\nlogy = log [(x + 3)2<\/sup> . (x + 4)3<\/sup> . (x + 5)4<\/sup>]
\n= log (x + 3)2<\/sup> + log (x + 4)3<\/sup> + log (x + 5)4<\/sup>
\nlog y = 2 log (x + 3) + 3 log (x + 4) + 4 log (x + 5)
\nDifferentiating w.r.t. x, we get
\n\"Ch
\nOn simplification,
\n\\(\\frac { dy }{ dx }\\) = (x + 3)(x + 4)\u00b2(x + 5)\u00b3(9x\u00b2 + 70x + 133)<\/p>\n

Question 6.
\n\\({ \\left( x+\\frac { 1 }{ x } \\right) }^{ x }+{ x }^{ \\left( 1+\\frac { 1 }{ x } \\right) }\\)
\nSolution:
\nLet u = \\(\\left(x+\\frac{1}{x}\\right)^{x}\\) = \\(\\left(\\frac{x^{2}+1}{x}\\right)^{x}\\)
\nv = \\(x^{\\left(1+\\frac{1}{x}\\right)}\\)
\nLet y = u + v
\nDifferentiating w.r.t. x,
\n\u2234 \\(\\frac { dy }{ dx }\\) = \\(\\frac { du }{ dx }\\) + \\(\\frac { dv }{ dx }\\) … (1)
\nu = \\(\\left(\\frac{x^{2}+1}{x}\\right)^{x}\\)
\nTaking logaritham on both sides,
\nlogu = x log \\(\\left(\\frac{x^{2}+1}{x}\\right)\\)
\n\u2234 log u = x(log(x\u00b2+ 1) – logx)
\nDifferentiating both sides w.r.t.x,
\n\"NCERT
\nv = \\(x^{\\left(1+\\frac{1}{x}\\right)}\\)
\nTaking logaritham on both sides,
\nlogv = (1 + \\(\\frac { 1 }{ x }\\)) log x
\nDifferentiating both sides w.r.t. x,
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 7.
\n(log x)x<\/sup> + xlogx<\/sup>
\nSolution:
\nLet u = (log x)x<\/sup>, v = xlogx<\/sup> and y = u + v
\nDifferentiating w.r.t. x,
\n\u2234 \\(\\frac { dy }{ dx }\\) = \\(\\frac { du }{ dx }\\) + \\(\\frac { dv }{ dx }\\) … (1)
\nu = (log x)x<\/sup>
\nTaking logaritham on both sides,
\nlogu = x log(log x)
\nDifferentiating both sides w.r.t. x,
\n\"NCERT
\nv = xlog x<\/sup>
\nTaking logarithm on both sides,
\nlogv = logx. logx = (logx)\u00b2
\nDifferentiating both sides w.r.t. x,
\n\"NCERT<\/p>\n

Question 8.
\n(sin x)x<\/sup>+sin-1<\/sup> \\(\\sqrt{x}\\)
\nSolution:
\nLet y = (sin x)x\u00a0<\/sup>+ sin-1\u00a0<\/sup>\\(\\sqrt{x}\\)
\nLet y = u + v
\nDifferentiating w.r.t. x,
\n\u2234 \\(\\frac { dy }{ dx }\\) = \\(\\frac { du }{ dx }\\) + \\(\\frac { dv }{ dx }\\) … (1)
\nu = (sin x)x<\/sup>
\n\\(\\frac { du }{ dx }\\) = (sin x)x<\/sup>[x cotx + log sinx] … (2)
\nLet y = (sinx)x<\/sup>
\nTaking logarithm on bath sides,
\nlogy = x.log sin x
\nDifferentiating both sides w.r.t. x,
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 9.
\nxsinx<\/sup> + (sin x)cosx<\/sup>
\nSolution:
\nLet y = xsinx<\/sup> + (sin x)cosx<\/sup>
\nDifferentiating both sides w.r.t. x,
\n\"NCERT
\n(i) Let y = (sin x)x<\/sup>
\nTaking logarithm on both sides,
\nlogy = sinx. logx
\nDifferentiating both sides w.r.t. x,
\n\"NCERT<\/p>\n

(ii) Let y = (sinx)cosx\u00a0<\/sup>
\nTaking logarithm on both sides,
\nlogy = cosx. log sinx
\nDifferentiating both sides w.r.t. x,
\n\"NCERT<\/p>\n

Question 10.
\n\\({ x }^{ x\\quad cosx }+\\frac { { x }^{ 2 }+1 }{ { x }^{ 2 }-1 } \\)
\nSolution:
\nLet u = xx cosx<\/sup> and v = \\(\\frac{x^{2}+1}{x^{2}-1}\\)
\nLet y = u + v
\nDifferentiating w.r.t. x,
\n\u2234 \\(\\frac { dy }{ dx }\\) = \\(\\frac { du }{ dx }\\) + \\(\\frac { dv }{ dx }\\) … (1)
\nu = xx cosx<\/sup>
\nTaking logarithm on both sides,
\nlogu = x cosx . logx
\nDifferentiating both sides w.r.t. x,
\n\"NCERT
\nDifferentiating both sides w.r.t. x,
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 11.
\n\\((x \\cos x)^{x}+(x \\sin x)^{\\frac{1}{x}}\\)
\nSolution:
\nLet u = (x cosx)x<\/sup> and v = \\((x \\sin x)^{\\frac{1}{x}}\\)
\nu = (x cosx)x<\/sup>
\nTaking logarithm on both sides,
\nlog u = x log (x cosx)
\nlog u = x[log x + log cosx]
\nDifferentiating w.r.t. x,
\n\"NCERT<\/p>\n

Question 12.
\nxy<\/sup> + yx<\/sup> = 1
\nSolution:
\nxy<\/sup> + yx<\/sup> = 1
\nlet u = xy<\/sup> and v = yx<\/sup>
\n\u2234 u + v = 1,
\n\\(\\frac { du }{ dx } +\\frac { dv }{ dx }=0\\)
\nNow u = xy<\/sup>
\nTaking logarithm on both sides,
\nlog u = y log x
\nDifferentiating w.r.t. x
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 13.
\nyx<\/sup> = xy<\/sup>
\nSolution:
\nxy<\/sup> = yx<\/sup>
\nTaking logarithm on both sides,
\ny log x = x log y
\nDifferentiating w.r.t. x
\n\"NCERT<\/p>\n

Question 14.
\n(cos x)y<\/sup> = (cos y)x<\/sup>
\nSolution:
\n(cos x)y<\/sup> = (cos y)x<\/sup>
\nTaking logarithm on both sides,
\ny log cosx = x log cosy
\nDifferentiating both sides w.r.t. x,
\n\"NCERT<\/p>\n

Question 15.
\nxy = e(x-y)<\/sup>
\nSolution:
\nlog(xy) = log e(x-y)<\/sup>
\n\u21d2 log(xy) = x – y
\n\u21d2 logx + logy = x – y
\n\\( \u21d2\\frac { 1 }{ x } +\\frac { 1 }{ y } \\frac { dy }{ dx } =1-\\frac { dy }{ dx } \u21d2\\frac { dy }{ dx } =\\frac { y(x-1) }{ x(y+1) } \\)<\/p>\n

Question 16.
\nFind the derivative of the function given by f (x) = (1 + x) (1 + x2<\/sup>) (1 + x4<\/sup>) (1 + x8<\/sup>) and hence find f'(1).
\nSolution:
\nLet f(x) = y = (1 + x)(1 + x2<\/sup>)(1 + x4<\/sup>)(1 + x8<\/sup>)
\nTaking log both sides, we get
\nlogy = log [(1 + x)(1 + x2<\/sup>)(1 + x4<\/sup>)(1 + x8<\/sup>)]
\nlogy = log(1 + x) + log (1 + x2<\/sup>) + log(1 + x4<\/sup>) + log(1 + x8<\/sup>)
\nDifferentiating w.r.t. x,
\n\"NCERT<\/p>\n

\"NCERT<\/p>\n

Question 17.
\nDifferentiate (x2<\/sup> – 5x + 8) (x3<\/sup> + 7x + 9) in three ways mentioned below:
\n(i) by using product rule
\n(ii) by expanding the product to obtain a single polynomial.
\n(iii) by logarithmic differentiation.
\nDo they all give the same answer?
\nSolution:
\n(i) By using product rule
\nf’ = (x2<\/sup> – 5x + 8) (3x2<\/sup> + 7) + (x3<\/sup> + 7x + 9) (2x – 5)
\nf = 5x4<\/sup> – 20x3<\/sup> + 45x2<\/sup> – 52x + 11.<\/p>\n

(ii) y = x5<\/sup> – 5x4<\/sup> + 15x\u00b3 – 26x\u00b2 + 11x + 72
\n(by expanding the product)
\nDifferentiating w.r.t. x, dy
\n\\(\\frac { dy }{ dx }\\) = 5x4<\/sup> – 20x\u00b3 + 45x\u00b2 – 52x + 11<\/p>\n

(iii) y = (x\u00b2 – 5x + 8)(x\u00b3 + 7x + 9)
\nTaking logarithm on both sides,
\nlog y = log(x\u00b2 – 5x 4- 8)(x\u00b3 + 7x + 9)
\nlog y = log(x\u00b2 – 5x + 8) + log(x\u00b3 + 7x + 9)
\nDifferentiating, w.r.t x,
\n\"NCERT
\n= (2x – 5) (x\u00b3 + 7x + 9) + (3x\u00b2 + 7) (x\u00b2 – 5x + 8)
\n= 5x4<\/sup> – 20x\u00b3 + 45x\u00b2 – 52x + 11
\nYes, the answers are the same.<\/p>\n

\"NCERT<\/p>\n

Question 18.
\nIf u, v and w are functions of w then show that
\n\\(\\frac { d }{ dx } (u.v.w)=\\frac { du }{ dx } v.w+u.\\frac { dv }{ dx } .w+u.v\\frac { dw }{ dx } \\)
\nin two ways-first by repeated application of product rule, second by logarithmic differentiation.
\nSolution:
\nLet y = u.v.w
\n(a) Product rule
\n\"NCERT<\/p>\n

(b) Logarithmic differentiation
\ny = uvw
\nTaking logarithm on both sides, we get
\nlog y = log uvw
\ni.e., log y = log u + log v + log w
\nDifferentiating both sides w.r.t. x, we get
\n\"NCERT<\/p>\n","protected":false},"excerpt":{"rendered":"

These NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5 Questions and Answers are prepared by our highly skilled subject experts. https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/ NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Exercise 5.5 Ex 5.5 Class 12 NCERT Solutions Question 1. cos x. cos 2x. cos 3x Solution: Let …<\/p>\n

NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5<\/span> Read More »<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"default","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[3],"tags":[],"yoast_head":"\nNCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5 - MCQ Questions<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5 - MCQ Questions\" \/>\n<meta property=\"og:description\" content=\"These NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5 Questions and Answers are prepared by our highly skilled subject experts. https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/ NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Exercise 5.5 Ex 5.5 Class 12 NCERT Solutions Question 1. cos x. cos 2x. cos 3x Solution: Let … NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5 Read More »\" \/>\n<meta property=\"og:url\" content=\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ Questions\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/NCERTSolutionsGuru\/\" \/>\n<meta property=\"article:published_time\" content=\"2022-03-29T06:30:24+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2022-03-29T06:58:05+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/mcq-questions.com\/wp-content\/uploads\/2021\/01\/NCERT-Solutions-Guru.png\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@ncertsolguru\" \/>\n<meta name=\"twitter:site\" content=\"@ncertsolguru\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Prasanna\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"12 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebSite\",\"@id\":\"https:\/\/mcq-questions.com\/#website\",\"url\":\"https:\/\/mcq-questions.com\/\",\"name\":\"MCQ Questions\",\"description\":\"MCQ Questions for Class 1 to 12\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/mcq-questions.com\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"en-US\"},{\"@type\":\"ImageObject\",\"@id\":\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/#primaryimage\",\"inLanguage\":\"en-US\",\"url\":\"https:\/\/i0.wp.com\/mcq-questions.com\/wp-content\/uploads\/2021\/01\/NCERT-Solutions-Guru.png?fit=170%2C17&ssl=1\",\"contentUrl\":\"https:\/\/i0.wp.com\/mcq-questions.com\/wp-content\/uploads\/2021\/01\/NCERT-Solutions-Guru.png?fit=170%2C17&ssl=1\",\"width\":170,\"height\":17,\"caption\":\"NCERT Solutions\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/#webpage\",\"url\":\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/\",\"name\":\"NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5 - MCQ Questions\",\"isPartOf\":{\"@id\":\"https:\/\/mcq-questions.com\/#website\"},\"primaryImageOfPage\":{\"@id\":\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/#primaryimage\"},\"datePublished\":\"2022-03-29T06:30:24+00:00\",\"dateModified\":\"2022-03-29T06:58:05+00:00\",\"author\":{\"@id\":\"https:\/\/mcq-questions.com\/#\/schema\/person\/4ba9570f32f2057e70e670c7885e47f3\"},\"breadcrumb\":{\"@id\":\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/#breadcrumb\"},\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/mcq-questions.com\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5\"}]},{\"@type\":\"Person\",\"@id\":\"https:\/\/mcq-questions.com\/#\/schema\/person\/4ba9570f32f2057e70e670c7885e47f3\",\"name\":\"Prasanna\",\"image\":{\"@type\":\"ImageObject\",\"@id\":\"https:\/\/mcq-questions.com\/#personlogo\",\"inLanguage\":\"en-US\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/174540ad43736c7d1a4c4f83c775e74d?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/174540ad43736c7d1a4c4f83c775e74d?s=96&d=mm&r=g\",\"caption\":\"Prasanna\"},\"url\":\"https:\/\/mcq-questions.com\/author\/prasanna\/\"}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5 - MCQ Questions","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/","og_locale":"en_US","og_type":"article","og_title":"NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5 - MCQ Questions","og_description":"These NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5 Questions and Answers are prepared by our highly skilled subject experts. https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/ NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Exercise 5.5 Ex 5.5 Class 12 NCERT Solutions Question 1. cos x. cos 2x. cos 3x Solution: Let … NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5 Read More »","og_url":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/","og_site_name":"MCQ Questions","article_publisher":"https:\/\/www.facebook.com\/NCERTSolutionsGuru\/","article_published_time":"2022-03-29T06:30:24+00:00","article_modified_time":"2022-03-29T06:58:05+00:00","og_image":[{"url":"https:\/\/mcq-questions.com\/wp-content\/uploads\/2021\/01\/NCERT-Solutions-Guru.png"}],"twitter_card":"summary_large_image","twitter_creator":"@ncertsolguru","twitter_site":"@ncertsolguru","twitter_misc":{"Written by":"Prasanna","Est. reading time":"12 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebSite","@id":"https:\/\/mcq-questions.com\/#website","url":"https:\/\/mcq-questions.com\/","name":"MCQ Questions","description":"MCQ Questions for Class 1 to 12","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/mcq-questions.com\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"ImageObject","@id":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/#primaryimage","inLanguage":"en-US","url":"https:\/\/i0.wp.com\/mcq-questions.com\/wp-content\/uploads\/2021\/01\/NCERT-Solutions-Guru.png?fit=170%2C17&ssl=1","contentUrl":"https:\/\/i0.wp.com\/mcq-questions.com\/wp-content\/uploads\/2021\/01\/NCERT-Solutions-Guru.png?fit=170%2C17&ssl=1","width":170,"height":17,"caption":"NCERT Solutions"},{"@type":"WebPage","@id":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/#webpage","url":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/","name":"NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5 - MCQ Questions","isPartOf":{"@id":"https:\/\/mcq-questions.com\/#website"},"primaryImageOfPage":{"@id":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/#primaryimage"},"datePublished":"2022-03-29T06:30:24+00:00","dateModified":"2022-03-29T06:58:05+00:00","author":{"@id":"https:\/\/mcq-questions.com\/#\/schema\/person\/4ba9570f32f2057e70e670c7885e47f3"},"breadcrumb":{"@id":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/mcq-questions.com\/ncert-solutions-for-class-12-maths-chapter-5-ex-5-5\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/mcq-questions.com\/"},{"@type":"ListItem","position":2,"name":"NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.5"}]},{"@type":"Person","@id":"https:\/\/mcq-questions.com\/#\/schema\/person\/4ba9570f32f2057e70e670c7885e47f3","name":"Prasanna","image":{"@type":"ImageObject","@id":"https:\/\/mcq-questions.com\/#personlogo","inLanguage":"en-US","url":"https:\/\/secure.gravatar.com\/avatar\/174540ad43736c7d1a4c4f83c775e74d?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/174540ad43736c7d1a4c4f83c775e74d?s=96&d=mm&r=g","caption":"Prasanna"},"url":"https:\/\/mcq-questions.com\/author\/prasanna\/"}]}},"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/posts\/30043"}],"collection":[{"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/users\/9"}],"replies":[{"embeddable":true,"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/comments?post=30043"}],"version-history":[{"count":3,"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/posts\/30043\/revisions"}],"predecessor-version":[{"id":37727,"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/posts\/30043\/revisions\/37727"}],"wp:attachment":[{"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/media?parent=30043"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/categories?post=30043"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mcq-questions.com\/wp-json\/wp\/v2\/tags?post=30043"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}