Question 1.<\/p>\n
(A) 2 : 1
\n(B) 1 : 2
\n(C) 4 : 1
\n(D) 1 : 4
\nAnswer:
\n(C) 4 :1
\nExplanation:
\n![\"MCQ](\"https:\/\/i0.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-1.png?resize=241%2C269&ssl=1\")
\n\\(\\frac{a T \\triangle A B C}{a r \\triangle B D E}\\) =\\(\\frac{\\frac{\\sqrt{3}}{4}(B C)^{2}}{\\frac{\\sqrt{3}}{4}(B D)^{2}}\\) = \\(\\frac{(B C)^{2}}{(B D)^{2}}\\)
\n= \\(\\frac{(B C)^{2}}{\\left(\\frac{B C}{2}\\right)^{2}}\\) = \\(\\frac{4 B C^{2}}{B C^{2}}\\) = \\(\\frac{4}{1}\\) = 4 : 1<\/p>\n
![\"MCQ](\"https:\/\/i0.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/01\/MCQ-Questions.png?resize=159%2C13&ssl=1\")
<\/p>\n
Question 2.<\/p>\n
(A) 2 : 3
\n(B) 4 : 9
\n(C) 81:16
\n(D) 16 : 81
\nAnswer:
\n(D) 16 : 81<\/p>\n
Explanation:
\nWe know that the ratio of the areas of the triangles will be equal to the square of the ratio of the corresponding sides of the triangles.
\nThus, required ratio of the areas of the two
\ntriangles = \\(\\left(\\frac{4}{9}\\right)^{2}\\) = \\(\\frac{16}{81}\\)<\/p>\n
Question 3.<\/p>\n
(A) BD x CD = BC2<\/sup> Explanation: Question 4.<\/p>\n (A) BC x EF = AC x FD Explanation: Question 5.<\/p>\n then: Question 6.<\/p>\n Question 7.<\/p>\n (A) \\(\\frac{E F}{P R}\\) = \\(\\frac{D F}{P Q}\\) Explanation: Question 8.<\/p>\n (A) congruent but not similar Explanation: Assertion and Reason Based MCQs<\/span><\/p>\n Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as. Question 1.<\/p>\n Assertion (A): If in two right triangles, one of the acute angles of one triangle is equal to an acute angle of the other triangle, then triangles will be similar. Answer; Explanation: Question 2.<\/p>\n Explanation: Question 3.<\/p>\n Answer: Explanation: Question 4.<\/p>\n Answer: Explanation: Case – Based MCQs<\/span><\/p>\n Attempt any four sub-parts from each question. Each sub-part carries 1 mark. Question 1.<\/p>\n (A) 20 cm Explanation: Question 2.<\/p>\n (A) They are flipped horizontally Explanation: Question 3.<\/p>\n (A) The ratio of their perimeters is 3 a:b Explanation: Question 4.<\/p>\n Question 5.<\/p>\n (A) 24 m Explanation: II. Read the following text and answer the below questions: Question 1.<\/p>\n (A) 105\u00b0 Explanation: Question 2.<\/p>\n (A) 1.5 cm Explanation: Question 3.<\/p>\n (A) 180\u00b0 Explanation: Question 4.<\/p>\n (A) 5 : 7 Explanation: Question 5.<\/p>\n (A) 105\u00b0 Explanation: III. Read the following text and answer the below questions: SIMILAR TRIANGLES Vijay is trying to find the average height of a tower near his house. He is using the properties of similar triangles. The height of Vijay’s house if 20 m when Vijay’s house casts a shadow 10 m long on the ground. At the same time, the tower casts a shadow 50 m long on the ground and the house of Ajay casts 20 m shadow on the ground. Question 1.<\/p>\n (A) 20 m Explanation: Question 2.<\/p>\n (A) 75 m Question 3.<\/p>\n (A) 30 m Explanation:<\/p>\n \\(\\frac{\\text { Height of Vijay’s house}}{\\text { Length of shadow }}\\) Question 4.<\/p>\n (A) 16 m Question 5.<\/p>\n (A) 15 m IV. Read the following text and answer the below questions: (A) Similarity of triangles Question 2.<\/p>\n (A) 50 m Explanation: Question 3.<\/p>\n (A) (7,24,25) Question 4.<\/p>\n (A) 12 m Question 5.<\/p>\n (A) 120 m Explanation: V. Read the following text and answer the below questions: SCALE FACTOR A scale drawing of an object is the same shape at the object but a different size. The scale of a drawing is a comparison of the length used on a drawing to the length it represents. The scale is written as a ratio. The ratio of two corresponding sides in similar figures is called the scale factor Scale factor = length in image \/ corresponding length in object Question 1.<\/p>\n (A) 22 cm Question 2.<\/p>\n (A) They are flipped horizontally Question 3.<\/p>\n (A) 0.7 m Question 4.<\/p>\n (A) The ratio of their perimeters is 15:1 Question 5.<\/p>\n Triangles Class 10 MCQ Questions with Answers Question 1. ABC and BDE are two equilateral triangles such that D is the mid-point of BC. Ratio of the areas of triangles ABC and BDE is: (A) 2 : 1 (B) 1 : 2 (C) 4 : 1 (D) 1 : 4 Answer: (C) 4 :1 Explanation: …<\/p>\n
\n(B) AB x AC = BC2<\/sup>
\n(C) BD x CD = AD2<\/sup>
\n(D) AB x AC = AD2<\/sup>
\nAnswer:
\n(C) BD x CD = AD2
\n![\"MCQ](\"https:\/\/i0.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-2.png?resize=287%2C152&ssl=1\")
\n<\/sup><\/p>\n
\nIn \u2206ABD and \u2206CAD, \u2220ADB = \u221aADC = 90\u00b0 and \u2220ABD = \u2220CAD = \u03b8 By AA Similarity, we get, \u2206ABD ~ \u2206CAD
\n\u21d2 \\(\\vec{a}\\) = \\(\\vec{a}\\) \u21d2 BD x CD = AD2<\/sup><\/p>\nIf \u2206ABC ~ \u2206EDF and AABC is not similar to \u2206DEF, then which of the following is not true?<\/h2>\n
\n(B) AB x EF = AC x DE
\n(C) BC x DE = AB x EF
\n(D) BC x DE = AB x FD
\nAnswer:
\n(C) BC x DE = AB x EF<\/p>\n
\nSince \u2206ABC ~ \u2206EDF, then we get AB = \\(\\frac{A B}{E D}\\) = \\(\\frac{A C}{E F}\\) = \\(\\frac{B C}{D F}\\)
\nFrom first two, AB x EF = AC x DE.
\nOption (B) is correct.
\nFrom last two, BC x EF = AC x FD.
\nOption (A) is correct.
\nFrom first and last, BC x DE = AB x FD.
\nOption (D) is correct.
\nThus, option (C) is incorrect<\/p>\nIf in two triangles ABC and PQR, \\(\\frac{A B}{Q R}\\) = \\(\\frac{B C}{P R}\\) = \\(\\frac{C A}{P Q}\\)<\/h2>\n
\n(A) \u2206PQR – \u2206CAB
\n(B) \u2206PQR – \u2206ABC
\n(C) \u2206CBA – \u2206PQR
\n(D) \u2206BCA – \u2206PQR
\nAnswer:
\n(A) \u2206PQR – \u2206CAB
\nExplanation: Given that, \\(\\frac{A B}{Q R}\\) =\\(\\frac{B C}{P R}\\) = \\(\\frac{C A}{P Q}\\) , by SSS similarity, we get \u2206PQR ~ \u2206CAB.<\/p>\nIn the figure given below\/- two line segments AC and BD intersect each other at the point P such that PA = 6 cm, PB = 3 cm, PC 2.5 cm, PD = 5 cm, \u2220APB = 50\u00b0 and \u2220CDP = 30\u00b0. Then, \u2220PBA is equal to :<\/h2>\n
![\"MCQ](\"https:\/\/i2.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-3.png?resize=353%2C132&ssl=1\")
\n(A) 50\u00b0
\n(B) 30\u00b0
\n(C) 60\u00b0
\n(D) 100\u00b0
\nAnswer:
\n(D) 100\u00b0
\nExplanation:
\nIn the given figure, \\(\\frac{P A}{P B}\\) = \\(\\frac{6}{3}\\) =2
\nand \\(\\frac{P D}{P C}\\) = \\(\\frac{5}{2.5}\\) = 2 Thus \\(\\frac{P A}{P B}\\) = \\(\\frac{P D}{P C}\\)
\n\u2220APB = \u2220DPC. By SAS similarity, we get \u2206APB ~ \u2206DPC. Hence,\u2220PBA = 100\u00b0<\/p>\nIf in two triangles DEF and PQR, \u2220D = \u2220Q and \u2220R = \u2220E, then which of the following is not true?<\/h2>\n
\n(B) \\(\\frac{D E}{P Q}\\) = \\(\\frac{F E}{R P}\\)
\n(C) \\(\\frac{D E}{Q R}\\) = \\(\\frac{D F}{P Q}\\)
\n(D) \\(\\frac{E F}{R P}\\) = \\(\\frac{D E}{Q R}\\)
\nAnswer:
\n(B) \\(\\frac{D E}{P Q}\\) = \\(\\frac{F E}{R P}\\)<\/p>\n
\nIn \u2206DEF and \u2206PQR, \u2220D – \u2220Q and \u2220R – \u2220E. By AA similarity, wo get \u2206DEE ~ \u2206QRP. Hence, \\(\\frac{D E}{Q R}\\) = \\(\\frac{E F}{R P}\\) = \\(\\frac{D F}{Q P}\\) . Option (B) is incorrect.<\/p>\n<\/p>\nIn triangles ABC and DEF, \u2220B = \u2220E, \u2220E = \u2220C and AB = 3DE. Then, the two triangles are:<\/h2>\n
\n(B) similar but not congruent
\n(C) neither congruent nor similar
\n(D) congruent as well as similar
\nAnswer:
\n(B) similar but not congruent<\/p>\n
\nIn \u2206ABC and \u2206DEE, \u2220B = \u2220E and \u2220E – \u2220C. By AA similarity, we get \u2206ABC ~ \u2206DEE. Thus, the triangles arc similar but not congruent.<\/p>\n
\n(A) Both A and R are true and R is the correct explanation of A
\n(B) Both A and R are true but R is NOT the correct explanation of A
\n(C) A is true but R is false
\n(D) A is false and R is True<\/p>\n
\nReason (R): If the ratio of the corresponding altitudes of two similar triangles is \\(\\frac{3}{5}\\) ratio of their areas is\\(\\frac{6}{5}\\).<\/p>\n
\n(C) A is true but R is false<\/p>\n
\nIn case of assertion:
\nIn the given two right triangles, both have equal right angles and one of the acute angles of one triangle is equal to an acute angle of the other triangle.
\nThus, by AA similarity, the given two triangles are similar.
\n\u2234 Assertion is correct.
\nIn case of reason:
\nWe know that the ratio of the areas of two similar triangles is the square of the ratio of the corresponding altitudes of two similar triangles.
\nThus, the ratio of the areas of two similar triangles is – \\(\\left(\\frac{3}{5}\\right)^{2}\\) = \\(\\frac{9}{25}\\)
\n\u2234Reason is incorrect.
\nHence, assertion is correct but reason is incorrect.<\/p>\nAssertion (A): If D is a point on side QR of \u2206PQR such that PD \u22a5QR, then \u2206PQD ~ \u2206RPD.
\nReason (R): In the figure given below, if \u2220D = \u2220C then \u2206ADE ~ \u2206ACB.<\/h2>\n![\"MCQ](\"https:\/\/i0.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-4.png?resize=161%2C127&ssl=1\")
\nAnswer:
\n(D) A is false and R is True<\/p>\n
\nIn case of assertion:
\n![\"MCQ](\"https:\/\/i0.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-5.png?resize=245%2C96&ssl=1\")
\nIN \u2206PQD and \u2220PDQ = \u2220PDR = 90\u00b0
\nThere is no other information to be similar. Thus, is not it will be correct to say that AAPQD = ARPD.
\n\u2234 Assertion is correct.
\nIn case of assertion:
\nIN AADE and AACB, we have
\n\u2220ADE = \u2220ACB [given ]
\n\u2220DAE = \u2220CAB [Common angle]
\nBy AA similarity, we get \u2206ADE ~ \u2206ACB
\n\u2234 Reason is correct
\nHence, assertion is incorrect but reason is correct<\/p>\nAssertion (A): Corresponding sides of two similar triangles are in the ratio of 2 : 3. If the area of the smaller triangle is 48 cm2<\/sup>, then the area of the larger triangle is 108 cm2<\/sup>.
\nReason (R): If D is a point on the side BC of a triangle ABC such that \u2220ADC = \u2220BAC, then CA2<\/sup> = CB x CD.<\/h2>\n
\n(B) similar but not congruent<\/p>\n
\nIn case of assertion:
\nLet \u2206ABC and \u2206DEE are two similar triangles.
\n\\(\\frac{a r \\triangle A B C}{a r \\triangle D E F}\\) = \\(\\left(\\frac{A B}{D E}\\right)^{2}\\)
\nGiven that ar \u2206ABC = 48 cm2<\/sup>. Then,
\n\\(\\frac{48}{a r \\Delta D E F}\\)
\n= \\(\\frac{4}{9}\\)
\n\u21d2 ar \u2206DEF = \\(\\vec{a}\\) x 48 = 108
\nThus, the area of larger triangle is 108 cm2<\/sup>.
\n\u2234Assertion is correct.
\nIn case of reason:
\n![\"MCQ](\"https:\/\/i2.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-6.png?resize=224%2C132&ssl=1\")
\nIn \u2206BAC and \u2206ADC,
\n\u2220BAC = \u2220ADC [Given]
\n\u2220BCA = \u2220ACD [Common angle]
\nBy AA similarity, \u2206BAC ~ \u2206ADC Thus,
\n\\(\\frac{C A}{C D}\\) = \\(\\frac{B C}{C A}\\)
\n\u2234 Reason is correct
\nHence, both assertion and reason are correct but reason is not the correct explanation for assertion.<\/p>\n<\/p>\nAssertion (A): In an equilateral triangle of side 3\u221a3 cm, then the length of the altitude is 4.5 cm.
\nReason (R): If a ladder 10 cm long reaches a window 8 m above the ground, then the distance of the foot of the ladder from the base of the wall is 6 m.<\/h2>\n
\n(B) similar but not congruent<\/p>\n
\nIn case of assertion:
\n![\"MCQ](\"https:\/\/i0.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-7.png?resize=191%2C159&ssl=1\")
\n\u2206ABD, \u2220D = 90\u00b0
\n\u2234(3\u221a3)2<\/sup> = h2<\/sup> + \\(\\left(\\frac{3 \\sqrt{3}}{2}\\right)^{2}\\)
\nor, 27 = h2 + \\(\\vec{a}\\)
\nor,h2 = 27 – \\(\\vec{a}\\)
\nor, h2 = \\(\\vec{a}\\)
\n\u2234 h = \\(\\vec{a}\\) = 4.5m
\n\u2234 Assertion is correct.
\nIn case of assertion:
\nLet BC be the height of the window above the ground and AAAC be a ladder.
\n![\"MCQ](\"https:\/\/i2.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-8.png?resize=179%2C145&ssl=1\")
\nHere, BC = 8cm and AC = 10 cm
\n\u2234 In right angled triangle ABC,
\nAC2<\/sup> = AB2<\/sup> + BC2<\/sup>(By using Pythagoras Theorem)
\n(10)2 = AB2 + (8)2
\nAB2 = 100 – 64
\n= 36
\nAB = 6 m.
\n\u2234 Reason is correct
\nHence, both assertion and reason are correct but reason is not the correct explanation for as sertion.<\/p>\n
\nI. Read the following text and answer the following questions on the basis of the same: SCALE FACTOR AND SIMILARITY SCALE FACTOR A scale drawing of an object is of the same shape as the object but of a different size. The scale of a drawing is a comparison of the length used on a drawing to the length it represents.The value of scale is written as a ratio.SIMILAR FIGURES The ratio of two corresponding sides in similar fig-ures is called the scale factor.
\nScale factor = \\(\\vec{a}\\)
\n![\"MCQ](\"https:\/\/i0.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-9.png?resize=237%2C168&ssl=1\")
\nIf one shape can become another using Resizing then the shapes are Similar.
\n![\"MCQ](\"https:\/\/i0.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-10.png?resize=370%2C362&ssl=1\")
\nHence, two shapes aaaarae Similar when one can become the other after a reisze, flip, slide or turn.<\/p>\nA model of a boat is made on the scale of 1 : 4. The model is 120 cm long. The full size of the boat has a width of 60 cm. What is the width of the scale model ?
\n![\"MCQ](\"https:\/\/i1.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-11.png?resize=373%2C134&ssl=1\")
<\/h2>\n
\n(B) 25 cm
\n(C) 15 cm
\n(D) 240 cm
\nAnswer:
\n(C) 15 cm<\/p>\n
\nWidth of the scale model = 60\/4 = 15 cm.<\/p>\nWhat will effect the similarity of any two polygons ?<\/h2>\n
\n(B) They are dilated by a scale factor
\n(C) They are translated down
\n(D) They are not the mirror image of on another.
\nAnswer:
\n(D) They are not the mirror image of on another.<\/p>\n
\nThey are not the mirror image of one another.<\/p>\nIf two similar triangles have a scale factor of a : b, which statement regarding the two triangles is true ?<\/h2>\n
\n(B) Their altitudes have a ratio a : b
\n(C) Their medians have a ratio \\(\\frac{a}{2}\\): b
\n(D) Their angle bisectors have a ratio a2<\/sup> : b2<\/sup>
\nAnswer:
\n(B) Their altitudes have a ratio a : b<\/p>\n
\nLet ABC and PQR be two simliar triangles and AD,PE are two altitudes:
\n\\(\\frac{A B}{P Q}\\) = \\(\\frac{B C}{Q R}\\) = \\(\\frac{A C}{P R}\\)
\n(corresponding sides)
\n![\"MCQ](\"https:\/\/i0.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-12.png?resize=299%2C138&ssl=1\")
\n\u2220B = \u2220Q and \u2220ADB = \u2220PEQ (each 90\u00b0)
\nNow, \\(\\frac{A D}{P E}\\) = \\(\\frac{A B}{P Q}\\) = \\(\\frac{a}{b}\\)<\/p>\n<\/p>\nThe shadow of a stick 5 m long is 2 m. At the same time the shadow of a tree 12.5 m high is<\/h2>\n
![\"MCQ](\"https:\/\/i0.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-13.png?resize=289%2C170&ssl=1\")
\n(A) 3 m
\n(B) 3.5 m
\n(C) 4. 5 m
\n(D) 5 m
\nAnswer:
\n(D) 5 m
\nExplanation:
\nLet shadow of the tree be x. By the property to similar triangles we have \\(\\frac{5}{2}\\) = \\(\\frac{12.5}{x}\\)
\nx = \\(\\frac{(12.5 \\times 2)}{5}\\) = 5 m<\/p>\nBelow you see a student’s mathematical model of a farmhouse roof with measurements. The attic floor, ABCD in the model, is a square. The beams that support the roof are the edge of a rectangular prism, EFGHKLMN. E is the middle of AT, F is the middle of BT, G is the middle of CT, and H is the middle of DT. All the edges of the pyramid in the model have length of 12 m.
\n![\"MCQ](\"https:\/\/i0.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-14.png?resize=228%2C183&ssl=1\")
\n![\"MCQ](\"https:\/\/i1.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-15.png?resize=281%2C198&ssl=1\")
\nWhat is the length of EF, where EF is one of the horizontal edges of the block ?<\/h2>\n
\n(B) 3 m
\n(C) 6 m
\n(D) 10 m
\nAnswer:
\n(C) 6 m<\/p>\n
\nLength of the horizontal edge EF = half of the edge of pyramid =\\(\\vec{a}\\) = 6 cm (as E is he mid-point of AT)<\/p>\n
\nSeema placed a light bulb at point O on the ceiling and directly below it placed a table. Now, she put a cardboard of shape ABCD between table and lighted bulb. Then a shadow of ABCD is casted on the table as A’B’C’D’ (see figure). Quadrilateral A’B’C’D’ in an enlargement of ABCD with scale factor 1 : 2, Also, AB = 1.5 cm, BC = 25 cm, CD = 2.4 cm and AD = 2.1 cm; \u2220A = 105\u00b0, \u2220B = 100\u00b0, \u2220C = 70\u00b0 and \u2220D = 85\u00b0.
\n![\"MCQ](\"https:\/\/i0.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-16.png?resize=291%2C307&ssl=1\")
<\/p>\nWhat is the measurement of angle A?<\/h2>\n
\n(B) 100\u00b0
\n(C) 70\u00b0
\n(D) 80\u00b0
\nAnswer:
\n(A) 105\u00b0<\/p>\n
\nQuadrilateral A’B’C’D’ is similar to ABCD.
\n\u2234\u2220A = \u2220A
\n\u21d2\u2220A = 105\u00b0<\/p>\nWhat is the length of A’B’ ?<\/h2>\n
\n(B) 3 cm
\n(C) 5 cm
\n(D) 2.5 cm
\nAnswer:
\n(B) 3 cm<\/p>\n
\nGiven scale factor is 1 : 2
\n\u2234 A’B’ = 2AB
\n\u21d2 A’B’ = 2 x 1.5 = 3 cm<\/p>\nWhat is the sum of angles of quadrilateral A’B’C’D’ ?<\/h2>\n
\n(B) 360\u00b0
\n(C) 270\u00b0
\n(D) None of these
\nAnswer:
\n(B) 360\u00b0<\/p>\n
\nSum of the angles of quadrilateral A’B’C\u2019D’ is 360\u00b0<\/p>\n<\/p>\nWhat is the ratio of sides A’B’ and A’D’ ?<\/h2>\n
\n(B) 7 : 5
\n(C) 1 : 1
\n(D) 1 : 2
\nAnswer:
\n(A) 5 : 7<\/p>\n
\nA’B\u2019 = 3 cm
\nand A’D’ = 2AD
\n= 2 x 2.1 = 4.2 cm
\n\\(\\frac{A^{\\prime} B^{\\prime}}{A^{\\prime} D^{\\prime}}\\) = \\(\\frac{3}{4.2}\\) = \\(\\frac{30}{42}\\)
\n= \\(\\frac{5}{7}\\) or 5 : 7<\/p>\nWhat is the sum of angles C’ and D’ ?<\/h2>\n
\n(B) 100\u00b0
\n(C) 155\u00b0
\n(D) 140\u00b0
\nAnswer:
\n(C) 155\u00b0<\/p>\n
\n\u2220C = \u2220C = 70\u00b0
\nand \u2220D’ = \u2220D = 85\u00b0
\n\u2234\u2220C’ + \u2220D\u2019 = 70\u00b0 + 85\u00b0 = 155\u00b0<\/p>\n
\n![\"MCQ](\"https:\/\/i1.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-17-1.png?resize=391%2C148&ssl=1\")
<\/p>\nWhat is the height of the tower?<\/h2>\n
\n(B) 50 m
\n(C) 100 m
\n(D) 200 m
\nAnswer:
\n(C) 100 m<\/p>\n
\nWhen two corresponding angles of two triangles are simliar, then ratio of sides are equal
\n\\(\\frac{\\text { Height of Vjay\u2019s house }}{\\text { Length of Shadow }}\\)
\n= \\(\\frac{\\text { Height of tower }}{\\text { Length of Shadow }}\\)
\n\\(\\frac{20 \\mathrm{~m}}{10 \\mathrm{~m}}\\) = \\(\\frac{\\text { Height of tower }}{\\text { 50 m }}\\)
\nHeight of tower = \\(\\frac{20 \\times 50}{10}
\n\\) = \\(\\frac{1000}{10}
\n\\) = 100 m<\/p>\nWhat will be the length of the shadow of the tower when Vijay’s house casts a shadow of 12 m?<\/h2>\n
\n(B) 50 m
\n(C) 45 m
\n(D) 60 m
\nAnswer:
\n(D) 60 m<\/p>\nWhat is the height of Ajay’s house?<\/h2>\n
\n(B) 40 m
\n(C) 50 m
\n(D) 20 m
\nAnswer:
\n(B) 40 m<\/p>\n
\n=\\(\\frac{\\text { Height of Aijay’s house}}{\\text { Length of shadow }}\\)
\n\\(\\frac{20 \\mathrm{~m}}{10 \\mathrm{~m}}\\) = \\([latex]\\frac{\\text { Height of Aijay’s house}}{\\text { 20 m }}\\)
\nHeight of Ajay’s house = \\(\\frac{20 \\mathrm{~m} \\times 20 \\mathrm{~m}}{10 \\mathrm{~m}}
\n\\)
\n= 40 m.<\/p>\nWhen the tower casts a shadow of 40 m, same time what will be the length of the shadow of Ajay’s house?<\/h2>\n
\n(B) 32 m
\n(C) 20 m
\n(D) 8 m
\nAns.
\n(A) 16 m<\/p>\nWhen the tower casts a shadow of 40 m, same time what will be the length of the shadow of Vijay’s house?<\/h2>\n
\n(B) 32 m
\n(C) 16 m
\n(D) 8 m
\nAnswer:
\n(D) 8 m<\/p>\n
\nRohan wants to measure the distance of a pond during the visit to his native. He marks points A and B on the opposite edges of a pond as shown in the figure below. To find the distance between the points, he makes a right-angled triangle using rope connecting B with another point C are a distance of 12 m, connecting C to point D at a distance of 40 m from point C and the connecting D to the point A which is are a distance of 30 m from D such the \u2220ADC = 90\u00b0<\/p>\n![\"MCQ](\"https:\/\/i1.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-18.png?resize=374%2C152&ssl=1\")
\nQuestion 1.<\/p>\nWhich property of geometry will be used to find the distance AC?<\/h2>\n
\n(B) Thales Theorem
\n(C) Pythagoras Theorem
\n(D) Area of similar triangles
\nAnswer:
\n(C) Pythagoras Theorem<\/p>\nWhat is the distance AC?<\/h2>\n
\n(B) 12 m
\n(C) 100 m
\n(D) 70 m
\nAnswer:
\n(A) 50 m<\/p>\n
\nAccording to the pythagoras.
\nAC2<\/sup> = AD2<\/sup>+ CD2<\/sup>
\nAC2<\/sup> = (30 m)2<\/sup> + (40 m)2<\/sup>
\nAC2<\/sup> = 900 + 1600
\nAC2<\/sup> = 2500
\nAC = 50 m<\/p>\nWhich is the following does not form a Pythagoras triplet?<\/h2>\n
\n(B) (15,8,17)
\n(C) (5,12,13)
\n(D) (21,20,28)
\nAnswer:
\n(D) (21,20,28)<\/p>\nFind the length AB?<\/h2>\n
\n(B) 38 m
\n(C) 50 m
\n(D) 100m
\nAnswer:
\n(B) 38 m<\/p>\nFind the length of the rope used.<\/h2>\n
\n(B) 70 m
\n(C) 82 m
\n(D) 22 m
\nAns.
\n(C) 82 m<\/p>\n
\nLength of Rope = BC + CD+DA
\n= 12 m + 40 m + 30 m
\n= 82 m<\/p>\n
\n![\"MCQ](\"https:\/\/i1.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-19.png?resize=397%2C163&ssl=1\")
\nIf one shape can become another using revising, then the shapes are similar. Hence, two shapes are similar when one can become the other after a resize, flip, slide or turn. In the photograph below showing the side view of a train engine. Scale factor is 1:200 This means that a length of 1 cm on the photograph above corresponds to a length of 200 cm or 2 m, of the actual engine. The scale can also be written as the ratio of two lengths.<\/p>\n<\/p>\nIf the length of the model is 11 cm, then the overall length of the engine in the photograph above, including the couplings(mechanism used to connect) is:<\/h2>\n
\n(B) 220 cm
\n(C) 220 m
\n(D) 22 m
\nAnswer:
\n(A) 22 cm<\/p>\nWhat will affect the similarity of any two polygons?<\/h2>\n
\n(B) They are dilated by a scale factor
\n(C) They are translated down
\n(D) They are not the mirror image of one another.
\nAnswer:
\n(D) They are not the mirror image of one another.<\/p>\nWhat is the actual width of the door if the width of the door in photograph is 0.35 cm?<\/h2>\n
\n(B) 0.7 cm
\n(C) 0.07 cm
\n(D) 0.07 m
\nAnswer:
\n(A) 0.7 m<\/p>\nIf two similar triangles have a scale factor 5:3 which statement regarding the two triangles is true?<\/h2>\n
\n(B) Their altitudes have a ratio 25:15
\n(C) Their medians have a ratio 10:4
\n(D) Their angle bisectors have a ratio 11:5
\nAnswer:
\n(B) Their altitudes have a ratio 25:15<\/p>\n<\/p>\nThe length of AB in the given figure: A<\/h2>\n
![\"MCQ](\"https:\/\/i1.wp.com\/mcq-questions.com\/wp-content\/uploads\/2022\/02\/MCQ-Questions-for-Class-10-Maths-Chapter-6-Triangles-20.png?resize=346%2C209&ssl=1\")
\n(A) 8 cm
\n(B) 6 cm
\n(C) 4 cm
\n(D) 10 cm
\nAnswer:
\n(C) 4 cm
\nExplanation:
\nSince AABC and AADE are similar, then their ratio of corresponding sides are equal
\n\\(\\frac{A B}{B C}\\) = \\(\\frac{A B+B D}{D E}\\)
\n\\(\\frac{x}{3 \\mathrm{~cm}}\\) = \\(\\frac{(x+4) \\mathrm{cm}}{6 \\mathrm{~cm}}\\)
\n6x = 3(x + 4)
\n6x = 3x + 12
\n6x – 3x = 12
\n3x = 12
\nx = 4
\nAB = 4 cm.<\/p>\nMCQ Questions for Class 10 Maths with Answers<\/a><\/h4>\n","protected":false},"excerpt":{"rendered":"