\u092a\u094d\u0930\u0936\u094d\u0928 \u0938\u0902\u0916\u094d\u092f\u093e 23 \u0938\u0947 30 \u0924\u0915 \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u092a\u094d\u0930\u0936\u094d\u0928 \u0915\u093e 4 \u0905\u0902\u0915 \u0939\u0948\u0964<\/strong><\/p>\nQuestion 23. \n\u0938\u093f\u0926\u094d\u0927 \u0915\u0940\u091c\u093f\u090f \u0915\u093f 3 + 2\u221a5 \u090f\u0915 \u0905\u092a\u0930\u093f\u092e\u0947\u092f \u0938\u0902\u0916\u094d\u092f\u093e \u0939\u0948\u0964<\/p>\n
Question 24. \n\u0938\u092e\u0940\u0915\u0930\u0923 x – y + 1 = 0 \u0924\u0925\u093e 3x + 2y – 12 = 0 \u0915\u093e \u0917\u094d\u0930\u093e\u092b \u0916\u0940\u0902\u091a\u093f\u090f\u0964 \u0907\u0928 \u0930\u0947\u0916\u093e\u0913\u0902 \u0924\u0925\u093e x-\u0905\u0915\u094d\u0937 \u0938\u0947 \u092c\u0928\u0947 \u0924\u094d\u0930\u093f\u092d\u0941\u091c \u0915\u0947 \u0936\u0940\u0930\u094d\u0937 \u0915\u0947 \u0928\u093f\u0930\u094d\u0926\u0947\u0936\u093e\u0902\u0915 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u094b\u0964 \n\u0905\u0925\u0935\u093e \n\u090f\u0915 \u0906\u0926\u092e\u0940 300 km \u0915\u0940 \u0926\u0942\u0930\u0940 \u0915\u0941\u091b \u0930\u0947\u0932\u0917\u093e\u0921\u093c\u0940 \u0926\u094d\u0935\u093e\u0930\u093e \u0924\u0925\u093e \u0915\u0941\u091b \u0915\u093e\u0930 \u0926\u094d\u0935\u093e\u0930\u093e \u0924\u092f \u0915\u0930\u0924\u093e \u0939\u0948\u0964 \u092f\u0926\u093f \u0935\u0939 60 km \u0930\u0947\u0932\u0917\u093e\u0921\u093c\u0940 \u0926\u094d\u0935\u093e\u0930\u093e \u0924\u0925\u093e \u0936\u0947\u0937 \u0915\u093e\u0930 \u0926\u094d\u0935\u093e\u0930\u093e \u092f\u093e\u0924\u094d\u0930\u093e \u0915\u0930\u0924\u093e \u0939\u0948 \u0924\u094b \u0909\u0938\u0947 4 \u0918\u0902\u091f\u0947 \u0932\u0917\u0924\u0947 \u0939\u0948\u0902\u0964 \u092f\u0926\u093f \u0935\u0939 100 km \u0930\u0947\u0932\u0917\u093e\u0921\u093c\u0940 \u0938\u0947 \u0924\u0925\u093e \u0936\u0947\u0937 \u0915\u093e\u0930 \u0938\u0947 \u092f\u093e\u0924\u094d\u0930\u093e \u0915\u0930\u0947, \u0924\u094b \u0909\u0938\u0947 10 \u092e\u093f\u0928\u091f \u0905\u0927\u093f\u0915 \u0932\u0917\u0924\u0947 \u0939\u0948\u0902\u0964 \u0930\u0947\u0932\u0917\u093e\u0921\u093c\u0940 \u090f\u0935\u0902 \u0915\u093e\u0930 \u0915\u0940 \u0915\u094d\u0930\u092e\u0936\u0903 \u091a\u093e\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f\u0964<\/p>\n
Question 25. \n\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0906\u0902\u0915\u0921\u093c\u094b\u0902 \u0915\u093e \u092e\u093e\u0927\u094d\u092f\u0915 525 \u0939\u0948\u0964 x \u0924\u0925\u093e y \u0915\u093e \u092e\u093e\u0928 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u094b \u092f\u0926\u093f \u0938\u092d\u0940 \u092c\u093e\u0930\u092e\u094d\u092c\u093e\u0930\u0924\u093e \u0915\u093e \u092f\u094b\u0917 100 \u0939\u0948\u0964 \n \n\u0905\u0925\u0935\u093e \n\u0926\u093f\u090f \u0917\u090f 100 \u0935\u093f\u0926\u094d\u092f\u093e\u0930\u094d\u0925\u093f\u092f\u094b\u0902 \u0915\u0947 \u0905\u0902\u0915\u094b\u0902 \u0915\u0947 \u0906\u0902\u0915\u0921\u093c\u094b\u0902 \u0938\u0947 ‘\u0938\u0947 \u0915\u092e \u092a\u094d\u0930\u0915\u093e\u0930’ \u0915\u093e \u0924\u094b\u0930\u0923 \u0916\u0940\u0902\u091a\u093f\u090f: \n <\/p>\n
Question 26. \n\u0924\u094d\u0930\u093f\u0915\u094b\u0923\u092e\u093f\u0924\u093f cos 60\u00b0 \u0915\u093e \u092e\u093e\u0928 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947\u0902\u0964 \u0905\u0924: \u0924\u094d\u0930\u093f\u0915\u094b\u0923\u092e\u093f\u0924\u0940 cosec 60\u00b0 \u0915\u093e \u092e\u093e\u0928 \u092d\u0940 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947\u0902\u0964 \n\u0905\u0925\u0935\u093e \n <\/p>\n
Question 27. \n\u0938\u093f\u0926\u094d\u0927 \u0915\u0940\u091c\u093f\u090f \u0915\u093f \u0935\u0943\u0924\u094d\u0924 \u0915\u0947 \u0915\u093f\u0938\u0940 \u092c\u093e\u0939\u094d\u092f \u092c\u093f\u0902\u0926\u0941 \u0938\u0947 \u0935\u0943\u0924\u094d\u0924 \u092a\u0930 \u0916\u0940\u0902\u091a\u0940 \u0917\u0908 \u0938\u094d\u092a\u0930\u094d\u0936 \u0930\u0947\u0916\u093e\u0913\u0902 \u0915\u0940 \u0932\u0902\u092c\u093e\u0907\u092f\u093e\u0901 \u0938\u092e\u093e\u0928 \u0939\u094b\u0924\u0940 \u0939\u0948\u0902\u0964<\/p>\n
Question 28. \n\u090f\u0915 \u0928\u093e\u0935 \u0915\u0940 \u0936\u093e\u0902\u0924 \u091c\u0932 \u092e\u0947\u0902 \u091a\u093e\u0932 15 \u0915\u093f\u092e\u0940\/\u0918\u0902\u091f\u093e \u0939\u0948\u0964 \u092f\u0939 \u0928\u093e\u0935 30 \u0915\u093f\u092e\u0940 \u0927\u093e\u0930\u093e \u0915\u0947 \u0935\u093f\u092a\u0930\u0940\u0924 \u0926\u093f\u0936\u093e \u092e\u0947\u0902 \u091c\u093e\u0915\u0930 \u092a\u0941\u0928\u0903 \u0909\u0938\u0940 \u091c\u0917\u0939 4 \u0918\u0902\u091f\u0947 30 \u092e\u093f\u0928\u091f \u092e\u0947\u0902 \u0935\u093e\u092a\u0938 \u0932\u094c\u091f \u0906\u0924\u0940 \u0939\u0948\u0964 \u0927\u093e\u0930\u093e \u0915\u0940 \u091a\u093e\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f\u0964<\/p>\n
Question 29. \n\u090f\u0915 \u091d\u0940\u0932 \u0915\u0947 \u092a\u093e\u0928\u0940 \u0915\u0940 \u0938\u0924\u0939 \u0938\u0947 60 \u092e\u0940 \u090a\u0902\u091a\u093e\u0908 \u092a\u0930 \u0938\u094d\u0925\u093f\u0924 \u090f\u0915 \u092c\u093f\u0902\u0926\u0941 \u0938\u0947, \u092c\u093e\u0926\u0932 \u0915\u093e \u0909\u0928\u094d\u0928\u092f\u0928 \u0915\u094b\u0923 30\u00b0 \u0939\u0948, \u0924\u0925\u093e \u091d\u0940\u0932 \u0915\u0947 \u092a\u093e\u0928\u0940 \u092e\u0947\u0902 \u092c\u093e\u0926\u0932 \u0915\u0940 \u092a\u0930\u091b\u093e\u0908 \u0915\u093e \u0905\u0935\u0928\u092e\u0928 \u0915\u094b\u0923 60\u00b0 \u0939\u0948\u0964 \u092c\u093e\u0926\u0932 \u0915\u0940 \u091d\u0940\u0932\u0947 \u0915\u0947 \u092a\u093e\u0928\u0940 \u0915\u0940 \u0938\u0924\u0939 \u0938\u0947 \u090a\u0901\u091a\u093e\u0908 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f\u0964<\/p>\n
Question 30. \n\u0926\u0940 \u0917\u0908 \u0906\u0915\u0943\u0924\u093f \u092e\u0947\u0902, \u0926\u093f\u090f \u0917\u090f \u0935\u0930\u094d\u0917 \u0915\u0940 \u092d\u0941\u091c\u093e 28 \u0938\u0947\u092e\u0940 \u0939\u0948 \u0924\u0925\u093e \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u0935\u0943\u0924\u094d\u0924 \u0915\u0940 \u0924\u094d\u0930\u093f\u091c\u094d\u092f\u093e \u0935\u0930\u094d\u0917 \u0915\u0940 \u092d\u0941\u091c\u093e \u0915\u0940 \u0906\u0927\u0940 \u0939\u0948 \u091c\u092c\u0915\u093f O \u0924\u0925\u093e O’ \u0935\u0943\u0924\u094d\u0924\u094b\u0902 \u0915\u0947 \u0915\u0947\u0928\u094d\u0926\u094d\u0930 \u0939\u0948\u0902\u0964 \u091b\u093e\u092f\u093e\u0902\u0915\u093f\u0924 \u092d\u093e\u0917 \u0915\u093e \u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f\u0964 \n <\/p>\n
SOLUTIONS<\/strong><\/p>\nSolution 1. \n <\/p>\n
Solution 2. \n \n <\/p>\n
Solution 3. \ntan \u03b1 = \u221a3 = tan 60\u00b0; tan \u03b2 = \\(\\frac { 1 }{ \\surd 3 }\\) = tan 30\u00b0 \n\u03b1 = 60\u00b0 \u0914\u0930 \u03b2 = 30\u00b0 \n\u0905\u0924: cot (\u03b1 + \u03b2) = cot (60\u00b0 + 30\u00b0) = cot 90\u00b0 = 0<\/p>\n
Solution 4. \nsin \u03b8 – cos \u03b8 = 0 \n\u21d2 sin \u03b8 = cos \u03b8 \n\u21d2 \\(\\frac { sin\\theta }{ cos\\theta }\\) = 1 \n\u21d2 tan \u03b8 = 1 \n\u21d2 \u03b8 = 45\u00b0 \n\u0905\u092c sin4<\/sup>\u03b8 + cos4<\/sup>\u03b8 = sin4<\/sup> 45\u00b0 + cos4<\/sup> 45\u00b0 \n <\/p>\nSolution 5. \n\u0905\u0930\u094d\u0927\u0917\u094b\u0932\u0947 \u0915\u093e \u0906\u092f\u0924\u0928 = \u0905\u0930\u094d\u0927\u0917\u094b\u0932\u0947 \u0915\u093e \u092a\u0943\u0966 \u0915\u094d\u0937\u0947\u0966 …[\u0926\u093f\u092f\u093e \u0939\u0948\u0964] \n\\(\\frac { 2 }{ 3 }\\) \u03c0r3<\/sup> = 2\u03c0r2<\/sup> \n\u21d2 \\(\\frac { 1 }{ 3 }\\) r = 1 \n\u21d2 r = 3 \n\u0905\u0930\u094d\u0927\u0917\u094b\u0932\u0947 \u0915\u093e \u0935\u094d\u092f\u093e\u0938 = 2r = 2(3) = 6 cm<\/p>\nSolution 6. \n(-3)2<\/sup> = 9; (-2)2<\/sup> = 4; (-1)2<\/sup> = 1; (0)2<\/sup> = 0; (1)2<\/sup> = 1; (2)2<\/sup> = 4; (3)2<\/sup> = 9 \nP(\u0938\u0902\u0916\u094d\u092f\u093e \u0915\u093e \u0935\u0930\u094d\u0917 1 \u092f\u093e 1 \u0938\u0947 \u0915\u092e) = \\(\\frac { 3 }{ 7 }\\)<\/p>\nSolution 7. \n \n\u2206ADB ~ \u2206CDA …… [\u0938\u092e\u0915\u094b\u0923 \u0924\u094d\u0930\u093f\u092d\u0941\u091c \u092e\u0947\u0902 \u0938\u092e\u0915\u094b\u0923 \u0935\u093e\u0932\u0947 \u0936\u0940\u0930\u094d\u0937 \u0938\u0947 \u0915\u0930\u094d\u0923 \u092a\u0930 \u0921\u093e\u0932\u093e \u0917\u092f\u093e \u0932\u0902\u092c \u092c\u0928\u0947 \u0938\u0902\u092a\u0942\u0930\u094d\u0923 \u2206 \u0915\u094b \u0926\u094b \u092c\u0930\u093e\u092c\u0930 \u0938\u092e\u0930\u0942\u092a \u0924\u094d\u0930\u093f\u092d\u0941\u091c\u094b\u0902 \u092e\u0947\u0902 \u092c\u093e\u0902\u091f\u0924\u093e \u0939\u0948\u0964] \n\\(\\frac { AD }{ CD }\\) = \\(\\frac { BD }{ AD }\\) \n…[\u0938\u092e\u093e\u0928\u0941\u092a\u093e\u0924\u0940 \u092d\u0941\u091c\u093e\u090f\u0902] \nAD2<\/sup> = BD. DC \n\u21d2 AD2<\/sup> = (2) (8) = 16 cm \n\u21d2 AD = 4 cm<\/p>\nSolution 8. \n <\/p>\n
Solution 9. \n <\/p>\n
Solution 10. \n <\/p>\n
Solution 11. \nx2<\/sup> + k(2x + k – 1) + 2 = 0 \nx2<\/sup> + 2kx + k2<\/sup> – k + 2 = 0 \n\u092f\u0939\u093e\u0901 a = 1, b = 2k, c = k2<\/sup> – k + 2 \nD = 0 …(\u0935\u093e\u0938\u094d\u0924\u0935\u093f\u0915 \u0935 \u0938\u092e\u093e\u0928 \u092e\u0942\u0932] \n\u21d2 b2<\/sup> – 4ac = 0 \n\u21d2 (2k)2<\/sup> – 4 x 1(k2<\/sup> – k + 2) = 0 \n\u21d2 4k2<\/sup> – 4(k2<\/sup> – k + 2) = 0 \n\u21d2 4(k2<\/sup> – 2 + k – 2) = 0 \n\u21d2 4(k – 2) = 0 \n\u21d2 k – 2 = 0 \n\u21d2 k = 2<\/p>\nSolution 12. \n \nPA = PB = 12 cm …(i) \nQC = AC = 3 cm …(ii) \nQD = BD = 3 cm …(iii) \n\u0935\u0943\u0924\u094d\u0924 \u0915\u0947 \u092c\u093e\u0939\u094d\u092f \u092c\u093f\u0902\u0926\u0941 \u0938\u0947 \u0916\u0940\u0902\u091a\u0940 \u0917\u0908 \u0938\u094d\u092a\u0930\u094d\u0936 \u0930\u0947\u0916\u093e\u0913\u0902 \u0915\u0940 \u0932\u0902\u092c\u093e\u0908 \u0938\u092e\u093e\u0928 \u0939\u094b\u0924\u0940 \u0939\u0948\u0902\u0964 \n\u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0928\u093e \u0939\u0948: \nPC + PD = (PA – AC) + (PB – BD) = (12 – 3) + (12 – 3) …[(i), (ii) \u0924\u0925\u093e (iii) \u0938\u0947] \n= 9 + 9 = 18 cm<\/p>\n
Solution 13. \n \n <\/p>\n
Solution 14. \n <\/p>\n
Solution 15. \n \n <\/p>\n
Solution 16. \n \n <\/p>\n
Solution 17. \n <\/p>\n
Solution 18. \n \n <\/p>\n
Solution 19. \n <\/p>\n
Solution 20. \n \n\u0926\u093f\u092f\u093e \u0939\u0948 : \u090f\u0915 \u0915\u0947\u0928\u094d\u0926\u094d\u0930 O \u0935\u093e\u0932\u093e \u0935\u0943\u0924\u094d\u0924 \u0926\u093f\u092f\u093e \u0917\u092f\u093e \u0939\u0948\u0964 \u091c\u093f\u0938\u0938\u0947 \u092c\u093e\u0939\u094d\u092f \u092c\u093f\u0902\u0926\u0941 T \u0924\u0925\u093e \u0926\u094b \u0938\u094d\u092a\u0930\u094d\u0936 \u0930\u0947\u0916\u093e\u090f\u0901 TP \u0924\u0925\u093e TQ \u0916\u0940\u0902\u091a\u0940 \u0917\u0908 \u0939\u0948\u0902, \u091c\u0939\u093e\u0901 P \u0924\u0925\u093e Q \u0938\u094d\u092a\u0930\u094d\u0936 \u092c\u093f\u0902\u0926\u0941 \u0939\u0948\u0902\u0964 \n\u0938\u093f\u0926\u094d\u0927 \u0915\u0930\u0928\u093e \u0939\u0948 : \n\u2220PTQ = 2\u2220OPQ \n\u092e\u093e\u0928\u093e \u2220PTQ = \u03b8 \n\u0905\u092c, TP = TQ [\u0935\u0943\u0924\u094d\u0924 \u0915\u0947 \u092c\u093e\u0939\u094d\u092f \u092c\u093f\u0902\u0926\u0941 \u0938\u0947 \u0916\u0940\u0902\u091a\u0940 \u0917\u0908 \u0938\u094d\u092a\u0930\u094d\u0936 \u0930\u0947\u0916\u093e\u0913\u0902 \u0915\u0940 \u0932\u0902\u092c\u093e\u0908 \u0938\u092e\u093e\u0928 \u0939\u094b\u0924\u0940 \u0939\u0948\u0902\u0964] \n\u0905\u0924\u0903, TPQ \u090f\u0915 \u0938\u092e\u0926\u094d\u0935\u093f\u092c\u093e\u0939\u0941 \u0394 \u0939\u0948\u0964 \n\u2220TPQ = \u2220TQP = \\(\\frac { 1 }{ 2 }\\) (180\u00b0 – \u03b8) = 90\u00b0 – \\(\\frac { 1 }{ 2 }\\) \u03b8 \n\u2220OPT = 90\u00b0 [\u0935\u0943\u0924\u094d\u0924 \u0915\u0940 \u0938\u094d\u092a\u0930\u094d\u0936 \u0930\u0947\u0916\u093e, \u0938\u094d\u092a\u0930\u094d\u0936 \u092c\u093f\u0902\u0926\u0941 \u0938\u0947 \u091c\u093e\u0928\u0947 \u0935\u093e\u0932\u0940 \u0924\u094d\u0930\u093f\u091c\u094d\u092f\u093e \u092a\u0930 \u0932\u0902\u092c \u0939\u094b\u0924\u0940 \u0939\u0948\u0964] \n\u0905\u0924: \u2220OPQ = \u2220OPT – \u2220TPQ = 90\u00b0 – (90\u00b0 – \\(\\frac { 1 }{ 2 }\\) \u03b8) …[(1) \u0938\u0947] \n\u2220OPQ = \\(\\frac { 1 }{ 2 }\\) \u03b8 \n\u2220OPQ = \\(\\frac { 1 }{ 2 }\\) \u2220PTQ \n\u2220PTQ = 2\u2220OPQ …(\u0907\u0924\u093f \u0938\u093f\u0926\u094d\u0927\u092e\u094d)<\/p>\n
Solution 21. \n <\/p>\n
Solution 22. \n \n <\/p>\n
Solution 23. \n <\/p>\n
Solution 24. \n \n \n <\/p>\n
Solution 25. \n \n \n <\/p>\n
Solution 26. \n \n \n \n <\/p>\n
Solution 27. \n \n\u0926\u093f\u092f\u093e \u0939\u0948: PT \u0924\u0925\u093e PS \u0935\u0943\u0924\u094d\u0924 \u0915\u0947 \u092c\u093e\u0939\u094d\u092f \u092c\u093f\u0902\u0926\u0941 P \u0938\u0947 \u0916\u0940\u0902\u091a\u0940 \u0917\u0908 \u0938\u094d\u092a\u0930\u094d\u0936 \u0930\u0947\u0916\u093e\u090f\u0901\u0964 \n\u0938\u093f\u0926\u094d\u0927 \u0915\u0930\u0928\u093e \u0939\u0948: PT = PS \n\u0930\u091a\u0928\u093e : O \u0938\u0947 P, T \u0924\u0925\u093e S \u0915\u094b \u092e\u093f\u0932\u093e\u092f\u093e\u0964 \n\u0909\u092a\u092a\u0924\u094d\u0924\u093f : \u0394OTP \u0924\u0925\u093e \u0394OSP \u092e\u0947\u0902 \nOT = OS …[\u0935\u0943\u0924\u094d\u0924 \u0915\u0940 \u0924\u094d\u0930\u093f\u091c\u094d\u092f\u093e\u090f\u0901] \nOP = OP …[\u0909\u092d\u092f\u0928\u093f\u0937\u094d\u0920] \n\u2220OTP = \u2220OSP ..[\u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 90\u00b0] \n\u0394OTP = \u0394OSP …[R.H.S.] \nPT = PS…[\u0938\u0930\u094d\u0935\u093e\u0902\u0917\u0938\u092e \u0394 \u0915\u0947 \u0938\u0902\u0917\u0924 \u0915\u094b\u0923 \u092c\u0930\u093e\u092c\u0930 \u0939\u094b\u0924\u0947 \u0939\u0948\u0964]<\/p>\n
Solution 28. \n\u092e\u093e\u0928\u093e \u0927\u093e\u0930\u093e \u0915\u0940 \u091a\u093e\u0932 = x km\/hr \n\u0928\u093e\u0935 \u0915\u0940 \u0938\u094d\u0925\u093f\u0930 \u091c\u0932 \u092e\u0947\u0902 \u091a\u093e\u0932 = 15 km\/hr \n\u0924\u092c, \u0928\u093e\u0935 \u0915\u0940 \u0927\u093e\u0930\u093e \u0915\u0947 \u092a\u094d\u0930\u0924\u093f\u0915\u0942\u0932 \u091a\u093e\u0932 = (15 – x) km\/hr \n\u0928\u093e\u0935 \u0915\u0940 \u0927\u093e\u0930\u093e \u0915\u0947 \u0905\u0928\u0941\u0915\u0942\u0932 \u091a\u093e\u0932 = (15 + x) km\/hr \n\u092a\u094d\u0930\u0936\u094d\u0928\u093e\u0928\u0941\u0938\u093e\u0930, \n <\/p>\n
Solution 29. \n \n <\/p>\n
Solution 30. \n\u092d\u0941\u091c\u093e = 28 cm, \n\u0924\u094d\u0930\u093f\u091c\u094d\u092f\u093e = \\(\\frac { 28 }{ 2 }\\) cm = 14 cm \n\u091b\u093e\u092f\u093e\u0902\u0915\u093f\u0924 \u092d\u093e\u0917 \u0915\u093e \u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932 = \u0935\u0930\u094d\u0917 \u0915\u093e \u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932 + \\(\\frac { 3 }{ 4 }\\) (\u0935\u0943\u0924\u094d\u0924 \u0915\u093e \u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932) + \\(\\frac { 3 }{ 4 }\\) (\u0935\u0943\u0924\u094d\u0924 \u0915\u093e \u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932) \n= \u0935\u0930\u094d\u0917 \u0915\u093e \u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932 + \\(\\frac { 3 }{ 2 }\\) (\u0935\u0943\u0924\u094d\u0924 \u0915\u093e \u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932) …[\u0935\u0930\u094d\u0917 \u0915\u093e \u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932 = (\u092d\u0941\u091c\u093e)2<\/sup>; \u0935\u0943\u0924\u094d\u0924 \u0915\u093e \u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932 = \u03c0r\u00b2] \n= (28)2<\/sup> + \\(\\frac { 3 }{ 2 } \\times \\frac { 22 }{ 7 } \\times 14\\times 14\\) \n= 784 + 924 \n= 1708 cm2<\/sup><\/p>\nWe hope the CBSE Sample Papers for Class 10 Maths in Hindi Medium Paper 2 help you. If you have any query regarding CBSE Sample Papers for Class 10 Maths in Hindi Medium Paper 2, drop a comment below and we will get back to you at the earliest.<\/p>\n","protected":false},"excerpt":{"rendered":"
CBSE Sample Papers for Class 10 Maths in Hindi Medium Paper 2 are part of CBSE Sample Papers for Class 10 Maths in Hindi Medium. Here we have given CBSE Sample Papers for Class 10 Maths in Hindi Medium Paper 2. CBSE Sample Papers for Class 10 Maths in Hindi Medium Paper 2 Board CBSE …<\/p>\n
CBSE Sample Papers for Class 10 Maths in Hindi Medium Paper 2<\/span> Read More »<\/a><\/p>\n","protected":false},"author":5,"featured_media":7817,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","spay_email":""},"categories":[29],"tags":[],"yoast_head":"\nCBSE Sample Papers for Class 10 Maths in Hindi Medium Paper 2 - MCQ Questions<\/title>\n \n \n \n \n \n \n \n \n \n \n \n \n\t \n\t \n \n \n \n \n\t \n\t \n\t \n