2<\/sup>\u00a0+ bx + c = 0 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0935\u094d\u092f\u0915\u094d\u0924 \u0915\u0930\u0928\u0947 \u092a\u0930<\/p>\na = 1, b = 0 \u0914\u0930 c = 7 \u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0939\u094b\u0924\u093e \u0939\u0948<\/p>\n
\u091a\u0942\u0901\u0915\u093f a\u00a0\u2260 0 \u0939\u0948, \u0905\u0924: \u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948 |<\/p>\n
(ii) x2<\/sup>\u00a0– 2x = (-2) (3 – x)<\/strong><\/p>\n\u0939\u0932 :<\/strong><\/p>\nx2<\/sup>\u00a0– 2x = – 6 + 2x<\/p>\n\u21d2 x2<\/sup>\u00a0– 2x – 2x + 6 = 0<\/p>\n\u21d2 x2<\/sup>\u00a0– 4x + 6 = 0<\/p>\nax2<\/sup>\u00a0+ bx + c = 0 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0935\u094d\u092f\u0915\u094d\u0924 \u0915\u0930\u0928\u0947 \u092a\u0930<\/p>\na = 1, b = – 4\u00a0\u0914\u0930 c = 6\u00a0\u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0939\u094b\u0924\u093e \u0939\u0948<\/p>\n
\u091a\u0942\u0901\u0915\u093f a\u00a0\u2260 0 \u0939\u0948, \u0905\u0924: \u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948 |<\/p>\n
(iii) (x – 2) (x + 1) = ( x – 1) (x + 3)<\/strong><\/p>\n\u0939\u0932 :\u00a0<\/strong>\u00a0(x – 2) (x + 1) = ( x – 1) (x + 3)<\/p>\n\u21d2\u00a0x2<\/sup>\u00a0+ x – 2x -2\u00a0 =\u00a0x2<\/sup>\u00a0+ 3x – x – 3<\/p>\n\u200b\u21d2\u00a0x2<\/sup>\u00a0–\u00a0x2<\/sup>+ x + x – 2x + 3x -2 + 3\u00a0= 0<\/p>\n\u200b\u21d2\u00a02x – x – 1 \u00a0= 0<\/p>\n
ax2<\/sup>\u00a0+ bx + c = 0 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0935\u094d\u092f\u0915\u094d\u0924 \u0928\u0939\u0940\u0902 \u0915\u093f\u092f\u093e \u091c\u093e \u0938\u0915\u0924\u093e\u00a0 \u0939\u0948 |<\/p>\n..<\/sup>.\u00a0\u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u0939\u0940\u0902\u00a0\u0939\u0948 |<\/p>\n(iv) (x – 3) (2x +1) = x( x + 5)<\/strong><\/p>\n\u0939\u0932 :<\/strong>\u00a0(x – 3) (2x +1) = x( x + 5)<\/p>\n\u21d2 2x2\u00a0<\/sup>+ x – 6x – 3= x2\u00a0<\/sup>+\u00a05x<\/p>\n\u21d2 2x2\u00a0<\/sup>– 5x – 3= x2\u00a0<\/sup>+\u00a05x<\/p>\n\u21d2\u00a0\u00a02x2\u00a0<\/sup>–\u00a0x2\u00a0<\/sup>– 5x\u00a0– 5x – 3 \u00a0=\u00a0\u00a0<\/sup>0<\/p>\n\u21d2\u00a0\u00a0x2\u00a0<\/sup>–\u00a010x – 3 \u00a0=\u00a0\u00a0<\/sup>0<\/p>\nax2<\/sup>\u00a0+ bx + c = 0 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0935\u094d\u092f\u0915\u094d\u0924 \u0915\u0930\u0928\u0947 \u092a\u0930<\/p>\na = 1, b = – 10 \u0914\u0930 c = – 3 \u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0939\u094b\u0924\u093e \u0939\u0948<\/p>\n
\u091a\u0942\u0901\u0915\u093f a\u00a0\u2260 0 \u0939\u0948, \u0905\u0924: \u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948 |<\/p>\n
(v) (2x – 1) 2(x – 3 ) = (x + 5) (x – 1)<\/strong><\/p>\n\u0939\u0932 :<\/strong>\u00a0\u00a0(2x – 1) 2(x – 3 ) = (x + 5) (x – 1)<\/p>\n\u21d2\u00a0(2x – 1) (2x – 6 ) = (x + 5) (x – 1)<\/p>\n
\u21d2 4x2\u00a0<\/sup>– 12x – 2x + 6 = x2\u00a0<\/sup>+ 4x – 5<\/p>\n\u21d2 4x2\u00a0<\/sup>– 14x + 6 =\u00a0x2<\/sup>\u00a0– x\u00a0+ 4x – 5<\/p>\n\u21d2 4x2\u00a0<\/sup>–\u00a0x2\u00a0<\/sup>–\u00a014x\u00a0– 4x + 6 + 5 =\u00a00<\/p>\n\u21d2 \u00a03x2\u00a0<\/sup>–\u00a018x + 11\u00a0 =\u00a0\u00a0<\/sup>0<\/p>\nax2<\/sup>\u00a0+ bx + c = 0 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0935\u094d\u092f\u0915\u094d\u0924 \u0915\u0930\u0928\u0947 \u092a\u0930<\/p>\na = 3, b = – 18 \u0914\u0930 c = 11 \u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0939\u094b\u0924\u093e \u0939\u0948<\/p>\n
\u091a\u0942\u0901\u0915\u093f a\u00a0\u2260 0 \u0939\u0948, \u0905\u0924: \u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948 |<\/p>\n
(vi) x2<\/sup>\u00a0+ 3x + 1 = (x – 2)2\u00a0<\/sup><\/strong><\/p>\n\u0939\u0932 :\u00a0<\/strong>x2<\/sup>\u00a0+ 3x + 1 = (x – 2)2<\/sup><\/p>\n\u21d2\u00a0\u00a0<\/strong>x2<\/sup>\u00a0+ 3x + 1\u00a0= x2\u00a0<\/sup>– 2x +4<\/p>\n\u21d2x2\u00a0<\/sup>–\u00a0x2\u00a0<\/sup>+ 4x + 3x + 1 –\u00a04 =\u00a00<\/p>\n\u21d2 7x – 3\u00a0=\u00a0\u00a0<\/sup>0<\/p>\nax2<\/sup>\u00a0+ bx + c = 0 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0935\u094d\u092f\u0915\u094d\u0924 \u0928\u0939\u0940\u0902 \u0915\u093f\u092f\u093e \u091c\u093e \u0938\u0915\u0924\u093e\u00a0 \u0939\u0948 |<\/p>\n..<\/sup>.\u00a0\u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u0939\u0940\u0902\u00a0\u0939\u0948 |<\/p>\n(vii) (x + 2)3<\/sup>\u00a0= 2x(x2<\/sup>\u00a0– 1)\u00a0<\/strong><\/p>\n\u0939\u0932 :<\/strong>(x + 2)3<\/sup>\u00a0= 2x(\u00a0x2\u00a0<\/sup>– 1)<\/p>\n\u21d2 x3\u00a0<\/sup>+ 8 + 6\u00a0<\/sup>+ 12x = 2x3\u00a0<\/sup>– 2x<\/p>\n\u21d2 2x3\u00a0<\/sup>–\u00a0x3<\/sup>\u00a0– 6-12x + 2x \u00a0– 8 = 0<\/p>\n\u21d2 \u00a0x3<\/sup>\u00a0– 6x2\u00a0<\/sup>-10x – 8 =0<\/p>\nax2<\/sup>\u00a0+ bx + c = 0 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0935\u094d\u092f\u0915\u094d\u0924 \u0928\u0939\u0940\u0902 \u0915\u093f\u092f\u093e \u091c\u093e \u0938\u0915\u0924\u093e\u00a0 \u0939\u0948 |<\/p>\n..<\/sup>.\u00a0\u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u0939\u0940\u0902\u00a0\u0939\u0948 |<\/p>\n(viii) x3<\/sup>\u00a0– 4x2<\/sup>\u00a0– x + 1 = (x – 2 )3<\/sup>\u00a0\u00a0<\/strong><\/p>\n\u0939\u0932 :\u00a0<\/strong>x3<\/sup>\u00a0– 4x2<\/sup>\u00a0<\/sup>– x + 1 = (x – 2 )3<\/sup><\/p>\n\u21d2x3<\/sup>\u00a0– 4x2<\/sup>\u00a0<\/sup>– x + 1 \u00a0= x3\u00a0<\/sup>–\u00a08 + 6x2\u00a0<\/sup>+ 12x<\/p>\n\u21d2 x3\u00a0<\/sup>–\u00a0x3<\/sup>\u00a0–\u00a0\u00a0<\/sup>4x2<\/sup>\u00a0<\/sup>+\u00a06x2\u00a0<\/sup>-12x + 1 =\u00a00<\/p>\n\u21d2 \u00a02x2\u00a0<\/sup>-13x\u00a0+ 1\u00a0= 0<\/p>\nax2<\/sup>\u00a0+ bx + c = 0 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0935\u094d\u092f\u0915\u094d\u0924 \u0915\u0930\u0928\u0947 \u092a\u0930<\/p>\na = 2, b = – 13 \u0914\u0930 c = 1 \u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0939\u094b\u0924\u093e \u0939\u0948<\/p>\n
\u091a\u0942\u0901\u0915\u093f a\u00a0\u2260 0 \u0939\u0948, \u0905\u0924: \u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948 |<\/p>\n
Ex 4.1 Class 10 \u0917\u0923\u093f\u0924\u00a0Q2. \u0928\u093f\u092e\u094d\u0928 \u0938\u094d\u0925\u093f\u0924\u093f\u092f\u094b\u0902 \u0915\u094b \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923\u094b\u0902 \u0915\u0947 \u0930\u0942\u092a \u092e\u0947\u0902 \u0928\u093f\u0930\u0941\u092a\u093f\u0924 \u0915\u0940\u091c\u093f\u090f :<\/strong><\/p>\n(i) \u090f\u0915 \u0906\u092f\u0924\u093e\u0915\u093e\u0930 \u092d\u0942\u0916\u0902\u0921 \u0915\u093e \u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932 528 m2\u00a0<\/sup>\u0939\u0948 | \u0915\u094d\u0937\u0947\u0924\u094d\u0930 \u0915\u0940 \u0932\u0902\u092c\u093e\u0908 (\u092e\u0940\u091f\u0930\u094b\u0902 \u092e\u0947\u0902) \u091a\u094c\u095c\u093e\u0908 \u0915\u0947 \u0926\u0941\u0917\u0941\u0928\u0947 \u0938\u0947\u00a0\u090f\u0915 \u0905\u0927\u093f\u0915 \u0939\u0948 | \u0939\u092e\u0947\u0902 \u092d\u0942\u0916\u0902\u0921 \u0915\u0940\u00a0\u0932\u0902\u092c\u093e\u0908 \u0914\u0930 \u091a\u094c\u095c\u093e\u0908\u00a0\u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0928\u0940\u00a0\u0939\u0948 |<\/strong><\/p>\n\u0939\u0932 : \u00a0\u00a0<\/strong>\u090f\u0915\u00a0\u00a0<\/sup>\u0906\u092f\u0924\u093e\u0915\u093e\u0930 \u092d\u0942\u0916\u0902\u0921 \u0915\u093e\u00a0\u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932\u00a0=\u00a0528 m2<\/sup><\/p>\n\u092e\u093e\u0928\u093e\u00a0\u0906\u092f\u0924\u093e\u0915\u093e\u0930 \u092d\u0942\u0916\u0902\u0921 \u0915\u0940\u00a0\u091a\u094c\u095c\u093e\u0908 = x\u00a0m<\/p>\n
\u0906\u092f\u0924\u093e\u0915\u093e\u0930 \u092d\u0942\u0916\u0902\u0921 \u0915\u0940\u00a0\u0932\u0902\u092c\u093e\u0908\u00a0\u00a0=\u00a02x + 1\u00a0m\u00a0<\/sup><\/p>\n\u0906\u092f\u0924\u093e\u0915\u093e\u0930 \u092d\u0942\u0916\u0902\u0921 \u0915\u093e\u00a0\u0915\u094d\u0937\u0947\u0924\u094d\u0930\u092b\u0932\u00a0=\u00a0528 m2<\/sup><\/p>\n\u0932\u0902\u092c\u093e\u0908 x \u091a\u094c\u095c\u093e\u0908 =\u00a0528<\/p>\n
(2x + 1)x =\u00a0528<\/p>\n
2x2<\/sup>\u00a0+ x\u00a0=\u00a0528<\/p>\n2x2<\/sup>\u00a0+ x –\u00a0528\u00a0= 0<\/p>\n2x2<\/sup>\u00a0+ 33x – 32x –\u00a0528\u00a0= 0<\/p>\nx(2x + 33) – 16(2x + 33\u00a0) = 0<\/p>\n
(2x + 33) (x\u00a0– 16) = 0<\/p>\n
2x + 33\u00a0= 0\u00a0\u0924\u0925\u093e\u00a0x\u00a0– 16\u00a0= 0<\/p>\n
2x\u00a0= –\u00a033\u00a0\u0924\u0925\u093e\u00a0x\u00a0=\u00a016<\/div>\n
x\u00a0= –\u00a033\/2\u00a0\u0924\u0925\u093e\u00a0x\u00a0=\u00a016<\/div>\n
<\/div>\n
\u091a\u0942\u0901\u0915\u093f<\/div>\n
\u0906\u092f\u0924\u093e\u0915\u093e\u0930 \u092d\u0942\u0916\u0902\u0921 \u0915\u0940\u00a0\u091a\u094c\u095c\u093e\u0908 =\u00a0X\u00a0m<\/div>\n
\n
\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 =\u00a016\u00a0m<\/p>\n
\u0906\u092f\u0924\u093e\u0915\u093e\u0930 \u092d\u0942\u0916\u0902\u0921 \u0915\u0940\u00a0\u0932\u0902\u092c\u093e\u0908\u00a0\u00a0=\u00a02X+ 1\u00a0m<\/p>\n
=\u00a02\u00a0x\u00a016 + 1\u00a0m<\/p>\n
= 32\u00a0+ 1\u00a0m<\/p>\n
= 33m<\/p>\n<\/div>\n
(ii) \u0926\u094b\u00a0\u0915\u094d\u0930\u092e\u093e\u0917\u0924 \u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u094b\u0902 \u0915\u093e \u0917\u0941\u0923\u0928\u092b\u0932 306 \u0939\u0948 | \u0939\u092e\u0947\u0902 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u094b\u0902 \u0915\u094b \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0928\u093e \u0939\u0948 |<\/strong><\/p>\n\u0939\u0932 :\u00a0<\/strong>\u0926\u094b\u00a0\u0915\u094d\u0930\u092e\u093e\u0917\u0924 \u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u094b\u0902 \u0915\u093e \u0917\u0941\u0923\u0928\u092b\u0932 \u00a0= 306<\/p>\n\u092e\u093e\u0928\u093e \u092a\u0939\u0932\u093e\u00a0\u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u00a0\u00a0= x<\/p>\n
\u0926\u0942\u0938\u0930\u093e\u00a0\u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u00a0 =\u00a0x + 1\u00a0\u00a0<\/sup><\/p>\n\u0926\u094b\u00a0\u0915\u094d\u0930\u092e\u093e\u0917\u0924 \u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u094b\u0902 \u0915\u093e \u0917\u0941\u0923\u0928\u092b\u0932 = 306<\/p>\n
\u092a\u0939\u0932\u093e\u00a0\u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915 x\u00a0\u0926\u0942\u0938\u0930\u093e\u00a0\u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915 = 306<\/p>\n
(x + 1)x \u00a0 \u00a0= 306<\/p>\n
x2<\/sup>\u00a0+ x\u00a0= 306<\/p>\nx2<\/sup>\u00a0+ x – 306\u00a0= 0<\/p>\n2x2<\/sup>\u00a0+ 18x – 17x – 306\u00a0= 0<\/p>\nx(x +\u00a0) – 17(x + 18\u00a0) = 0<\/p>\n
(x +\u00a018) (x\u00a0– 17) = 0<\/p>\n
x + 18\u00a0= 0\u00a0\u0924\u0925\u093e\u00a0x\u00a0– 17\u00a0= 0<\/p>\n
x\u00a0= – 18\u00a0\u0924\u0925\u093e\u00a0x\u00a0=\u00a017<\/div>\n
<\/div>\n
\u091a\u0942\u0901\u0915\u093f<\/div>\n
\u092a\u0939\u0932\u093e\u00a0\u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u00a0= x<\/div>\n
\n
\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0= 17<\/p>\n
\u0926\u0942\u0938\u0930\u093e\u00a0\u0927\u0928\u093e\u0924\u094d\u092e\u0915 \u092a\u0942\u0930\u094d\u0923\u093e\u0915\u00a0\u00a0=\u00a0x + 1<\/p>\n
= 17\u00a0+ 1<\/p>\n<\/div>\n
= 18<\/p>\n
(iii) \u0930\u094b\u0939\u0928 \u0915\u0940 \u092e\u093e\u0901 \u0909\u0938\u0938\u0947 26 \u0935\u0930\u094d\u0937 \u092c\u095c\u0940 \u0939\u0948 |\u0909\u0928\u0915\u0940 \u0906\u092f\u0941 (\u0935\u0930\u094d\u0937\u094b\u0902 \u092e\u0947\u0902) \u0915\u093e \u0917\u0941\u0923\u0928\u092b\u0932 \u0905\u092c \u0938\u0947 \u0924\u0940\u0928 \u0935\u0930\u094d\u0937 \u092a\u0936\u094d\u091a\u093e\u0924\u094d 360 \u0939\u094b \u091c\u093e\u090f\u0917\u0940| \u0939\u092e\u0947\u0902 \u0930\u094b\u0939\u0928 \u0915\u0940 \u0935\u0930\u094d\u0924\u092e\u093e\u0928 \u0906\u092f\u0941 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0923\u0940 \u0939\u0948 |<\/strong><\/p>\n\u0939\u0932 :\u00a0<\/strong>\u092e\u093e\u0928\u093e\u00a0\u0930\u094b\u0939\u0928\u00a0\u0915\u0940 \u0935\u0930\u094d\u0924\u092e\u093e\u0928\u00a0\u0906\u092f\u0941\u00a0\u00a0= x<\/p>\n\u0930\u094b\u0939\u0928 \u0915\u0940 \u092e\u093e\u0901 \u0915\u0940 \u0906\u092f\u0941 \u00a0=\u00a0x + 26<\/p>\n
\u0924\u0940\u0928 \u0935\u0930\u094d\u0937 \u092a\u0936\u094d\u091a\u093e\u0924\u00a0\u0930\u094b\u0939\u0928 \u0915\u0940 \u0906\u092f\u0941\u00a0\u00a0= x + 3<\/p>\n
\u0924\u0940\u0928 \u0935\u0930\u094d\u0937 \u092a\u0936\u094d\u091a\u093e\u0924\u00a0\u0930\u094b\u0939\u0928 \u0915\u0940 \u092e\u093e\u0901 \u0915\u0940 \u0906\u092f\u0941\u00a0\u00a0\u00a0=\u00a0x + 26\u00a0+ 3<\/p>\n
\u00a0<\/sup>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0=\u00a0x + 29<\/p>\n\u0926\u094b\u0928\u094b \u0915\u0940 \u0906\u092f\u0941\u00a0\u0915\u093e \u0917\u0941\u0923\u0928\u092b\u0932 = 306<\/p>\n
(x + 29)(x + 3)\u00a0= 306<\/p>\n
x2<\/sup>\u00a0+ 29x\u00a0+ 3x\u00a0+ 87\u00a0= 306<\/p>\nx2<\/sup>\u00a0+ 32x + 87\u00a0= 306<\/p>\nx2<\/sup>\u00a0+ 32x\u00a0= 273<\/p>\nx2<\/sup>\u00a0+ 32x –\u00a0273\u00a0= 0<\/p>\nx2\u00a0<\/sup>+ 39x – 7x –\u00a0273\u00a0= 0<\/p>\nx2\u00a0<\/sup>+ 39x – 7x –\u00a0273\u00a0=0<\/p>\nx(x + 39) – 7(x + 39) = 0<\/p>\n
(x + 39) (x\u00a0– 7) = 0<\/p>\n
x + 39\u00a0= 0\u00a0\u0924\u0925\u093e\u00a0x\u00a0– 7\u00a0= 0<\/p>\n
x\u00a0= – 39\u00a0\u0924\u0925\u093e\u00a0x\u00a0=\u00a07<\/div>\n
<\/div>\n
\u091a\u0942\u0901\u0915\u093f<\/div>\n
\u0930\u094b\u0939\u0928\u00a0\u0915\u0940 \u0935\u0930\u094d\u0924\u092e\u093e\u0928\u00a0\u0906\u092f\u0941\u00a0\u00a0= 7 \u0935\u0930\u094d\u0937<\/div>\n
\u0930\u094b\u0939\u0928 \u0915\u0940 \u092e\u093e\u0901 \u0915\u0940 \u0906\u092f\u0941 \u00a0=\u00a0\u00a0x + 26<\/div>\n