Solution:<\/strong><\/p>\n\u092a\u094d\u0930\u0925\u092e \u0915\u093f\u0932\u094b\u092e\u0940\u091f\u0930 \u0915\u093e \u0915\u093f\u0930\u093e\u092f\u093e = 15 \u0930\u0941\u092a\u092f\u0947 |<\/p>\n
\u0905\u0924\u093f\u0930\u093f\u0915\u094d\u0924 \u0915\u093f\u0932\u094b\u092e\u0940\u091f\u0930 \u0915\u093e \u0915\u093f\u0930\u093e\u092f\u093e = 8 \u0930\u0941\u092a\u092f\u0947<\/p>\n
\u0936\u094d\u0930\u0943\u0902\u0916\u0932\u093e : 15, 23, 31, 39 …………………………..<\/p>\n
\u091c\u093e\u0901\u091a:<\/p>\n
a = 15<\/p>\n
d1<\/sub>\u00a0= a2<\/sub>\u00a0– a1<\/sub><\/p>\n= 23 – 15 = 8<\/p>\n
d2<\/sub>\u00a0= a3\u00a0<\/sub>– a2<\/sub><\/p>\n= 31 – 23 = 8<\/p>\n
d3<\/sub>\u00a0= a4\u00a0<\/sub>– a3<\/sub><\/p>\n= 39 – 31 = 8<\/p>\n
\u091a\u0942\u0901\u0915\u093f \u0938\u092d\u0940 \u0905\u0902\u0924\u0930\u094b\u0902 \u0915\u093e \u0905\u0902\u0924\u0930 \u0938\u093e\u092e\u093e\u0928 \u0939\u0948 \u0905\u0930\u094d\u0925\u093e\u0924 \u0938\u093e\u0930\u094d\u0935\u0905\u0902\u0924\u0930 = 8 \u0939\u0948 |<\/p>\n
\u0907\u0938\u0932\u093f\u090f \u0926\u093f\u092f\u093e \u0917\u092f\u093e \u0938\u0942\u091a\u0940 A. P \u0939\u0948 |<\/p>\n
(ii) \u0915\u093f\u0938\u0940 \u092c\u0947\u0932\u0928 (cylinder) \u092e\u0947\u0902 \u0909\u092a\u0938\u094d\u0925\u093f\u0924 \u0939\u0935\u093e \u0915\u0940 \u092e\u093e\u0924\u094d\u0930\u093e, \u091c\u092c\u0915\u093f \u0935\u093e\u092f\u0941 \u0928\u093f\u0915\u093e\u0932\u0928\u0947 \u0935\u093e\u0932\u093e \u092a\u092e\u094d\u092a \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u092c\u093e\u0930 \u092c\u0947\u0932\u0928 \u0915\u0940 \u0939\u0935\u093e \u0915\u093e\u00a0<\/strong>\u00bc\u00a0\u092d\u093e\u0917 \u092c\u093e\u0939\u0930 \u0928\u093f\u0915\u093e\u0932 \u0926\u0947\u0924\u093e \u0939\u0948 |<\/strong><\/p>\nSolution:<\/strong><\/p>\n\u092e\u093e\u0928\u093e \u092c\u0947\u0932\u0928 \u092e\u0947\u0902 \u0939\u0935\u093e \u0915\u0940 \u092e\u093e\u0924\u094d\u0930\u093e 1 \u0939\u0948 |<\/p>\n
<\/p>\n
(iii) \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u092e\u0940\u091f\u0930 \u0915\u0940 \u0916\u0941\u0926\u093e\u0908 \u0915\u0947 \u092c\u093e\u0926, \u090f\u0915 \u0915\u0941\u0906\u0902 \u0916\u094b\u0926\u0928\u0947 \u092e\u0947\u0902 \u0906\u0908 \u0932\u093e\u0917\u0924, \u091c\u092c\u0915\u093f \u092a\u094d\u0930\u0925\u092e \u092e\u0940\u091f\u0930 \u0916\u0941\u0926\u093e\u0908 \u0915\u0940 \u0932\u093e\u0917\u0924\u00a0<\/strong>150 \u0930\u0941o\u00a0<\/strong>\u0939\u0948 \u0914\u0930 \u092c\u093e\u0926 \u092e\u0947\u0902 \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u0916\u0941\u0926\u093e\u0908 \u0915\u0940 \u0932\u093e\u0917\u0924\u00a0<\/strong>50 \u0930\u0941o \u092c\u095d\u0924\u0940 \u091c\u093e\u0924\u0940 \u0939\u0948 |<\/strong><\/p>\nSolution:<\/strong><\/p>\n\u092a\u094d\u0930\u0925\u092e \u092e\u0940\u091f\u0930 \u0915\u093e \u0932\u093e\u0917\u0924 = 150,<\/p>\n
\u0926\u0941\u0938\u0930\u0947 \u092e\u0940\u091f\u0930 \u0916\u0941\u0926\u093e\u0908 \u0915\u0940 \u0932\u093e\u0917\u0924 = 150 + 50 = 200<\/p>\n
\u0924\u0940\u0938\u0930\u0947 \u092e\u0940\u091f\u0930 \u0916\u0941\u0926\u093e\u0908 \u0915\u0940 \u0932\u093e\u0917\u0924 = 200 + 50 = 250<\/p>\n
\u0936\u094d\u0930\u0943\u0902\u0916\u0932\u093e : 150, 200, 250, 300 ………………………<\/p>\n
\u091c\u093e\u0901\u091a:<\/p>\n
a = 150<\/p>\n
d1<\/sub>\u00a0= a2<\/sub>\u00a0– a1<\/sub><\/p>\n= 200 – 150 = 50<\/p>\n
d2<\/sub>\u00a0= a3\u00a0<\/sub>– a2<\/sub><\/p>\n= 250 – 200 = 50<\/p>\n
d3<\/sub>\u00a0= a4\u00a0<\/sub>– a3<\/sub><\/p>\n= 300 – 250 = 50<\/p>\n
\u0938\u093e\u0930\u094d\u0935 \u0905\u0902\u0924\u0930 = 50<\/p>\n
\u092f\u0939\u093e\u0901 \u0938\u093e\u0930\u094d\u0935 \u0905\u0902\u0924\u0930 \u0938\u092e\u093e\u0928 \u0939\u0948 \u0907\u0938\u0932\u093f\u090f \u092f\u0939 \u0936\u094d\u0930\u0943\u0902\u0916\u0932\u093e A.P \u0939\u0948 |<\/p>\n
(iv) \u0916\u093e\u0924\u0947 \u092e\u0947\u0902 \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u0935\u0930\u094d\u0937 \u0915\u093e \u092e\u093f\u0936\u094d\u0930\u0927\u0928, \u091c\u092c\u0915\u093f\u00a0<\/strong>10000 \u0930\u0941o \u0915\u0940 \u0930\u093e\u0936\u093f 8 % \u0935\u093e\u0930\u094d\u0937\u093f\u0915 \u0915\u0940 \u0926\u0930 \u0938\u0947 \u091a\u0915\u094d\u0930\u0935\u0943\u0926\u094d\u0927\u093f \u092c\u094d\u092f\u093e\u091c \u092a\u0930 \u091c\u092e\u093e \u0915\u0940 \u091c\u093e\u0924\u0940 \u0939\u0948 |<\/strong><\/p>\nSolution:<\/strong><\/p>\n\u092a\u0939\u0932\u0947 \u0935\u0930\u094d\u0937 \u0915\u0940 \u0930\u093e\u0936\u093f = 10000<\/p>\n
<\/p>\n
\u0924\u0940\u0938\u0930\u0947 \u0935\u0930\u094d\u0937 \u0915\u0940 \u0930\u093e\u0936\u093f = 11664<\/p>\n
\u0936\u094d\u0930\u0943\u0902\u0916\u0932\u093e: 10000, 10800, 11664 …………………<\/p>\n
\u0938\u094d\u092a\u0937\u094d\u091f \u0939\u0948 \u0915\u093f \u0907\u0938 \u0936\u094d\u0930\u0943\u0902\u0916\u0932\u093e \u0915\u093e \u0938\u093e\u0930\u094d\u0935 \u0905\u0902\u0924\u0930 \u0938\u092e\u093e\u0928 \u0928\u0939\u0940\u0902 \u0939\u0948 \u0905\u0924: A.P \u0928\u0939\u0940\u0902 \u0939\u0948 |<\/p>\n
Ex 5.1 Class 10 \u0917\u0923\u093f\u0924\u00a0Q2. \u0926\u0940 \u0939\u0941\u0908 A.P \u0915\u0947 \u092a\u094d\u0930\u0925\u092e \u091a\u093e\u0930 \u092a\u0926 \u0932\u093f\u0916\u093f\u090f, \u091c\u092c\u0915\u093f \u092a\u094d\u0930\u0925\u092e \u092a\u0926 a \u0914\u0930 \u0938\u093e\u0930\u094d\u0935 \u0905\u0902\u0924\u0930 d \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0939\u0948\u0902 :<\/strong><\/p>\n(i) \u00a0a\u00a0<\/em>= 10,\u00a0d\u00a0<\/em>= 10<\/strong><\/p>\nSolution:<\/strong><\/p>\na = 10<\/p>\n
a2<\/sub>\u00a0= a + d\u00a0\u21d2\u00a010 + 10 = 20<\/p>\na3<\/sub>\u00a0= a + 2d\u00a0\u21d2\u00a010 + 2 \u00d7 10 = 30<\/p>\na4<\/sub>\u00a0= a + 3d\u00a0\u21d2\u00a010 + 3 \u00d7 10 = 40<\/p>\n\u0936\u094d\u0930\u0943\u0902\u0916\u0932\u093e:\u00a0<\/strong>10, 20, 30, 40 ………………….<\/p>\n\u092a\u094d\u0930\u0925\u092e \u091a\u093e\u0930 \u092a\u0926\u00a0<\/strong>: 10, 20, 30 \u0914\u0930 40<\/p>\n(ii)\u00a0a\u00a0<\/em>= \u20132,\u00a0d\u00a0<\/em>= 0<\/strong><\/p>\nSolution:<\/strong><\/p>\na = \u20132<\/p>\n
a2<\/sub>\u00a0= a + d\u00a0\u21d2\u00a0\u20132 + 0 = \u20132<\/p>\na3<\/sub>\u00a0= a + 2d\u00a0\u21d2\u00a0\u20132 + 2 \u00d7 0 = \u20132<\/p>\na4<\/sub>\u00a0= a + 3d\u00a0\u21d2\u00a0\u20132 + 3 \u00d7 0 = \u20132<\/p>\n\u0936\u094d\u0930\u0943\u0902\u0916\u0932\u093e:\u00a0<\/strong>\u20132, \u20132, \u20132, \u20132 ………………….<\/p>\n\u092a\u094d\u0930\u0925\u092e \u091a\u093e\u0930 \u092a\u0926\u00a0<\/strong>: \u20132, \u20132, \u20132 \u0914\u0930 \u20132<\/p>\n(iii)\u00a0a\u00a0<\/em>= 4,\u00a0d\u00a0<\/em>= \u2013 3<\/strong><\/p>\nSolution:<\/strong><\/p>\na = 4<\/p>\n
a2<\/sub>\u00a0= a + d\u00a0\u21d2\u00a04 + \u2013 3 = 1<\/p>\na3<\/sub>\u00a0= a + 2d\u00a0\u21d2\u00a04 + 2 \u00d7 \u2013 3 = \u20132<\/p>\na4<\/sub>\u00a0= a + 3d\u00a0\u21d2\u00a04 + 3 \u00d7 \u2013 3 = \u20135<\/p>\n\u0936\u094d\u0930\u0943\u0902\u0916\u0932\u093e:\u00a0<\/strong>4, 1, \u2013 3, \u20135 ………………….<\/p>\n\u092a\u094d\u0930\u0925\u092e \u091a\u093e\u0930 \u092a\u0926\u00a0<\/strong>: 4, 1, \u2013 3 \u0914\u0930 \u20135<\/p>\n<\/p>\n
(v)\u00a0a\u00a0<\/em>= \u2013 1.25,\u00a0d\u00a0<\/em>= \u2013 0.25<\/strong><\/p>\nSolution:<\/strong><\/p>\na = \u2013 1.25<\/p>\n
a2<\/sub>\u00a0= a + d\u00a0\u21d2\u00a0\u2013 1.25 + \u2013 0.25 = – 1.5<\/p>\na3<\/sub>\u00a0= a + 2d\u00a0\u21d2\u00a0\u2013 1.25 + 2 \u00d7 \u2013 0.25 = \u20131.75<\/p>\na4<\/sub>\u00a0= a + 3d\u00a0\u21d2\u00a0\u2013 1.25 + 3 \u00d7 \u2013 0.25 = \u20132<\/p>\n\u0936\u094d\u0930\u0943\u0902\u0916\u0932\u093e:\u00a0<\/strong>\u2013 1.25, – 1.5, \u20131.75, \u20132 ………………….<\/p>\n\u092a\u094d\u0930\u0925\u092e \u091a\u093e\u0930 \u092a\u0926\u00a0<\/strong>: \u2013 1.25, – 1.5, \u20131.75 \u0914\u0930 \u20132<\/p>\nEx 5.1 Class 10 \u0917\u0923\u093f\u0924\u00a0Q4. \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092e\u0947\u0902 \u0938\u0947 \u0915\u094c\u0928-\u0915\u094c\u0928 A.P \u0939\u0948\u0902? \u092f\u0926\u093f \u0915\u094b\u0908 A.P \u0939\u0948, \u0924\u094b \u0907\u0938\u0915\u093e \u0938\u093e\u0930\u094d\u0935 \u0905\u0902\u0924\u0930 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f \u0914\u0930 \u0907\u0928\u0915\u0947 \u0924\u0940\u0928 \u092a\u0926 \u0932\u093f\u0916\u093f\u090f |<\/strong><\/p>\n(i) 3, 1, \u2013 1, \u2013 3, . . .<\/strong><\/p>\nSolution:<\/strong><\/p>\nd1<\/sub>\u00a0= a2<\/sub>\u00a0– a1<\/sub><\/p>\n= 1 – 3 = – 2<\/p>\n
d2<\/sub>\u00a0= a3\u00a0<\/sub>– a2<\/sub><\/p>\n= -1 – (1) = – 2<\/p>\n
d3<\/sub>\u00a0= a4\u00a0<\/sub>– a3<\/sub><\/p>\n= -3 – (-1) = -3 + 1 = – 2<\/p>\n
\u0938\u093e\u0930\u094d\u0935 \u0905\u0902\u0924\u0930 = – 2<\/p>\n
\u091a\u0942\u0901\u0915\u093f \u0938\u093e\u0930\u094d\u0935 \u0905\u0902\u0924\u0930 \u0938\u092e\u093e\u0928 \u0939\u0948 \u0907\u0938\u0932\u093f\u090f \u092f\u0939 A.P \u0939\u0948 |<\/p>\n
\u0907\u0928\u0915\u0947 \u0905\u0917\u0932\u0947 \u0924\u0940\u0928 \u092a\u0926 \u0939\u0948\u0902 :<\/p>\n
a5<\/sub>\u00a0= a + 4d = 3 + 4\u00d7(- 2) = 3 – 8 = – 5<\/p>\na6<\/sub>\u00a0= a + 4d = 3 + 5\u00d7(- 2) = 3 – 10 = – 7<\/p>\na7<\/sub>\u00a0= a + 4d = 3 + 6\u00d7(- 2) = 3 – 12 = – 9<\/p>\n– 5, – 7, – 9<\/p>\n
<\/p>\n
(iii) \u2013 1.2, \u2013 3.2, \u2013 5.2, \u2013 7.2, . . .<\/strong><\/p>\nSolution:<\/strong><\/p>\na = \u2013 1.2<\/p>\n
d1<\/sub>\u00a0= a2<\/sub>\u00a0– a1<\/sub><\/p>\n= \u20133.2 \u2013 (\u20131.2 )<\/p>\n
= \u2013 3.2 + 1.2 = \u00a0\u2013 2<\/p>\n
d2<\/sub>\u00a0= a3\u00a0<\/sub>– a2<\/sub><\/p>\n= \u20135.2 \u2013 (\u20133.2 )<\/p>\n
= \u2013 5.2 + 3.2 = \u00a0\u2013 2<\/p>\n
d3<\/sub>\u00a0= a4\u00a0<\/sub>– a3<\/sub><\/p>\n= \u20137.2 \u2013 (\u20135.2 )<\/p>\n
= \u2013 7.2 + 5.2 = \u00a0\u2013 2<\/p>\n
\u0938\u093e\u0930\u094d\u0935 \u0905\u0902\u0924\u0930 = \u2013 2<\/p>\n
\u091a\u0942\u0901\u0915\u093f \u0938\u093e\u0930\u094d\u0935 \u0905\u0902\u0924\u0930 \u0938\u092e\u093e\u0928 \u0939\u0948 \u0907\u0938\u0932\u093f\u090f \u092f\u0939 A.P \u0939\u0948 |<\/p>\n
\u0907\u0928\u0915\u0947 \u0905\u0917\u0932\u0947 \u0924\u0940\u0928 \u092a\u0926 \u0939\u0948\u0902 :<\/p>\n
a5<\/sub>\u00a0= a + 4d = \u2013 1.2 \u00a0+ 4\u00d7(- 2) = \u2013 1.2 – 8 = \u2013 9.2<\/p>\na6<\/sub>\u00a0= a + 4d = \u2013 1.2 \u00a0+ 5\u00d7(- 2) = \u2013 1.2 \u00a0– 10 = \u00a0\u2013 11.2<\/p>\na7<\/sub>\u00a0= a + 4d = \u2013 1.2 \u00a0+ 6\u00d7(- 2) = \u2013 1.2 \u00a0– 12 = \u2013 13.2<\/p>\n\u21d2\u00a0\u2013 9.2, \u2013 11.2, \u2013 13.2<\/p>\n
(iv) \u2013 10, \u2013 6, \u2013 2, \u00a02, . . .<\/strong><\/p>\nSolution:<\/strong><\/p>\na = \u2013 10<\/p>\n
d1<\/sub>\u00a0= a2<\/sub>\u00a0– a1<\/sub><\/p>\n= \u20136 \u2013 (\u201310 )<\/p>\n
= \u2013 6 + 10 = \u00a04<\/p>\n
d2<\/sub>\u00a0= a3\u00a0<\/sub>– a2<\/sub><\/p>\n= \u20132 \u2013 (\u20136 )<\/p>\n
= \u2013 2 + 6 = \u00a04<\/p>\n
d3<\/sub>\u00a0= a4\u00a0<\/sub>– a3<\/sub><\/p>\n= 2 \u2013 (\u20132 )<\/p>\n
= 2 + 2 = \u00a04<\/p>\n
\u0938\u093e\u0930\u094d\u0935 \u0905\u0902\u0924\u0930 = 4<\/p>\n
\u091a\u0942\u0901\u0915\u093f \u0938\u093e\u0930\u094d\u0935 \u0905\u0902\u0924\u0930 \u0938\u092e\u093e\u0928 \u0939\u0948 \u0907\u0938\u0932\u093f\u090f \u092f\u0939 A.P \u0939\u0948 |<\/p>\n
\u0907\u0928\u0915\u0947 \u0905\u0917\u0932\u0947 \u0924\u0940\u0928 \u092a\u0926 \u0939\u0948\u0902 :<\/p>\n
a5<\/sub>\u00a0= a + 4d = \u2013 10 + 4\u00d7(4) = \u2013 10 + 16 = 6<\/p>\na6<\/sub>\u00a0= a + 4d = \u2013 10 + 5\u00d7(4) = \u2013 10 + 20 = \u00a010<\/p>\na7<\/sub>\u00a0= a + 4d = \u2013 10 + 6\u00d7(4) = \u2013 10 + 24 = 14<\/p>\n\u21d2\u00a06, 10, 14<\/p>\n<\/div>\n
<\/a>\u092a\u094d\u0930\u0936\u094d\u0928\u093e\u0935\u0932\u0940 5.2<\/strong><\/span><\/p>\n\u0915\u0915\u094d\u0937\u093e – 10 (NCERT Solution)<\/strong><\/p>\nEx 5.2 Class 10 \u0917\u0923\u093f\u0924 Q1. \u00a0\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u093e\u0930\u0923\u0940 \u092e\u0947\u0902, \u0930\u093f\u0915\u094d\u0924 \u0938\u094d\u0925\u093e\u0928\u094b\u0902 \u0915\u094b \u092d\u0930\u093f\u090f, \u091c\u0939\u093e\u0901 A.P \u0915\u093e \u092a\u094d\u0930\u0925\u092e \u092a\u0926 a, \u0938\u093e\u0930\u094d\u0935 \u0905\u0902\u0924\u0930 d \u0914\u0930 n\u0935\u093e\u0901 \u092a\u0926 an<\/sub>\u00a0\u0939\u0948:\u00a0<\/strong><\/p>\n<\/p>\n
Solution:<\/strong><\/p>\n(i) a = 7, d = 3, n = 8 an<\/sub>\u00a0= ?<\/p>\nan<\/sub>\u00a0= a + (n – 1)d<\/p>\na8<\/sub>\u00a0= 7 + (8 – 1)3<\/p>\n= 7 + 7 \u00d73 = 7 + 21<\/p>\n
= 28<\/p>\n
(ii) a = – 18, n = 10, an<\/sub>\u00a0= 0, d = ?,<\/p>\nan<\/sub>\u00a0= a + (n – 1)d<\/p>\na10<\/sub>\u00a0= – 18 + (10 – 1)d<\/p>\n0 \u00a0\u00a0\u00a0= -18 + 9d<\/p>\n
9d = 18<\/p>\n
<\/p>\n
(iii) \u00a0d = -3, n = 18, an<\/sub>\u00a0= -5, a = ?<\/p>\nan<\/sub>\u00a0= a + (n – 1)d<\/p>\na18<\/sub>\u00a0= a + (18 – 1)d<\/p>\n-5\u00a0\u00a0 = a + 17(- 3)<\/p>\n
-5 + 51 = a<\/p>\n
a = 46<\/p>\n
(iv) a = – 18.9, \u00a0d = 2.5, \u00a0an<\/sub>\u00a0= 3.6 \u00a0n = ?<\/p>\nan<\/sub>\u00a0= a + (n – 1)d<\/p>\n3.6 = – 18.9 + (n – 1)2.5<\/p>\n
3.6 + 18.9\u00a0\u00a0 = (n – 1)2.5<\/p>\n
(n – 1)2.5 \u00a0= 22.5<\/p>\n
<\/p>\n
(v) a = 3.5, d = 0, n = 105, an\u00a0<\/sub>= ?<\/p>\nan<\/sub>\u00a0= a + (n – 1)d<\/p>\n= 3.5 + (105 – 1)0<\/p>\n
= 3.5 + 0<\/p>\n
= 3.5<\/p>\n
Ex 5.2 Class 10 \u0917\u0923\u093f\u0924\u00a0Q2. \u00a0<\/strong>\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092e\u0947\u0902 \u0938\u0939\u0940 \u0909\u0924\u094d\u0924\u0930 \u091a\u0941\u0928\u093f\u090f \u0914\u0930 \u0909\u0938\u0915\u093e \u0914\u091a\u093f\u0924\u094d\u092f \u0926\u0940\u091c\u093f\u090f:<\/strong><\/p>\n(i) A.P: 10, 7, 4, …………………. \u0915\u093e 30 \u0935\u093e\u0901 \u092a\u0926 \u0939\u0948:<\/strong><\/p>\n(A) 97 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (B) \u00a077 \u00a0\u00a0\u00a0\u00a0 (C) \u201377 \u00a0\u00a0\u00a0 (D) \u00a0\u2013 87<\/p>\n
Solution:<\/strong><\/p>\na = 10, d = 7 – 10 = -3<\/p>\n
30 \u0935\u093e\u0901 \u092a\u0926 = ?<\/p>\n
a30<\/sub>\u00a0= a + 29d<\/p>\n= 10 + 29(-3)<\/p>\n
= 10 – 87<\/p>\n
= – 77<\/p>\n
Correct Answer: (C) – 77<\/p>\n
\n
\nCorrect Answer: (B) 22<\/p>\n
Ex 5.2 Class 10 \u0917\u0923\u093f\u0924\u00a0Q3. \u00a0\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u092e\u093e\u0902\u0924\u0930 \u0936\u094d\u0930\u0947\u095d\u0940 \u092e\u0947\u0902, \u0930\u093f\u0915\u094d\u0924 \u0916\u093e\u0928\u094b\u0902 (boxes) \u0915\u0947 \u092a\u0926\u094b\u0902 \u0915\u094b \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f |\u00a0<\/strong><\/p>\n<\/p>\n
(i) a = 2, b = ?, c = 26\u00a0<\/strong><\/p>\nSolution:\u00a0<\/strong><\/p>\n<\/p>\n
Solution:<\/strong>\u00a0(ii) \u00a0a2<\/sub>\u00a0= 13,<\/p>\n\u2234\u00a0\u00a0 a + d = 13\u00a0 ……………. (1)<\/p>\n
a4<\/sub>\u00a0= 3<\/p>\n\u2234\u00a0\u00a0 a + 3d = 3\u00a0 ……………..(2)<\/p>\n
\u0938\u092e\u0940o (2) \u092e\u0947\u0902 \u0938\u0947 (1) \u0918\u091f\u093e\u0928\u0947 \u092a\u0930<\/p>\n
a + 3d – (a + d) = 3 – 13<\/p>\n
a + 3d – a – d = -10<\/p>\n
2d = – 10<\/p>\n
<\/p>\n
d = -5<\/p>\n
d\u00a0 \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940o (1) \u092e\u0947\u0902 \u0930\u0916\u0928\u0947 \u092a\u0930<\/p>\n
a + d = 13<\/p>\n
a + (- 5) = 13<\/p>\n
a = 13 + 5<\/p>\n
a = 18<\/p>\n
a3<\/sub>\u00a0= a + 2d = 18 + 2 (-5)<\/p>\n= 18 – 10 = 8<\/p>\n
\u0905\u0924:\u00a018<\/strong>, 13,\u00a08<\/strong>, 3<\/p>\n