These NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5 Questions and Answers are prepared by our highly skilled subject experts.

## NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Exercise 10.5

Question 1.

Construct the right-angled ∆PQR, where m∠Q = 90° QR = 8 cm and PR = 10 cm. Ans: Steps of Construction

(i) Draw a rough diagram with measures marked on it.

(ii) Draw a line segment QR = 8 cm.

(iii) At Q, Construct ∠RQX = 90° .

(iv) With centre at R and radius 10 cm, draw an arc to cut QX at P.

(v) Join PR.

Thus, PQR is the required right-angled triangle.

Question 2.

Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.

Answer:

Steps of Construction

(i) Draw a rough diagram with measures marked on it.

(ii) Draw a line segment QR = 4 cm.

(iii) At Q, construct ∠RQX = 90

(iv) With R as centre and radius 6 cm draw an arc to cut QX at R

(v) Join PR.

Thus, PQR is the required right angled triangle.

Question 3.

Construct an isosceles right-angled triangle ABC, where m∠ACB = 90° and AC = 6 cm.

Answer:

Steps of Construction

(i) Draw a rough diagram with measures marked on it.

(ii) Draw a line segment AC = 6 cm.

(iii) At ‘C’, construct ∠ACX – 90°.

(iv) With centre ‘C’ and radius 6 cm, draw an arc to cut CX at B.

(v) Join AB.

Thus, ∆ABC is the required isosceles right-angled triangle.