NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.4

These NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.4 Questions and Answers are prepared by our highly skilled subject experts.

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Exercise 10.4

Question 1.
Construct ∆ABC given m∠A = 60° , m ∠B = 30 and AB = 5.8 cm.
Steps of Construction
(i) Draw a rough diagram with measures marked on it.
(ii) Draw a line segment AB = 5.8 cm.
(iii) Construct ∠BAX = 60° at A.
(iv) At B, construct ∠ABY = 30° .

(v) Let the rays AX and BY intersect at C. Thus, ∆ABC is the required triangle.

Question 2.
Construct ∆PQR if PQ = 5 cm, m∠PQR = 105° and m ∠QRP = 40°.
(Hint : Recall angle-sum property of a triangle)
Here the line segment PQ is given. We can construct the triangle, if the measure of ∠QPR is known.
∠QPR = 180° – [∠PQR + ∠QRP]
= 180°-(105°+ 40°)
= 180° – 145°
∠QPR = 35°
Steps of Construction

(i) Draw a rough diagram with measures marked on it.
(ii) Draw a line, segment PQ = 5 cm.
(iii) At P, construct ∠QPX = 35 .
(iv) At Q, construct ∠PQY = 105 .
(v) Let the rays $$\overline{\mathrm{PX}}$$ and $$\overline{\mathrm{QY}}$$ intersect at R.
Thus, ∆PQR is the required triangle.

Question 3.
Examine whether you can construct ∆DEF such that EF = 7.2 cm, m∠E = 110 and m∠F = 80°. Justify your answer.