These NCERT Solutions for Class 8 Maths Chapter 5 Data Handling Ex 5.3 Questions and Answers are prepared by our highly skilled subject experts.

## NCERT Solutions for Class 8 Maths Chapter 5 Data Handling Exercise 5.3

Question 1.

List the outcomes you can see in these experiments

(a) Spinning a wheel

(b) Tossing two coins together

Solution:

(a) Outcomes in spinning the given wheel are A, B, C, or D.

(b) Outcomes in tossing two coins together are HH, HT, TH, TT

[HT means Head on first coin + Tail on the second coin]

Question 2.

When a die is thrown, list the outcomes of an event of getting.

(i) (a) prime number

(b) not a prime number

(ii) (a) a number greater than 5

(b) a number not greater than 5

Solution:

Possible outcomes are 1, 2, 3, 4, 5 and 6

(i) (a) Outcomes are 2, 3 and 5

(b) Outcomes are 1, 4 and 6

(ii) (a) Outcomes greater than 5 is 6

(b) Outcomes of getting a number not greater than 5 are 1, 2, 3, 4 and 5

Question 3.

Find the

(a) Probability of the pointer stopping on D in (Question 1-(a))?

(b) Probability of getting an ace from a well-shuffled deck of 52 playing cards?

(c) Probability of getting a red apple. (See figure below)

Solution:

(a) On the spinning wheel there are 5 sectors containing A, B, C, and D.

Since, there is only one sector containing D,

Number of possible outcome = 1

Number of equally likely outcomes = 5

∴ Probability = \(\frac{1}{5}\)

(b) Number of possible outcomes = 52

Since there are 4 aces in a pack of 52 cards, and out of the one ace can be obtained in 4 ways

∴ Probability of getting an ace = \(\frac{4}{52}=\frac{1}{13}\)

(c) There are 7 apples in all

Possible number of ways = 7

Since there are 4 red apples

No. of equally likely outcomes = 4

∴ Probability of getting a red apple = \(\frac{4}{7}\)

Question 4.

Numbers 1 to 10 are written on ten separate slips (one number on one slip), kept in a box, and mixed well. One slip is chosen from the box without looking into it. What is the probability of?

(i) getting a number 6?

(ii) getting a number less than 6?

(iii) getting a number greater than 6?

(iv) getting a 1-digit number?

Solution:

Since there are 10 slips,

Total number of outcomes = 10

(i) We can get a slip containing the number ‘6’ only once

Number of favourable outcome = 1

∴ Probability of getting the number = \(\frac{6}{10}\)

(ii) Numbers less than 6 are 1, 2, 3, 4 and 5

No. of Favourable outcomes are 5

∴ Probability of getting a no. less than 6 = \(\frac{5}{10}=\frac{1}{2}\)

(iii) Numbers greaterthan 6 are 7, 8, 9 and 10

No. of favourable outcomes = 4

∴ Probability of getting a number greater than 6 = \(\frac{4}{10}=\frac{2}{5}\)

(iv) One-digit numbers are 1, 2, 3, 4, 5, 6, 7, 8 and 9

No. of favourable outcomes = 9

∴ Probability of getting a one-digit number = \(\frac{9}{10}\)

Question 5.

If you have a spinning wheel with 3 green sectors, 1 blue sector, and 1 red sector, what is the probability of getting a green sector? What is the probability of getting a non-blue sector?

Solution:

There are 5 sectors is all (3 green + 1 blue + 1 red)

Total possible outcomes = 5

Since there are 3 green sectors

Number of favourable outcomes = 3

∴ Probability of getting a green sector = \(\frac{3}{5}\)

Again there are 4 non-blue sectors.

Number of favourable outcomes = 4

∴ Probability of getting a non blue sector = \(\frac{4}{5}\)

Question 6.

Find the probabilities of the events given in question 2.

Solution:

When a die is thrown there are 6 outcomes in all (1, 2, 3, 4, 5 and 6)

(i) Since there are 3 prime numbers 2, 3 and 5

Number of favourable outcomes = 3

∴ Probability of getting a prime number = \(\frac{3}{6}=\frac{1}{2}\)

(ii) Since there are 3 non-prime numbers (1, 4 and 6)

Number of favourable outcomes = 3

∴ Probability of getting a non prime number = \(\frac{3}{6}=\frac{1}{2}\)

(iii) Since there is 1 number greater than 5 (i.e., 6)

Number of favourable outcome = 1

∴ Probability of number greater than 5 = \(\frac{1}{6}\)

(iv) Since there are 5 numbers which are not greater than 5 (i.e., 1, 2, 3, 4 and 5)

Number of favourable outcomes = 5

∴ The probability of a number which is not greater than 5 = \(\frac{5}{6}\)